Answers
Related Questions
What amount of hydrogen peroxide should result ( theoretical yield) when 1.50g of barium peroxide is treated with 25.0 mL of hydrochloric acid solution containing 0.0272 g of HCl per mL
Answers
Answer:
[tex]m_{H_2O_2}=0.317gH_2O_2[/tex]
Explanation:
Hello!
In this case, for the chemical reaction between hydrochloric acid and barium peroxide is:
[tex]BaO_2(s)+2HCl(aq)\rightarrow H_2O_2(aq)+BaCl_2(aq)[/tex]
Thus, since the barium peroxide (169.33 g/mol) and hydrochloric acid (36.45 g/mol) are reacting in a 1:2 mole ratio, we need to identify the limiting reactant first by computing the yielded moles of hydrogen peroxide by each reactant:
[tex]n_{H_2O_2}^{by\ BaO_2}=1.50gBaO_2*\frac{1molBaO_2}{169.33gBaO_2}*\frac{1molH_2O_2}{1molBaO_2}=0.00886molH_2O_2\\\\ n_{H_2O_2}^{by\ HCl}=0.0272\frac{gHCl}{mL}*25.0mL *\frac{1molHCl}{36.46gHCl}*\frac{1molH_2O_2}{2molHCl}=0.00933molH_2O_2[/tex]
That's why the HCl is the limiting reactant, so the resulting mass of hydrogen peroxide, theoretical yield, is:
[tex]m_{H_2O_2}=0.00933molH_2O_2*\frac{34.02gH_2O_2}{1molH_2O_2}\\\\m_{H_2O_2}=0.317gH_2O_2[/tex]
Best regards!
A student is making a glucose solution. The student is using 12.55 g of glucose (C6H1206) and a 500 mL volumetric flask. Use this information to calculate the molarity of the glucose solution.
Answers
Answer:
M = 0.138 M
Explanation:
Given data:
Mass of glucose = 12.55 g
Volume of solution = 500 mL
Molarity of solution = ?
Solution:
Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.
Formula:
Molarity = number of moles of solute / L of solution
Number of moles of glucose:
Number of moles = mass/molar mass
Number of moles = 12.55 g/ 180.156 g/mol
Number of moles = 0.069 mol
Volume in L:
500 mL × 1 L /1000 mL
0.5 L
Molarity:
M = 0.069 mol / 0.5 L
M = 0.138 M
Can anybody answer this question of chemistry?
Answers
Answer:
Answer:A
Answer:AExplanation:
Answer:AExplanation:Molar Mass of glucose = (6×12)+(1×12)+(16×6)= 180g/mol
= 180g/molNumber of moles of Glucose = Mass/Molar Mass
= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180
= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778moles
= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778molesIn the balanced equation of fermentation, the ratio of glucose to ethanol is 2:1
= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778molesIn the balanced equation of fermentation, the ratio of glucose to ethanol is 2:1Therefore the number of moles of ethanol is 2×27.7778
= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778molesIn the balanced equation of fermentation, the ratio of glucose to ethanol is 2:1Therefore the number of moles of ethanol is 2×27.7778=55.5556moles
= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778molesIn the balanced equation of fermentation, the ratio of glucose to ethanol is 2:1Therefore the number of moles of ethanol is 2×27.7778=55.5556molesMass of ethanol= Molar Mass of ethanol × Number of moles
= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778molesIn the balanced equation of fermentation, the ratio of glucose to ethanol is 2:1Therefore the number of moles of ethanol is 2×27.7778=55.5556molesMass of ethanol= Molar Mass of ethanol × Number of moles={(12×2)+(1×6)+16} × 55.5556
= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778molesIn the balanced equation of fermentation, the ratio of glucose to ethanol is 2:1Therefore the number of moles of ethanol is 2×27.7778=55.5556molesMass of ethanol= Molar Mass of ethanol × Number of moles={(12×2)+(1×6)+16} × 55.5556= 46.5×55.5556
= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778molesIn the balanced equation of fermentation, the ratio of glucose to ethanol is 2:1Therefore the number of moles of ethanol is 2×27.7778=55.5556molesMass of ethanol= Molar Mass of ethanol × Number of moles={(12×2)+(1×6)+16} × 55.5556= 46.5×55.5556= 2555.55
Answer:
Answer:A
Answer:AExplanation:
Answer:AExplanation:Molar Mass of glucose = (6×12)+(1×12)+(16×6)= 180g/mol
= 180g/molNumber of moles of Glucose = Mass/Molar Mass
= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180
= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778moles
= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778molesIn the balanced equation of fermentation, the ratio of glucose to ethanol is 2:1
= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778molesIn the balanced equation of fermentation, the ratio of glucose to ethanol is 2:1Therefore the number of moles of ethanol is 2×27.7778
= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778molesIn the balanced equation of fermentation, the ratio of glucose to ethanol is 2:1Therefore the number of moles of ethanol is 2×27.7778=55.5556moles
= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778molesIn the balanced equation of fermentation, the ratio of glucose to ethanol is 2:1Therefore the number of moles of ethanol is 2×27.7778=55.5556molesMass of ethanol= Molar Mass of ethanol × Number of moles
= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778molesIn the balanced equation of fermentation, the ratio of glucose to ethanol is 2:1Therefore the number of moles of ethanol is 2×27.7778=55.5556molesMass of ethanol= Molar Mass of ethanol × Number of moles={(12×2)+(1×6)+16} × 55.5556
= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778molesIn the balanced equation of fermentation, the ratio of glucose to ethanol is 2:1Therefore the number of moles of ethanol is 2×27.7778=55.5556molesMass of ethanol= Molar Mass of ethanol × Number of moles={(12×2)+(1×6)+16} × 55.5556= 46.5×55.5556
= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778molesIn the balanced equation of fermentation, the ratio of glucose to ethanol is 2:1Therefore the number of moles of ethanol is 2×27.7778=55.5556molesMass of ethanol= Molar Mass of ethanol × Number of moles={(12×2)+(1×6)+16} × 55.5556= 46.5×55.5556= 2555.55
Write the balanced COMPLETE ionic equation for the reaction when aluminum nitrate and sodium hydroxide are mixed in aqueous solution. If no reaction occurs, simply write only NR.
Answers
Answer:See explanation
Explanation:
MOLECULAR REACTION EQUATION;
Al(NO3)3(aq) + 3NaOH(aq) --->Al(OH)3(s) +3NaNO3(aq)
complete ionic equation:
Al^3+(aq) + 3NO3^-(aq) + 3Na^+(aq) + 3OH^-(aq) ---->Al(OH)3(s) + 3Na^+(aq) + 3NO3^-(aq)
Net ionic reaction equation;
Al^3+(aq) + 3OH^-(aq) ------> Al(OH)3(s)
An oxygen atom has a mass of 2.66 x 10 g and a glass of water has a mass of 0.050 kg. Use this information to answer the questions below. Be sure your answers have the correct number of significant digits. What is the mass of 1 mole of oxygen atoms? 0x10 Х 5 ? How many moles of oxygen atoms have a mass equal to the mass of a glass of water?
Answers
Answer:
A. 16.0 grams
B. 3.1 mol of oxygen
Explanation:
A.
The oxygen atom has mass = 2.66x10^-23g
A mole of oxygen atoms can be calculated as:
[2.66x10^-23/1 oxygen atom] x [6.023x10²³ oxygen atoms/1 mol]
= 16.0 grams of oxygen
So a mole of oxygen has 16.0 grams of O2
B.
For 0.050 kg of water, we have 16.0 grams
(0.050x10³g/kg )x (1mol/16)
= 3.1 mol of oxygen
So 3.1 mol of oxygen has mass which is equal to the mass of water.
The flask contains 10.0 mL of HCl and a few drops of phenolphthalein indicator. The buret contains 0.150 M NaOH. It requires 21.4 mL of the NaOH solution to reach the end point of the titration. A buret filled with a titrant is held above a graduated cylinder containing an analyte solution. What is the initial concentration of HCl
Answers
Answer:
0.321 M
Explanation:
The neutralization reaction of HCl with NaOH is the following:
HCl(aq) + NaOH(aq) → NaCl(aq) + H₂O(l)
So, 1 equivalent of HCl reacts with 1 equivalent of NaOH. In this case:
1 equivalent HCl = 1 mol HCl
1 equivalent NaOH = 1 mol NaOH
At the equivalence point, the amount of HCl reacts completely with the added amount of titrant (NaOH). As 1 mol of reactant is calculated from the product of the molarity of the solution and the volume, in the equivalent point:
moles HCl = moles NaOH
M(HCl) x V(HCl) = M(NaOH) x V(NaOH)
We have:
M(NaOH) = 0.150 M
V(NaOH) = 21.4 mL = 0.0214 L
V(HCl) = 10.0 mL = 0.01 L
Thus, we calculate the initial concentration HCl as follows:
M(HCl) = (M(NaOH) x V(NaOH))/ (V(HCl))
= (0.150 M x 0.0214 L)/(0.01 L) = 0.321 M
A scientist measures the standard enthalpy change for the following reaction to be -17.2 kJ : Ca(OH)2(aq) 2 HCl(aq)CaCl2(s)
2 H2O(l) Based on this value and the standard enthalpies of formation for the other substances, the standard enthalpy of formation of HCl(aq) is kJ/mol.
