help do number 16 and 17
Answer:
16 is d and i have no idea for 17
Determine the weight of a 10.0-kg person who is running with a speed of 5.0 m/s. Enter a
numerical answer.
Answer:
weight=mass*gravity
weight=10.0*10
so weight=100N
16. True/False: Protons are exchanged between objects by induction
chemical formulawhat is the chemical formula
Answer: A chemical formula is a way of showing and representing information about a chemical proportion of atoms that constitute a particular chemical compound or molecule
The gradual change in a species over time is called
a.
mutation.
b.
evolution.
c.
migration.
d.
variation.
PLZ HURRY WILL GIVE BRAINLIEST
Answer: B. Evolution
Explanation:
As species grow older over time they will gradually evolve through natural selection and evolution.
The gradual change in a species over time is known as evolution (b).
The process of evolution occurs through several mechanisms, including mutation, migration, and natural selection.
Mutation (a) is the spontaneous change in the genetic material of an organism. These changes can result in new traits that may be advantageous, disadvantageous, or neutral for survival. When mutations occur, they can introduce genetic variation within a population, which serves as the raw material for evolution.
Natural selection is a crucial factor driving evolution. Individuals with advantageous traits that better suit their environment are more likely to survive and reproduce, passing on these advantageous traits to their offspring. Over generations, the frequency of beneficial traits increases in the population, leading to the adaptation and evolution of the species.
Variation (d) encompasses the differences in physical traits and genetic makeup among individuals within a population. This variation is essential for evolution to occur since it provides the raw material for natural selection to act upon.
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A car starts from rest and accelerates for 2.9 s
with an acceleration of 2 m/s2.
How far does it travel?
Answer in units of m.
Answer:
[tex]a \: = \frac{v - u}{t} [/tex]
2 = v-0/2.9
2× 2.9 = v
v = 5.8 m/s
[tex]v \: = \frac{d}{t} [/tex]
5.8 = d/2.9
5.8×2.9 = d
d = 16.82 m
An object has an acceleration of 6m/s/s. If the net force was tripled and the mass was doubled, then the new acceleration would be
A football player kicks a football off a tee with a speed of 21 m/s at an angle of 51°. what is the horizontal component of the velocity?
Answer:
The horizontal component of the velocity is approximately 13.22 m/s
Explanation:
The velocity of the kick which the football player gives the ball = 21 m/s
The angle of the path taken by the ball = 51°
The velocity can be represented vectorially, showing the vertical and horizontal components as follows;
v = 21 × cos(51°)·[tex]\hat i[/tex] + 21 × sin(51°)·[tex]\hat j[/tex]
Where we have;
The horizontal component of the velocity = 21 × cos(51°)
The vertical component of the velocity = 21 × sin(51°)
Therefore;
The horizontal component of the velocity = 21 × cos(51°) ≈ 13.22 m/s
The horizontal component of the velocity ≈ 13.22 m/s.
Activity 3. Let's Do The Mathi
Direction: Use Newton's second law equation to solve for force, mass, and acceleration
Problem 1- A ball with a mass of 0.5 kg is hit with a force of 2.5N. What is its acceleration?
Problem 2- What is the acceleration of a 15kg box that is pushed across a horizontal surface
with a force of 50N?
Problem 3- An object with a mass of 2.0 kg has a force of 5.0 N applied to it. What is the
resulting acceleration of the object?
Problem 4- An object with a mass of 3.0 kg accelerates 2.5 m/s2 when an unknown force is
applied to it. What is the amount of the force?
Problem 5- An object accelerates 12.0 m/s2 when a force of 6.0 N is applied to it. What is the
mass of the object?
Answer:
Problem 1-
The acceleration = 5 m/s²
Problem 2 -
The acceleration = 3.[tex]\overline 3[/tex] m/s²
Problem 3 -
The acceleration = 2.5 m/s²
Problem 4-
The force applied = 7.5 N
Problem 5-
The mass of the object, = 0.5 kg.
