Each state imposes its own excise tax on gasoline. Suppose, for example, that the state of Massachusetts imposes a state gasoline tax of $0.26 per gallon. Suppose further that an average of 1,022,000 gallons of gasoline per day were sold in Massachusetts in 2010.

Answers

Answer 1

Complete question :

Each state imposes its own excise tax on gasoline. Suppose, for example, that the state of Massachusetts imposes a state gasoline tax of $0.26 per gallon. Suppose further that an average of 1,022,000 gallons of gasoline per day were sold in Massachusetts in 2010. The average revenue from gasoline tax in 2010 is approximately?

Answer:

$265,720

Step-by-step explanation:

Given that:

State gasoline tax = $0.26 per gallon

Average number of gasoline sold per day = 1,022,000 gallons

. From the availabke information given :

Revenue generated = gasoline tax per gallon multiplied by the average number of gallons sold

= $0.26 * 1,022,000

= $265,720

Answer 2

The average revenue from gasoline tax in 2010 is $265,720.

Calculation of the average revenue:

Since the state of Massachusetts imposes a state gasoline tax of $0.26 per gallon. Suppose further that an average of 1,022,000 gallons of gasoline per day

So, here the average revenue should be

= 0.26 of 1,022,000

= $265,720

hence, The average revenue from gasoline tax in 2010 is $265,720.

This is an incomplete question. Please find the complete details below.

Each state imposes its own excise tax on gasoline. Suppose, for example, that the state of Massachusetts imposes a state gasoline tax of $0.26 per gallon. Suppose further that an average of 1,022,000 gallons of gasoline per day were sold in Massachusetts in 2010. The average revenue from gasoline tax in 2010 is approximately?

Learn more about revenue here: https://brainly.com/question/16834673


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-----------------------------------

Explanation:

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This means that

DF = 0.67*AC

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Side note: AC and DF are the first and last letters of ABC and DEF respectively. This is why AC and DF correspond together.

===========================================================

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-----------------------------------

Explanation:

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new side = (scale factor)*(old side)

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Answers

Answer:

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Answer:

Step-by-step explanation:

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Find an equation of the line perpendicular to the graph of 10x - 5y = 8 that passes through the point at (-4, 7).
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a.
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b.
d.
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Answer:

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Answers

Answer && Step-by-step explanation:

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Answers

Answer:

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Answers

9514 1404 393

Answer:

maximum: 12at x = 0

Step-by-step explanation:

The x-term has even degree so is never negative. The x-term is subtracted from 12, so the maximum value of the function will be found where x=0. That value is 12 -0 = 12.

  f(0) = 12 . . . . absolute maximum

Answer:

The function [tex]f(x)=12-6x^4[/tex] has an absolute maximum value of [tex]12[/tex] and this occurs at [tex]x $\ equals 0.[/tex]

Step-by-step explanation:

The maximum value of this function is at 12, because if you rewrite this function:

[tex]f(x)=-6x^4+12[/tex]

The +12 is the k-value (the graph of this function is a parabola) of the vertex form of a quadratic. Just a reminder:

Vertex form of a parabola:

[tex]a(x-h)^2+k[/tex]

You can see the 12 is the k-value. The k-value of the vertex form is the vertical shift of the parabola, meaning that this parabola is shifted 12 units upwards.

Since the parabola opens down (you can tell by the negative a-value [tex]-6[/tex]), there is a maximum value at the k-value, i.e. the vertical shift.

[tex]f(x)=-6x^4+12[/tex] has an absolute maximum value of [tex]12[/tex].

To find where the maximum value occurs at, the formula:

[tex]-\frac{b}{2a}[/tex]

Tells us the x-value of the vertex of the parabola, whose y-value is the maximum value.

Using our rearranged equation, the a, b, and c-values are:

[tex]a=-6[/tex][tex]b=0[/tex][tex]c=12[/tex]

Plug in the a and c values into the formula to find the x-value of the maximum point:

[tex]-\frac{b}{2a}[/tex][tex]-\frac{(0)}{2(-6)}=0[/tex]

Therefore, the absolute maximum value of 12 occurs at x = 0.

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