Dissolving NaOH (s) in water is exothermic. Two calorimetry experiments are set up.

Exp 1: 2 g of NaOH are dissolved in 100 mL of water

Exp 2: 4 g of NaoH are dissolved in 200 mL of water.

Which of the following is true?

A. both temperature changes will be the same
B. the second temeprature change will be approximately twice the first
C. the second temperature change will be approximately four times the first
D. the second temperature change will be approximately one-half of the first
E. the second temperature change will be approximately one-fourth the first

Answer:

8

Explanation:

When you balance the entire equation, you should get:

C5H12 + 8O2 ---> 5CO2 + 6H2O

Answer:

Explanation:

molar mass of any subtance in 1 litre water gives 1N solution

for NaOH molar mass =40 g

40g  --- 1000ml ---1N

Xg---- 150 ----0.02

X= 40*150*0.02/1000*1 =0.12 g

Answer:

[tex]pk_a = 4.69[/tex]

Explanation:

[tex]V_b = \frac{1}{2} V_e[/tex]

[tex]pk_a(c) = 4.62\\pk_a(c) = - logk_a(c)\\4.62 = - logk_a(c)\\k_a(c) = antilog (-4.62)\\k_a(c) = 2.4 * 10^{-65}[/tex]

Activity coefficients:

[tex]f_A = 0.854\\f_H = 1.00\\f_{HA} = 1.00[/tex]

[tex]k_a = k_a(c) *f_A* \frac{f_H}{f_{HA}} \\k_a = 2.4 * 10^{-5} *0.854* \frac{1.0}{1.0}\\k_a = 2.05 * 10^{-5}[/tex]

[tex]pk_a = -log(k_a)\\pk_a = -log(2.05*10^{-5})\\pk_a = 4.69[/tex]

Answer:

1. Solid

2. Particles.

3. Space.

Explanation:

1. The particles in a solid are packed very closely together. This is the most reason why solid particles have definite shapes of volume. This closeness is as a result of strong intermolecular forces force that exist between the particles. Hence, they can not flow but only vibrates about their mean position. Solids can not be compressed because of the strong intermolecular forces between their particles.

2. The particles of liquid are loosely together. In liquid, the particles are loosely packed and free to move about to certain degree. This is so because the intermolecular force between the particles are not as strong as those within the solid particles. Hence liquid has no definite shape but they have definite volume. They only assume the shape of the container they are poured into. Liquid can no be compressed..

3. In a gas, the space between the particles are bigger. This is so because the intermolecular forces between the particles are negligible i.e very small and so, the gas particles are free to move about and only restricted by the wall of the container they poured into. This negligible intermolecular forces are the reason why gas has no definite shapes and no volume. They can be compressed to fill a particular container.

Answer:

128 gram of CaC2O4 contains 40 gram of Calcium

40.3 gram of CaC2O4 cotnains = 40*40.3/128 = 12.59 gram of Calcium

out of 15 gram 12.59 gram is Calcaim that means around 50% of orginal sample has Calcium

Answer:

a. 2.959x10⁻²m

b. 5.327x10⁻⁴

c. 0.272%

d. 2718 PPM

Explanation:

A solution of 2.950x10⁻²M contains 2.950x10⁻² moles of Glycerol per Liter of solution. As the volume of the solution made was 1.000L, moles of glycerol are 2.950x10⁻².

a. molality: Molality is defined as the ratio between moles of solute (2.950x10⁻²) in kg of solvent. As there are 998.7mL of solvent and density is 0.9982g/mL, kg are:

998.7mL ₓ (0.9982g/mL) ₓ (1kg / 1000g) = 0.9969kg of solvent.

Molality: 2.950x10⁻² moles / 0.9969kg of solvent = 2.959x10⁻²m

b. Mole fraction is the ratio between moles of solute and total moles. Moles of water are:

998.7mL ₓ (0.9982g/mL) ₓ (1mol / 18.01g) = 55.35 moles of water.

Mole fraction glycerol:

2.950x10⁻² moles / (2.950x10⁻²moles + 55.35) = 5.327x10⁻⁴

c. Percent by mass Is the ratio by mass of solute and solution multiplied 100 times.

Mass of glycerol (Molar mass:  92.09g/mol):

2.950x10⁻² moles × (92.09g / mol) = 2.717g of glycerol

Mass of water:

998.7mL ₓ (0.9982g/mL) = 996.9g of water.

