Enter your answers in the boxes to correctly complete this statement. 6.184×105= because the number 105 has zeros when it is written without an exponent.+
Answer:
74.94×103= 3
because the number 10³ has
zeros when it is written without an exponent.
Step-by-step explanation:
74.94×103=
because the number 10³ has
zeros when it is written without an exponent.
3 zeros
I need help on this..... FAST. Think you can help me?
Answer:
.si sey el senocar 18
Step-by-step explanation:.basflone ne ombla
Assume that the helium porosity (in percentage) of coal samples taken from any particular seam is normally distributed with true standard deviation 0.78.
(a) Compute a 95% CI for the true average porosity of a certain seam if the average porosity for 15 specimens from the seam was 4.85. (Round your answers to two decimal places.)
(b) Compute a 98% CI for true average porosity of another seam based on 11 specimens with a sample average porosity of 4.56. (Round your answers to two decimal places.)
(c) How large a sample size is necessary if the width of the 95% interval is to be 0.46? (Round your answer up to the nearest whole number.)
(d) What sample size is necessary to estimate true average porosity to within 0.18 with 99% confidence? (Round your answer up to the nearest whole number.)
Answer:
a) The 95% CI for the true average porosity of a certain seam if the average porosity for 15 specimens from the seam was 4.85 is (4.46, 5.24).
b) The 98% CI for true average porosity of another seam based on 11 specimens with a sample average porosity of 4.56 is (4.01, 5.11).
c) A sample size of 12 is needed.
d) A sample size of 125 is needed.
Step-by-step explanation:
(a) Compute a 95% CI for the true average porosity of a certain seam if the average porosity for 15 specimens from the seam was 4.85.
We have that to find our [tex]\alpha[/tex] level, that is the subtraction of 1 by the confidence interval divided by 2. So:
[tex]\alpha = \frac{1 - 0.95}{2} = 0.025[/tex]
Now, we have to find z in the Ztable as such z has a pvalue of [tex]1 - \alpha[/tex].
That is z with a pvalue of [tex]1 - 0.025 = 0.975[/tex], so Z = 1.96.
Now, find the margin of error M as such
[tex]M = z\frac{\sigma}{\sqrt{n}}[/tex]
In which [tex]\sigma[/tex] is the standard deviation of the population and n is the size of the sample.
[tex]M = 1.96\frac{0.78}{\sqrt{15}} = 0.39[/tex]
The lower end of the interval is the sample mean subtracted by M. So it is 4.85 - 0.39 = 4.46
The upper end of the interval is the sample mean added to M. So it is 4.85 + 0.39 = 5.24
The 95% CI for the true average porosity of a certain seam if the average porosity for 15 specimens from the seam was 4.85 is (4.46, 5.24).
(b) Compute a 98% CI for true average porosity of another seam based on 11 specimens with a sample average porosity of 4.56. (Round your answers to two decimal places.)
We have that to find our [tex]\alpha[/tex] level, that is the subtraction of 1 by the confidence interval divided by 2. So:
[tex]\alpha = \frac{1 - 0.98}{2} = 0.01[/tex]
Now, we have to find z in the Ztable as such z has a pvalue of [tex]1 - \alpha[/tex].
That is z with a pvalue of [tex]1 - 0.01 = 0.99[/tex], so Z = 2.327.
Now, find the margin of error M as such
[tex]M = z\frac{\sigma}{\sqrt{n}}[/tex]
In which [tex]\sigma[/tex] is the standard deviation of the population and n is the size of the sample.
[tex]M = 2.327\frac{0.78}{\sqrt{11}} = 0.55[/tex]
The lower end of the interval is the sample mean subtracted by M. So it is 4.56 - 0.55 = 4.01
The upper end of the interval is the sample mean added to M. So it is 4.56 + 0.55 = 5.11
The 98% CI for true average porosity of another seam based on 11 specimens with a sample average porosity of 4.56 is (4.01, 5.11).
(c) How large a sample size is necessary if the width of the 95% interval is to be 0.46?
95% CI means that [tex]z = 1.96[/tex]
A sample of n is needed, and n is found when M = 0.46. So
[tex]M = z\frac{\sigma}{\sqrt{n}}[/tex]
[tex]0.46 = 1.96\frac{0.78}{\sqrt{n}}[/tex]
[tex]0.46\sqrt{n} = 1.96*0.78[/tex]
[tex](\sqrt{n})^2 = (\frac{1.96*0.78}{0.46})^2[/tex]
[tex]n = 11.05[/tex]
Rounding up
A sample size of 12 is needed.
(d) What sample size is necessary to estimate true average porosity to within 0.18 with 99% confidence?
99% CI means that [tex]z = 2.575[/tex]
A sample of n is needed, and n is found when M = 0.18. So
[tex]M = z\frac{\sigma}{\sqrt{n}}[/tex]
[tex]0.18 = 2.575\frac{0.78}{\sqrt{n}}[/tex]
[tex]0.18\sqrt{n} = 2.575*0.78[/tex]
[tex](\sqrt{n})^2 = (\frac{2.575*0.78}{0.18})^2[/tex]
[tex]n = 124.5[/tex]
Rounding up
A sample size of 125 is needed.
Is there enough information to determine if the following triangles are similar? Justify your response.
Answer:
No.
Step-by-step explanation:
Triangle DFE justifies itself with the SAS (side-angle-side) postulate, while Triangle ABC simply shows that ∡B & A are similar. They are not justified by the same standard, and so there is no way to tell if these triangles are similar.
Three of the sides will require fencing and the fourth wall already exists. If the farmer has 144 feet of fencing what is the largest area the farmer can enclose ?
Complete question is;
A farmer is building a fence to enclose a rectangular area against an existing wall. Three of the sides will require fencing and the fourth wall already exists. If the farmer has 144 feet of fencing, what is the largest area the farmer can enclose?
Answer:
A_largest = 2592 ft²
Step-by-step explanation:
Let the width which is going to be perpendicular to the already existing fourth wall be denoted by y. Since there will be 2, it means total width = 2y.
Since the farmer has 144 ft of fencing and the total width is 2y,it means that the length of the fence will be expressed as;
Length = 144 - 2y
Area of rectangular fencing is;
A = y(144 - 2y)
A = 144y - 2y²
To find the largest area, we will find the first derivative and the equate to 0 after which we plug the value of y back into the area equation to get it.
dA/dy = 144 - 4y
At dA/dy = 0;
144 - 4y = 0
y = 144/4
y = 36 ft
Thus, largest area is;
A_largest = 144(36) - 2(36)²
A_largest = 2592 ft²
The largest area the farmer can enclose with the fence with him will be 2592 square feet.
Let the length of the field = [tex]x[/tex] feet
And the width of the field = [tex]y[/tex] feet
Therefore, area of the rectangular field = Length × Width
A = [tex]x\times y[/tex] square feet
Since, length of the fence = 144 feet
And the farmer has to enclose three sides of the rectangle as shown in the figure attached.
Therefore, length of the fence = length + 2(width)
= [tex](x+2y)[/tex] feet
Hence, [tex](x+2y)=144[/tex]
[tex]x=144-2y[/tex]
By substituting the value of 'x' in the expression for the area of the rectangular field.
[tex]A=(144-2y)y[/tex]
[tex]A=-2y^2+144y[/tex]
Find the derivative of the expression with respect to [tex]y[/tex],
[tex]A'=-4y+144[/tex]
Now equate it to zero to get the value of y,
[tex]A'=-4y+144=0[/tex]
[tex]y=36[/tex]
Now substitute the value of 'y' in the expression of area to get the maximum area enclosed.
[tex]A=-2(36)^2+144(36)[/tex]
[tex]=-2592+5184[/tex]
[tex]=2592[/tex] square feet
Therefore, maximum area the farmer can enclose with the 144 feet of fencing will be 2592 square feet.
Learn more,
https://brainly.com/question/16880549
What’s 123988+81937297+81937192827-29283729?
