Ellie’s new kitten is 412 inches long. Her rabbit is 325 inches longer than her kitten. Which equation can be used to find the length of Ellie’s rabbit, r? A.412−325=r
B.325+412=r C.412−r=325 D.325+r=412

Answers

Answer 1

The equation can be used to find the length of Ellie’s rabbit, r is B. 325+412=r

What is an equation?

In mathematics, an equation is a formula that expresses the equality of two expressions by connecting them with the equal sign = .

Now it is given that,

Ellie’s new kitten length = 412 inches

Ellie's rabbit length = r

Since it is said in the question that,

Ellie's rabbit is 325 inches longer than her kitten

Therefore,

rabbit length = 325 + Ellie’s new kitten length

Put the values,

r  = 325 + 412

Hence,The equation can be used to find the length of Ellie’s rabbit, r is B. 325+412=r

More about equations :

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Related Questions

Find the area of the circle. Use 3.14 for pi

Answers

Answer:

b) 153.86 m^2

Step-by-step explanation:

Area=Pi x R^2

Area=3.14 X 7^2

Area=3.14 x 49

Area=153.86

d. 38.47 [tex]m^{2}[/tex]

circumference is 21.99114858.

diameter is 7.000000002.

radius is 3.500000001.

area is 38.48451003.

Hope I helped you!Succes!

A piece of paper is to display 150, space square inches of text. If there are to be one-inch margins on the sides and the top and a two-inch margin at the bottom, what are the dimensions of the smallest piece of paper that can be used? Choose 1 answer:

Answers

Answer:

[tex]Height = 8.660\ in[/tex]

[tex]Width = 17.321\ in[/tex]

Step-by-step explanation:

Given

[tex]Area= 150in^2[/tex]

[tex]Side\ Margin = 1\ in[/tex]

[tex]Top\ \&\ Bottom\ Margins = 2\ in[/tex]

Required

Determine the smallest dimension to use

To answer this question, I'll make use of the attached figure as a point of reference.

The area of the printed matter is:

[tex]Area = Length * Width[/tex]

[tex]A_1 = H * W[/tex]

Substitute 150 for A1

[tex]150 = H * W[/tex]

Make H the subject

[tex]H = \frac{150}{W}[/tex]

The area of the full paper is:

[tex]Area = Length * Width[/tex]

[tex]A_2 = (W + 2+2) * (H + 1 + 1)[/tex]

[tex]A_2 = (W + 4) * (H + 2)[/tex]

Substitute 150/W for H

[tex]A_2 = (W + 4) * (\frac{150}{W} + 2)[/tex]

Open brackets

[tex]A_2 = W(\frac{150}{W} + 2) + 4(\frac{150}{W} + 2)[/tex]

[tex]A_2 = 150 + 2W + \frac{600}{W} + 8[/tex]

Collect Like Terms

[tex]A_2 =2W + \frac{600}{W} + 8+150[/tex]

[tex]A_2 =2W + \frac{600}{W} + 158[/tex]

Differentiate with respect to w and set the result to 0

[tex]A_2' = 2 - \frac{600}{W^2} + 0[/tex]

[tex]A_2' = 2 - \frac{600}{W^2}[/tex]

Set to 0

[tex]0 = 2 - \frac{600}{W^2}[/tex]

Collect Like Terms

[tex]2 = \frac{600}{W^2}[/tex]

Cross Multiply

[tex]2 * W^2 = 600[/tex]

Make [tex]W^2[/tex] the subject

[tex]W^2 = \frac{600}{2}[/tex]

[tex]W^2 = 300[/tex]

Take positive square root of both sides

[tex]W = 17.321[/tex]

Recall that:

[tex]H = \frac{150}{W}[/tex]

[tex]H = \frac{150}{17.321}[/tex]

[tex]H = 8.660[/tex]

Hence, the smallest dimension of the paper is:

[tex]Height = 8.660\ in[/tex]

[tex]Width = 17.321\ in[/tex]

Answer:

H=18

W=12

Step-by-step explanation:

The question says 1 inch margins on the sides AND the top. And THEN a 2 inch margin ONLY on the bottom.

First, solve for y,

A = xy

150 = xy

150/x = y

If the center dimensions is A and its it equals x*y, then plus the margins, the outer dimensions would just be x+(size of margins) for width and y+(size of margins) for height.

This gives us

Width: x + 2

Height: y + 3  

Putting height into terms of x: (Substitute y) = 3 + 150/x

Now, since the area of a rectangle is b*h, the equation is:

(x + 2)(3 + 150/x)

Simplify:

3x + 150 + 6 + 300/x

= 3x + 156 + 300/x

Next, we find the derivative of this and then solve for x.

= 3 - 300/x^2

Solving for x:

0 = 3 - 300/x^2

3 = 300/x^2

3x^2 = 300

x^2 = 100

x = 10

Now that we have x, we plug this into the different equations for height and base:

Base=(10) + 2 = 12

Height=3 + 150/(10) =3+15 = 18

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Answers

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Answer:

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Answer:

Step-by-step explanation:

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Answers

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Answers

Answer:

The question is not written, so i will answer in a general way.

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Let's define the function:

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Step-by-step explanation:

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Step-by-step explanation:

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Answers

Answer:

There's a very simple way to solve this kind of problem. All we have to do is change the percent to a decimal and multiply it by her current grade.

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look above

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Answer:

Step-by-step explanation:

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Answers

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[tex]\boxed{\large{\bold{\blue{ANSWER~:) }}}}[/tex]

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Answers

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Answers

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Step-by-step explanation:

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Answers

Answer

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874

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Answers

Quick answer :

[tex]= \tt\$570[/tex]

Answer with steps :

Money Dayami earns for an hour's work = $10.50

Number of hours Dayami worked last week = 40

Money Dayami would have gotten for her work :

[tex] =\tt 10.50 \times 40[/tex]

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Answers

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