Explanation:
Problem 1-
The mass of the ball, m = 0.5 kg
The force (applied) with which it was hit, F = 2.5 N
The acceleration, a = Force/Mass = 2.5 N/(0.5 kg) = 5 m/s²
The acceleration = 5 m/s²
Problem 2 -
The mass of the box, m = 15 kg
The force (applied) with which it was hit, F = 50 N
The acceleration, a = Force/Mass = 50 N/(15 kg) = 10/3 = 3.[tex]\overline 3[/tex] m/s²
The acceleration = 3.[tex]\overline 3[/tex] m/s²
Problem 3 -
The mass of the object, m = 2.0 kg
The force (applied) with which it was hit, F = 5.0 N
The acceleration, a = Force/Mass = 5.0 N/(2.0 kg) = 2.5 m/s²
The acceleration = 2.5 m/s²
Problem 4-
The mass of the object, m = 3.0 kg
The acceleration, a, of the object = 2.5 m/s²
The force applied to it, F = Mass × Acceleration = 3.0 kg × 2.5 m/s² = 7.5 N
The force applied = 7.5 N
Problem 5-
The acceleration, a, of the object = 12 m/s²
The force applied, F = 6.0 N
The mass of the object, m = Force/Acceleration = 6.0 N/(12 m/s²) = 0.5 kg
The mass of the object, = 0.5 kg.
how can magnetic potential energy be transferred to kinetic energy
Answer:
A magnetic force can convert kinetic energy stored in a magnetic field to potential energy. Kinetic energy can convert potential energy stored in a gravitational field. A magnetic energy can convert potential energy stored in a gravitational field to kinetic energy.
Help PLZ ;)
If the distance between two objects increases, what happens to the force of gravity between them?
(A) Increases
(B) Decreases
(C) Stays the same
Answer:
B) Decreases
Explanation:
Gravitational force is inversely proportional to distance. As distance between 2 objects increase, gravitational force between the 2 objects decreases.
Hope this helps!
Answer:
The answer would be B
Explanation:
Which information did the Glomar Challenger study in 1968?
Answer:
c
Explanation:
i took the test
The planet's hawks and block their near each other in the door again system the dworkin's have very advanced technology and a dork and scientist want to increase the pull of gravity between the 2 planets which proposals with the scientists make to accomplish this goal check all that aply
Answer: A,B, and E
Explanation: Just checked I got them right:)
What is the speed of an object that travels 60 meters in 4 seconds?
a) 240 m/s
b) 15 m/s
c) 0.067 m/s
d) 15 mph
Answer:
B) 15 m/s
Explanation:
Since most of the answer choices are in m/s, you can try dividing 60 meters/4 seconds in order to get the seconds on the bottom to become 1 second.
You want to find how many meters the object can travel in 1 second, rather than 4 seconds.
[tex]\frac{60 \ m}{4 \ s} \div \frac{4}{4} = \frac{15 \ m}{1 \ s}[/tex]Now you can see that for every 1 second of time, the object can travel 15 meters. This corresponds to answer choice B) 15 m/s.
The last option, D, is incorrect because we are not dealing with hours as our unit of time. We are dealing with seconds.
Answer:
b) 15 m/s
hope it help you
Alguien ayudeme con estos problemas de fisica porfa 1. Una persona recorre 4200 m en 25 minutos, luego 4.54 Km en un hora y finalmente 9000 m en 55 minutos. Halle, el tiempo total empleado en minutos, su velocidad y rapidez. 2. Una partícula en una circunferencia de 40 cm de diámetro da 30 vueltas completas en dos minutos. Halle la velocidad y rapidez de la partícula. 3. Una persona da 500 pasos de 40 cm al oeste, luego 400 pasos de 35 cm al norte y finalmente 300 pasos de 30 cm al este utilizando en total 2 min y 120 segundos. Halle la distancia recorrida, desplazamiento, velocidad y rapidez. 4. Una persona recorre una pista circular de 250 metros de radio, ¿Cuál es su distancia, desplazamiento, velocidad y rapidez en dar media vuelta a la pista si el tiempo empleado es de 90 segundos
Answer:
1) t_total = 140 min , v = 126.7 m / min , 2) v = 0.628 m / s ,
3) v = 0.592 m / s , θ = -39.3 º
Explanation:
Here we have some short kinematics problems
1) d₁ = 4200 m at T1 = 25 min
d₂ = 4.54 km at t2 = 1 h
d₃ = 9000 m at t3 = 55 min
of the statement the direction of each route is the same
Let's reduce the distances to the SI system
d₂ = 4.54 km (1000 m / 1 km) = 4540 m
t₂ = 1 h (60 min / 1 h) = 60 min
Total time is
t_total = t1 + t2 + t3
t_total = 25 + 60 +55
t_total = 140 min
the distance is
d_total = 4200 + 4540 +9000
d_total = 17740 m
with movement it is in one dimension and all displacement is in the same direction, distance equals displacement.
