Does the shape of a skateboard affect how will travel?

Answer:

It's definitely Nucleus

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Answer:

When frequency increases more wave crests pass a fixed point each second. That means the wavelength shortens. So, as frequency increases, wavelength decreases. The opposite is also true—as frequency decreases, wavelength increases.

Explanation:

0.10kg

0.5kg×0.2kg=

0.10

Answer:

reflection

Explanation:

Answer:

reflection

Explanation:

A p e x

Answer:

9 - 10N to the left

10 - There is no change on the object

Explanation:

Can I have brainliest answer pls?

Answer:

I think it's false

Explanation:

clouds also help regulate the Earth's energy balance by reflecting and scattering solar radiation and by absorbing the Earth's infrared radiation.

Answer:

false

Explanation:

Answer:

this is in the middle of the wheel and helps it rotate it is an axle

Answer:

His third law states that for every action (force) in nature there is an equal and opposite reaction. Explanation:

Answer:

His third law states that for every action (force) in nature there is an equal and opposite reaction

Explanation:

In other words, if object A exerts a force on object B, then object B also exerts an equal and opposite force on object A. Notice that the forces are exerted on different objects.

Answer:

The shortest possible distance is  [tex]|s| = 91.9 \ m[/tex]

Explanation:

From the question we are told that

   The mass of the car is   [tex]m = 1800 \ kg[/tex]

    The speed along the horizontal road is  [tex]v_o =u = 18.4 \ m/s[/tex]

     The static friction coefficient is  [tex]\mu_s = 0.188[/tex]

      The kinetic friction coefficient is  [tex]\mu_k = 0.1316[/tex]

Generally the static frictional force acting on the car is  mathematically represented as

          [tex]F_f = m * g * \mu_s[/tex]

Generally the force propelling the car is mathematically represented as

        [tex]F = m * a[/tex]

Here a is the maximum acceleration

at the point which the car stops ,

       [tex]F = F_f[/tex]  

=> [tex]m * g * \mu_s = ma[/tex]

=> [tex]g * \mu_s =a[/tex]

=> [tex]a = 9.8 * 0.188[/tex]

=> [tex]a = 1.8424 \ m/s^2[/tex]

Generally from kinematic equation

    [tex]v^2 = u^2 + 2as[/tex]

Here v  is the final velocity of the car and the value is zero given that the car comes to rest

So

        [tex]0^2 = 18.4^2 + 2* 1.8424 s[/tex]

=>     [tex]s = - \frac{18.4^2}{2 * 1.8424}[/tex]

=>     [tex]|s| = 91.9 \ m[/tex]

Answer:

b

Explanation:

Answer:

a

Explanation:

because the crest and trough are the same length when together and they squeeze together making the length shorter for higher frequencies and are spaced apart when lower frequencies occur

The conservation of momentum P states that the amount of momentum remains constant when there are not external forces.

We don't have external forces, so:

[tex]P_0 = P_1\\m_bv_{0b}+m_pv_{0p}=m_bv_{1b}+m_pv_{1p}\\[/tex]

Where:

Solving for v0b:

[tex]v_{0b} =\dfrac{m_bv_{1b}+m_pv_{1p}- m_pv_{0p}}{m_{b}}\\\\v_{0b} =\dfrac{(7\;kg)(4\;m/s)+(2\;kg)(6\;m/s)- (2\;kg)(0 \;m/s)}{7\;kg}\\v_{0b}=\dfrac{40}{7}\;m/s\\\\\boxed{v_{0b}\approx5.71\;m/s}[/tex]

The original velocity of the ball is 5.71 m/s.

The principle of conservation of momentum: In a closed system, The total momentum before collision is equal to total momentum after collision.

From the principle of conservation of momentum,

MU+mu = MV+mv.................... Equation 1

Where M = mass of the bowling ball, m = mass of the pin, U = initial velocity of the bowling ball, u = initial velocity of the pin, V = final velocity of the bowling ball, v = final velocity of the pin.

From the question,

Given: M = 7 kg, m = 2 kg, u = 0 m/s (at rest), v = 6.0 m/s, V = 4 m/s.

Substitute these values into equation 1 and solve for U

7(U)+2(0) = 7(4)+2(6)

7U = 28+12

7U = 40

U = 40/7

U = 5.71 m/s.

Hence, The original velocity of the ball is 5.71 m/s.

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Answer:

t = 3.35 s

Explanation:

It is given that,

Mass of a pumpkin, m = 8 kg

It is dropped from a height of 55 m

We need to find the time taken by it to hit the ground.

Initial velocity of the pumpkin, u = 0

Using second equation of motion to find it as follows :

[tex]h=ut+\dfrac{1}{2}at^2\\\\t=\sqrt{\dfrac{2h}{g}} \\\\t=\sqrt{\dfrac{2(55)}{9.8}} \\\\t=3.35\ s[/tex]

So, it will take 3.35 seconds to hit the ground.

Answer:

men

Explanation:

Answer:

c = 894.90 m/s

Explanation:

Given data:

Frequency of wave = 471 Hz

Wavelength of wave = 1.9 m

Speed of wave = ?

Solution:

Formula:

Speed of wave = frequency × wavelength

c = f×λ

c = 471 Hz × 1.9 m

  Hz = s⁻¹

c = 471s⁻¹ × 1.9 m

c = 894.90 m/s

The speed of wave is 894.90 m/s.

Mass if a substance is the product of its volume and density. The mass of gold of 0.02 m³ with a density of 19300 kg/m³ is 386 kg.

Density of a substance is the measure of its mass per unit volume. Thus, it says how much denser the object is in a given volume. Density of a substance is dependent on its bond type, temperature and pressure beside the volume and mass.

Volume can be defined as the space occupied by the substance. Larger the volume , less dense the substance is. However as the mass increases volume also increases.

Mass of an object is the product of its volume and density.

Given the volume of gold = 0.02 m³

density = 19300 kg/m³.

mass = volume ×  density

         = 0.02 m³ × 19300 kg/m³

         = 386 kg

Therefore, the mass of gold is 386 Kg.

To find more on gold, refer here:

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Answer:

Explanation:

The car will fall with acceleration due to gravity which is equal to 9.8 m /s²

For downward fall ,

initial velocity u = o

acceleration due to gravity = g = 9.8 m /s

final velocity v = ?

displacement h = 5.2 m

v² = u² + 2 gh

v² = 0 + 2 x 9.8 x 5.2

= 101.92

v = 10.1 m /s

Answer:

Acceleration = 3m/s^2

Vf= 0  Vi =35m/s   t= 13s

Explanation:

[tex]Acceleration = \frac{Change in velocity}{Change in time}\\ = \frac{35m/s}{13s}\\ a = 2.69m/s^2\\ a = 2.7m/s^2\\ a = 3m/s^2[/tex]

Answer:

The force needed to launch the projectile is 150000 N.

Explanation:  

We can find the force using the following equation:

[tex] F = ma [/tex]

Where:

m: is the mass = 15 kg

a: is the acceleration

First, we need to find the acceleration of the projectile:

[tex] v_{f}^{2} = v_{0}^{2} + 2ax [/tex]                          

Where:

[tex]v_{f}[/tex]: is the final speed

[tex]v_{0}[/tex]: is the initial speed = 0

x: is the distance = 2 m

The final speed is:

[tex]v_{f} = \frac{1 km}{5 s}*\frac{1000 m}{1 km} = 200 m/s[/tex]

Then, the acceleration is:

[tex]a = \frac{v_{f}^{2}}{2x} = \frac{(200 m/s)^{2}}{2*2 m} = 10000 m/s^{2}[/tex]

Finally, the force is:

[tex]F = ma = 15 kg*10000 m/s^{2} = 150000 N[/tex]

Therefore, the force needed to launch the projectile is 150000 N.

I hope it helps you!  

Answer:

Evidence for continental drift

Wegener knew that fossil plants and animals such as mesosaurs, a freshwater reptile found only South America and Africa during the Permian period, could be found on many continents. He also matched up rocks on either side of the Atlantic Ocean like puzzle pieces.

Explanation:

Answer:

A.100J

Explanation:

Given parameters:

Force on car = 20N

Distance  = 5m

Unknown:

Work done  = ?

Solution:

Work done is the product of force and distance;

  Work done  = force x distance;

Insert given parameters and solve;

        Work done  = 20 x 5  = 100J

Answer:

c

Explanation:

c. the ability to do work or to produce heat

Answer:

I think it's part c . but sorry if its wrong

Answer:

The potential is  [tex]V_A = 9600 \ V[/tex]

Explanation:

From the question we are told that  

   The  magnitude of the charge is  [tex]q_1 = 4 \mu C = 4*10^{-6} \ C[/tex]

   The position of the charge is  [tex]x = + 3.0 \ m[/tex]

   The magnitude of the second charge is  [tex]q_2 = -2.0 \mu C = -2.0 *10^{-6} \ C[/tex]

   The position is  [tex]y_1 = - 1.0 \ m[/tex]

     The position of point A is  [tex]y_2 = + 4.0 \ m[/tex]  

Generally the electric potential  at A due to the first charge is mathematically represented as

         [tex]V_a = \frac{k * q_1 }{r_1 }[/tex]

Here k is the coulombs constant with value [tex]k = 9*10^{9} \ \ kg\cdot m^3\cdot s^{-4} \cdot A^{-2}[/tex]

        [tex]r_1[/tex]  is the distance between first charge and a which is mathematically represented as

         [tex]r_1 = \sqrt{x^2 + y_2 ^2 }[/tex]

=>      [tex]r_1 = \sqrt{3^2 + 4 ^2 }[/tex]    

=>      [tex]r_1 = 5 \ m[/tex]    

So

           [tex]V_a = \frac{9*10^9 * 4*10^{-6} }{5 }[/tex]

      [tex]V_a = 7200 \ V[/tex]

Generally the electric potential  at A due to the second charge is mathematically represented as

         [tex]V_b = \frac{k * q_2 }{r_2 }[/tex]

Here k is the coulombs constant with value [tex]k = 9*10^{9} \ \ kg\cdot m^3\cdot s^{-4} \cdot A^{-2}[/tex]

        [tex]r_2[/tex]  is the distance between second charge and a which is mathematically represented as

         [tex]r_2 = y_2 - y[/tex]

=>      [tex]r _2 = 4.0 - (-1.0)[/tex]    

=>      [tex]r = 5 \ m[/tex]    

So

           [tex]V_a = \frac{9*10^9 * -2*10^{-6} }{5 }[/tex]

      [tex]V_a = -3600 \ V[/tex]

So the net potential difference at point A  due to the charges is mathematically represented as

       [tex]V_n = V_a + V_b[/tex]

=>     [tex]V_n = 7200 - 3600[/tex]

=>     [tex]V_n = 3600 V[/tex]

Generally the net potential difference at the origin due to both charges is mathematically represented as

     [tex]V_N = V_c + V_d[/tex]

Here  

      [tex]V_c = \frac{k * q_1 }{x}[/tex]

=>   [tex]V_c = \frac{9*10^9 * 4*10^{-6} }{3}[/tex]

=>   [tex]V_c = 12000 V[/tex]

and

              [tex]V_d= \frac{k * q_2 }{y}[/tex]

=>   [tex]V_c = \frac{9*10^9 * -2*10^{-6} }{1}[/tex]

=>   [tex]V_c =- 18000 V[/tex]

Generally the net potential difference at the origin is  

       [tex]V_N = 12000 - 18000[/tex]

=>     [tex]V_N = -6000[/tex]

Generally the potential difference at A relative to zero at the origin is mathematically evaluated as

         [tex]V_A = V_n - V_N[/tex]

=>      [tex]V_A = 3600 - (-6000)[/tex]

=>      [tex]V_A = 9600 \ V[/tex]

Answer:

Digestion begins in the mouth, when you chew.

Answer:

a. endothermic

Explanation:

The reaction shown is an endothermic reaction. In such reaction, they require an input of energy.