Answer:
81989970383
Step-by-step explanation:
10in 8 in 8 in What is the surface area of the solid? A. 384 square inches B. 184 square inches C. 192 square inches D. 224 square inches
Answer:
Step-by-step explanation:
224 sq in.
What is the slope of a line that is perpendicular to the line y = 1/6+ 4
+4?
Answer:
y = 6x + 8?
Step-by-step explanation:
The starting equation was unclear but if its perpindecular, flip the given slope. For example, if the slope was 3/4, its perpindecular slope would be 4/3.
A probability experiment is conducted in which the sample space of the experiment is S={7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18}. Let event E={9, 10, 11, 12, 13, 14, 15, 16}, event F={5, 6, 7, 8, 9}, event G={9, 10, 11, 12}, and event H={2, 3, 4}. Assume that each outcome is equally likely. List the outcome s in For G. Now find P( For G) by counting the numb er of outcomes in For G. Determine P (For G ) using the General Addition Rule.
Answer:
[tex]F\ or\ G= \{5,6,7,8,9,10,11,12\}[/tex]
[tex]P(F\ or\ G) = \frac{2}{3}[/tex]
Step-by-step explanation:
Given
[tex]S= \{7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18\}[/tex]
[tex]E=\{9, 10, 11, 12, 13, 14, 15, 16\}[/tex]
[tex]F=\{5, 6, 7, 8, 9\}[/tex]
[tex]G=\{9, 10, 11, 12\}[/tex]
[tex]H=\{2, 3, 4\}.[/tex]
Solving (a): Outcomes of F or G
F or G is the list of items in F, G or F and G.
So:
[tex]F=\{5, 6, 7, 8, 9\}[/tex]
[tex]G=\{9, 10, 11, 12\}[/tex]
[tex]F\ or\ G= \{5,6,7,8,9,10,11,12\}[/tex]
Solving (b): P(F or G)
The general addition rule is:
[tex]P(F\ or\ G) = P(F) + P(G) - P(F\ and\ G)[/tex]
Where:
[tex]P(F) = \frac{n(F)}{n(S)} = \frac{5}{12}[/tex]
[tex]P(G) = \frac{n(G)}{n(S)} = \frac{4}{12}[/tex]
[tex]P(F\ and\ G) = \frac{n(F\ and\ G)}{n(S)}[/tex]
[tex]F\ and\ G = \{9\}[/tex]
So:
[tex]P(F\ and\ G) = \frac{1}{12}[/tex]
[tex]P(F\ or\ G) = P(F) + P(G) - P(F\ and\ G)[/tex]
[tex]P(F\ or\ G) = \frac{5}{12} + \frac{4}{12} - \frac{1}{12}[/tex]
[tex]P(F\ or\ G) = \frac{5+4-1}{12}[/tex]
[tex]P(F\ or\ G) = \frac{8}{12}[/tex]
[tex]P(F\ or\ G) = \frac{2}{3}[/tex]
Brainliest will be given ASAP question below!
Answer:
3/32
Step-by-step explanation:
9/16 × 3/4=27/144=3/16×1/2=3/32
what is the quotient of the polynomials shown below? (10x^3+16x^2+16)÷(2x+4)
Answer:
5x^2 - 2x + 4
Step-by-step explanation:
A state university locks in costs for a student once a student starts attending the university. The total cost is $23,500. A student has
the following help in covering the costs of school.
• An academic scholarship of $8,200.
• Other scholarships and grants of $7.400.
Grandparents pay $1,000
.
What is the amount that the student will need to save every month in order to pay off the remaining costs in 10 months ?
$690
S820
S1 660
$2 350
Answer:
720
Step-by-step explanation:
24500 (total) subtracted by (10,700 + 5000 + 1600) =7200. 7200 divide by 10 mo=720
If the student will need to save every month in order to pay off the remaining costs in 10 months, the amount she will need to save per month is $690
Amount and interestGiven the following information from the question
The total cost of fee = $23,500
Amount got as help;
An academic scholarship of $8,200.
Other scholarships and grants of $7.400.
Grandparents pay $1,000
Amunt she had = 8200 + 7400 + 1000
Amount she had = $16600
Amount remaining = 23500 - 16600
Amount remaining = $6900
If the student will need to save every month in order to pay off the remaining costs in 10 months, the amount she will need to save per month is $690
Learn more on the amount here:
https://brainly.com/question/25109150
si f(X)=1/X2, determina el conjunto finito de pares ordenados para X={1,3,7,11,13}
Answer:
El conjunto finito de pares ordenados son;
(1, 1), (1, 1/9), (1, 1/49), (1, 1/121), (1, 1/169)
Step-by-step explanation:
si f (X) = 1 / X2, determine el conjunto finito de pares ordenados para X = {1,3,7,11,13}
Dado que f (X) = 1 / X²
Para X = {1, 3, 7, 11, 13}
Tenemos;
f (X) = 1 / X²
f (1) = 1 / 1² = 1, Por lo tanto, tenemos el primer par ordenado, (1, 1)
f (3) = 1 / 3² = 1/9, por lo tanto, tenemos el segundo par ordenado (1, 1/9) ≈ (1. 0.11)
f (7) = 1 / 7² = 1/49, por lo tanto, tenemos el tercer par ordenado (1, 1/49) ≈ (1. 0.02)
f (11) = 1 / 11² = 1/121, por lo tanto, tenemos el cuarto par ordenado (1, 1/121) ≈ (1. 0083)
f (13) = 1 / 13² = 1/169, por lo tanto, tenemos el quinto par ordenado (1, 1/169) ≈ (1. 0.006)
3. Mateus recebe a visita do seu avô Pedro a cada 15 dias. João, o tio dele, o visita a cada 100
e, devido a escalas de trabalho, a cada 12 dias Mateus vai à praia com seus pais. Um belo dia Mans
recebeu a visita do seu avô, do seu tio e foi à praia com seus pais (com o avô e o tio que o visitavam nese
dia). Quantos dias depois este acontecimento se repetirà?
Answer:
Este acontecimento se repetirá 300 dias depois.
Step-by-step explanation:
Quando os eventos se repetirão no mesmo dia?
Cada evento tem uma frequência.
Eles ocorrem simultaneamente a cada x dias, e x é dado pelo MMC(Mínimo Múltiplico Comum) entre as frequência.
Neste problema:
A cada 15 dias o avô visita.
A cada 100 dias o tio visita.
A cada 12 dias vai à praia.
Quantos dias depois este acontecimento se repetirá?
Os três no mesmo dia vão se repetir após x dias, em que x é dado pelo MMC de 15, 100 e 12
MMC de 15, 100 e 12
Fatorando simultâneamente estes valores:
15 - 100 - 12|2
15 - 50 - 6|2
15 - 25 - 3|3
5 - 25 - 1|5
1 - 5 - 1|5
1 - 1 - 1
Então:
mmc(15,100,12) = 2*2*3*5*5 = 300
Este acontecimento se repetirá 300 dias depois.
la probabilidad de que un caballo viva 20 años es dos tercios y la de una vaca viva 20 años es decir 3 puntos Cuál es la probabilidad de que tanto el caballo como la vaca vivan 20 años
Answer:
La probabilidad de que tanto el caballo como la vaca vivan 20 años es [tex]\frac{2a}{3b}[/tex], en que [tex]\frac{a}{b}[/tex] es la probabilidad de que una vaca viva 20 años.
Step-by-step explanation:
Probabilidades Independientes:
Quanto las probabilidades de dos eventos son independientes, la probabilidad de los dos ocurrir simultáneamente es la multiplicacion de las dos probabilidades.
La probabilidad de que un caballo viva 20 años es dos tercios
Entonces [tex]P(C) = \frac{2}{3}[/tex]
La de una vaca viva 20 años es
Incomplete, entonces dire que es [tex]P(V) = \frac{a}{b}[/tex]
Cuál es la probabilidad de que tanto el caballo como la vaca vivan 20 años
[tex]P(C \cap V) = P(C) \times P(V) = \frac{2}{3}*\frac{a}{b} = \frac{2a}{3b}[/tex]
La probabilidad de que tanto el caballo como la vaca vivan 20 años es [tex]\frac{2a}{3b}[/tex], en que [tex]\frac{a}{b}[/tex] es la probabilidad de que una vaca viva 20 años.
