Answer:
No. All four hybrids are equivalent and the angles between them are all the same, so we can use any of the two to hold the nonbonding pairs.
Explanation:
Orbital hybridization has been the combination of the atomic orbitals for the formation of a new hybrid. No, it does not matter which orbitals are used to hold the nonbonding electron pairs.
What are hybrid orbitals?Hybrid orbitals are said to be formed by the mixing of the atomic orbitals with different energy and geometrical shape that allows the understanding of the atomic bonding and molecular geometry of the compounds.
It includes sp, sp², sp³, sp³d, and sp³d² which have various arrangements, including linear, trigonal planar, tetrahedral, trigonal bipyramidal, and octahedral. The hybrid orbitals are formed by the combination and overlapping of the s and p orbital.
It does not matter which sp³ orbital holds the two non-bonding electron pairs as all four hybrids have been known to have equivalent angles between them so it will not matter which hybrid has the non-bonded electrons in them.
Therefore, it will not matter which two sp³ hybrid holds the electron pairs that are not involved in bonding.
Learn more about orbital hybridization, here:
https://brainly.com/question/16251845
#SPJ6
1. How many moles of water molecules are there in 39 grams of Chlorine?
2. How many molecules are there in 39 grams of Gold?
Answer:
1. There is no moles of water in 39g of chlorine.
2. 1.19x10²³ molecules of Au.
Explanation:
First, we need to remember that molar mass of a compound represents the mass of 1 mole (6.022x10²³ molecules) of molecules.
Molar mass of Chlorine, Cl₂ is 70.9g/mol
Molar mass of gold, Au, is 197g/mol
1. Moles of 39g of Cl₂ are:
39g Cl₂ * (1mol / 70.9g) = 0.55 moles moles of chlorine
But there is no moles of water in 39g of chlorine.
2. First, moles of Au are:
39g Au * (1mol / 197g) = 0.198 moles Au.
Molecules are:
0.198 moles Au * (6.022x10²³ molecules / 1 mol) =
1.19x10²³ molecules of AuPlzz helppppppppppppp
Answer:
i got you stop doing work and forget about this one class you will still pass trust me i did it it 8th grade and still made it to 9th but today im not even in school so just do better in your other classes
Explanation: