Answer:
17.7kg/[tex]m^{2}[/tex]
Explanation:
BMI =
= [tex]\frac{weight (kg)}{height (m) . height (m)}[/tex]
= 47kg/(1.63m×1.63m)
= 17.689kg/[tex]m^{2}[/tex]
≈ 17.7kg/[tex]m^{2}[/tex]
How much work is done when a force of 33 N pulls a wagon 13 meters?
*Round your answer to the nearest whole number.
Answer:
Work = (force) x (distance)
Work = (33N) x (13m) = 429 N-m = 429 joules
IF the force is in exactly the same direction as the motion of the wagon.
Explanation:
pa mark ng brainliest
the following can increase the amount of friction in the surface, except ______.
a. glue
b. paper
c. lubricant
d. foil
Answer:
c. lubricant..........
Which will be different on the moon than it is on Earth?
weight
mass
Answer:
Below
Explanation:
On the moon, an objects weight will be different than it is on earth. This is because we cannot change the mass of an object, the mass of an object is the measure of matter an object has. However the weight is depended on the gravitational pull of whatever planet you are on. In this case, weight will be lighter on the moon than it is on earth because the moon's gravitational pull is 1.62 m/s^2 while earths is around 9.8 m/s^2.
Hope that helps!
Mercury’s natural state is where the atoms are close to each other but are still free to pass by each other. In which state(s) could mercury naturally exist?
Answer:
Mercury's natural state is where the atoms are close to each other but are still free to pass by each other. In which state(s) could mercury naturally exist?
Liquid is the answer
Explanation:
Using public transports.
Turn off the lights when not in use
Recycle and Reuse
No to plastic bags
Reduction of forest fires and smoking
Use of fans instead of Air Conditioner
Use filters for chimneys
Avoid usage of crackers
how do I put this in a paragraph.
a tube of constant circular cross-section, sealed at on end, contains an ideal gas trapped by a cylinder of mercury of length 0.035m. The whole arrangement is in the Earth's atmosphere. The density of mercury is 1.36*10^4, more details provided in the images.
Answer:
P V = N R T ideal gas equation
V = .19 * A volume of enclosed gas
.19 P = N R T / A using volume of enclosed gas
P = Po + Phg pressure on gas = atmospheric (Po) + Phg pressure due to column of mercury
.19 (Po + Phg) = N R T / A which is what was asked
Note Phg = density of Hg * height of Hg * acceleration due to gravity
A tube of constant circular cross-section, sealed at on end, contains an ideal gas trapped by a cylinder of mercury of length 0.035m. There will atmospheric pressure and pressure due to mercury column on trapped gas column having length 0.19m which is given by,
(p₀+pm)×0.190 = nRT÷A.
What is Pressure?Pressure is defined as force per unit area. i.e. P = F/A it gives the force on unit area. its SI unit is Pascal (Pa) which is equal to N/m². is a scalar quantity. its dimensions are [M¹ L⁻¹ T⁻²].
Looking at the figure from top to bottom, we can see the top end of the tube is opened. There is 0.035m of mercury column below which we have a air 0.190m of gas column.
We can feel the physics behind this figure what is happening here, top of the tube is open so there is atmospheric pressure acting on the mercury column and mercury column is above the gas column, it means that both atmospheric pressure and mercury pressure will act on gas column.
i.e. (p₀+pm) = pressure on the air column
this (p₀+pm) is downward pressures, hence gas inside the tube gets compressed due to this pressure because bottom end is closed. it means that back pressure will be created inside the gas in upward direction and both pressures becomes equal at equilibrium.
i.e. (p₀+pm) = back pressure inside the gas column......1)
according to ideal gas equation, PV=nRT
pressure inside the air column is P = nRT÷V
where V is volume of gas that is A×0.190.
P = nRT÷(A×0.190).....( back pressure inside the gas column).
equation 1 becomes
(p₀+pm) = nRT÷(A×0.190).
Hence we get
(p₀+pm) ×0.190= nRT÷(A).
Hence proved.
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Block 1, of mass m1, moves across a frictionless surface with speed ui. It collides elastically with block 2, of mass m2, which is at rest (vi=0). (Figure 1)After the collision, block 1 moves with speed uf, while block 2 moves with speed vf. Assume that m1>m2, so that after the collision, the two objects move off in the direction of the first object before the collision. What is the final speed vf of block 2?
The conservation of the momentum allows to find the velocity of the second body after the elastic collision is:
[tex]v_f = \frac{2u_o}{1- \frac{m_2}{m_1} }[/tex]
the momentum is defined by the product of the mass and the velocity of the body.
p = mv
The bold letters indicate vectors, p is the moment, m the mass and v the velocity of the body.
If the system is isolated, the forces during the collision are internal and the it is conserved. Let's find the momentum is two instants.
Initial instant. Before crash.
p₀ = m₁ u₀ + 0
Final moment. After crash.
[tex]p_f = m_1 u_f + m_2 v_f[/tex]
The momentum is preserved.
p₀ = [tex]p_f[/tex]
[tex]m_1 u_o = m_1 u_f + m_2 v_f[/tex]
Since the collision is elastic, the kinetic energy is conserved.
K₀ = [tex]K_f[/tex]
½ m₁ u₀² = ½ m₁ [tex]u_f^2[/tex] + ½ m₂ [tex]v_f^2[/tex]
Let's write our system of equations.
[tex]m_1 u_o = m_1 u_f + m_2 v_f \\m_1 u_o^2 = m_1 u_f^2 + m_2 v_f^2[/tex]
Let's solve
[tex]u_f = u_o - \frac{m_2}{m_2} \ v_f \\u_f^2 = u_o^2 - \frac{m_2}{m_1} \ v_f^2[/tex]
[tex]( u_o - \frac{m_2}{m_1} v_f)^2 = u_o - \frac{m_2}{m_1} \ v_f^2 \\u_o^2 - 2 \frac{m_2}{m_1} \ u_o v_f + (\frac{m_2}{m_1} )^2 v_f^2 = u_o^2 - \frac{m_2 }{m_1} \ v_f^2[/tex]
[tex]2 \frac{m_2}{m_1} \ u_o = \frac{m_2}{m_1} v_f \ ( 1 - \frac{m_2}{m_1}) \\v_f = \frac{2u_o}{1-\frac{m_2}{m_1} }[/tex]
In conclusion, using the conservation of momentum, we can find the velocity of the second body after the elastic collision is:
[tex]v_f = \frac{2u_o}{1-\frac{m_2}{m_1} }[/tex]
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According to the table, what was the hiker's average speed for
the entire hike?
A: 2.0 km/h B: 5.7 km/h C: 6.7 km/h D: 10 km/h
Answer:
6.7 km/h (C)
Explanation:
According to the table, the hiker's average speed for the entire hike would be 6.7 kilometers/hour.
What is speed?The total distance covered by any object per unit of time is known as speed. It depends only on the magnitude of the moving object. The unit of speed is a meter/second. The generally considered unit for speed is a meter per second.
The total distance traveled by the hiker = 4 kilometers + 6 kilometers + 4 kilometers west + 6 kilometers north
= 20 kilometers
The total time is taken by the hiker = 45 min + 60 min + 30 min+ 45 min
= 180 min
=3 hours
The average speed of the hiker = 20 kilometers / 3 hours
= 6.7 kilometers / hours
Thus, the hiker's average speed for the entire hike would be 6.7 kilometers/hour.
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Two cars A and B are moving along a straight road in the OPPOSITE direction with velocities of 25 km/h and 40 km/h, respectively. Find the velocity of car B relative to car
Answer:
65km/h
Explanation:
Here,
Relative velocity of car moving in different directions with different velocities =Va + Vb
=25+40
=65 km/h
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A. Read these sentences carefully. Choose the correct form of adjectives.
1. Solomon is the
king of all.
a wise
b. wiser
c. wisest
2. Yogurt is
than candies.
a delicious b. more delicious c. most delicious
3. Mayon Volcano is the
volcano for me.
a most majestic b. more majestic
c. majestic
4 My father is an
man
a industrious b. more industrious c. most industrious
5. I was the
when my friend graduated with honors.
a happy b. happier
c. happiest
Answer:
1. wisest
2. more delicious
3. majestic (not sure about this one)
4. industrious
5. happiest
Look at the diagram shown below. The reading on ammeter 1 is 0.15 A. What will the reading on ammeter 2 be
There's no way to tell, without knowing the resistance of either X-1 or X-2, or the reading on A3.
Four landing sites are proposed for a lander. Data about the sites are listed in the table. A 3 column table with 4 rows. The first column is labeled landing site with entries W, X, Y, Z. The second column is labeled height above surface in meters with entries 32, 16, 35, 12. The last column is labeled acceleration due to gravity in meters per second squared with entries 1. 6, 3. 7, 1. 6, 3. 7. At which landing site would the lander have the greatest amount of gravitational potential energy? W X Y Z.
Answer:
its B just finished
Explanation:
Answer:
The answer above is correct! The correct option is B.
Explanation:
Just took the review on edge :)
Hope this helped - brainliest would be appreciated!
Have a great day everyone :D
You and your friend are pushing a box at the same constant speed. You pushed 20 feet in 10 minutes, your friend was pushing for 5 minutes. What distance must she travel so the two of you can travel at the same speed?
Answer:
60 N.C
Explanation:
The box will move in the direction of the push and pull with a force of 60 N. C.
If you and your friend are pushing a box at the same constant speed. You pushed 20 feet in 10 minutes, your friend was pushing for 5 minutes. , then the distance must she travel so the two of you can travel at the same speed would be 30 feet.
What is speed?The total distance covered by any object per unit of time is known as speed. It depends only on the magnitude of the moving object.
As given in the problem If you and your friend are pushing a box at the same constant speed. You pushed 20 feet in 10 minutes, your friend was pushing for 5 minutes.
The distance traveled by box = 20 + 10
= 30 feets
Thus, the distance must she travel so the two of you can travel at the same speed would be 30 feet.
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The spark plugs are threaded into the top of each cylinder and provide a place for the spark to jump within the ________.
Answer:
"the spark plug gap"
The plug provides a gap between the input voltage and the ground supplied by the car chassis.
which is not a general characteristic of starburst galaxies?
Starburst galaxies is simply known as the rate at which the galaxy is now converting gas into stars. The statement that is not a general characteristic of starburst galaxies is that The "starburst" is thought to be caused by the presence of a supermassive black hole in the galaxy's center.
The starburst galaxy is also regarded as the free quantity of gas with which stars can be formed.They are known to be rare. A starburst is known to be an astrophysical process. It is the process of star formation happening at a rate that is large when compared to the rate that is often observed.
See full question below
Which is not a general characteristic of starburst galaxies?
The "starburst" is thought to be caused by the presence of a supermassive black hole in the galaxy's center. The observed features that us to classily a galaxy as a 'starburst" galaxy must be only temporaryphenomena in the galaxy' Supernovae occur so frequently that their effects combine to drive a galactic wind that blows material into intergalactic space. The galaxy's rate of star formation is many times higher than the rate of star formation in the Milky WayLearn more from
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Image credit: The Hubble Heritage Team (AURASTSCI/NASA)
To which category does galaxy #2 belong? Why does it belong in this category?
WRITER
Can i ask u a question
how to do the next ques for moreBrainliest me please
Which statement describes the flow of heat? Question 8 options: Heat moves from a warmer object to a cooler object. Heat moves from a cooler object to a warmer object. Heat moves from a cooler object to a warmer object. Heat moves only between two cold objects.
Answer:
A
Explanation:
HELPPPPPPPPPPPPPPPPPPP
Answer:
directly proportional
Explanation:
What kind of feature results from the convergence of two oceanic plates?
A.
island arcs
B.
massive continental volcanoes
C
rift valleys
D.
tall mountain ranges
Answer:
A
Explanation:
Convergence is pushing them together so C is out of the question.
B and D are wrong because it is an oceanic plate. B and D are for continental plates.
A rock excerts a pressure of 20 N/cm^2 on the ground. what does 20N/cm^2 mean?
A force of __________ acts on each _________ of area
Answer:
A force of 20N acts on each cm^2 of area
2hrt 20 min +60 sec
Answer:
2hr 21 min
Explanation:
0 days 2 hours 20 minutes 0 seconds
+ 0 days 0 hours 0 minutes 60 seconds
= 0 days 2 hours 21 minutes 0 seconds
A rock on the moon has 0.5kg. It is brought to Earth where the gravitational field is stronger. On Earth, the rock will have:
a) Less mass and same weight
b) The same mass and more weight
c) Less mass and less weight
d) The same mass and same weight
Answer:
Explanation:
It will be B.
The correct answer is the same mass and less weight.
