Engine 1 produces twice the power of engine 2.
If it takes engine 1 the time T to do the work W, how long does it take engine 2 to do the same work?
Express your answer in terms of some of all of the variables T and W.
T2=________________

Answers

Answer 1

Answer:

[tex]T_2=\frac{T}{2}[/tex]

Explanation:

Given that engine 1 produces twice the power of engine 2.

Let [tex]P_1[/tex] and [tex]P_2[/tex] be the power of engine 1 and engine2.

So, the power of the engine 2,

[tex]P_2 = 2P_1\cdots(i)[/tex]

As, Work = Power x time,

So, the work, W, done by an engine 1:

[tex]W=P_1\timesT\cdots(ii)[/tex]

The work, W, done by an engine 2:

[tex]W_2=P_2\times T_2\cdots(iii)[/tex]

If the work done by both the engines are the same, then

[tex]W_2=W[/tex]

[tex]\Rightarrow P_2\times T_2=P_1\timesT[/tex] [from (ii) nd (iii)]

[tex]\Rightarrow 2P_1\times T_2=P_1\timesT[/tex] [by using (i)]

[tex]\Rightarrow 2 T_2=T \\\\\Rightarrow T_2=\frac{T}{2}[/tex]

Hence, [tex]T_2=\frac{T}{2}.[/tex]

Answer 2

The time taken for engine 2 to do the same amount of work is given by:

T₂ = 2T

Let the power of the 1st engine be P₁

Let the power of the 2nd engine be P₂

Power = Work / time

From the question given above,

Engine 1 produces twice the power of engine 2.

Thus,

P₁ = 2P₂

P₂ = ½P₁

Next, we shall determine the power used by engine 1 to do the work in time T.

Work = W

Time (T₁) = T

Power (P₁) =?

Power = Work / time

[tex]P_{1} = \frac{W}{T}\\\\[/tex]

Finally, we shall determine the time taken for engine 2 to do the same work.

Work = W

Power of engine 1 (P₁) = [tex]\frac{W}{T}\\\\[/tex]

Power of engine 2 (P₂) = ½P₁

Power of engine 2 (P₂) = [tex]\frac{1}{2} (\frac{W}{T}) = \frac{W}{2T}[/tex]

Time (T₂) =?

[tex]Power = \frac{Work}{time} \\\\ P_{2} = \frac{W}{T_{2}} \\\\\frac{W}{2T} = \frac{W}{T_{2}} \\\\\frac{1}{2T} = \frac{1}{T_{2}}\\\\[/tex]

Invert

T₂ = 2T

Therefore, the time taken for engine 2 to do the same amount of work is: T₂ = 2T

Learn more: https://brainly.com/question/21822614


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A car of mass 1500 kg starting from rest can reach a speed of 20
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F=MA

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When you put on the brakes of your bike, the wheels stop
turning. Then friction between the wheels and the road slows
your bike to a stop. Which type of friction is this?
a static friction
b sliding friction
ċ fluid friction
d rolling friction
7t?
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Answer:

b

Explanation:

ibecause the wheels are sliding on the ground i think

The radius of the planet Mercury is 2.43 x 10^6m and its mass
is 3.2 x 10^23 kg. What is the speed of a satellite in orbit
265.000 m above the surface?

Answers

Hey There!_____________________________________Answer:

[tex]\huge\boxed{Option D}[/tex]

_____________________________________DATA:

Radius of Mercury = [tex]R_m[/tex] = [tex]2.43x10^6m[/tex]

Mass of Mercury = [tex]M_m = 3.2x10^{23}m[/tex]

Distance Satellite above the surface of the Mercury = d = 265,000m

Gravitational Constant =  [tex]G = 6.67x10^{-11} \frac{N.m^2}{kg^2}[/tex]

_____________________________________SOLUTION:

Since the Satellite is orbiting around the Planet Mercury, due to the centripetal force, and Centripetal force is the force that acts towards the center of the circle, Whereas The gravitational force also acts towards the center of the circle thus we can say that Centripetal force is equal or same as centripetal force.  So,

               

                                             [tex]F_g =F_C[/tex]

Fg is Given by,

                                           [tex]F_g = \frac{GM_MM_S}{r^2}[/tex]

Fc is Given by,

                                           [tex]F_c=\frac{M_SV^2}{r}[/tex]

Where,

            G is Gravitational Constant

            [tex]M_e[/tex] is mass of Planet Mercury

            [tex]M_S[/tex] is Mass of Satellite

             r(small letter) is the distance between the center of the Planet Mercury and the satellite.

             V is velocity of satellite

_____________________________________

Now,

                                 [tex]\frac{GM_MM_S}{r^2} =\frac{M_SV^2}{r}[/tex]

                         

                                 [tex]V = \sqrt\frac{GM_M}{r}[/tex]

 r can also be written as,

                           

                                  [tex]V = \sqrt\frac{GM_M}{R_M +d}[/tex]

Substitute the variables,

         

                                  [tex]V = \sqrt{\frac{(6.67x10^{-11})x(3.2x10^{23})}{2695000}[/tex]

Simplify the equation,

           

                                  V = 2814 [tex]\frac{m}{s}[/tex]

Approximately,

                                  V = 2800 [tex]\frac{m}{s}[/tex]

_____________________________________Best Regards,'Borz'

An example of a poor coping mechanism is ?

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Answer: A bad, maladaptive, unhealthy or destructive coping mechanism is one where the behavior does not resolve the problem in the long-term and may actually increase the harm. Unhealthy coping strategies may feel like they are having the desired effect in the short term.

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Which element most likely interacts with water the same way lithium interacts with water?

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Answer:

Is there a multiple choice or select all that apply? I would say Potassium (K) or Sodium (Na)

Explanation:


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Answer:

Is Mercury an answer on your thing?

Explanation:

Mercury has the least amount of gravity, so therefore you can jump the highest on Mercury.

Answer:

Jupiter

Explanation:

Jupiter has more than 300 time the mass as earth. so, it's gravitational pull is stronger.

Hopefully this helps

When momentum is conserved it is called _____. (multiple choice)
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C.) The Physics of Momentum
D.) The Rules of Momentum

Answers

Answer:

Based off the word "conserved" I would say

A. Conservation of Momentum.

Explanation:

Answer:

A.) Conservation of Momentum

Question 4 of 10
Which option is a good blackbody radiator?
O A. A lightbulb
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Answer:

A lightbulb

Explanation:

Answer:

Lightbulb

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What is the work energy transfer equation?

Answers

Answer:

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Answer:

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Answers

Answer:

Explanation:

From the question given above, the following data were obtained:

Mass (m) = 1250 kg

Velocity (v) = 20.0 m/s.

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K.E = ½mv²

Where:

K.E is the kinetic energy

m is the mass of the object

v is the velocity of the object.

Thus, we can obtain the kinetic energy of the automobile by using the above formula as illustrated below:

Mass (m) = 1250 kg

Velocity (v) = 20.0 m/s.

Kinetic energy (K.E) =?

K.E = ½mv²

K.E = ½ × 1250 × 20²

K.E = 625 × 400

K.E = 250000 J

Therefore, the kinetic energy of the automobile is 250000 J

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Answer:

a

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Answer:

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Answers

Answer:

True

Explanation:

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Jenny puts a book on her desk. Jenny’s book has an area of 200 cm2.It exerts a pressure of 0.05 N/cm2 on the desk. What is the weight of the book? *

Answers

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Answer:

Identify the object to be analyzed. For some systems in equilibrium, it may be necessary to consider more than one object. Identify all forces acting on the object. Identify the questions you need to answer. Identify the information given in the problem. In realistic problems, some key information may be implicit in the situation rather than provided explicitly.

Explanation:

Identify the object to be analyzed. For some systems in equilibrium, it may be necessary to consider more than one object. Identify all forces acting on the object. Identify the questions you need to answer. Identify the information given in the problem. In realistic problems, some key information may be implicit in the situation rather than provided explicitly.

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Answers

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Explanation:

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Answers

Answer:

45 degrees

Explanation:

Given that the coefficient of friction, [tex]\mu=1.0[/tex]

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Answer:

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Explanation:

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Answer:

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Because it weights less which means it faster and yea

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Answer:

I do drink bottled water but not to often, I live about 2.8 miles away from its water source and if i did'nt drink bottled water and I had to found out how my drinking water is treated I would go ask the people that are taking care of the water.

Explanation:

hope this helps

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Answer:

The Coriolis Effect makes things appear to move in a curve around our planet, like, for example, a plane. This is also due to the fact that our Earth is round, so nothing really moves in a straight line. It is "an effect whereby a mass moving in a rotating system experiences a force (the Coriolis force ) acting perpendicular to the direction of motion and to the axis of rotation."

Explanation:

The most important characteristic in designing the soundproof room is to create walls that

Answers

Answer:

make sound bounce off walls

Answer:

Explanation:

Walls that absorb the sound and dont just bounce or reflect the sound straight back. Like how video makers have foam walls with ridges on their walls.

A stone dropped from the top of a 80m high building strikes the ground at 40 m/s after falling for 4 seconds. The stone's potential energy with respect to the ground is equal to its kinetic energy

Answers

Answer:

A

Explanation:

Given that a stone dropped from the top of a 80m high building strikes the ground at 40 m/s after falling for 4 seconds. The stone's potential energy with respect to the ground is equal to its kinetic energy. (use 9 - 10 m/s)

O at the moment of impact

2 seconds after the stone is released after the stone has fallen 40 m

when the stone is moving at 20 m/s

At the top of the hill, the P.E = mgh

P.E = 10 × 80 × m

P.E = 800m

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A girl pushes a wagon at constant velocity. If the
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Answers

Answer; 100 m/s
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Explain you own words why energy is considered to be naturals money. Give an example to support your explanation

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Answer:

because we naturally use energy everyday in everyway , energy is also a bill for instance you electric bill used by energy

Explanation:

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Answer:

a lever that is what is used

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A car travels 14 km due west, then does a
U-turn, and travels 43 km due west.
I. What total distance has the car
traveled?
II.
What is the total displacement of the
car?
III. If the entire trip took 3.20 hours.
determine the average speed of the
car. Give
your answer in both
km hour, and m s. (show
conversion)
IV. If the entire trip took 2.50 hours.
determine the average velocity of
the car. Give your answer in both
km h, and mph (show conversion)

Answers

Explanation:

It is given that,

A car travels 14 km due west, then does a U-turn and travels 43 km due east (when it takes U-turn, it will change direction from west to east)

i. Total distance = total path covered

= 14 km + 43 km

= 57 km

ii. Let east is positive and west is negative.

Displacement = final position-initial position

= 43-14

= 29 km

iii. If time taken in the entire trip = 3.2 hours

Average speed = distance/time

[tex]s=\dfrac{57\ km}{3.2\ h}\\\\=17.81\ km/h[/tex]

1 km/h = 0.2777 m/s

17.81 km/h = 4.94 m/s

iv. If time taken in the entire trip = 2.5 hours

Average velocity = displacement/time

[tex]v=\dfrac{29\ km}{2.5\ h}\\\\=11.6\ km/h[/tex]

1 km/h = 0.621 mph

11.6 km/h = 7.2 mph

Henc, this is the required solution.

A book that weighs 5 N sits on a table. What force does the table apply to the book?

Answers

Answer:

E =F.d =[1/2]mv^2

mad = [1/2]mv^2

d= v^2/2a ,v=u+at , v^2 = [at]^2 since u=0

So d = at^2/2

F = ma= 20a= 50 , a=5/2 and t=2

so d = [5/2][2^2]/2=5

Explanation:

Every action has an equal and opposite reaction. It is an action-reaction principle. Therefore the table exerts a force of 5 N on the book in order to be in stable condition.

What is Newton's third law of motion?

Newton's third law of motion state that every action has an equal and opposite reaction. It is an action-reaction principle. It stated that the force always exists in a pair.

Therefore the table exerts a force of 5 N on the book in order to be in stable condition.

The given data in the problem is ;

W is the weight of the book sits on table = 5N

N is the normal force on the book

From the equilibrium equation ;

Weight -Normal force on the book  =0

Weight =Normal force on the book

The normal force on the book =5N

Hence the table exerts a force of 5 N on the book in order to be in stable condition.

To learn more about Newton's third law of motion refer to the link;

https://brainly.com/question/1077877

An astronaut rides in a circular training accelerator at 16 m/s. If the radius of the accelerator is 8.0 meters, what is his centripetal acceleration? m/s2 Enter the answer Submit Answer I don't know this mprove this question​

Answers

Answer:

[tex]a=32\ m/s^2[/tex]

Explanation:

Given that,

The velocity of an astronaut in a circular path, v = 16 m/s

The radius of the accelerator, r = 8 m

We need to find his centripetal acceleration. The formula that is used to find the centripetal acceleration is given by :

[tex]a=\dfrac{v^2}{r}\\\\a=\dfrac{(16)^2}{8}\\\\a=32\ m/s^2[/tex]

So, the required centripetal acceleration is [tex]32\ m/s^2[/tex].

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