Draw the major organic product in the reaction scheme. Be sure to clearly show stereochemistry (if applicable). The starting material is an alkyne where carbon 1 is bonded to cyclopentane and carbon 2 is bonded to H. Step 1 is N a N H 2. Step 2 is C H 3 I. Step 3 is sodium in liquid ammonia. Draw the major organic product.

Answer:

[tex]\frac{250}{3}[/tex]

Explanation:

you can expect to get a 3 (theoretically) 1 time every 6 times you roll. A 1/6 chance.

Here's the equation:

[tex]\frac{1}{6} =\frac{x}{500}[/tex]

cross multiply (i think that's what it is called)

500=6x

divide by 6 on both sides:

x=[tex]\frac{250}{3}[/tex] or approx 83 times.

Hope this helps! Lmk if u have more questions <3

Answer:

(J) All organisms are composed of cells

Answer:

H2O2 reduces itself to H2O and also oxidizes to O2 simultaneously thereby acting both as an oxidizing and reducing agent .

Explanation:

When

H2O2 acts as an oxidizing agent

H2O2 + 2e- 2H+--->   2H2O

Reducing agent

H2O2 --> O2 + 2e + 2H+

H2O2 reduces itself to H2O and also oxidizes to O2 simultaneously thereby acting both as an oxidizing and reducing agent .

Covalent bonding involving covalent bonds is depicted between these two atoms as they form diatomic molecule.

Covalent bond is defined as a type of bond which is formed by the mutual sharing of electrons to form electron pairs between the two atoms.These electron pairs are called as bonding pairs or shared pair of electrons.

Due to the sharing of valence electrons , the atoms are able to achieve a stable electronic configuration . Covalent bonding involves many types of interactions like σ bonding,π bonding ,metal-to-metal bonding ,etc.

Sigma bonds are the strongest covalent bonds while the pi bonds are weaker covalent bonds .Covalent bonds are affected by electronegativities of the atoms present in the molecules.Compounds having covalent bonds have lower melting points as compared to those with ionic bonds.

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Answer:

what is the volume of the water at 307 k?

Answer:

A

Explanation:

Law of conservation of matter

Answer:

It will go faster each time because she is stirring therefore the water can get to the salt faster than it just sitting at the top

Explanation:

The 3.13 g of K would be needed to completely react with the remaining [tex]Cl_2[/tex].

To determine which reactant is limiting, we need to calculate the amount of product that can be formed from each reactant and compare them. The reactant that produces less product is the limiting reactant, since the reaction cannot proceed further once it is consumed.

The balanced chemical equation for the reaction between solid potassium and chlorine gas is:

2 K(s) + [tex]Cl_2[/tex](g) -> 2 KCl(s)

From the equation, we can see that 2 moles of K react with 1 mole of [tex]Cl_2[/tex] to form 2 moles of KCl.

First, we need to convert the masses of K and [tex]Cl_2[/tex] into moles:

moles of K = 15.20 g / 39.10 g/mol = 0.388 mol

moles of [tex]Cl_2[/tex] = 2.830 g / 70.90 g/mol = 0.040 mol

Now, we can use the mole ratio from the balanced equation to calculate the theoretical yield of KCl from each reactant:

Theoretical yield of KCl from K: 0.388 mol K x (2 mol KCl / 2 mol K) = 0.388 mol KCl

Theoretical yield of KCl from [tex]Cl_2[/tex]: 0.040 mol [tex]Cl_2[/tex] x (2 mol KCl / 1 mol [tex]Cl_2[/tex]) = 0.080 mol KCl

We can see that the theoretical yield of KCl from K is 0.388 mol, while the theoretical yield of KCl from [tex]Cl_2[/tex] is 0.080 mol. Therefore, the limiting reactant is [tex]Cl_2[/tex], since it produces less product.

To determine how much more of the limiting reactant would be needed to completely consume the excess reactant, we can use the stoichiometry of the balanced equation.

We know that 1 mole of [tex]Cl_2[/tex] reacts with 2 moles of K to produce 2 moles of KCl. Therefore, the amount of additional K needed to react with the remaining [tex]Cl_2[/tex] can be calculated as follows:

moles of K needed = 0.040 mol [tex]Cl_2[/tex] x (2 mol K / 1 mol [tex]Cl_2[/tex])

                                = 0.080 mol K

This means that 0.080 moles of K would be needed to completely consume the remaining [tex]Cl_2[/tex]. We can convert this to a mass by multiplying by the molar mass of K:

mass of K needed = 0.080 mol K x 39.10 g/mol

                              = 3.13 g K

Therefore, The 3.13 g of K would be needed to completely react with the remaining.