Speed is
v = 17740/140
v = 126.7 m / min
in the direction of travel
Speed is the modulus of speed
| v | = 126.7 m / min
2) the angular velocity is
w = θ / t
In this exercise
t = 2 min (60 s / 1min) = 120 s
θ = 30 rev (2π rad / 1 rev) = 60π rad
w = 60π / 120
w = 1.57 rad / s
linear velocity is
v = w r
v = 1.57 0.40
v = 0.628 m / s
velocity is the speed tangential to the trajectory
3) the data for this exercise are
distance = (number of steps) (distance of one step)
d₁ = 500 0.40 m = 200 m West
d₂ = 400 0.35 m = 140 m North
d₃ = 300 0.30 m = 90 m East
in a total time of t = 2 min and 120 s
t = 2 60 + 120 = 240 s
the distance traveled is
x axis we assume the direction towards + x (East) positive
x_total = d₃ -d₁
x_total = 90-200 = -110 m
y axis
y_total = d₂
y_total = 140 m
we use the Pythagorean theorem to find the distance0
D = √ (x_total² + y_total²)
D = √ (110² + 90²)
D = 142.13 m
The speed is
v = D / t
v = 142.13 / 240
v = 0.592 m / s
speed is
v = 0592 m / s
tan θ = Y / X
θ = tan -1 y / x
θ = tan -1 (90 / (- 110))
θ = -39.3 º
4) This angle is measured on the positive side of the x axis in a clockwise direction
θ = 1.5 rev (2π rad / 1 rev) = 3π rad
t = 90 s
the angular velocity is
w = θ / t
w = 3πi / 90
w = 0.1047 rad / s
the speed is
v = w R
v = 0.14047 250
v = 26.17 m / s
velocity is tangent to path
How long would it take Jesse with an acceleration of -2.50 m/s2 to bring his bicycle with an initial velocity of 13.5 m/s to a complete stop?
Answer: 5.4 seconds
Explanation:
The time taken to stop the bicycle is 5.4 seconds. The final velocity is zero. Then, the distance travelled by the bicycle is 36.45 m.
What is acceleration ?Acceleration is a physical quantity that, measures the rate of change in velocity. It is a vector quantity thus having both magnitude and direction. It can be defines as the ratio of change in velocity to the change in time.
Given initial velocity = 13.5 m/s
final velocity is zero since the bicycle is stopping.
then Δt = Δv/a
Δt = 13.5 m/s/ 2.50 m/s² = 5.4 seconds.
Hence, the bicycle will take 5.4 s to complete stop.
The distance covered within this time can be determined using the equation as follows:
s = ut + 1/2 at²
where u is the initial velocity
s = (13 m/s × 5.4 s) + (-2.50 m/s² ×5.4 s ×5.4 s) = 36.4 m.
Therefore, the bicycle will travel up to 36.4 m before stopping.
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A mover applies a net force of 28 N to a sofa that has a mass of 70 kg.
What will the sofa's acceleration be?
Answer: .4 m/s^2= acceleration
Explanation:
f = m*a
We can rearrange this equation to solve for acceleration. Therefore,
a=f/m
a= 28N/70kg
a= 0.4 m/s^2
1. Which of the following provides a correct answer for a problem that can be solved using the kinematic equations?
A A body starts from rest and accelerates at 8 m/s/s for 3 s. The body's final
position is 32 m.
B A body starts from rest and accelerates at 8 m/s/s for 3 s. The body's final
velocity is 16 m/s
C A body starts from rest and accelerates at 8 m/s/s for 3 s. The body's travels a
distance of 16 m
A body starts from rest and accelerates at 8 m/s/s for 3 s. The body's final
velocity is 24 m/s
E A body starts from rest and accelerates at 8 m/s/s for 3 s. The body's final
position is 30 m.
1 of 14
2
3
5 6 7 8
9
Answer:
12
Explanation:
12
Explain how if a solid, liquid, and gas are put into individual containers how they fill the container.
Answer:
serial in which container is filled
Solid -base of container
Liquid- above solid
Gas- above liquid
Explanation:
If any mixture of matter in different state (that solid , liquid or gas )are kept in any container, then substance with higher density will be settled at lowest surface first and similarly the substance with lowest density will be at upper part of container.
In the given container we have to keep solid, liquid and gas
sold has the highest density,gas the lowest density andliquid has the density higher than gas but less than solid.based on this
solid will be at surface of container
above sold will be liquid
above liquid will be presence of Gas
serial in which container is filled
Solid -base of container
Liquid- above solid
Gas- above liquid
please can i have help with this question
Two ropes are attached a wagon one horizontal to the west with a tension force of 75N and other east and at an angle of 38 degrees upward from horizontal with a lension force of 125 N Find the components of the net force on the cart Show your work
Answer:
The components of the net force acting on the cart are;
Horizontal force, Fₓ ≈ 23.5 N acting east
The vertical force, [tex]F_y[/tex] ≈ 76.96 N
Explanation:
The parameters given in the question are;
The magnitude of the force on the rope acting horizontally to the west = 75 N
The magnitude of the force on the other rope east acting at an angle to the horizontal = 125 N
The angle to the horizontal of the force on the other rope east to the horizontal = 38°
Therefore, we have;
The horizontal component of the force acting east = 125 × cos(38°) ≈ 98.5 N
The net sum of the horizontal forces, ∑Fₓ noting that the horizontal forces are acting in opposite direction is given as follows;
∑Fₓ = 75 - 125 × cos(38°) = 75 - 98.3 = -23.5N
Given that the difference in forces is negative, and hat we took the force acting east as negative, we have that the net horizontal force is acting east with a horizontal component of 23.5N
The net vertical force, ∑F[tex]_y[/tex], is given as follows;
∑F[tex]_y[/tex] = 125 × sin(38°) ≈ 76.96 N
Therefore, the components of the net force acting on the cart are;
Horizontal force, Fₓ ≈ 23.5 N, the vertical force, [tex]F_y[/tex] ≈ 76.96 N
The components of the net force on the cart are 23.5 Newton and 76.96 Newton.
Given the following data:
Tension force (horizontal) due west = 75 NTension force (horizontal) due east = 125 NAngle of inclination = 38°To find the components of the net force on the cart:
First of all, we would determine the horizontal component of the force acting due east.
[tex]F_y = Fcos(\theta)\\\\F_y = 125cos(38)\\\\F_y = 125 \times 0.7880\\\\F_y = 98.5 \; Newton[/tex]
Next, we would find the resultant horizontal forces:
[tex]\sum F_y = F + F_y\\\\\sum F_y = 75 + (- 98.5)\\\\\sum F_y = -23.5 \;Newton[/tex]
Therefore, the horizontal component of the net force acts in the opposite direction due east.
Horizontal component of the net force = 23.5 Newton
For the vertical component of the net force:
[tex]\sum F_x = Fsin(\theta)\\\\\sum F_x = 125cos(38)\\\\ \sum F_x = 125 \times 0.6157\\\\ \sum F_x = 76.96\; Newton[/tex]
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Why should you never do an exercise such as the bench press without a spotter?
Answer:
you could hurt yourself
Explanation:
Answer
You should never do an exercise such as the bench press without a spotter because you could hurt yourself or push your self too much.
Explanation:
Which property describes the number of waves that move past a point each second.
A) Speed
B) Frequency
C) Period
D) Wavelength
Answer:B) Frequency
Explanation:
Answer:
B) Frequency
Explanation:
can you help me doing an essay about actual self
Answer:
yes absolutely
Explanation:
why not
m1=200g m2=150g
find the acceleration
the track is horizontal and frictionless
Answer:
50 or 1.3333
Explanation: Explanation you cancel out the mass and the force to see what your acceleration would be or you could divide F by M
You walk east for 30 m, then decide to walk north foranother 30 m. What is the angle of direction of your displacement?
Answer:
Displacement is 42.426 m NE and the angle is opposite/adjacent or 30/30 which would equal 1 degree which doesn't seem right but hopefully its an answer.
Explanation:
Give reasons.
a. A stretched catapult has potential energy.
b A stone on ground has zero energy.
C. Rolling a drum is work against friction.
d. Lifting a stone is work against gravity.
e. Work and energy both have same unit.
How do you find the distance a object has traveled
Answer: Got this from a web search... Change the answer up a bit
Explanation:
The distance travelled is the path taken by a body to get from an initial point to an end point in a given period of time, at a certain velocity. If the velocity is constant: Distance = time * velocity. d = v*t.
Answer:
I researched and found it to be TIME * VELOCITY ( d= v*t)
Explanation:
When I use * I just mean multiply. So its time 'multiplied by velocity' in order to get 'distance'
Who am I answer key
Answer:
huh
Explanation:
What would you not find on an acceleration graph? *
O pie chart
O x axis
O time
O velocity