La probabilidad de que tanto el caballo como la vaca vivan 20 años es [tex]\frac{2}{5}[/tex].
Sean [tex]A[/tex] y [tex]B[/tex] dos eventos independientes aunque no mutuamente excluyentes, es decir, que la esperanza de vida del caballo ([tex]A[/tex]) no dependa de la esperanza de vida de la vaca ([tex]B[/tex]) y viceversa y que pueden ocurrir al mismo tiempo.
En este caso, la probabilidad de que tanto el caballo como la vaca vivan 20 años equivale a una operación de intersección que se manifiesta en la siguiente ecuación:
[tex]P(A \cap B) = P(A)\cdot P(B)[/tex] (1)
Si sabemos que [tex]P(A) = \frac{2}{3}[/tex] y [tex]P(B) = \frac{3}{5}[/tex], entonces la probabilidad de que tanto caballo como la vaca vivan 20 años es:
[tex]P(A\cap B) = \frac{2}{3}\times \frac{3}{5}[/tex]
[tex]P(A\cap B) = \frac{2}{5}[/tex]
La probabilidad de que tanto el caballo como la vaca vivan 20 años es [tex]\frac{2}{5}[/tex].
Invitamos cordialmente a ver esta pregunta sobre probablidades: https://brainly.com/question/24290732
Nota - El enunciado original presenta omisiones y errores tipográficos, la forma completa se presenta a continuación:
La probabilidad de que un caballo viva 20 años es de dos tercios y la de que una vaca viva 20 años es de tres quintos. ¿Cuál es la probabilidad de que tanto el caballo como la vaca vivan 20 años?
An airplane’s altitude changes −378 feet over 7 minutes. The airplane's current altitude is 2,700 feet.
Determine the number of minutes required for the plane to reach the ground.
Enter your answer in the box _______.
It will take 50 minutes!
-378/7=-54
2700/-54=-50
Which regular polygon would have each of its interior angles measure 140°?
octagon
nonagon
decagon
heptagon
9514 1404 393
Answer:
nonagon
Step-by-step explanation:
The adjacent exterior angle is 180° -140° = 40°. There are 360°/40° = 9 of those angles around the regular polygon, so it is 9-sided.
The polygon is a nonagon.
Answer:
nonagon
Step-by-step explanation:
i got 100%
liana cubed the number of flowering plants in her garden, then added 2 vegetable plants. Let p represent the original number of plants in her garden. Which shows an expression to represent the total number of plants in her garden and the total number of plants if p = 3? 3 p minus 2; when p = 3 the number of plants is 7 3 p + 2; when p = 3 the number of plants is 11 p cubed minus 2; when p = 3 the number of plants is 25 p cubed + 2; when p = 3 the number of plants is 29
Answer:
11 maybe
Step-by-step explanation:
cant recheck the test
3 units
8 units
9 units
13 units
21 units
What is the area of the figure in
square units.
Answer:
Area = 132 Square units
Step-by-step explanation:
Looking at the diagram, the top horizontal chord distance that's missing is calculated as;
21 - (9 + 3) = 9 units
Total distance of top horizontal chord = 9 + 3 = 12 units
Now, formula for area of trapezium is;
Area = ½(a + b)h
Where h is height = 8 units
The parallel sides are a & B.
In this case; a = 12 units
b = 21 units
Thus;
Area = ½(12 + 21)8
Area = 4 × 33
Area = 132 Square units
Find such a coefficient a for the linear equation ax –y=4, so that the graph of the equation would pass through the point M (3, 5).
