Draw a structural formula for the organic anion (i.e., do not include NH4 ) formed when propanal is reacted with Tollens reagent. Don't forget the charge on the ion.

Answer:

I hope you understand please follow me please

Answer:

Celsius + 273 = Kelvin

Explanation:

Answer:

A) -277.6 KJ/mol

Explanation:

The enthalpy data for first equation is not given but it should be somewhere around  ΔH = –1367 kJ/mol.

So, Basically you want to rearrange the given three equations to match the equation they want you to have. To get the final equation, reverse reaction first reaction (turn its value into positive), multiply second equation by 2, multiply third equation by 3 and you add em all up:

You get 1367 + (2* -393.5) + (3 * -285.8) ~ -277.6 KJ/mol

Answer:

because they were thought in college

Explanation:

hope that helps

Answer:

[tex]$10.97 \ g/cm^3$[/tex]

Explanation:

Given :

Mass of a bar of lead = 115.2 g

Initial water level [tex]$\text{in the graduated cylinder}$[/tex] = 25 mL

Final water level [tex]$\text{in the graduated cylinder}$[/tex] = 35.5 mL

Difference in the water level = 35.5 - 25

                                               = 10.5 mL

                                               = [tex]10.5 \ cm^3[/tex]

We know that when a body is submerged in water, it displaces its own volume of water.

Therefore, the volume of the lead bar = volume of the water displaced = 10.5 mL  = [tex]10.5 \ cm^3[/tex]

We know that mathematically, density is the ratio of mass of body to its volume.

Density of the lead bar is given by :

[tex]$\rho =\frac{\text{mass}}{\text{volume}}$[/tex]

[tex]$\rho =\frac{\text{115.2 g}}{\text{10.5 cm}^3}$[/tex]

  = [tex]$10.97 \ g/cm^3$[/tex]

Answer:

Number of moles Magnesium (Mg) = 7.40 moles

Number of moles Chlorine (Cl) = 14.8 moles

Number of moles of oxygen atoms = 29.6 moles

7.40;14.8;29.6

Explanation:

Step 1: Data given

Number of moles of magnesium perchlorate, Mg(ClO4)2 = 7.40 moles

Step 2: Calculate number of moles

In 1 mol of magnesium perchlorate, Mg(ClO4)2, we have:

1 Mol Magnesium (Mg)

2 moles of Chlorine (Cl)

8 moles of oxygen (O)

This means that for 1 mol of magnesium perchlorate, Mg(ClO4)2, we have the same amount of moles Magnesium (Mg), the double amount of moles of Chlorine (Cl) and 4x the amount of moles of oxygen (O)

Number of moles Magnesium (Mg)= 1 * 7.40 moles = 7.40 moles

Number of moles Chlorine (Cl) = 2 * 7.40 moles = 14.8 moles

Number of moles of oxygen atoms = 4 * 7.40 moles = 29.6 moles

7.40;14.8;29.6

Answer:

407 pm

Explanation:

For any elemental face-centered cubic structure, the relationship between the edge length of the unit cell and the atomic radius of its element is:

Where L is the edge length and r is the atomic radius.

With that in mind we can calculate the edge length:

Answer:

National fire protection Association

Explanation:

the nfpa is a global self funded nonprofit orgnazation establised in 1896 devoted to eliminating death injury protery loss and ecomomic loss due to fire and electrical hazards

Explanation:

Proton +1.60 x 10-19 C 1.672 x 10-24 g

Electron -1.60 x 10-19 C 9.05 x 10-28 g

Neutron neutral 1.674 x 10-24 g

Answer:

0.0831 moles of NaOH were in the original mixture

Explanation:

The strontium hydroxide, Sr(OH)2, requires 2 moles of HCl per mole of hydroxide to be neutralized.

The sodium hydroxide, NaOH, requires 1 mol of HCl per mol of hydroxide.

To solve this question we must write 2 equations:

(1) 0.19mol = X + Y

Where X = Moles NaOH; Y = Moles Sr(OH)2

The moles of HCl required are:

0.100L * (2.969mol / L) = 0.2969 moles HCl

0.2969 mol = X + 2Y(2)

Replacing (1) in (2):

0.19mol - Y = X

0.2969 mol = (0.19mol - Y) + 2Y

0.1069mol = Y

Moles X = Moles NaOH:

0.19mol = X + 0.1069mol

X = 0.0831 moles of NaOH were in the original mixture

Answer:

Explanation:

ANCHOR ANCHOR ANCHOR ANCHOR

Explanation:

Solubility product is defined as the product of the concentrations or solubilities of the ions each raised to the power their stoichiometric coefficients present in the solution. It is expressed as [tex]K_{sp}[/tex].

(a): CuBr

The chemical equation for the dissociation of CuBr into its ions follows:

[tex]CuBr\rightleftharpoons Cu^++Br^-[/tex]

The expression of [tex]K_{sp}[/tex] for CuBr follows:

[tex]K_{sp}=[Cu^+][Br^-][/tex]

(b): [tex]ZnC_2O_4[/tex]

The chemical equation for the dissociation of [tex]ZnC_2O_4[/tex] into its ions follows:

[tex]ZnC_2O_4\rightleftharpoons Zn^{2+}+C_2O_4^{2-}[/tex]

The expression of [tex]K_{sp}[/tex] for [tex]ZnC_2O_4[/tex] follows:

[tex]K_{sp}=[Zn^{2+}][C_2O_4^{2-}][/tex]

(c): [tex]Ag_2CrO_4[/tex]

The chemical equation for the dissociation of [tex]Ag_2CrO_4[/tex] into its ions follows:

[tex]Ag_2CrO_4\rightleftharpoons 2Ag^{+}+CrO_4^{2-}[/tex]

The expression of [tex]K_{sp}[/tex] for [tex]Ag_2CrO_4[/tex] follows:

[tex]K_{sp}=[Ag^{+}]^2[CrO_4^{2-}][/tex]

(d): [tex]ZnC_2O_4[/tex]

The chemical equation for the dissociation of [tex]Hg_2Cl_2[/tex] into its ions follows:

[tex]Hg_2Cl_2\rightleftharpoons 2Hg^{+}+2Cl^{-}[/tex]

The expression of [tex]K_{sp}[/tex] for [tex]Hg_2Cl_2[/tex] follows:

[tex]K_{sp}=[Hg^{+}]^2[Cl^{-}]^2[/tex]

(e): [tex]AlCl_3[/tex]

The chemical equation for the dissociation of [tex]AlCl_3[/tex] into its ions follows:

[tex]AlCl_3\rightleftharpoons Al^{3+}+3Cl^{-}[/tex]

The expression of [tex]K_{sp}[/tex] for [tex]AlCl_3[/tex] follows:

[tex]K_{sp}=[Al^{3+}][Cl^{-}]^3[/tex]

(f): [tex]ZnC_2O_4[/tex]

The chemical equation for the dissociation of [tex]Mn_3(PO_4)_2[/tex] into its ions follows:

[tex]Mn_3(PO_4)_2\rightleftharpoons 3Mn^{2+}+2PO_4^{3-}[/tex]

The expression of [tex]K_{sp}[/tex] for [tex]Mn_3(PO_4)_2[/tex] follows:

[tex]K_{sp}=[Mn^{2+}]^3[PO_4^{3-}]^2[/tex]

Answer:

See explanation and image attached

Explanation:

During beta emission, neutrons are converted into protons and electrons. The anti neutrino balances the spins.

When a nucleus undergoes beta emission, the mass number of the daughter nucleus produced in the process is the same as that of the parent nucleus but the atomic number of the daughter nucleus increases by one unit.

The product of the beta decay of the nuclides shown in the question is described in the image attached to this answer.

Answer:

Therefore, Pnitrogen=97.5kpa

Explanation:

100.0-2.49

=97.5

435= i don't know

Answer:

See explanation and image attached

Explanation:

During alpha decay, the mass number of the daughter nucleus is less than that of the parent nucleus by 4 units while the atomic number of the daughter nucleus is less than that of the parent nucleus by two units.