Percent by mass:

2.717g of glycerol / (996.9g of water + 2.717g) × 100 = 0.272%

d. Parts per million are defined as the ratio between mg of solute and kg of solution.

mg of 2.717g of glycerol are 2717mg

kg of solution are (996.9g + 2.717g) / 1000 = 0.9996kg

Parts per million:

2717mg / 0.9996kg = 2718 PPM

Answer:

5) 1.147 moles Cl2

6) 12.57 grams ClF3

7)  339.10 grams ClF3

8) 5.63 grams F2

Explanation:

Step 1: Data given

Number of moles F2 = 3.44 moles

Molar mass F2 = 38.00 g/mol

Step 2: The balanced equation

Cl2 + 3F2 → 2ClF3

Step 3: Calculate moles F2

For 1 mol Cl2 we need 3 moles F2 to produce 2 moles ClF3

For 3.44 moles F2 we'll need 3.44/3 = 1.147 moles Cl2

Step 1: Data given

Number of moles F2 = 0.204 moles

Molar mass F2 = 38.00 g/mol

Molar mass ClF3 = 92.448 g/mol

Step 2: The balanced equation

Cl2 + 3F2 → 2ClF3

Step 3: Calculate moles ClF3

For 1 mol Cl2 we need 3 moles F2 to produce 2 moles ClF3

For 0.204 moles F2 we'll have 2/3 * 0.204 = 0.136 moles

Step 4: Calculate mass ClF3

Mass ClF3 = Moles ClF3 * molar mass ClF3

Mass ClF3 = 0.136 moles * 92.448 g/mol

Mass ClF3 = 12.57 grams ClF3

Step 1: Data given

Mass of Cl2 = 130.0 grams

Molar mass F2 = 38.00 g/mol

Molar mass ClF3 = 92.448 g/mol

Step 2: The balanced equation

Cl2 + 3F2 → 2ClF3

Step 3: Calculate moles Cl2

Moles Cl2 = mass Cl2 / molar mass Cl2

Moles Cl2 = 130.0 grams / 70.9 g/mol

Moles Cl2 = 1.834 moles

Step 4: Calculate moles

For 1 mol Cl2 we need 3 moles F2 to produce 2 moles ClF3

For 1.834 moles Cl2 e'll have 2*1.834 = 3.668 moles ClF3

Step 5: Calculate mass ClF3

Mass ClF3 = Moles ClF3 * molar mass ClF3

Mass ClF3 = 3.668 moles * 92.448 g/mol

Mass ClF3 = 339.10 grams ClF3

Step 1: Data given

Mass of Cl2 = 3.50 grams

Molar mass F2 = 38.00 g/mol

Molar mass ClF3 = 92.448 g/mol

Step 2: The balanced equation

Cl2 + 3F2 → 2ClF3

Step 3: Calculate moles Cl2

Moles Cl2 = Mass Cl2 / molar mass Cl2

Moles Cl2 = 3.50 grams / 70.9 g/mol

Moles Cl2 = 0.0494  moles

Step 4: Calculate moles F2

For 1 mol Cl2 we need 3 moles F2

For 0.0494 moles we need 3*0.0494 = 0.1482 moles

Step 5: Calculate mass F2

Mass F2 = moles F2 * molar mass F2

Mass F2 = 0.1482 moles * 38.00 g/mol

Mass F2 = 5.63 grams F2

Answer:

It was because the vaccine generated actively acquired immunity, that is, inoculation of a portion of the measles virus so that the body forms the antibodies for a second contact and thus can destroy it without triggering the pathology.

Explanation:

Vaccines are methods of active acquired immunity since the antibody is not passively inoculated, it is manufactured by the body with a physiological process once part of the virus is inoculated.

The measles virus most of all affected the lives of infants or newborn children with severe rashes and high fevers that led to death.

Answer:

El número de átomos de una molécula depende de la "valencia" de los elementos, ya que es la capacidad de la unión de los átomos.

Explanation:

La valencia de un elemento se define como la medida de la capacidad de combinación de un elemento. Es la capacidad de combinación de un elemento con otros elementos para formar un compuesto químico o molécula.

Básicamente es el número de electrones de valencia que un elemento puede perder, ganar o compartir para formar enlaces químicos requeridos a partir de compuestos o moléculas.

¡¡¡Espero que esto ayude!!!

English Translation

The number of atoms of a molecule depends on the "valency" of the elements since it is the capacity of the union of atoms.

The valency of an element is defined as the measure of the combining ability of an element. It is the combining capacity of an element with other elements to form a chemical compound or molecule.

It is basically the number of valence electrons that an element can lose, gain or share in order to form chemical bonds required to from compounds or molecules.

Hope this Helps!!!

Answer:

1.73g of H2O

Explanation:

The following data were obtained from the question:

Volume (V) of O2 = 1.3L

Temperature (T) = 325 K

Pressure (P) = 0.991 atm

Gas constant (R) = 0.0821 atm.L/Kmol

Next, we shall determine the number of mole (n) of O2 produced from the reaction. This can be obtained by using the ideal gas equation as shown below:

PV = nRT

0.991 x 1.3 = n x 0.0821 x 325

Divide both side by 0.0821 x 325

n = (0.991 x 1.3) /(0.0821 x 325)

n = 0.048 mole

Therefore, 0.048 mole of O2 was produced from the reaction.

Next, we shall determine the number of mole H2O that produce 0.048 mole of O2. This is illustrated below:

2H2O(l) → 2H2(g) + O2(g)

From the balanced equation above,

2 moles of H2O produced 1 mole of O2.

Therefore, Xmol of H2O will produce 0.048 mole of O2 i.e

Xmol of H2O = (2 x 0.048)/1

Xmol of H2O = 0.096 mole

Therefore, 0.096 mole of H2O was used in the reaction.

Finally, we shall convert 0.096 mole of H2O to grams. This is illustrated below:

Molar mass of H2O = (2x1) + 16 = 18g/mol

Number of mole H2O = 0.096 mole

Mass of H2O =..?

Mole = mass /molar mass

0.096 = mass /18

Cross multiply

Mass = 0.096 x 18

Mass of H2O = 1.73g

Therefore, 1.73g of H2O is required for the reaction.

Answer:

Ba>Sn>Pb>As>S

Explanation:

Hello,

In this case, we can write the atomic radius for the given elements:

[tex]r_{Ba}=268pm\\r_{Sn}=225pm\\r_{S}=100pm\\r_{Pb}=202pm\\r_{As}=185pm[/tex]

In such a way, the required order is:

Ba>Sn>Pb>As>S

This is also in agreement as a periodic trend which states that the higher the period, the higher the radius.

Regards.

Answer:

The correct option is "Triscsuit"

Explanation:

In my opinion the correct option is tricsuit, because it has 0% saturated fat and TRANS fat, which is healthy fats since these fats are the worst for our body.

They also contain sodium but their levels are not high enough to trigger hypertension.

Answer:

The electrons in an atom move around the nucleus in specific regions called electron shells. Every electron shell can just contain a specific number of electrons. The manner in which the electrons are arranged in an iota is known as the atom's electronic structure or electronic configuration of the specific atom.

Atoms or molecules are arranged in molecular compounds in set proportions by forming bonds, where outer shell valence electrons from each atom are shared between two same or different atoms of the compound.

Answer:

D. rate = k [(CH3)3CCl]

Explanation:

(CH3)3CCl + OH- → (CH3)3COH + Cl-

The mechanisms are;

Step 1)

(CH3)3CCl → (CH3)3C+ + Cl- (slow)

Step 2)

(CH3)3C+ + OH- → (CH3)3COH (fast)

In kinetics, the slowest step is the ratee determining step.

For a given reaction;

A → B + C, the rate law expression is given as;

rate = k [A]

In this problem, from step 1. The rate expression is;

rate = k [(CH3)3CCl]

Answer:

The lock-and-key model:

c. Enzyme active site has a rigid structure complementary

The induced-fit model:

a. Enzyme conformation changes when it binds the substrate so the active site fits the substrate.

Common to both The lock-and-key model and The induced-fit model:

b. Substrate binds to the enzyme at the active site, forming an enzyme-substrate complex.

d. Substrate binds to the enzyme through non-covalent interactions

Explanation:

Generally, the catalytic power of enzymes are due to transient covalent bonds formed between an enzyme's catalytic functional group and a substrate as well as non-covalent interactions between substrate and enzyme which lowers the activation energy of the reaction. This applies to both the lock-and-key model as well as induced-fit mode of enzyme catalysis.

The lock and key model of enzyme catalysis and specificity proposes that enzymes are structurally complementary to their substrates such that they fit like a lock and key. This complementary nature of the enzyme and its substrates ensures that only a substrate that is complementary to the enzyme's active site can bind to it for catalysis to proceed. this is known as the specificity of an enzyme to a particular substrate.

The induced-fit mode proposes that binding of substrate to the active site of an enzyme induces conformational changes in the enzyme which better positions various functional groups on the enzyme into the proper position to catalyse the reaction.

Answer:

Pressure

Explanation:

In an open system, the vapor pressure is equal to the outside air pressure.

Answer: The final concentration is 0.16 M.

Explanation:

According to the dilution law:

[tex]M_1V_1=M_2V_2[/tex]

where,

[tex]M_1[/tex] = molarity of stock solution = 1.60 M

[tex]V_1[/tex] = volume of stock  solution = 54.0 ml

[tex]M_2[/tex] = molarity of diluted solution = ?

[tex]V_2[/tex] = volume of diluted solution = 218 ml

Putting these values:

[tex]1.60\times 54.0=M_2\times 218[/tex]

[tex]M_2=0.40M[/tex]

Now 109 ml of this diluted solution is further diluted by adding 161 mL of water.

Again applying dilution law:

[tex]0.40\times 109=M_3\times (109+161)[/tex]

[tex]0.40\times 109=M_3\times 270[/tex]

[tex]M_3=0.16M[/tex]

Thus the final concentration is 0.16 M

Explanation:

First element

1s2 2s2 2p6 3s2 3p6

Atomic Number = 18

Element = Argon

Second Element

1s2 2s2 2p6 3s2

Atomic Number = 12

Element = Magnesium

Second Element

1s2 2s2 2p6 3s2 3p6 4s1

Atomic Number = 19

Element = Potassium

In the periodic table;

The general trend is for ionization energy to increase moving from left to right across an element period. It would decrease down the group.

Both Argon and Magnesium are on the same period. Potassium is o the period below.

This leads us to;

Magnesium - 0.7377 MJ/mol

Argon -  1.505 MJ/mol

Potassium - 0.4189 MJ/mol

The atomic radius of atoms generally decreases from left to right across a period.  It would increase down the group.

This leads to;

Magnesium - 1.60

Argon -  0.94

Potassium - 2.35

Answer:

The boiling and freezing temperatures of krypton at absolute scale are 119.95 K and 116.05 K, respectively.

Explanation:

The absolute temperature on SI units corresponds to Kelvin scale, whose conversion formula in terms of the Celsius scale is:

[tex]T_{K} = T_{C} + 273.15[/tex]

Where:

[tex]T_{K}[/tex] - Absolute temperature, measured in Kelvins.

[tex]T_{C}[/tex] - Relative temperature, measured in Celsius.

Finally, freezing and boiling temperatures are converted into absolute scale:

Boiling temperature

[tex]T_{K} = (-153.2 + 273.15)\,K[/tex]

[tex]T_{K} = 119.95\,K[/tex]

Freezing temperature

[tex]T_{K} = (-157.1 + 273.15)\,K[/tex]

[tex]T_{K} = 116.05\,K[/tex]

The boiling and freezing temperatures of krypton at absolute scale are 119.95 K and 116.05 K, respectively.

Answer:

i hope it will help you

Explanation:

electronic configuration 1s²,2s,²2p^6,3s²3p^6,4s^1

as it has one electron in its valence shell so it is the member of group 1A(ALKALI METALS)  and the number of shells is 4 so it is in period 4

Answer:

109

Explanation:

Let silver-107 be isotope A

Let silver-109 be isotope B

Let silver-107 abundance be A%

Let silver-109 abundance be B%

The following data were obtained from the question:

Atomic weight of silver = 108

Mass of isotope A (silver-107) = 107

Abundance of isotope A (silver-107) = 51.8%

Abundance of isotope B (silver-109) = 48.2%

Mass of isotope B (silver-109) =?

Now, we shall determine the mass silver-109 as follow:

Atomic weight = [(Mass of A x A%)/100] + [(Mass of B x B%)/100]

108 = [(107 x 51.8)/100] + [(Mass of B x 48.2)/100]

108 = 55.426 + (Mass of B x 0.482)

Collect like terms

Mass of B x 0.482 = 108 – 55.426

Mass of B x 0.482 = 52.574

Divide both side by 0.482

Mass of B = 52.574/0.482

Mass of B = 109

Therefore, the mass of silver-109 is 109.

