Mathematics High School

El largo de una casa es el triple de su ancho. Si a la longitud se suma 40 metros y al ancho 1 metro, el área se triplica

Answers

Answer 1

Answer:

el ancho es de 8 metros y el largo es 3 * 8 = 24 metros

width is 8 meters and length is 3*8= 24 meters

Step-by-step explanation:

Spanish

Si el ancho de la casa de la casa es x, entonces el largo de la casa es 3x.

Entonces el área = largo * ancho

área = 3x * x = 3x²

3 multiplicado por área = 9x²

9x² = (3x + 40) (x + 1)

9x² = 3x² + 3x + 40x +40

9x² = 3x² + 43x +40

0 = -6x² + 43x +40

0 = 6x²- 43x - 40

6x²- 43x - 40 = 0

Usando ecuación cuadrática

a = 6, b = -43, c- = -40

x = - b ± √b²- 4ac / 2a

x = 43 ± √1849- 4 (6) (- 40) / 12

x = 43 ± √1849 + 960/12

x = 43 ± 53/12

x = 43+ 53/12 y x = 43-53 / 12

x = 96/12 y x = -10/12

x = 8 y x = - 5/6

Ignorando el valor negativo x = 8 el ancho es de 8 metros y el largo es 3 * 8 = 24 metros

English

The length of a house is three times its width. If 40 meters are added to the length and 1 meter to the width, the area is tripled

If the width of the house of the house is x then the length of the house is 3x.

Then the area = length * breadth

area= 3x*x= 3x²

3 times area= 9x²

9x²= (3x+40 )(x+1)

9x²= 3x²+ 3x +40x +40

9x²= 3x²+ 43x  +40

0 = -6x²+ 43x  +40

0 = 6x²- 43x - 40

6x²- 43x - 40= 0

Using quadratic equation

a= 6 , b= -43 , c-= -40

x= - b±√b²- 4ac/ 2a

x= 43±√1849- 4(6)(-40)/ 12

x= 43±√1849+960/ 12

x= 43± 53/ 12

x= 43+ 53/ 12  and x= 43- 53/ 12

x= 96/ 12       and x= -10/ 12

x= 8    and x= - 5/6

Ignoring the negative value  x= 8  width is 8 meters and length is 3*8= 24 meters

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