Distribute this expression: ab(5c+9)

Answer:

ΔSTU ≅ ΔBDC

Step-by-step explanation:

In ΔSTU and ΔBDC,

∠S ≅ ∠B [Given]

∠T ≅ ∠D [Given]

SU ≅ BC [Given]

Since, two corresponding angles and non included side of the angles are equal in measure.

Therefore, ΔSTU ≅ ΔBDC [By AAS property of congruence]

Answer:

347,392

Step-by-step explanation:

yes

Answer:

13.5 inches

Step-by-step explanation:

11.5 x 2.25 x 4

I could be wrong

Answer:

13.5 inches is correct :)

Answer:

10.5

Step-by-step explanation:

Answer: $2

Step-by-step explanation:

if you meant to put a link there is none

i dont know this questions

Answer:

37.5x

Step-by-step explanation:

Answer:

answer: 36.67

Hope that helps!

Answer:

[tex]36\frac{2}{3}[/tex] %

Step-by-step explanation:

[tex]\frac{33}{90}: \frac{y}{100}[/tex]

y · 90 = 33 · 100

90y = 3300

90y ÷ 90 = 3300 ÷ 90

[tex]y=36\frac{2}{3}%[/tex]

Answer:

64

Step-by-step explanation:

A square has 4 equal sides so all you have to do is divide 4 by 256. 256/4 is equal to 64. Therefore, the answer is 64 paving stones.

If this has helped please mark as brainliest

Answer:

Growth.

Step-by-step explanation:

y = 2(1/2)x is the same as y = x. as it multiplies and divides x by 2. y = x is exponential growth.

Hope that this helps!

Answer:

For a data set of N elements:

{x₁, x₂, ..., xₙ}

The median is the middle value (or the average of the two middle values)

The average or mean is:

[tex]m = \frac{x_1 + ... + x_n}{N}[/tex]

The mode is the value that is more repeated.

The range is the difference between the largest value and the smallest value.

Now, let's try to construct two sets A and B that meet the required conditions:

Let's suppose two sets of 5 values each:

A = {2, 2, 3, 4, 5}

The median of A is 3.

The range of A is = 5 - 2 = 3

The average of A is: (2 + 2 +3 +4 +5)/5 = 16/5

And the value "2" appears two times, so the mode is 2.

Now, let's try to find a data set B such that:

The mode is smaller than 2  (so for example, we can have a "1" that repeats two times)

The median is smaller than 3 (let's have a median equal to 2)

The average is larger than 16/5

The range is larger than 3

This is ratter simple:

B = {1, 1, 2, 6, 9}

The median of B is 2.

The mode of B is 1

The range of B is: 9 - 1 = 8

The average of B is: (1 + 1 + 2 + 6 + 9)/5 = 19/5

So, we just found an example for two data sets A and B such that A has a greater median and mode, while B has a greater average and range.

So the answer is yes, it is possible.

Answer:

Distance in ft = 597.57 feet

Step-by-step explanation:

As per the

First equation of motion

84 mph = 37.5514 m/s

45 mph = 20.1168 m/s

v-u = a* t

Substituting the given values, we get -

37.5514 m/s - 20.1168 m/s = a * 6.3

a = 2.76 m/s^2

Now as per Newton's third law of motion

v^2-u^2 = 2 *a*S

Substituting the given values, we get -

37.5514^2 - 20.1168^2 = 2 * 2.76 m/s^2 * S

S = 182.142 Meters

Distance in ft = 597.57 feet

Answer:

0.1764

Step-by-step explanation:

This problem meets requirement that enables us to use the binomial probability relation :

Probability of success, p = 17% = 0.17

number of trials = 9

(1 - p) = 1 - 0.17 = 0.83

The binomial probability relation :

P(x = x) = nCx * p^x * (1 - p)^(n-x)

P(x = 3) = 9C3 * 0.17^3 * 0.83^6

P(x = 3) = 84 * 0.001606258054361897

P(x = 3) = 0.134925676566399348

P(x = 3) = 0.13492

P(x = 4) = 9C4 * 0.17^4 * 0.83^5

P(x = 4) = 126 * 0.000328992613544003

P(x = 4) = 0.041453069306544378

P(x = 4) = 0.04145

P(x = 3 or x = 4) = P(x = 3) + p(x = 4)

= 0.13492 + 0.04145

= 0.17637

= 0.1764

Answer:

tenths.........

Step-by-step explanation:

.....is the answer

Answer: [tex]||cu||=39[/tex]

Step-by-step explanation:

Given

[tex]u=<5,-12>[/tex] and [tex]c=-3[/tex]

[tex]cu[/tex] is a vector with 3 times the vector u in opposite direction

[tex]|u|=\sqrt{5^2+(-12)^2}\\|u|=\sqrt{25+144}\\|u|=13[/tex]

[tex]\therefore ||cu||=|3\times 13|\\\Rightarrow ||cu||=39[/tex]

option (a) is correct.

Answer:

The volume of the pyramid is 126in^3

Step-by-step explanation:

To find the volume of a pyramid you need to use this formula which is

V=lw·h/3

V=9·6·7/3

V=54·7/3

V=126in^3

Answer:

circumference = 2πr

diameter = 3ft, so radius =3/2 =1.5

                       =2π ×1.5=3π= 9.42ft

Answer:

here diameter =3 ft

radius=diameter/2

=3/2

=1.5 ft

now use formula 2 pie r where pie =3.14

=2*3.14*1.5 ft

=9.42 ft

Step-by-step explanation:

Hope this helps u!!

Answer:

44.4 units

Step-by-step explanation:

Recall: 2 tangents drawn from an external point from a circle are congruent

Perimeter of the quadrilateral = AB + BC + CD + AD

AB = 3.1 + 8 = 11.1

BC = 3.1 + 8 = 11.1

CD = 11.1 (given)

AD = 8 + 3.1 = 11.1

Perimeter = 11.1 + 11.1 + 11.1 + 11.1

= 44.4 units

Answer:

19.4 in.

Step-by-step explanation:

Answer:

(-6,2)

Step-by-step explanation:

when it asks for the scale factor all you do is take your coordinates and multiply it by whatever the question gives you. Like in this question you would multiply -3 and 1 by 2 and whatever the number comes out to be then thats your answers.

Sorry if the explanation isnt very good!

Answer:

B

Step-by-step explanation:

To find the answer you can just input a number for x and then you should come up with a y-value.

The graph mentioned in option B is correct.

We have the the following function -

f(x) = -3 |x|

We have to select the correct graph from the given ones.

For a function f(x) = x, which is real in nature -

f(x) = |x| =  [tex]\left \{ {{-x\;\;\;for\;x < 0} \atop {x\;\;\;for\;x > 0}} \right.[/tex]

We will use this modulus property to solve the graph. We can further expand the function y = -3|x| as -

f(x) = -3|x| = [tex]\left \{ {{-3(-x)\;\;\;for\;x < 0} \atop {-3x\;\;\;for\;x > 0}} \right.[/tex]

For every negative value of x -

y = f(x) = 3x = negative value in a multiple of 3.

For every positive value of x -

y = f(x) = - 3x = negative value in a multiple of 3.

Hence, the graph mentioned in option B is correct.

To solve more questions on Modulus, visit the link below-

brainly.com/question/2288321

#SPJ5

(Hypotenuse)² = (Base)²+ (Perpendicular)²

Taking, Hypotenuse As H

Base As B

Perpendicular As P

_________________________

H²= B²+ P²

[tex](9 \sqrt{2} ) {}^{2} = x {}^{2} + {x}^{2} \\ \\ \implies \: 81 \times 2 = 2x {}^{2} \\ \\ \implies162 = 2x {}^{2} \\ \\ \implies \frac{162}{2} = x {}^{2} \\ \\ \implies \cancel\frac{162}{2} = x {}^{2} \\ \\ \implies81 = {x}^{2} \\ \\ \implies x = \sqrt{81} \\ \\ \implies \: x = 9[/tex]

Answer:

x=[tex]\frac{4}{5}[/tex]

y=[tex]\frac{23}{5}[/tex]

Step-by-step explanation:

Look at the pictures!

Answer:

C, D and F

Step-by-step explanation:

Procedure:

9x+5=5x+21

4x+5=21 (subtract 5x)

4x=16 (subtract 5)

x=4 (divided by 4)

Answer:

Volume of iron used is 58982cm

Step-by-step explanation:

For hollow cylinder,

\bold{Height=9cm}Height=9cm

\bold{Internal \ radius=21cm}Internal radius=21cm

\bold{Externa \ radius=28cm}Externa radius=28cm

volume \: of \: cylinder = \pi \times {r}^{2} \times h \:volumeofcylinder=π×r

2

×h

\bold{Volume \ of \ cylinder \ with \ hollow \ part}Volume of cylinder with hollow part

\bold{=\frac{22}{7}×28^2×9}=

7

22

×28

2

×9

\bold{=22×4×28×9}=22×4×28×9

\bold{=71456cm^3}=71456cm

3

\bold{Volume \ of \ hollow \ part}Volume of hollow part

\bold{=\frac{22}{7}×21^2×9}=

7

22

×21

2

×9

\bold{=22×3×21×9}=22×3×21×9

\bold{=12474cm^3}=12474cm

3

\bold{Volume \ of \ iron \ used=}Volume of iron used=

\bold{Volume \ of \ cylinder \ with \ hollow \ part}Volume of cylinder with hollow part

\bold{- Volume \ of \ hollow \ part}−Volume of hollow part

{=71456-12474}=71456−12474

{=58982cm^3}=58982cm

3

\bold\red{Volume \ of \ iron \ used \ is \ 58982cm^3}Volume of iron used is 58982cm

3