ETM Co is considering investing in machinery costing K150,000 payable at the start of first year. The new machine will have a three-year life with K60,000 salvage value at the end of 3 years. Other details relating to the project are as follows.


Year 1 2 3


Demand (units) 25,500 40,500 23,500


Material cost per unit K4. 35 K4. 35 K4. 35


Incremental fixed cost per year K45,000 K50,000 K60,000


Shared fixed costs K20,000 K20,000 K20,000


The selling price in year 1 is expected to be K12. 00 per unit. The selling price is expected to rise by 16% per year for the remaining part of the project’s life.


Material cost per unit will be constant at K4. 35 due to the contract that ETM has with its suppliers. Labor cost per unit is expected to be K5. 00 in year 1 rising by 10% per year beyond the first year. Fixed costs (nominal) are made of the project fixed cost and a share of head office overhead. Working capital will be K35,000 per year throughout the project’s life. At the end of three years working will be recovered in full.


ETM pays tax at an annual rate of 35% payable one year in arrears. The firm can claim capital allowances (tax-allowable depreciation) on a 20% reducing balance basis. A balancing allowance is claimed in the final year of operation.


ETM uses its after-tax weighted average cost of capital of 15% when appraising investment projects. The target discounted payback period is 2 years 6 months.


Required:


a) Calculate the net present value of buying the new machine and advise on the acceptability of the proposed purchase (work to the nearest K1).


b) Calculate the internal rate of return of buying the new machine and advise on the acceptability of the proposed purchase (work to the nearest K1).


c) Calculate the discounted payback period of the project and comment on the results.


d) Briefly discuss why good projects are very difficult to find as well as challenging to maintain or sustain

To find the battery life of the latest model 10 months from now, we need to calculate the cumulative increase in battery life over the 10-month period.

The battery life of each model increases by 4% compared to the previous model. Therefore, the battery life of the second model is [tex]\displaystyle 100\% + \dfrac{4}{100} = 104\%[/tex] of the first model's battery life. Similarly, the battery life of the third model is [tex]\displaystyle 104\% + \dfrac{4}{100} = 108.16\%[/tex] of the second model's battery life, and so on.

Using this pattern, the battery life of the latest model 10 months from now can be calculated as follows:

[tex]\displaystyle 632.0 \, \text{minutes} \times \left(1 + \dfrac{4}{100}\right)^{10}[/tex]

Simplifying this expression, we get:

[tex]\displaystyle 632.0 \times \left(1.04\right)^{10}[/tex]

Calculating this expression, we find that the latest model's battery life 10 months from now is approximately 1057.1 minutes.

Therefore, the correct answer is A) 1057.1.

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The clerk sold three pieces of ribbon to different customers. The lengths of the ribbons were 3 yards, 9 yards, and 20 yards. To find the total length of the ribbon sold, we need to add the lengths of the three pieces together.

First, let's add the lengths of the ribbons:

3 yards + 9 yards + 20 yards = 32 yards.

Therefore, the total length of the ribbon sold is 32 yards.

To explain this in simpler terms, imagine you have three ribbons, one that is 3 yards long, another that is 9 yards long, and a third that is 20 yards long. If you add up the lengths of all three ribbons, you will get a total of 32 yards.

In summary, the clerk sold a total of 32 yards of ribbon, combining the lengths of the three pieces.

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The Euler's method with h = 0.5, the approximation of y(2) for the given initial value problem is -11.5.

Using Euler's method with a step size of h = 0.5, we can approximate the value of y(2) for the given initial value problem y' = 4x - 8y + 10, y(1) = 5.

Euler's method is an iterative numerical method used to approximate solutions to ordinary differential equations. It involves dividing the interval of interest into smaller steps and approximating the solution at each step based on the slope of the differential equation at that point.

To apply Euler's method, we start with the initial condition (x₀, y₀) = (1, 5) and compute the next approximation using the formula:

yₙ₊₁ = yₙ + h * f(xₙ, yₙ),

where h is the step size and f(x, y) is the differential equation.

In this case,

f(x, y) = 4x - 8y + 10.

Using h = 0.5,

we can calculate the approximation of y(2) as follows:

x₁ = x₀ + h = 1 + 0.5 = 1.5,

y₁ = y₀ + h * f(x₀, y₀) = 5 + 0.5 * (4 * 1 - 8 * 5 + 10) = -11.5.

Therefore, using Euler's method with h = 0.5, the approximation of y(2) for the given initial value problem is -11.5.

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The approximation of y(2) from the differential equation using Euler's method with a step size of 0.5 is 29.

To approximate the value of y(2) using Euler's method, we'll follow these steps:

1. Define the given differential equation: y' = 4x - 8y + 10.

2. Determine the step size, h, which is given as 0.5.

3. Identify the initial condition: y(1) = 5.

4. Set up the iteration using Euler's method:

  - Start with the initial condition: x(0) = 1, y(0) = 5.

  - Calculate the slope at (x(0), y(0)): m = 4x(0) - 8y(0) + 10.

  - Update the next values:

    x(1) = x(0) + h

    y(1) = y(0) + h * m

  Repeat the above step until you reach the desired value, x = 2.

5. Calculate the approximation of y(2) using Euler's method.

Let's go through the steps:

Step 1: The given differential equation is y' = 4x - 8y + 10.

Step 2: The step size is h = 0.5.

Step 3: The initial condition is y(1) = 5.

Step 4: Using Euler's method iteration:

For x = 1, y = 5:

m = 4(1) - 8(5) + 10 = -26

x(1) = 1 + 0.5 = 1.5

y(1) = 5 + 0.5 * (-26) = -7

For x = 1.5, y = -7:

m = 4(1.5) - 8(-7) + 10 = 80

x(2) = 1.5 + 0.5 = 2

y(2) = -7 + 0.5 * 80 = 29

Step 5: The approximation of y(2) using Euler's method is 29.

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The correct regular expressions to describe the language L = {w | na(w) is odd} are b* ab* (b* ab* ab*)* and b*a(b* ab*a)*b*.

The language L consists of strings in which the number of 'a's is odd. To construct a regular expression that describes this language, we need to consider the possible combinations of 'a's and 'b's.

The first correct expression, b* ab* (b* ab* ab*)*, breaks down as follows:

- b* matches zero or more occurrences of 'b'.

- ab* matches 'a' followed by zero or more occurrences of 'b'.

- (b* ab* ab*)* matches zero or more occurrences of 'b' followed by zero or more occurrences of 'a' followed by zero or more occurrences of 'b' followed by one or more occurrences of 'a'.

The second correct expression, b*a(b* ab*a)*b*, can be explained as:

- b* matches zero or more occurrences of 'b'.

- a matches a single occurrence of 'a'.

- (b* ab*a)* matches zero or more occurrences of 'b' followed by zero or more occurrences of 'a' followed by zero or more occurrences of 'b' followed by one or more occurrences of 'a'.

- b* matches zero or more occurrences of 'b'.

These regular expressions accurately capture the language L, as they allow for any combination of 'a's and 'b's where the number of 'a's is odd. The expressions account for the possibility of leading and trailing 'b's, as well as the presence of multiple groups of 'a's and 'b's.

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Answer:

Your answer is here 1.56666666667

Step-by-step explanation:

first make 2.35 in form of p/q then multiply by 2/3 then divide the answer

you cannot also write in fractions

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a) AD can be expressed as AD = 6a - 4b.

b) ABCD is a parallelogram.

a) To express AD in terms of 'a' and/or 'b', we can observe that AD is the difference between AB and BC. Using the given values, we have:

AD = AB - BC

= (8a + 12b) - (2a + 16b)

= 8a + 12b - 2a - 16b

= 6a - 4b

Therefore, AD can be expressed as 6a - 4b.

b) Based on the given information, the shape ABCD is a parallelogram. This is because a parallelogram has opposite sides that are parallel and equal in length, which is satisfied by the given sides AB and DC.

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The vectors 9 + 15 -3x², - 129x15x₂ and -9- 4x16x₂ are linearly independent.

The proof is as follows:Given that 0 = (9+15x-3x²)+(-12-9x15x2)+(-9-4x-16x2).

Let's rearrange the terms in the equation and simplify it:0

= (9 - 12 - 9) + (15x - 135x + 4x) + (-3x² - 15x2 - 16x²)0

= -12 - 116x² - 130x²

Since there are no values of x that make this equation true other than x = 0, the only solution is where each term in the equation is zero. Therefore, the vectors 9 + 15 -3x², - 129 x 15x2 and -9- 4x16x2 are linearly independent.

: Therefore, the vectors 9 + 15 -3x², - 129x15x2 and -9- 4x16x2 are linearly independent.

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The solution to the equation -10x - 2(8x + 5) = 4(x - 3) is x = 1/15.

To solve the equation: -10x - 2(8x + 5) = 4(x - 3), we can start by simplifying both sides of the equation:

-10x - 2(8x + 5) = 4(x - 3)

-10x - 16x - 10 = 4x - 12

Next, let's combine like terms on both sides of the equation:

-26x - 10 = 4x - 12

To isolate the variable x, we can move the constants to one side and the variables to the other side of the equation:

-26x - 4x = -12 + 10

-30x = -2

Finally, we can solve for x by dividing both sides of the equation by -30:

x = -2 / -30

x = 1/15

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The argument is valid, and the possible truth value of the conclusion is true (T).

(i) Let's define the propositional variables as follows:

P: It is going to snow.

Q: The school is closed.

The premises and conclusion can be represented as:

Premise 1: P → Q (If it is going to snow, then the school is closed.)

Premise 2: Q (The school is closed.)

Conclusion: P (Therefore, it is going to snow.)

(ii) To determine the validity of the argument, we can construct a truth table for the premises and the conclusion. The truth table will consider all possible combinations of truth values for P and Q.

(truth table is attached)

In the truth table, we can see that there are two rows where both premises are true (the first and third rows). In these cases, the conclusion is also true.

Since the argument is valid (the conclusion is true whenever both premises are true), the possible truth values of the conclusion are true (T).

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The automorphism group Aut(S) of a subfield S of Q[i, z] can be determined by examining the properties of the subfield and the elements it contains.

To list each Aut(S) (Q[i, z]), we need to consider the structure of the subfield S and its elements. Aut(S) refers to the automorphisms of the field S that are also automorphisms of the larger field Q[i, z]. The specific automorphisms will depend on the characteristics of the subfield.

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The solution to the equation is x = -5.

To solve the equation (0.8 + 0.7x) / x = 0.86, we can begin by multiplying both sides of the equation by x to eliminate the denominator:

0.8 + 0.7x = 0.86x

Next, we can simplify the equation by combining like terms:

0.7x - 0.86x = 0.8

-0.16x = 0.8

To isolate x, we divide both sides of the equation by -0.16:

x = 0.8 / -0.16

Simplifying the division:

x = -5

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The explicit formula for the nth term (an) of the sequence 27, 9, 3, ... can be expressed as an = 27 / 3^(n-1), where n represents the position of the term in the sequence.

To find the explicit formula for the nth term of the sequence 27, 9, 3, ..., we need to identify the pattern or rule governing the sequence.

From the given sequence, we can observe that each term is obtained by dividing the previous term by 3. Specifically, the first term is 27, the second term is obtained by dividing 27 by 3, giving 9, and the third term is obtained by dividing 9 by 3, giving 3. This pattern continues as we divide each term by 3 to get the subsequent term.

Therefore, we can express the nth term, denoted as aₙ, as:

aₙ = 27 / 3^(n-1)

This formula states that to obtain the nth term, we start with 27 and divide it by 3 raised to the power of (n-1), where n represents the position of the term in the sequence.

For example:

When n = 1, the first term is a₁ = 27 / 3^(1-1) = 27 / 3^0 = 27.

When n = 2, the second term is a₂ = 27 / 3^(2-1) = 27 / 3^1 = 9.

When n = 3, the third term is a₃ = 27 / 3^(3-1) = 27 / 3^2 = 3.

Using this explicit formula, you can calculate any term of the sequence by plugging in the value of n into the formula.

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The given system of differential equations is transformed into the desired form [:) = PC by replacing the derivative terms with new variables P and Q, which represent the respective derivatives in the original equations.

The given system of differential equations can be rewritten in the form:

Z' = e^(-9ty) + 8sin(t),

Y' = 7tan(t)Y + 85 - 9cos(t).