Example verification:

Suppose we had an additional 0.50 g of [tex]Cl_2[/tex] in the reaction. Would all of the K be consumed, or would there still be excess K?

Moles of additional [tex]Cl_2[/tex] = mass of [tex]Cl_2[/tex] / molar mass of [tex]Cl_2[/tex]

Moles of additional [tex]Cl_2[/tex] = 0.50 g / 70.90 g/mol

Moles of additional [tex]Cl_2[/tex] = 0.0070 mol

The theoretical yield of KCl that can be formed from the additional [tex]Cl_2[/tex] is:

0.0070 mol [tex]Cl_2[/tex] x (2 mol KCl / 1 mol [tex]Cl_2[/tex]) x (74.55 g KCl / 1 mol KCl) = 1.04 g KCl

Therefore, the total amount of KCl that can be formed from all of the [tex]Cl_2[/tex] is:

5.95 g + 1.04 g = 6.99 g

The amount of K that would be needed to completely consume all of the [tex]Cl_2[/tex].

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Answer:

C

Explanation:

The correct option is option C. which is "are in motion".

All the particles inside an object have kinetic energy, which implies that the particles are moving. Kinetic energy is the force that drives an object's or its constituent parts in motion. As a result, it can be inferred from this fact that the object's particles are in motion.

Options A, B, and D are not necessarily true based on the given information. The fact that particles have kinetic energy does not imply that they contain the same atoms (option A), are hotter than their surroundings (option B), or are covalently bonded (option D). These characteristics are not directly related to the presence of kinetic energy in particles.

Therefore, option c is the correct option.

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Answer:

the answer is like same we do last I know the answer I will help you to get more questionable and paste it to you do you know what time you do it me william and paste Now bro hurry up please and then let's go play with me again Go to bed ️ I don't know what to do patch right Now or just a question for you to get more questionable

Answer:

D Both are made of rock ,ice and solar dust from the beginning of the solar system

Answer:

The answer is D

Explanation:

Answer:

The final volume will be "70.08 mL".

Explanation:

The given values are:

Molar mass,

M1 = 548 nM

or,

     = [tex]5.48\times 10^{-7} \ M[/tex]

M2 = 484 nM

or,

      = [tex]4.84\times 10^{-7} \ M[/tex]  

Volume,

V1 = 61.9 mL

V1 = ?

By using the expression, we get

⇒ [tex]M1\times V1=M2\times V2[/tex]

or,

⇒            [tex]V2=\frac{M1\times V1}{M2}[/tex]

By substituting the values, we get

                    [tex]=\frac{5.48\times 10^{-7}\times 61.9}{4.84\times 10^{-7}}[/tex]

                    [tex]=\frac{339.212}{4.84}[/tex]

                    [tex]=70.08 \ mL[/tex]

Answer:

The activated complex

Explanation:

The activated complex are the species that exists maximum in every energy profile of a reaction.

Activated complex is nothing but an intermediate state of reactants formed during its conversion from a reactant to product state in coarse of reaction.

The activated complex is formed at the maximum energy level in the reaction path. And this difference between energy of the activated complex and the energy of the reactants is only known as activation energy

Answer:

don't get the question2

Answer:

An atom with one or two valence electrons more than a closed shell The number of valence electrons of an element can be determined Groups 3-12 (transition metals), 2* (The 4s shell is complete and cannot hold any more electrons)  in explaining the molecular structure of many organic compounds.

Explanation:

Answer:

Radioactive decay is a random event.

Explanation:

on edge

Answer:

Radioactive decay is a random event.

Explanation:

Edge 2020

Explanation:

The number of moles of Al2O3 formed is approximately 4.25 moles. Second find the limiting reactant. Since O2 has less value that is 2.126 than Al that is 2.287, O2 is the limiting reactant in this reaction.

Answer:

89 L

Explanation:

Step 1: Given data

Step 2: Calculate the final volume of the weather balloon

If we assume that the gas inside the balloon behaves as an ideal gas, we can calculate the final volume of the gas using the combined gas law.

P₁ × V₁ / T₁ = P₂ × V₂ / T₂

V₂ = P₁ × V₁ × T₂ / T₁ × P₂

V₂ = 0.97 atm × 105 L × 293 K / 318 K × 1.05 atm = 89 L

Answer:

1.44 g

Explanation:

From the question given above, the following data were obtained:

Number of mole of HCl = 0.06 mole

Mass of Mg =?

From the question given above, we discovered the number of mole of HCl is equivalent to the number of mole of Mg. Thus,

Number of mole of Mg = number of mole of HCl

Number of mole of Mg = 0.06 mole

Finally, we shall determine the mass of Mg. This can be obtained as follow:

Number of mole of Mg = 0.06 mole

Molar mass of Mg = 24 g/mol

Mass of Mg =?

Mass = mole × molar mass

Mass of Mg = 0.06 × 24

Mass of Mg = 1.44 g

Therefore, the mass of magnesium is 1.44 g

Answer:

1280.5g

Explanation:

Answer:

2.39 atm

Explanation:

We'll begin by calculating the number of mole in 0.41 g of neon (Ne). This can be obtained as follow:

Mass of Ne = 0.41 g

Molar mass of Ne = 20 g/mol

Mole of Ne =.?

Mole = mass / molar mass

Mole of Ne = 0.41 / 20

Mole of Ne = 0.0205 mole

Next we shall convert 200 mL to L.

1000 mL = 1 L

Therefore,

200 mL = 200 mL × 1 L / 1000 mL

200 mL = 0.2 L

Next, we shall convert 11 °C to Kelvin temperature.

T(K) = T(°C) + 273

T(°C) = 11 °C

T(K) = 11 + 273

T (K) = 284 K

Finally, we shall determine the pressure. This can be obtained as follow:

Mole of Ne (n) = 0.0205 mole

Volume (V) = 0.2 L

Temperature (T) = 284 K

Gas constant (R) = 0.0821 atm.L/Kmol

Pressure (P) =?

PV = nRT

P × 0.2 = 0.0205 × 0.0821 × 284

P × 0.2 = 0.4779862

Divide both side by 0.2

P = 0.4779862 / 0.2

P = 2.49 atm

Therefore, the pressure of the gas is 2.39 atm

Answer:

Salty

Explanation:

Becuase sugar isn't good for you. Unless the sweet foods are fruits but like deserted aren't good for you

Answer:

Salty

Explanation:

Too sweet foods would just crush you, but with salt at least you can drink water :)

50500Nm^2 or 5.05Nm^2

Explanation:

so bring out the parameters

p1= 0.12dm3, T1= 60c , because temperature is in kelvin add 273= 333k, v1= 0.12dm3 , T2= to the same value because the temperature didn't change = 333k, v2= 0.24dm3,P2= ?

general gas equation p1v1 over T1 = P2V2 over T2, when you input everything or make p2 the subject of the formula first you'll get the answer, pressure can have an s.i unit of mmhg but I'm using the same si unit as the question given and always check your units in the question to convert. please if this question has options please check, I don't want you to fail so verify from others if I made a mistake

Answer:

See EXPLANATION

Explanation:

We must bear in mind that in balancing chemical reaction equations, the number of atoms of each element on the right hand side must be the same as the number of atoms of the same element on the left hand side of the reaction equation. This follows from the law of conservation of mass.

Based on this;

There are two oxygen atoms on the  left hand side of the reaction equation, thus total mass of oxygen = 2 * 16 amu = 32 amu

There are two oxygen atoms on the product side of the reaction equation, thus the total mass of oxygen = 2 * 16 amu = 32 amu

Answer:

2.09 atm

Explanation:

Step 1: Given and required data

We won't need the data of water and uncombusted fuel, since the partial pressures are independent of each other.

Step 2: Calculate the number of moles (n) corresponding to 60.0 g of CO₂

The molar mass of CO₂ is 44.01 g/mol.

60.0 g × 1 mol/44.01 g = 1.36 mol

Step 3: Calculate the partial pressure of CO₂

We will use the ideal gas equation.

P × V = n × R × T

P = n × R × T/ V

P = 1.36 mol × (0.0821 atm.L/mol.K) × 468.2 K/ 25.0 L = 2.09 atm

The partial pressure of [tex]\rm CO_2[/tex] in 25 L fuel combustion vessel has been 2.09 atm.

From the ideal gas equation:

PV =nRT

P= partial pressure

V = volume = 25 L

n = moles of carbon dioxide

Moles = [tex]\rm \dfrac{weight}{molecular\;weight}[/tex]

Moles of [tex]\rm CO_2[/tex] = [tex]\rm \dfrac{60}{44}[/tex] mol

Moles of [tex]\rm CO_2[/tex] = 1.36 mol

R = constant = 0.0821 atm.L/mol.K

T = temperature in Kelvin =  468.2 K

Partial pressure of [tex]\rm CO_2[/tex] = [tex]\rm \dfrac{1.36\;\times\0.0821\;\times\;468.2}{25}[/tex]

Partial pressure of [tex]\rm CO_2[/tex] = 2.09 atm.

The partial pressure of [tex]\rm CO_2[/tex] in 25 L fuel combustion vessel has been 2.09 atm.

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Answer:

316.227766

Explanation: