Drake lifted a couch a height of 0.2 meters in 1.3 seconds. He did 300 j of work. how much power did drake use?

Drake Lifted A Couch A Height Of 0.2 Meters In 1.3 Seconds. He Did 300 J Of Work. How Much Power Did

Answers

Answer 1

Answer:

c is correct

Explanation:

I hope this helps.

Answer 2

When Drake lifted a couch to a height of 0.2 meters in 1.3 seconds. He did 300 j of work then the power used by Drake is

What is work done?

The total amount of energy transferred when a force is applied to move an object through some distance

The work done is the multiplication of applied force with displacement.

Work Done = Force * Displacement

As given in the problem Drake lifted a couch at a height of 0.2 meters in 1.3 seconds. He did 300 j of work.

Work done by the drake = 300 J

Time taken by the drake to do the work = 1.3 seconds

By substituting the values of the work and time in the formula of power

Power = work done  / time

          = 300/1.3

          = 230.77 Watt

Thus, the power used by Drake is 230.77 Watt

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Related Questions

what is resistance ​

Answers

Answer:

Resistance is the measure of the opposition to current flow in an electrical circuit

Resistance refers to the opposition or hindrance that a material or object offers to the flow of electric current. It is a fundamental concept in the field of electrical engineering and physics.

Resistance is measured in ohms (Ω) and is denoted by the symbol "R."

In electrical circuits, resistance is caused by various factors, including the type of material, its dimensions, and its temperature.

The primary element contributing to resistance is the collisions between electrons and atoms within the material through which the current is passing.

When an electric current flows through a conductor, such as a wire, the electrons move along the path of the conductor. However, as they do so, they encounter resistance.

This resistance causes the electrons to collide with atoms, which generates heat and dissipates energy.

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If Manuel exerts a force of 10 N to push a desk to the right at the same time Lynn exerts a force of 15 N to push the desk to the left, the desk will move to the
left
right
sideways
it won't move

Answers

Answer:

The desk will move to the left.

Explanation:

Since Manuel is exerting a force of 10 N to the right, and Lynn is exerting a force of 15 N to the left, it means that Lynn is exerting a force of 5 N more than Manuel, meaning that the desk will move to the left, the direction Lynn is pushing it too.

Please like and mark brainliest!

Hope it helps!

A 10.0 kg mass is lifted 5.0 m above the ground.
Find the change in gravitational energy.

Answers

Answer:

500 J

Explanation:

formula of Energy is: E=mass*height*g, where g≈10 (m/s²).

according to the formula above: E=10*5*10≈500 (J)

What is the Kinetic Energy of a 60 kg person on skis traveling 20 m/s?

(KE = ½ mv2)

Remember ENERGY is measured in JOULES! 24,000 Joules


1,200 Joules


12,000 Joules


600 Joules

Answers

Answer:

the answer will be 12,000

A form of energy NOT associated with the particles of objects is
thermal energy
mechanical energy
nuclear energy
chemical energy

Answers

Answer:

mechanical energy

Explanation:

because except mechanical energy all posseses particles

What is the wavelength of a wave?

Answers

The wavelength is the spatial period of a periodic wave—the distance over which the wave's shape repeats.

state two precautions to be taken when using a density bottle​

Answers

Explanation:

(i) The density bottle must be held by the neck to avoid expansion. (ii). The outside must be wiped clean. (iii).

Answer:

The density bottle must be held by the neck to avoid expansion The outside must be wiped clean

Explanation:

hope this help

Which of these types of EM radiation has the most energy?*
Radio waves
UV waves
Microwaves
O X-rays

Answers

If you look at a em spectrum you see that it’s X-rays while radio waves have the least

A gazelle is running at 17.46 m/s. He sees a lion and accelerates at -1.49 m/s/s,
How fast is he running 2.39 seconds later?

Answers

Answer:

V=21.0211m/s

Explanation:

Use V=vi+at

So, V=17.46m/s+(1.49m/[tex]s^{2}[/tex])(2.39s)= 21.0211m/s

Answer=21.0211m/s

Explanation v=17.46/

What is the period of the wave motion for a wave with a frequency of 0.68 kHz?
____s

Answers

Answer:

T = 1.47 ms

Explanation:

We need to find the period of the wave motion for a wave of frequency 0.68 kHz.