Using prime notation for derivatives, we can write the system as:

Z' = P,

Y' = Q,

where P = e^(-9ty) + 8sin(t) and Q = 7tan(t)Y + 85 - 9cos(t).

In the given system of differential equations, we have two equations:

Z' = e^(-9ty) + 8sin(t),

Y' = 7tan(t)Y + 85 - 9cos(t).

To write the system in the form [:) = PC, we use prime notation to represent derivatives. So, Z' represents the derivative of Z with respect to t, and Y' represents the derivative of Y with respect to t.

By replacing Z' with P and Y' with Q, we obtain:

P = e^(-9ty) + 8sin(t),

Q = 7tan(t)Y + 85 - 9cos(t).

Now, the system is expressed in the desired form [:) = PC, where [:) represents the vector of variables Z and Y, and PC represents the vector of functions P and Q. The vector notation allows us to compactly represent the system of equations.

To summarize, the given system of differential equations is transformed into the desired form [:) = PC by replacing the derivative terms with new variables P and Q, which represent the respective derivatives in the original equations.

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In order to determine if the trapezoids in the design are isosceles, you can measure the lengths of their bases and legs. If the trapezoids have congruent bases and congruent non-parallel sides, then they are isosceles trapezoids.

1. Identify the trapezoids in the design. Look for shapes that have one pair of parallel sides and two pairs of non-parallel sides.

2. Measure the length of each base of the trapezoid. The bases are the parallel sides of the trapezoid.

3. Compare the lengths of the bases. If the bases of a trapezoid are equal in length, then it has congruent bases.

4. Measure the length of each non-parallel side of the trapezoid. These are the legs of the trapezoid.

5. Compare the lengths of the legs. If the legs of a trapezoid are equal in length, then it has congruent non-parallel sides.

6. If both the bases and non-parallel sides of a trapezoid are congruent, then it is an isosceles trapezoid.

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The concentration of salt in the tank  is 0.87 lbs/gallon of water.

A 120-gallon tank initially contains 90 lb of salt dissolved in 90 gallons of water. Saltwater containing 2 lb salt/gallon of water flows into the tank at the rate of 4 gallons/minute. The mixture flows out of the tank at a rate of 3 gallons/minute. Assume that the mixture in the tank is uniform.

To compute for the amount of salt in the tank at any given time, we will utilize the formula:

Amount of salt in = Amount of salt in + Amount of salt added – Amount of salt out

Amount of salt in = 90 lbs

A total of 2 lbs of salt per gallon of water is flowing into the tank.

Amount of salt added = 2 lbs/gallon × 4 gallons/minute = 8 lbs/minute

The mixture flows out of the tank at a rate of 3 gallons/minute.

Therefore, the amount of salt flowing out is given by:

Amount of salt out = 3 gallons/minute × (90 lbs + 8 lbs/minute)/(4 gallons/minute)

Amount of salt out = 69.75 lbs/minute

Therefore, the total amount of salt in the tank at any given time is:

Amount of salt in = 90 lbs + 8 lbs/minute – 69.75 lbs/minute = 28.25 lbs/minute

We can compute the amount of salt in the tank after t minutes using the formula below:

Amount of salt in = 90 lbs + (8 lbs/minute – 69.75 lbs/minute) × t

Amount of salt in = 90 – 61.75t (lbs)

The total volume of the solution in the tank after t minutes can be computed as follows:

Volume in the tank = 90 + (4 – 3) × t = 90 + t (gallons)

Given that the mixture in the tank is uniform, we can now compute the concentration of salt in the tank as follows:

Concentration of salt = Amount of salt in ÷ Volume in the tank

Concentration of salt = (90 – 61.75t)/(90 + t) lbs/gallon

Therefore, the concentration of salt in the tank  is (90 – 61.75 × 150)/(90 + 150) = 0.87 lbs/gallon of water.

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To find the coordinates of point R, we can use the concept of proportionality in the line segment PQ.

The proportionality states that if a line segment is increased or decreased by a certain percentage, the coordinates of the new point can be found by extending or reducing the coordinates of the original points by the same percentage.

Given that line segment PQ is increased by 200%, we can calculate the change in the x-coordinate and the y-coordinate separately.

Change in x-coordinate:

[tex]\displaystyle \Delta x=200\%\cdot ( 1-3)=-4[/tex]

Change in y-coordinate:

[tex]\displaystyle \Delta y=200\%\cdot ( 3-4)=-2[/tex]

Now, we can add the changes to the coordinates of point Q to find the coordinates of point R:

[tex]\displaystyle x_{R} =x_{Q} +\Delta x=1+(-4)=-3[/tex]

[tex]\displaystyle y_{R} =y_{Q} +\Delta y=3+(-2)=1[/tex]

Therefore, the coordinates of point R are [tex]\displaystyle (-3,1)[/tex].

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Box R's coordinates, after a 200% increase from PQ in its lengths, are (-3, 1) as determined by multiplying PQ's x and y displacement by three and adding those to the original coordinates of P.

To solve this problem, we can use the concept of vectors and displacement. We know the line segment PQ x-displacement (x2 - x1) = 1 - 3 = -2 and its y-displacement (y2 - y1) = 3 - 4 = -1. Noting that the point R is generated by increasing the length of PQ by 200%, the displacement from P to R would be three times the displacement from P to Q. Therefore, Rx = 3*(-2) = -6 and Ry = 3*(-1) = -3. Since these displacements are measured from initial point P(3,4), the coordinates of R would be (3 + Rx, 4 + Ry) = (3 - 6, 4 - 3) = (-3, 1).

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The rational roots of the polynomial equation are -3/2, 1/2, -1, and 5/2.

To find the rational roots of the polynomial equation P(x) = 6x⁴ - 13x³ + 13x² - 39x - 15, we can use the Rational Root Theorem.

The Rational Root Theorem states that if a rational number p/q is a root of the polynomial, then p is a factor of the constant term (-15 in this case) and q is a factor of the leading coefficient (6 in this case).

To find the factors of -15, we can list all possible combinations of positive and negative factors of 15: ±1, ±3, ±5, ±15.

To find the factors of 6, we list all possible combinations of positive and negative factors of 6: ±1, ±2, ±3, ±6.

Now, we can test each combination of p and q to see if it satisfies the equation P(p/q) = 0.

By trying all the possible combinations, we find that the rational roots of P(x) = 6x⁴ - 13x³ + 13x² - 39x - 15 are:

x = -3/2, x = 1/2, x = -1, x = 5/2.

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The radius of curvature (r) is -100 cm and Magnification (m) is 11.26. The mirror is a concave mirror.

Given Data: Object distance, u = -1.03 cm; Image distance, v = 11.6 cm

To find: The radius of curvature (r) and Magnification (m).

Formula used:

1/f = 1/v - 1/u;

Magnification, m = -v/u

Calculation:

Using the formula,

1/f = 1/v - 1/u

1/f = 1/11.6 - 1/-1.03 = -0.02

f = -50 cm

The radius of curvature,

r = 2f

r = 2 × (-50) = -100 cm

Since the radius of curvature is negative, the mirror is a concave mirror.

Magnification, m = -v/u= -11.6/-1.03= 11.26

Hence, the radius of curvature (r) is -100 cm and Magnification (m) is 11.26.

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Answer:

B

Step-by-step explanation:

The domain is asking for all the values of x and according to the graph, the only values of x are in between 0 and 4, therefore B

The last digit in the product of the given expression is 3.

Here, we have,

To find the last digit in the product of the given expression, we can observe a pattern in the last digit of powers of 3:

3¹ = 3 (last digit is 3)

3² = 9 (last digit is 9)

3³ = 27 (last digit is 7)

3⁴ = 81 (last digit is 1)

3⁵ = 243 (last digit is 3)

3⁶ = 729 (last digit is 9)

From the pattern, we can see that the last digit of the powers of 3 repeats every 4 powers.

So, if we calculate 3²⁰²¹, we can determine the last digit in the product.

3²⁰²¹ can be written as

(3⁴)⁵⁰⁵ × 3

= 1⁵⁰⁵ × 3

= 3.

Therefore, the last digit in the product of the given expression is 3.

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The standard deviation of the data set is 3.66.

The mean of the data set:

= (10 + 12 + 10 + 6 + 18 + 11 + 18 + 14 + 10) / 9

= 109 / 9

= 12.11

The difference between each data point and the mean:

(10 - 12.11), (12 - 12.11), (10 - 12.11), (6 - 12.11), (18 - 12.11), (11 - 12.11), (18 - 12.11), (14 - 12.11), (10 - 12.11)

Square each difference:

[tex](-2.11)^2, (-0.11)^2, (-2.11)^2, (-6.11)^2, (5.89)^2, (-1.11)^2, (5.89)^2, (1.89)^2, (-2.11)^2[/tex]

Calculate the sum of the squared differences:

[tex]= (-2.11)^2 + (-0.11)^2 + (-2.11)^2 + (-6.11)^2 + (5.89)^2 + (-1.11)^2 + (5.89)^2 + (1.89)^2 + (-2.11)^2\\= 120.46[/tex]

Divide the sum by the number of data points:

[tex]= 120.46 / 9\\= 13.3844[/tex]

The standard deviation:

[tex]= \sqrt{13.3844}\\= 3.66.[/tex]

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The standard deviation of the given data set is approximately 3.60.

To find the standard deviation of a set of data, you can follow these steps:

Calculate the mean (average) of the data set.

Subtract the mean from each data point and square the result.

Calculate the mean of the squared differences.

Take the square root of the mean from step 3 to obtain the standard deviation.

Let's calculate the standard deviation for the given data set: 10, 12, 10, 6, 18, 11, 18, 14, 10.

Step 1: Calculate the mean

Mean = (10 + 12 + 10 + 6 + 18 + 11 + 18 + 14 + 10) / 9 = 109 / 9 = 12.11 (rounded to two decimal places)

Step 2: Subtract the mean and square the differences

(10 - 12.11)^2 ≈ 4.48

(12 - 12.11)^2 ≈ 0.01

(10 - 12.11)^2 ≈ 4.48

(6 - 12.11)^2 ≈ 37.02

(18 - 12.11)^2 ≈ 34.06

(11 - 12.11)^2 ≈ 1.23

(18 - 12.11)^2 ≈ 34.06

(14 - 12.11)^2 ≈ 3.56

(10 - 12.11)^2 ≈ 4.48

Step 3: Calculate the mean of the squared differences

Mean = (4.48 + 0.01 + 4.48 + 37.02 + 34.06 + 1.23 + 34.06 + 3.56 + 4.48) / 9 ≈ 12.95 (rounded to two decimal places)

Step 4: Take the square root of the mean

Standard Deviation = √12.95 ≈ 3.60 (rounded to two decimal places)

Therefore, the standard deviation of the given data set is approximately 3.60.

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Answer:

n^2 + 2

Step-by-step explanation:

1st term =1^2 +2 = 3

2nd term = 2^2 + 2 =6

3rd term = 3^2 + 2=11

4th term = 4^2 + 2=18

(a) Without knowing the effect size, it is not possible to calculate the type II error for the given hypothesis test. (b) To detect a true mean diameter of 1.55 inches with a power of at least 0.9, approximately 65 bearings would be needed.

(a) If the true mean diameter is 1.55 inches, the probability of not rejecting the null hypothesis when it is false (i.e., the type II error) depends on the chosen significance level, sample size, and effect size. Without knowing the effect size, it is not possible to calculate the type II error.

(b) To calculate the required sample size to detect a true mean diameter of 1.55 inches with a power of at least 0.9, we need to know the chosen significance level, the standard deviation of the population, and the effect size.

Using a statistical power calculator or a sample size formula, we can determine that a sample size of approximately 65 bearings is needed.

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The value of x is: D. x = 14.

In Mathematics, the exterior angle theorem or postulate states that the measure of an exterior angle in a triangle is always equal in magnitude (size) to the sum of the measures of the two remote or opposite interior angles of that triangle.

By applying the exterior angle theorem, we can reasonably infer and logically deduce that the sum of the measure of the two interior remote or opposite angles in the given triangle is equal to the measure of angle x (∠x);

7x - 3 = 41 + 4x - 2

7x - 4x = 39 + 3

3x = 42

x = 14

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The measure of angle TSR is 113 degrees.

To find the measure of angle TSR, we need to use the properties of angles in a triangle.

Given that ST = 3 (13/16) feet

PS = 7 feet

m∠PTQ = 67 degrees

Now we can determine the measure of angle TSR. In triangle PTS, we have two known angles:

m∠PTQ = 67 degrees

m∠PSQ = 90 degrees (since PS is perpendicular to ST).

To find m∠TSR, we subtract the sum of these two angles from 180 degrees (the total angle measure of a triangle):

m∠TSR = 180 - (m∠PTQ + m∠PSQ)

m∠TSR = 180 - (67 + 90)

m∠TSR = 180 - 157

m∠TSR = 113 degrees.

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We have found a line segment joining two lattice points whose midpoint is also a lattice point. So, among any five lattice points, there must be a pair, the midpoint of which is also a lattice point.

Let’s assume that there are five lattice points on a plane and they are represented as follows:

(x1, y1), (x2, y2), (x3, y3), (x4, y4), (x5, y5)

To prove that among any five lattice points, there must be a pair, the midpoint of which is also a lattice point, we can follow the following steps.

Step 1: Let's consider any two points from the five lattice points, and let's call them P and Q.

Their coordinates are represented as (x1, y1) and (x2, y2), respectively.

Step 2: Let's apply the midpoint formula to find the midpoint of the line segment PQ. The midpoint formula is given by,

Midpoint of PQ = ( (x1+x2)/2, (y1+y2)/2 )

We know that the sum of two integers is always an integer, and the product of two integers is always an integer. Therefore, (x1+x2) and (y1+y2) are integers, and thus the midpoint of PQ is also a lattice point.

Step 3: Let's repeat step 2 with other pairs of points. There are a total of 10 pairs of points in five lattice points, and we can apply the midpoint formula to each pair. Therefore, we have 10 midpoints.

Step 4: Let’s observe that if one of these midpoints coincides with any of the five lattice points, then we are done. If not, then each midpoint must be a new point that is not among the five lattice points. And because the coordinates of each midpoint are the average of two integer coordinates, we know that each midpoint must be a point with integer coordinates (as mentioned in step 2).

Step 5: Let’s consider two midpoints, M1 and M2, that we calculated in step 3. Since M1 and M2 are each midpoints of a line segment joining two lattice points, we know that M1M2 is also a line segment. And because the coordinates of M1 and M2 are both integers, we know that the coordinates of the endpoints of M1M2 are integers too.

Hence Proved.

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If g¹ (f(x)) = 16x² + 8x + 6and g(x) = x²+5 then (f - g) (-2) = 4(-2) - (-2)² - 4= -8 - 4 - 4= -16 and  g¹ (f(x)) = 16x² + 8x + 6.

Given that f(x) = 4x + 1 and g(x) = x² + 5

a) Find (f-g) (-2)(f - g) (x) = f(x) - g(x)

Substitute the values of f(x) and g(x)f(x) = 4x + 1g(x) = x² + 5(f - g) (x) = 4x + 1 - (x² + 5) = 4x - x² - 4

On substituting x = -2, we get

(f - g) (-2) = 4(-2) - (-2)² - 4= -8 - 4 - 4= -16

b) Find g¹ (f(x))f(x) = 4x + 1g(x) = x² + 5

Let y = f(x) => y = 4x + 1

On substituting the value of y in g(x), we get

g(x) = (4x + 1)² + 5= 16x² + 8x + 1 + 5= 16x² + 8x + 6

Therefore, g¹ (f(x)) = 16x² + 8x + 6

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The area of the regular octogon is 196.15 square inches.

For a regular octogon with apothem A and side length L, the area is given by:

area =(2*A*L) * (1 + √2)

Here we know that:

A = 7in

L = 5.8 in

Replacing these values in the area for the formula, we will get the area:

area = (2*7in*5.8in) * (1 + √2)

area = 196.15 in²

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Answer: x = 12

Step-by-step explanation:
To find the value of x, you're gonna need to know that all the angles of a triangle put together should equal 180 degrees.


We should start by adding the two angles we do have: 67 + 70 = 137.
Now that we know the amount of angle space we DO have, we need to subtract 137 from 180.
180 - 137 = 43
We now know that our missing angle has a total of 43 degrees.

Solving for x:
Now, we need to write out our problem, and we need to solve for x.
3x + 7 = 43

To solve for x, we need to get rid of the 7 first, using the inverse of addition: subtraction.
3x + (7 - 7) = (43 - 7)

The two 7s cancel out, and 43 - 7 is 36.
3x = 36

To get rid of the 3, and get x alone, we need to do the opposite of multiplication: division.
(3 ÷ 3) x = (36 ÷ 3)

Finish solving:
x = 12

Checking your work:
Implant the new value for x back into the main equation:

3(12) +7 = 43
36 + 7 = 43
43 = 43

Hope this helps you!

- Eigenvalues: λ₁ = (1 + √5)/2 and λ₂ = (1 - √5)/2.

- Eigenspaces: Eigenspace corresponding to λ₁ is span{(1 + √5)/2, 0, 0, 0}. Eigenspace corresponding to λ₂ is span{(1 - √5)/2, 0, 0, 0}.

- Diagonalizability: The matrix B is not diagonalizable.

To find the eigenvalues, eigenspaces, and determine diagonalizability for matrix B, let's proceed with the following steps:

Step 1: Find the eigenvalues λ by solving the characteristic equation det(B - λI) = 0, where I is the identity matrix of the same size as B.

B = [0 0 0 -1; 1 0 0 0; 0 1 0 -2; 0 0 1 0]

|B - λI| = 0

|0-λ 0 0 -1; 1 0-λ 0; 0 1 0-2; 0 0 1 0-λ| = 0

Expanding the determinant, we get:

(-λ)((-λ)(0-2) - (1)(1)) - (0)((-λ)(0-2) - (0)(1)) + (0)((1)(1) - (0)(0-λ)) - (-1)((1)(0-2) - (0)(0-λ)) = 0

-λ(2λ - 1) + λ + 2 = 0

-2λ² + λ + λ + 2 = 0

-2λ² + 2λ + 2 = 0

Dividing the equation by -2:

λ² - λ - 1 = 0

Applying the quadratic formula, we get:

λ = (1 ± √5)/2

So, the eigenvalues for matrix B are λ₁ = (1 + √5)/2 and λ₂ = (1 - √5)/2.

Step 2: Find the eigenspaces corresponding to each eigenvalue.

For λ₁ = (1 + √5)/2:

Solving the equation (B - λ₁I)v = 0 will give the eigenspace for λ₁.

For λ₁ = (1 + √5)/2, we have:

(B - λ₁I)v = 0

[0 -1 0 -1; 1 -λ₁ 0 0; 0 1 -λ₁ -2; 0 0 1 -λ₁]v = 0

Converting the augmented matrix to reduced row-echelon form, we get:

[1 0 0 (1 + √5)/2; 0 1 0 0; 0 0 1 0; 0 0 0 0]

The resulting row shows that v₁ = (1 + √5)/2, v₂ = 0, v₃ = 0, and v₄ = 0. Therefore, the eigenspace corresponding to λ₁ is span{(1 + √5)/2, 0, 0, 0}.

Similarly, for λ₂ = (1 - √5)/2:

Solving the equation (B - λ₂I)v = 0 will give the eigenspace for λ₂.

For λ₂ = (1 - √5)/2, we have:

(B - λ₂I)v = 0

[0 -1 0 -1; 1 -λ₂ 0 0; 0 1 -λ₂ -2; 0 0 1 -λ₂]v = 0

Converting the augmented matrix to reduced row-echelon form, we get:

[1 0 0 (1 - √5)/2; 0 1 0 0; 0 0 1 0; 0 0

0 0]

The resulting row shows that v₁ = (1 - √5)/2, v₂ = 0, v₃ = 0, and v₄ = 0. Therefore, the eigenspace corresponding to λ₂ is span{(1 - √5)/2, 0, 0, 0}.

Step 3: Determine diagonalizability.

To determine if the matrix B is diagonalizable, we need to check if the matrix has n linearly independent eigenvectors, where n is the size of the matrix.

In this case, the matrix B is a 4x4 matrix. However, we only found one linearly independent eigenvector, which is (1 + √5)/2, 0, 0, 0. The eigenspace for λ₂ is the same as the eigenspace for λ₁, indicating that they are not linearly independent.

Since we do not have a set of n linearly independent eigenvectors, the matrix B is not diagonalizable.

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