Hence, the daughter nucleus is found two places before the parent in the periodic table.

The alpha decay of the species shown in the question are described in the image attached to this answer.

Answer:

6.05 × 10⁴ cal

Explanation:

Step 1: Given and required data

Mass of water (m): 112 g

Enthalpy of vaporization of water (ΔHvap): 540 cal/g

Step 2: Calculate how much energy is required to vaporize 112 g of water

Vaporization is a physical change in which a substance goes from the liquid state to the gaseous state. We can calculate the energy required (Q) using the following expression.

Q = ΔHvap × m

Q = 540 cal/g × 112 g = 6.05 × 10⁴ cal

Answer:

Both lone pairs reside in sp3 orbitals; they are co-planar with the CH3 group.

Explanation:

In the compound, methyl acetate, the  lone-pair of electrons on the singly bonded oxygen atom is accommodated in sp3 hybridized orbitals.

If we look at the compound, we will notice the both lone pair of electrons on oxygen are accommodated in sp3 orbitals which are co-planar with the  CH3 group  in the molecule.

Answer:  he basic components or 4'A' s of tourism are as follows:

ATTRACTION: It is the most important element & object that attract people to travel. ...

ACCESSIBILITY: It is important key factor for the development of tourism. ...

ACCOMMODATION: -It includes food & lodging facilities to the guest. ...

AMENITIES:

What are the components of tourism and hospitality?

Accommodations and.

Lodging.

Recreation and.

Entertainment.

Travel Services.

Food and Beverage Services.

Conventions and Event.

Management.

Explanation:

NOT MY WORDS! I HOPE ThIS HELPS!

Answer:

b

Explanation:

because it is products /reactants :)

Answer: The increase in solubility or the rate of dissolving process of a gaseous solute in a liquid solvent is due to following:

Explanation:

When agitation is increased then there will occur an increase in kinetic energy of the molecules of a substance. As a result, more number of collisions will take place due to which more amount of solute will dissolve into the solvent.

Similarly, increasing the temperature will further increase the kinetic energy of molecules. Hence, this will lead to more solubility of gaseous solute into the liquid solvent.

As solubility of a gas is directly proportional to the pressure of the gas above surface of the solution. So, an increase in solute's partial pressure over solvent will also lead to an increase in solubility of gaseous solute into liquid solvent.

When surface area of solute is increased then there will be more solute particles available for reaction. Hence, more collisions will take place. As a result, rate of reaction is more due to which there will be an increase in solubility.

Thus, we can conclude that the increase in solubility or the rate of dissolving process of a gaseous solute in a liquid solvent is due to following:

Answer: The molar mass of the metal is 96.45 g/mol

Explanation:

The fluoride of the metal formed is [tex]MF_3[/tex]

The oxidation half-reaction follows:

[tex]M\rightarrow M^{3+}+3e^-[/tex]

Calculating the theoretical mass deposited by using Faraday's law, which is:

[tex]m=\frac{M\times I\times t(s)}{n\times F}[/tex]       ......(1)

where,

m = actual mass deposited = 1.25 g

M = molar mass of metal = ?

I = average current = 3.86 A

t = time period in seconds = 16.2 min = 972 s            (Conversion factor: 1 min = 60 sec)

n = number of electrons exchanged = [tex]3mol^{-1}[/tex]

F = Faraday's constant = 96500 C

Putting values in equation 1, we get:

[tex]1.25g=\frac{M\times 3.86A\times 972s}{3mol^{-1}\times 96500 C}\\\\M=\frac{1.25g\times 3mol^{-1}\times 96500 C}{3.86A\times 972s}\\\\M=96.45g/mol[/tex]

Hence, the molar mass of the metal is 96.45 g/mol

The molar mass of metal present in MF₃ is calculated by using faraday's law and is equal to 96.45 g/mole.

Molar mass of the metal will be calculated by using the Faraday's law as:

m = (M × I × t(s)) / n × F.

Chemical reaction for the given metal will be represented as:
M → M³⁺ + 3e⁻

And according to the Faraday's law given entities are:

m = given deposited mass = 1.25 g

I = average current = 3.86 A

t = time period in seconds = 16.2 min = 972 s

n = number of electrons exchanged = 3

F = Faraday's constant = 96500 C

M = molar mass of metal = to find?

Putting all these values in the above equation and calculate for M as:

M = (1.25)(3)(96500) / (3.86)(972) = 96.45 g/mole

Hence, the molar mass of metal is 96.45 g/mole.

To know more about Faraday's law, visit the below link:
https://brainly.com/question/1640558

Answer:

a. molecules that gain or lose an atom to develop a bonding charge

Explanation:

Answer:909

Explanation:

Answer:

Answer:Cu

Explanation

First letter is usually capital then the other letters are usually in small letters

Answer:

The temperature rise is 25°C

Explanation:

The heat of a substance is obtained using the equation:

Q = m*S*ΔT

Where Q is heat in kJ, m is the mass of the susbtance, S is specific heat of the material and ΔT change in temperature.

Replacing:

Q/S = m*ΔT

As Q is constant because the heat is the same and S is the specific heat of the material (Constant). We can write:

m1*ΔT1 = m2*ΔT2

Where m is mass and ΔT change in temperature of 1, initial conditions of the substance and 2, final conditions of the substance.

Replacing:

m1 = 10kg

ΔT1 = 55°C

m2 = 22kg

ΔT2 = ?

10kg*55°C = 22kg*ΔT2

ΔT2 = 25°C

Solution :

Given :

Amount of anserine solution = 0.200 M

pH value is = 7.20

Preparation of 0.04 M solution of anserine from the 0.2 M solution.

0.2 M x [tex]x[/tex] = 0.04 M x 1000 ml

[tex]x[/tex] = 200 ml

So the 200 ml of 0.2 M anserine solution is required to prepare0.04 M of anserine.

0.1 M x [tex]x[/tex] = 0.04 x 1000 ml

[tex]x[/tex] = 400 ml

Therefore, 400 ml of HCl is needed.

Answer:

cis-1-Ethyl-2-propylcyclopropane <1-Cyclopropylpentane <cis-1,4-Dimethylcyclohexane <Ethylcyclohexane

Explanation:

The least is the number of additives especially at the position 1,4 of the cyclohexane, the more is the stability.

Hence, the correct order of increasing stability is

cis-1-Ethyl-2-propylcyclopropane <1-Cyclopropylpentane <cis-1,4-Dimethylcyclohexane <Ethylcyclohexane

Answer:

false

Explanation:

It is because the pH for Hydroxide ions is 7

Answer:

True

Explanation:

Acids have a low concentration of hydroxide ions and a pH of 1-6, while bases have a high concentration of hydroxide ions and a pH of 8-14

Answer:

33.4 °C

Explanation:

The final temperature of water will be the equilibrium temperature. This can be obtained as follow:

Mass of copper (M꜀) = 300 g

Initial temperature of copper (T꜀) = 285 °C

Specific heat capacity of copper (C꜀) = 0.385 J/gºC

Mass of water (Mᵥᵥ) = 1000 g

Initial temperature of water (Tᵥᵥ) = 26.5 °C

Specific heat capacity of water (Cᵥᵥ) = 4.184 J/gºC

Equilibrium temperature (Tₑ) =?

Heat lost by copper = Heat gained by water

M꜀C꜀(T꜀ – Tₑ) = MᵥᵥCᵥᵥ(Tₑ – Tᵥᵥ)

300 × 0.385 (285 – Tₑ) = 1000 × 4.184 (Tₑ – 26.5)

115.5(285 – Tₑ) = 4184(Tₑ – 26.5)

Clear the bracket

32917.5 – 115.5Tₑ = 4184Tₑ – 110876

Collect like terms

32917.5 + 110876 = 4184Tₑ + 115.5Tₑ

143793.5 = 4299.5Tₑ

Divide both side by 4299.5

Tₑ = 143793.5 / 4299.5

Tₑ = 33.4 °C

Therefore, the final temperature of water is 33.4 °C.