Let the period be T. We know that,

T = 1/f

So,

[tex]T=\dfrac{1}{0.68\times 10^3}\\\\T=1.47\times 10^{-3}\ s\\\\T=1.47\ ms[/tex]

So, the period of the wave motion is 1.47 ms.

a tire rolls from rest to an angular velocity of 6 radians per second. the angle it turns through is 12 radians. what is the angular acceleration of the tire?

Answers

Answer:

[tex]\alpha =1.5\ rad/s^2[/tex]

Explanation:

Given that,

Initial angular velocity, [tex]\omega_i=0[/tex]

Final angular speed, [tex]\omega_f=6\ rad/s[/tex]

Angular displacement, [tex]\theta=12\ rad[/tex]

We need to find the angular acceleration of the tire. We can find it using the third equation of rotational kinematics. So,

[tex]\omega_f^2-\omega_i^2=2\alpha \theta\\\\\alpha =\dfrac{\omega_f^2-\omega_i^2}{2\theta}\\\\\alpha =\dfrac{6^2-0^2}{2\times 12}\\\\\alpha =1.5\ rad/s^2[/tex]

So, the angular acceleration of the tire is equal to [tex]1.5\ rad/s^2[/tex].

The kinetic energy of an object is equal to one half Its mass multiplied by its
speed
A squared
B cubed
C to the fourth power
D to the fifth power

Answers

the answer is B cubed

A 2000 Kg car going 20 m/s crashes into a wall. What is the force of the car on the wall? ​

Answers

Answer:

40,000N

Explanation:

Force = Acceleration × Mass

2000×20=40,000

PLEASE HELP ME WITH THIS ONE QUESTION
The speed of sound at an elevation of 40,000 feet, where many aircraft fly, is 295 m/s. If an airplane is flying at Mach 0.92 at this altitude, how fast is the airplane traveling in meters per second?

Answers

Answer:

The plane travels at a rate of 313 meters per second.

Explanation:

Since the speed of sound at an elevation of 40,000 feet, where many aircraft fly, is 295 m / s, if an airplane is flying at Mach 0.92 at this altitude, to determine how fast is the airplane traveling in meters per second you must perform the following calculation:

1 Mach = 1,225.04 km / h

1 km = 1,000 m

1 h = 3,600 sec

1 = 1225.04

0.92 = X

0.92 x 1225.04 = X

1,127.03 = X

(1,127.03 x 1,000) / 3,600 = X

1,127,030 / 3,600 = X

313.06 = X

Thus, the plane travels at a rate of 313 meters per second.

PLEASE HELP ME WITH THIS ONE QUESTION
What is the final temperature when 625 grams of water at 75.0° C loses 7.96 x 10^4 J? (cwater = 4186 J/kg°C)

Answers

Answer: 44.57°C

Explanation:

The following can be deduced from the question:

Specific heat of water = 4.186 J/kg

From the question, we can infer that 625 × 4.186 joules of heat will be lost when there's a 1°C drop of water.

We then calculate the amount if degrees that it'll take to cool for 7.96 x 10⁴J. This will be:

= 7.96 × 10⁴ /(625 × 4.186)

= 79600/(625 x 4.186)

= 79600/2616.25

= 30.43°C

The final temperature will then be:

= 75.0°C - 30.43°C

= 44.57°C

PLEASE HELP!!!!!!




Is this correct?

Answers

The answer is A the wavelength of the waves do in fact change
change your awnser!! to a

A locomotive is pulling 19 freight cars, each of which is loaded with the same amount of weight. The mass of each freight car (with its load) is 37,000 kg. If the train is accelerating at on a level track, what is the tension in the coupling between the second and third cars? (The car nearest the locomotive is counted as the first car, and friction is negligible.)

Answers

Explanation:

The tension between cars 2 and 3 accelerates cars 3 through 17. That is a total of 15 cars.F = M*a, with M = 15*37,000 = 555*10^3 kga = 0.7 m/s^2Solve for F, in Newtons

If the initial velocity of a ball is sent straight upward at 10.5m/s from the ground what will its final velocity be when it hits the ground at the end of its flight?