Answers
Answer: [tex]\Delta H^{0}=-173.72[/tex] kJ/mol
Explanation: Enthalpy Change is the amount of energy in a reaction - absorption or release - at a constant pressure. So, Standard Enthalpy of Formation is how much energy is necessary to form a substance.
The standard enthalpy of formation of HCl is calculated as:
[tex]\Delta ^{0}=\Sigma H_{products}-\Sigma H_{reactants}[/tex]
[tex]Ca(OH)_{2}_{(aq)}+2HCl_{(aq)}[/tex] → [tex]CaCl_{2}_{(s)}+2H_{2}O_{(l)}[/tex]
Standard Enthalpy of formation for the other compounds are:
Calcium Hydroxide: [tex]\Delta H^{0}=[/tex] -1002.82 kJ/mol
Calcium chloride: [tex]\Delta H^{0}=[/tex] -795.8 kJ/mol
Water: [tex]\Delta H^{0}=[/tex] -285.83 kJ/mol
Enthalpy is given per mol, which means we have to multiply by the mols in the balanced equation.
Calculating:
[tex]-17.2=[-795.8+2(285.85)]-[-1002.82+2\Delta H][/tex]
[tex]-17.2=-1367.46+1002.82-2\Delta H[/tex]
[tex]2\Delta H=17.2-364.64[/tex]
[tex]\Delta H=-173.72[/tex]
So, the standard enthalpy of formation of HCl is -173.72 kJ/mol
When C2H4(g) reacts with H2O(g) to form CH3CH2OH(g) according to the following equation, energy is released into the surroundings. C2H4(g) H2O(g) CH3CH2OH(g) Is this reaction endothermic or exothermic
Answers
Answer:
Exothermic
General Formulas and Concepts:
Chemistry
Thermodynamics
Exothermic - releases heat as a productEndothermic - absorbs heat as a reactantExplanation:
We are given that the reaction takes place between C₂H₄ (g) and H₂O (g) to form CH₃CH₂OH (g) and is releasing heat.
This means that heat would be product as it is being released during the reaction.
Therefore, we have an exothermic reaction.
A metal sphere of 0.5 kg is heated to 300 o C, than dropped into a beaker holding 4.08 kg mercury at 20 o C. The temperature of the mercury stabilizes at 99o C after a couple of minutes. What metal was the sphere made of
Answers
Answer:
The metal sphere was made of iron.
Explanation:
From the question,
Heat lost by the metal sphere = heat gained by the mercury.
Cm(t₁-t₃) = C'm'(t₃-t₂)................... Equation 1
Where C = specific heat capacity of the metal sphere, m = mass of the metal sphere, C' = specific heat capacity of the mercury, m' = mass of the mercury.
t₁ = initial temperature of the metal sphere, t₂ = initial temperature of the mercury, t₃ = Final temperature of the mixture.
Make C the subject of the equation
C = C'm'(t₃-t₂)/m(t₁-t₃)................. Equation 2
Given: m = 0.5 kg, m' = 4.08 kg, t₁ = 300 °C, t₂ = 20 °C, t₃ = 99 °C
Constant: C' = 140 J/kgK.
Substitute into equation 2
C = [140×4.08×(99-20)]/[0.5×(300-99)]
C = 45124.8/100.5
C = 449.0 J/kgK.
Hence from the specific heat capacity data sheet, the metal is suspected to be made of iron.
what is the molarity of a solutoin which contains 38.5 g of sodium chloride disolved in 325 ml solution ?
Answers
Answer:
Molarity = 2.02 M
Explanation:
Given data:
Molarity of solution = ?
Mass of sodium chloride = 38.5 g
Volume of solution = 325 mL (0.325 L)
Solution:
Number of moles = mass/molar mass
Number of moles = 38.5 g/ 58.44 g/mol
Number of moles = 0.658 mol
Molarity:
Molarity = number of moles / volume of solution in L
Molarity = 0.658 mol /0.325 L
Molarity = 2.02 M
Does acid rain make new substances? Construct an argument that uses data from this investigation as evidence for your claim.
Answers
Answer:
Acid rain, like all acids, generates dissolution of chemical compounds, and reacts together with bases to be able to carry out oxide reduction reactions, which by deduction is very likely to form new substances as a result of the dissolution or acid erosion caused.
Explanation:
Acid rain is more likely to occur in large cities or large sources of pollution, since the excess of carbon dioxide in the atmosphere causes it to increase its partial pressure in a condensed way in the clouds, this is how then this cloud when being loaded with water and then generating the rain drags these masses of condensed carbon dioxide in the form of acid rain.
The degree of acidity is directly proportional to the amount of partial pressure of carbon dioxide in the atmosphere.
An irregularly-shaped piece of aluminum (Al) has a mass of 66.0 grams. What is the volume in cm³ of this piece of aluminum if its density is 2.70 g/cm³?
Answers
Answer:
[tex]V=24.45\ \text{cm}^3[/tex]
Explanation:
Given that,
Mass of a piece of Aluminium, m = 66 grams
The density of Aluminium, d = 2.70 g/cm³
We need to find the volume of this piece in cm³.
We know that,
Density = mass per unit volume
[tex]d=\dfrac{m}{V}\\\\V=\dfrac{m}{d}\\\\V=\dfrac{66\ g}{2.7\ g/cm^3}\\\\V=24.45\ \text{cm}^3[/tex]
So, the volume of the piece is [tex]24.45\ \text{cm}^3[/tex].
A substance has a density of .80g/cm3 if you have 60cm3 what is the mass?
Answers
Answer:
168.56
Explanation:
Answer:
48 grams
Explanation:
If p and V are already given, calculate m by multiplying those two values.
m = pV
m = 4/5 * 60/1
m = 240/5
m = 48 grams
The mass of that substance is 48 grams.
Using today's current price of gold - $1838.80 per troy ounce, how much are 5.17x1017 atoms of gold worth? (Hint: You will have to convert from grams to troy ounces as well.)
Answers
Answer:
0.010 $.
Explanation:
Hello!
In this case, since 1 troy ounce equals 31.1 grams, we can compute the price of gold per gram first:
[tex]1,838.80\frac{\$}{try\ ounce} * \frac{1try\ ounce}{31.1g} = 59.1\frac{\$}{g}[/tex]
Now, we need to compute the grams of copper in 5.17 x10¹⁷ atoms via the Avogadro's number:
[tex]m=5.17x10^{17}atomsAu*\frac{197.0gAu}{6.022x10^{23}atomsAu} \\\\m=1.69x10^{-4}g[/tex]
Thus, the price is:
[tex]\$ = 59.1\frac{\$}{g}*1.69x10^{-4}g \\\\\$ =0.010\$[/tex]
Best regards!
What are the ingredients in a margaritaWhat are the ingredients in a margarita drink
Answers
Answer:
cointreau, tequila,lime juice
A 2.54 g piece of zinc (density = 7.14 g/mL) is added to a graduated cylinder that contains 12.13 mL h2o. What will be the final volume reading on the graduated cylinder, in mL?
Answers
Answer: If I'm correct it's 12.54 mL but don't rely on this because I'm not sure
Explanation:
Answer:
12.49 ml
Explanation:
Density = mass / volume
Volume = mass / density
Volume of zinc = 2.54/7.14
Volume of zinc = 0.3557
Initial volume = 12.13 ml
Total volume = initial volume+ volume of zinc
Total volume = 12.13 + 0.3557
Total volume = 12.4857 = 12.49 ml
if you know an object's distance from the sun in kilometers,how can you find the distance in AU?
Answers
Answer:
We divide our value by 1.5×10⁸
Explanation:
AU is a unit to determine distance in the space.
We know that AU means astronomic unit.
The value for conversion is 1.5×10⁸ Km
1 AU = 1.5×10⁸ Km
Let's see the example:
One star is located from the sun, around 3.35×10¹⁰ Km away. To determine the distance in AU we use the conversion factor:
3.35×10¹⁰ Km . 1 AU / 1.5×10⁸ Km = 223.3 AU
Why do earthquakes occur more often in some countries than in others?
Answers
Answer:
Some places have more earthquakes than others because they sit on the edges of tectonic plates.
here is paragraph 2 and i need help pls..lmk if u need more info
Answers
Answer:
i would say the first one!
Calculate the molar mass of hafnium (II) iodide, HfI2. This is 1 Hf and 2 Iodine. No hydrogen.
Answers
An ion can be created when a .................... is lost or gained by an element.
Answers
Answer:
electron and ignore this woejdnks
A student measures 48.8 mL of concentrated nitric acid, which has a density of 1.55g/ mL. What is the mass of the acid?