What happens to the weight of an object when it is brought from the moon to the Earth?
The weight decreases. Your weight will be 1/6 of the weight on the moon that you had on Earth. This is because the mass of the moon is less hence the gravitational pull is very low compared to Earth.
What happens to the mass of an object when you take it to the moon?
Therefore, the mass of an object on the Moon remains the same as its mass on Earth. But its weight gets less because the gravity on the moon is less than on the Earth.
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Suppose measure the mass of an orange. Then you peel the orange and separate out the slices. If you measure the orange peel and all the slices, will that mass equal the mass of the whole orange?
yes
no
The mass of the orange after it has been cut into pieces will still remain the same as the mass of the whole orange.
Let us recall that the law of conservation of mass states that, mass can neither be created nor destroyed but is converted from one form to another. In accordance with this law of conservation of mass. The mass of the orange must remain the same after it has been cut in pieces.
Hence, If the mass of an orange is measured after it has been cut into pieces, the mass of the orange after it has been cut into pieces will still remain the same as the mass of the whole orange.
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Fuses of ________________________
a. same kind are used for different purposes
b. different kind are used for different purposes
c. both of the above are correct
d. none of these
Answer:
C
Explanation:
fuses of same kind can be used for different things, and of different kinds could be used for different things as well.
who agree?? with this
Explanation:
ME!!!!!!!!!!!!!!!!!!
Answer:
I Fully Agree with this becoz it is only the key...
Do u agree?
Two cars a and b are moving along a straight road in the same direction with velocities of 25km/h and 40km/h . Find the velocity of car b relative to car a
Please find attached photograph for your answer.
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1. A stone is thrown vertically upward with velocity of 15 m/s at the same time, 10 m vertically above a second stone is allowed to fall. After what time and at what height do they collide (take g = 10 ms^-2)
Let the ball at the ground be A and that at the top be B.
Assume that you see the motion of A while sitting at B.
You(B) are obviously at rest w.r.t. yourselves. However you(B) and A have the same acceleration in the same direction. Thus acceleration of A w.r.t. you(B) is 0.
Thus, to you, it will appear as if A is travelling towards you with an uniform speed of 20m/s.
Dividing the distance 20m with that speed, we get that A reaches you(B) in 1s.
Now, you have considered these motions and time by assuming you were stationed at B. However, the time taken for A to meet B shouldn't be dependent on which reference frame you assume. Thus, time taken for A and B to collide is 1s.
Since B falls freely, he covers a distance of 1/2(g)(1²)=5 (assuming g = 10m/s²)
Thus, they meet at a height of (20–5)m = 15m from the ground.
how can the motion of an object that is already moving change?
Answer: A force can change the direction in which an object is moving
Explanation: A bigger force of an object will produce a bigger change in motion
A car goes from 60 m/s to 75 m/s in 10 seconds.calculate the car’s acceleration?
Explanation:
Uhhhh here is an example
a=vt. =27 m/s10 s. =2.7 m/s2.
[tex]▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪[/tex]
Acceleration of the car is ~
[tex] \boxed{1.5 \: \: m/s}[/tex]
[tex] \large \boxed{ \mathfrak{Step\:\: By\:\:Step\:\:Explanation}}[/tex]
We know that,
Acceleration = rate of change in velocity ~
that is ~
[tex]a = \dfrac{v - u}{t} [/tex]where,
v = final velocityu = initial velocity t = time taken ~now, let's solve ~
[tex]a = \dfrac{75 - 60}{10} [/tex][tex]a = \dfrac{15}{10} [/tex][tex]a = 1.5 \: \: m/s[/tex]if you exert a force on an object, but the object remains stationary as you apply the force, then how much work have you done on the object?
Answer:
no work done
Explanation:
unless you moved the object
When we apply a force on an object, but the object remains at rest when the force is applied, then we have zero work done on the object because the object does not move.
What is Work done?Work done by a force is defined as the product of the displacement and the component of the force exerted by the object in the direction of displacement. Work done is expressed as:
Work done= Force* Displacement
When an object is at rest, there is no external force on it except gravity acting on it, in which case work will be zero because the force acting on it is perpendicular. Thus displacement is zero and if displacement is zero then work done will be zero.
Suppose that displacement is zero then,
W=f×0
Work done is zero
Thus, the work done is zero.
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