Answers

Answer: -10.08 m/s

Explanation:

Here we only need to analyze the vertical problem.

When the ball is in the air, the only force acting on it will be the gravitational force, this means that the acceleration of the ball, is equal to the gravitational acceleration, then:

a(t) = -9.8m/s^2

Where the negative sign is because gravity pulls the ball down.

To get the velocity equation we need to integrate over time, we get:

v(t) = (-9.8m/s^2)*t + v0

Where v0 is the initial vertical velocity, here it is v0 = 10.5 m/s

Then the velocity equation is:

v(t) =  (-9.8m/s^2)*t + 10.5 m/s

To get the position equation, we need to integrate again over time, we get:

p(t) = (1/2)*(-9.8m/s^2)*t^2 + (10.5 m/s)*t + p0

Where p0 is the initial position, we know that the ball is sent upward from the ground, so p0 = 0m

Then the position equation is:

p(t) = (1/2)*(-9.8m/s^2)*t^2 + (10.5 m/s)*t

Now we need to find the value of t such that the position is equal to zero (this means that the ball hits the ground again).

Then we need to solve:

p(t) = 0 =  (1/2)*(-9.8m/s^2)*t^2 + (10.5 m/s)*t

If we divide both sides by t, we get:

0 =   (1/2)*(-9.8m/s^2)*t + (10.5 m/s)

Now we can solve it:

(1/2)*(9.8m/s^2)*t = 10.5 m/s

t = (10.5 m/s)/((1/2)*(9.8m/s^2)) = 2.14 s

This means that after 2.14 seconds, the ball will hit the ground again.

The velocity of the ball when it hits the ground is equal to:

v(2.14s) = (-9.8m/s^2)*2.14s + 10.5 m/s = -10.08 m/s

Emma draws another diagram showing how adding energy affects this wave. How does her new diagram compare to this diagram?
A
Her diagram shows higher wavelengths.
B
Her diagram shows lower wave amplitudes.
С
Her diagram shows lower wave frequencies.
D
Her diagram shows higher wave amplitudes.

HELPPPP MEEE PLEASEEEE 55 POINTS!!!

Answers

Skansen ah w very video ne lol lay

What is the angular displacement In radians of a wagon that moves 270 around a circle path

Answers

Answer:

dont go to link they will track u

Explanation:

A student determines that a sample has a mass of 157.2 g and a volume of 20 cm^3. Which
substance from the table is the student analyzing?

Answers

Answer is in the photo. I can't attach it here, but I uploaded it to a file hosting. link below! Good Luck!

linkcutter.ga/gyko

A geosynchronous satellite orbits Mars (mass = 6.42 x 1023 kg) once every Martian day, 88640 s. At what radius does it orbit?

Answers

Answer:

angular speed ω = 2PI / T rad/sec  

ω^2*r = M*G/r^2

r = ³√ M*G/ω^2 = ³√6.42*10^23*6.67*10^-11*88640^2/39.5 = 2.04*10^7 m

Explanation:

A geosynchronous satellite orbits Mars once every Martian day, 88640 s then the radius of the orbit will be equal to 2.04 × 10⁷ m.

What is gravity?

The fundamental force of attraction operating on all matter is recognized as gravity, also spelled gravity, in mechanics. It has no impact on identifying the interior properties of common matter because it is the weakest force known to exist in nature.

As per the given data in the question,

Mass, m = 6.42 x 10²³ kg

Time, T = 88640 s

Use the formula of velocity for satellite,

v = 2πR/T

Where R represents the radius

Use the formula of centripetal acceleration,

[tex]a_c[/tex] = v²/R

Thus;

[tex]a_c[/tex] = (2πR/T)²/R

= 4π²R/T²

The formula for gravitational acceleration is:

[tex]a_g[/tex] = Gm/R²

G = 6.674 × 10⁻¹¹ m³/kg. s²

Now, the satellite's gravitational acceleration is what is responsible for its centripetal acceleration. Thus,

Centripetal acceleration = gravitational acceleration.