Answer:

H = 4,034,250 J

Explanation:

Mass, m = 165kg = 165,000g (Converting to grams)

Initial temperature = 15.7°C

Final temperature = 95.7°C

Temperature change, ΔT = 95.7 - 15.7 = 50°C

Specific heat capacity, c = 0.489 J/g·°C

Heat = ?

All the parameters are related with the equation below;

H = m * c * ΔT

H = 165000 * 0.489  * 50

H = 4,034,250 J

Answer:

Po - 206

Explanation:

Think about the nuclear equation for the alpha decay of Po - 210. Po - 210 has 84 protons and 126 neutrons in it's nucleus, and an alpha particle is identical to a helium - 4 nucleus, meaning it is present with 2 protons and 2 neutrons.

_______________________________________________________

Knowing that, during the alpha decay, Po - 210 will form a daughter nucleus identical to a polonium - 210 present with 4 less of it's atomic mass ( number of protons and neutrons ), and 2 less of it's atomic number ( number of protons ). Why? Because Po - 210 will split into this daughter nucleus and an alpha particle.

Po - 210 has an atomic mass of 210 and an atomic number of 84. It's daughter nucleus will have an atomic mass of 206, and an atomic number of 82, Po - 206.

Hope that helps!

The daughter nucleus (nuclide) produced when Po210 undergoes alpha decay is lead 206 decays by alpha emission to lead-206 (atomic number 82).

The process of radioactive decay known as "alpha decay," in which an atomic nucleus produces an alpha particle and changes into a separate atomic nucleus with a mass number that is reduced by four and an atomic number that is reduced by two, is known as radioactive decay.

When a nucleus has too many protons, it becomes unstable and undergoes alpha decay. Energy and an alpha particle are released by the nucleus.

Po-210's atomic mass and atomic number both decrease by four after the emission of an alpha particle. The resulting atomic mass will be 2016, and the atomic number will be 82. This is an example of the lead isotope.

Thus, The daughter nucleus (nuclide) produced when Po210 undergoes alpha decay is lead 206.

To learn more about an alpha decay, follow the link;

https://brainly.com/question/2600896

#SPJ5

Answer:

[tex]Y=58.15\%[/tex]

Explanation:

Hello,

For the given chemical reaction:

[tex]Al_2S_3(s) + 6 H_2O(l) \rightarrow 2 Al(OH)_3(s) + 3 H_2S(g)[/tex]

We first must identify the limiting reactant by computing the reacting moles of Al2S3:

[tex]n_{Al_2S_3}=5.00gAl_2S_3*\frac{1molAl_2S_3}{150.158 gAl_2S_3} =0.0333molAl_2S_3[/tex]

Next, we compute the moles of Al2S3 that are consumed by 2.50 of H2O via the 1:6 mole ratio between them:

[tex]n_{Al_2S_3}^{consumed}=2.50gH_2O*\frac{1molH_2O}{18gH_2O}*\frac{1molAl_2S_3}{6molH_2O}=0.0231mol Al_2S_3[/tex]

Thus, we notice that there are more available Al2S3 than consumed, for that reason it is in excess and water is the limiting, therefore, we can compute the theoretical yield of Al(OH)3 via the 2:1 molar ratio between it and Al2S3 with the limiting amount:

[tex]m_{Al(OH)_3}=0.0231molAl_2S_3*\frac{2molAl(OH)_3}{1molAl_2S_3}*\frac{78gAl(OH)_3}{1molAl(OH)_3} =3.61gAl(OH)_3[/tex]

Finally, we compute the percent yield with the obtained 2.10 g:

[tex]Y=\frac{2.10g}{3.61g} *100\%\\\\Y=58.15\%[/tex]

Best regards.

Answer:

Q = 1.08x10⁻¹⁰

Yes, precipitate is formed.

Explanation:

The reaction of CoF₂ with NaOH is:

CoF₂(aq) + 2 NaOH(aq) ⇄ Co(OH)₂(s) + 2 NaF(aq).

The solubility product of the precipitate produced, Co(OH)₂, is:

Co(OH)₂(s) ⇄ Co²⁺(aq) + 2OH⁻(aq)

And Ksp is:

Ksp = 3x10⁻¹⁶= [Co²⁺][OH⁻]²

Molar concentration of both ions is:

[Co²⁺] = 0.018Lₓ (8.43x10⁻⁴mol / L) / (0.018 + 0.022)L = 3.79x10⁻⁴M

[OH⁻] = 0.022Lₓ (9.72x10⁻⁴mol / L) / (0.018 + 0.022)L = 5.35x10⁻⁴M

Reaction quotient under these concentrations is:

Q = [3.79x10⁻⁴M] [5.35x10⁻⁴M]²

Q = 1.08x10⁻¹⁰

As Q > Ksp, the equilibrium will shift to the left producing Co(OH)₂(s) the precipitate

Answer:

The correct option is b) SO₃(g) + NO(g) ⇌ SO₂(g) + NO₂(g)

Explanation:

The relation between Kc and Kp is given by the following equation:

[tex]Kp = Kc (RT)^{dn}[/tex]

where R is the gas constant (0,082 L.atm/K.mol), T is the temperature (in K) and dn is the change in moles.

The change in moles (dn) is calculated as:

dn = moles of products - moles reactants

If dn=0, RT= 1 ⇒ Kc=Kp

We calculate dn for each reaction from the estequiometrial coefficients of products and reactants as follows:

a) 4 NH₃(g) + 3 O₂(g) ⇌ 2 N₂(g) + 6 H₂O(g)

dn= (2+6) - (4+3) = 1 ⇒ Kc ≠ Kp

b) SO₃(g) + NO(g) ⇌ SO₂(g) + NO₂(g)

dn = (1+1) - (1+1)= 0 ⇒ Kc = Kp

c) 2 N₂(g) + O₂(g) ⇌ 2 N₂O(g)

dn= 2 - (2+1) = -1 ⇒ Kc ≠ Kp

d) 2 SO₂(g) + O₂(g) ⇌ 2 SO₃(g)

dn = 2 - (2+1) = -1 ⇒ Kc ≠ Kp

The reaction in which Kc=Kp is b), because reactants and products have the same number of moles.

Answer:

certain lightbulb containing argon at 1.20 atm and 18 0 C is heated to 85 0 C at constant volume. What is the final pressure of argon in the lightbulb (in atm)? P 1 T 1 P 2 T 2 ... Ideal Gas Equation 5.4 Charles' law: V T (at constant n and P ) ... Consider a case in which two gases, A and B , are in a container of volume V.

Explanation:

Answer:

Mass H2SO4 = 3.42 grams

Mass of lead acetate = 0 grams

Mass PbSO4 = 4.58 grams

Mass of CH3COOH = 1.81 grams

Explanation:

Step 1: Data given

Mass of sulfuric acid = 4.90 grams

Molar mass of sulfuric acid = 98.08 g/mol

Mass of lead acetate = 4.90 grams

Molar mass of lead acetate = 325.29 g/mol

Step 2: The balanced equation

H2SO4 + Pb(C2H3O2)2 → PbSO4 + 2CH3COOH

Step 3: Calculate moles

Moles = mass / molar mass

Moles H2SO4 = 4.90 grams / 98.08 g/mol

Moles H2SO4 = 0.0500 moles

Moles lead acetate = 4.9 grams / 325.29 g/mol

Moles lead acetate = 0.0151 moles

Step 4: Calculate the limiting reactant

For 1 mol H2SO4 we need 1 mol lead acetate to produce 1 mol PbSO4 and 2 moles CH3COOH

The limiting reactant is lead acetate. It will completzly be consumed (0.0151 moles). H2SO4 is in excess. There will react 0.0151 moles. There will remain 0.0500 - 0.0151 = 0.0349 moles

Step 5: Calculate moles of products

For 1 mol H2SO4 we need 1 mol lead acetate to produce 1 mol PbSO4 and 2 moles CH3COOH

For 0.0151 moles lead acetate we'll have 0.0151 moles PbSO4 and 2*0.0151 = 0.0302 moles CH3COOH

Step 6: Calculate mass

Mass = moles * molar mass

Mass H2SO4 = 0.0349 moles * 98.08 g/mol

Mass H2SO4 = 3.42 grams

Mass PbSO4 = 0.0151 moles * 303.26 g/mol

Mass PbSO4 = 4.58 grams

Mass of CH3COOH = 0.0302 moles * 60.05 g/mol

Mass of CH3COOH = 1.81 grams