Answers
The mass of the acid : 75.64 g
Further explanationGiven
volume = 48.8 ml
density = 1.55 g/ml
Required
the mass
Solution
Further explanation
Density is a quantity derived from the mass and volume
Density is the ratio of mass per unit volume
Density formula:
[tex]\large{\boxed {\bold {\rho~=~ \frac {m} {V}}}}[/tex]
Input the value :
mass = ρ x V
mass = 1.55 g/ml x 48.8 ml
mass = 75.64 g
The heat gained by the ice melted the ice and raised the temperature of the melted ice from its initial temperature to the final temperature of the water.
a. True
b. False
Answers
Answer:
True
Explanation:
When ice is heated, the ice gains heat.
This heat gained by the ice is both used to break the intermolecular forces in ice to form water, as well as to raise the temperature of the water to it's final temperature.
Calculate the number of moles of magnesium, chlorine, and oxygen atoms in 5.40 moles moles of magnesium perchlorate, Mg(ClO4)2Mg(ClO4)2. Express the number of moles of MgM, Cl Cl, and OO atoms numerically, separated by commas.
Answers
Answer:Moles of Mg, Cl, 0 = 5.40, 10.80, 43.2
Explanation:
1 mole of Mg(ClO4)2 contains 1 mole of Magnesium, Mg atoms
2 Moles of Chlorine, Cl atoms
8 Molresof Oxygen atoms
Such that to find the number of moles of each element, We have that
------1 mole Magnesum atoms/ 1 mol of Mg(ClO4)2 x 5.40 moles of magnesium perchlorate, Mg(ClO4)2 = 1 x 5.40 =5.40 moles
------2 moles ofChlorine atoms/ 1 mol of Mg(ClO4)2 x 5.40 moles of magnesium perchlorate, Mg(ClO4)2 = 2 x 5.40 = 10.80 moles
------8 moles Oxygen atoms/ 1 mol of Mg(ClO4)2 x 5.40 moles of magnesium perchlorate, Mg(ClO4)2 = 8 x 5.40 = 43.2 moles
P4010
+ 4P + 5 O2
How many moles of phosphorus would be
produced if 8.19 mol of P4010 reacted? Enter
your answer with 2 decimal places.
Answers
Answer:
32.76mole of P
Explanation:
The reaction expression is given as;
P₄O₁₀ → 4P + 5O₂
Given parameters:
Number of moles of P₄O₁₀ = 8.19mol
Unknown:
Number of moles of P produced = ?
Solution:
From the balanced reaction expression;
1 mole of P₄O₁₀ will produce 4 mole of P
8.19mole of P₄O₁₀ will therefore produce 4 x 8.19 = 32.76mole of P
PLEASE HELP!!!!!
4. Assume that the water stream is replaced by a stream of CCl4. Predict what would happen in each case:
a. charged comb
b. PVC pipe
C. charged balloon
5. Explain your predictions.
Answers
Water is a polar substance, while CCL4 is non polar, which implies that Charged comb and charged balloon will not react with CCL4 as they react with water which is polar substance.
Reactivity of carbon tetrachloride CCL4
Carbon tetrachloride CCL4 has practically no flammability at lower temperatures.
CCl4 is nonpolar because all the four bonds are symmetrical, and they are they extended in all the directions.
Water is a polar substance, while CCL4 is non polar, which implies that Charged comb and charged balloon will not react with CCL4 as they react with water which is polar substance.
However, when CCL4 is passed into PVC it will be swollen due to the presence of chlorinated hydrocarbon.
Learn more about Carbon tetrachloride here: https://brainly.com/question/10963193
#SPJ1
What is the formula for zinc fluoride?
Answers
?
Which of the following can you conclude about a particle labeled
Check all that apply.
D A. It has one nucleon.
B. It has one proton.
I C. It has no neutrons.
D. It has one neutron.
E. It is a beta particle.
F. It has one electron.
G. It is an alpha particle.
Answers
Answer:it has one proton,
and one electron
Explanation:
It has one neutron and It has one nucleon
what example best illustrates the difference between a community and a population.
Answers
Answer:
a community is a place with people and a population is like animals
Question text What is the mole fraction of benzene in a benzene-toluene solution whose vapor pressure is 51 torr at 20°C?
Answers
Answer:
Mole fraction for benzene is 0.683
Explanation:
We need to determine the colligative property about vapour pressure which formula is:
ΔP = P° . Xm
where P° is vapour pressure of pure solvent.
ΔP = Vapor pressure of pure solvent - Vapor pressure of solution
In this case, our solvent is benzene and the solute is toluene. For this colligative property vapour pressure of solution is lower than pure solvent.
P° of benzene at 20°C is 74.7 Torr
Xm is the value for the mole fraction of solute.
Let's replace data: 74.7 Torr - 51 Torr = 74.7 Torr . Xm
Xm = 0.317 → That's the mole fraction for toluene.
Then, mole fraction for benzene will be: 1 - 0.317 → 0.683