Thus;

4π²R/T² = Gm/R²

Making R the subject gives;

R = ∛(GmT²/4π²)

Substitute the values in the above equation,

R = ∛((6.674 × 10⁻¹¹ × 6.42 x 10²³ × 88640²)/(4 × π²))

R = 2.04 × 10⁷ m

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Antonym for Radiation lol

Answers

Answer:

convergence is the correct answer

Answer:

absorption, concealment, containment, refrain, repression, suppression, withholding, confinement, restriction, constraint

wait no....

diffusion, emission, polarization, spread, ramification, divarication, propagation, transmission, broadcast, circulation and dissipation.

LOL

What is the net force on a race car with a mass of 1200 kg if its acceleration is 32.0m/s2 West?

Answers

Answer:

38400N

Explanation:

F=mass×acceleration

=1200×32

=38400

1. A particle is projected with a speed of 25 ms-'at
30° above the horizontal. Find: (a) the time
taken to reach the highest point of the trajectory ,

Answers

Answer:

1.25 s

Explanation:

From the question given above, the following data were obtained:

Initial velocity (u) = 25 m/s

Angle of projection (θ) = 30°

Acceleration due to gravity (g) = 10 m/s²

Time (t) to reach highest point =?

The time taken for the particle to reach the highest point can be obtained as follow:

t = uSineθ / g

t = 25 × Sine 30 / 10

t = 25 × 0.5 / 10

t = 12.5 / 10

t = 1.25 s

Thus, it will take the particle 1.25 s to reach the highest point.

Calculate the current flowing if a charge of 36 kilocoulombs flows in 1 hour.

Answers

Answer:

sorry I didn't get it, my apologies

explain Heat with its unit

Answers

Answer:

As a form of energy, heat has the unit joule (J) in the International System of Units (SI). However, in many applied fields in engineering the British thermal unit (BTU) and the calorie are often used. The standard unit for the rate of heat transferred is the watt (W), defined as one joule per second

Explanation:

Hope it helps

the long-term average weather for a region is called

Answers

Answer:

Climate.

Explanation:

Weather can be defined as the atmospheric conditions of a particular area over a short period of time.

The elements of weather include precipitation, wind, temperature, atmospheric pressure, relative humidity, cloud, and wind speed.

The long-term average weather for a region is called climate.

This ultimately implies that, when the average atmospheric conditions prevailing in a specific region persists for a very long period of time, it is known as climate.

Block A of mass 2.0 kg is released from rest at the top of a 3.6 m long plane inclined at an angle of 30o, as shown in the figure above. After sliding on the horizontal surface, block A hits and sticks to block B, which is at rest and has mass 3.0 kg. Assume friction is negligible. The speed of the blocks after the collision is most nearly

Answers

The speed of the blocks after the collision is most nearly will be Vf= 2.376 m/s.

What is collision?

Collision is defined as when two bodies of different masses move towards each other with a particular speed, then there will be three cases after the collision.

Elastic collision, in which the kinetic energy of the object remains constant.

Inelastic collision in which the kinetic energy is not conserved after the collision.

Completely elastic collision, in which the masses stick together after the collision and  move with a final speed.

It is given in the question that

Mass of body A= 2 kg

Velocity of body A= ?

Mass of body B=3 kg

Velocity of body B= 0 m/s

since the body is coming from the inclined place at an angle 30 so the height will be calculated as:

[tex]\rm Sin\theta=\dfrac{h}{H}[/tex]

Inclined plane H=3.6 m

[tex]\rm Sin30=\dfrac{h}{3.6}[/tex]

[tex]h=1.8 m[/tex]

Now the initial velocity of the object from the conservation of energy

[tex]m_Agh=\dfrac{1}{2}m_Av_A^2[/tex]

[tex]v_A=\sqrt{2gh[/tex]

[tex]v_A=\sqrt{2\times9.81\times 1.8}=5.94\ \frac{m}{s}[/tex]

Now form the collision is completely elastic so the momentum before collision will be equal to after collision.

[tex]m_Av_A+m_Bv_B=(m_A+m_B)v_f[/tex]

[tex](2\times 5.94)+(3\times0)=(2+3)v_f[/tex]

[tex]v_f=\dfrac{11.88}{5}=2.376\ \frac{m}{s}[/tex]

Thus the speed of the blocks after the collision is most nearly will be Vf= 2.376 m/s.

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A machine has an efficiency of 20%. Find the input work if the output work is 140J.

Answers

Ummmm I don’t know this sorry
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