GRAPH AFTERWARDS/TELL ME POINTS TO PUT ON GRAPH I BEG YOU
Answer:
a=3; (3,5) and (4,0) for the graph
Step-by-step explanation:
ax-y=4
x=3, y=5 so...
a(3)-5=4
3a-5=4
+5 +5
3a=9
/3 . /3
a=3
For the graph, use (3,5) and substitute x and y for anything:
ax-y=4
if x=0...
a(0)-y=4
-y=4
y=4
a=3; (3,5) and (4,0) for the graph!
Helppppp meeeee!!!!!!!!!!!
Answer and Step-by-step explanation:
When it says (f + g)(x), it means that it wants you to add the functions together.
So, let's add them.
[tex](2x^2 + 6x - 4) + (5x^3 -6x^2-3)\\\\\\5x^3 - 4x^2 + 6x - 7\\\\\\\\\\\\\\5x^3 - 4x^2 + 6x - 7[/tex]is the answer. (Answer choice B.)
#teamtrees #PAW (Plant And Water)
Use the following number line to determine if the expressions are true or false.
0
True False
akb
Valo O
(al <10 D
Answer:
true
Step-by-step explanation:
If ST = 17 and RT = 61, find RS.
what is it??
Answer:
24
Step-by-step explanation:
NEED HELP I SUCK AT GEOMETRY (OFFERING 100POINTS)!!! best answer get brainlest
Find the measure of angle C
show work and explain!
Answer:
Angle C = 45°
Step-by-step explanation:
Hello There!
If you didn't know opposite angles are congruent in parallelograms
So ∠A≅∠C and ∠B≅∠D
So if ∠A = 45° then ∠C also equals 45°
As it is a parallelogram
[tex]\\ \sf\longmapsto <B\cong <D[/tex]
[tex]\\ \sf\longmapsto <A\cong <C[/tex]
<A=45°[/tex][tex]\\ \sf\longmapsto <C=<A=45°[/tex]
na 5-day
a) in 1 hour
7. If you run a half marathon (21 km) in 2 hours 6 minutes, how
a) t
b) t
c)
does it take you to run one kilometre?
find the area of the figure 27 1/2 yd and 17 1/5 yd
if the figure is a rectangle the answer is 473
Answer:
473
Step-by-step explanation:
First you need to make the fractions mixed numbers
27 1/2= 55/2
17 1/5= 86/5
Then you multiply across
55/2*86/5= 4730/10
then you divide 4730 by 10 to make it an improper fraction.
(because the denominator is 10 just take the 0 out of the end of 4630, this trick only works if the last number in the numerator is 0.)
And your anwser should be 473
I hope this helps!!!!!
What is the perimeter of triangle OJL?
A.24, B.23, C. 19, D.17
Answer: 24
Step-by-step explanation:
Megan bought two baseball gloves
and one baseball bat. She paid for 40%
with her birthday money and her uncle
paid the remaining amount. How much
did Megan pay and how much did her
uncle pay?
well if she payed 40% and an average baseball glove costs $120 – $300
and a bat costs $75-$185. that would mean she spent around $197 or $485
which would mean
40% out of 197 is 78.8
and 291
i believe is the correct answer
Determine the measure of angle ECB.
Question 1 options:
1)
88.25°
2)
183.5°
3)
176.5°
4)
91.75°
Answer:
4) 91.75
Step-by-step explanation:
7x+20+9x-4=180
16x=164
x=10.25
7(10.25)+20=
71.75+20=91.75
Answer:
You are correct 91.75 is the answer
Step-by-step explanation:
This is a cyclic quadralterial since all the. vertices of the quadralterials touch the circle circumference. Opposite angles are supplementary in cyclic quadralterials. Angle C and Angle D are opposite angles so
[tex]7x + 20 + 9x - 4 = 180[/tex]
[tex]16x + 16 = 180[/tex]
[tex]16x = 164[/tex]
[tex]x = 10 \frac{4}{16} [/tex]
[tex]x = 10.25[/tex]
Plug 10.25 into 7x+20
[tex]7(10.25) + 20 = 91.75[/tex]
You are correct
the volume of a rectangular prism is 504 in cube. If the area of the bask is 56 in cube, find its height.
Answer: 9
Step-by-step explanation: