Discuss the relationship between size and wieght of an object and the amount

Answer: All UV can have harmful effects on biological matter (such as causing cancers) with the highest energies causing the most damage.

Explanation:

Answer: c. 1.89 x 10^14 J

Explanation:

By Einstein's equation, we know that:

E = m*c^2

Where m is the mass-consumed in this case:

m = 2.10g

And we must rewrite this in Kg, knowing that:

1kg = 1000g

Then:

m = 2.10g = (2.10/1000) kg = 0.0021 kg

And c is the speed of light:

c = 3*10^8 m/s.

Then the energy will be:

E = 0.0021 kg*(3*10^8 m/s)^2 = 1.89*10^14 Joules.

The correct option is:

c. 1.89 x 10^14J

Given that,

The rate of change of current = 3.2 A/s

Emf induced in the coil = 5.7 V

To find,

The magnitude of the mutual inductance of the two coils.

Solution,

The mutual inductance between the coils is given by the formula as follows :

[tex]\epsilon=M\dfrac{dI}{dt}\\\\M=\dfrac{\epsilon}{\dfrac{dI}{dt}}\\\\M=\dfrac{5.7}{3.2}\\\\=1.78\ H[/tex]

So, the mutual inductance of the two coils is 1.78 H.

Answer:

8

Explanation:

The energy levels is given as

E(n) = n² * h² / ( 8 * m * L²), where

n = 1, 2, 3, 4,... etc

At ground state energy (n = 1), therefore is E(g) = h² / (8 * m * L²).

We can then say that

E(n) = n² * Eg

Therefore, to have E = 64 Eg, we must have n² = 64. And for n² to be equal to 64, we find the square root of n

n = √64

n = 8

Essentially, the needed quantum number is 8

Given that,

Mass of a sprinter = 70 kg

Initial velocity, u = 0

Final velocity, v = 10 m/s

Time, t = 3 s

To find,

Power output.

Solution,

The work done by the sprinter is equal to its kinetic energy.

[tex]W=\dfrac{1}{2}m(v^2-u^2)\\\\=\dfrac{1}{2}\times 70\times 10^2\\\\=3500\ J[/tex]

Let P is power output. Power is equal to work done per unit time. So,

[tex]P=\dfrac{3500\ J}{3\ s}\\\\=1166.67\ W[/tex]

So, the power output is 1166.66 W.

Answer:

T = 10 s

Explanation:

First, we need to find the frequency of the object as follows:

[tex]Frequency = f = \frac{Speed\ in\ rpm}{60}[/tex]

where,

Speed = Angular Speed = 6 rpm

Therefore,

[tex]f = \frac{6\ rpm}{60}\\\\f = 0.1\ Hz[/tex]

Now, for time period (T):

[tex]Time\ Period = T = \frac{1}{f}\\\\T = \frac{1}{0.1\ Hz}\\\\[/tex]

T = 10 s

Answer:

6

Explanation:

The magnetic field inside a solenoid is given by the following formula:

[tex]B = \mu_{0}nI[/tex]

where,

B = Magnetic Field Inside Solenoid

μ₀ = permittivity of free space

n = No. of turns per unit length

I = Current Passing through Solenoid

For Solenoid 1:

[tex]B_{1} = \mu_{0}n_{1}I ------------------- equation 1[/tex]

For Solenoid 2:

n₂ = 6n₁

Therefore,

[tex]B_{1} = \mu_{0}n_{2}I\\B_{1} = 6\mu_{0}n_{1}I ----------------- equation 2[/tex]

Diving equation 1 and equation 2:

[tex]\frac{B_{2}}{B_{1}} = \frac{6\mu_{0}nI}{\mu_{0}nI}\\\\\frac{B_{2}}{B_{1}} = 6[/tex]

Hence, the correct option is:

6

The ratio of the magnetic fields in interior 2 to interior 1 will be

[tex]\dfrac{B_2}{B_1} =\dfrac{6}{1}[/tex]

The formula for the magnetic fields inside the solenoid will be given:

[tex]B=\mu_onI[/tex]

here,

B = Magnetic Field Inside Solenoid

μ₀ = permittivity of free space

n = No. of turns per unit length

I = Current Passing through Solenoid

For the first Solenoid

[tex]B_1=\mu_on_1I[/tex]..................(1)

For the second solenoid

[tex]n_2=6n_1[/tex]

Now

[tex]B_2=\mu_on_2I[/tex]

[tex]B_2=\mu_o(6n_1)I[/tex]..................(2)

Diving equation 1 and equation 2:

[tex]\dfrac{B_2}{B_1} =\dfrac{\mu_o(6n_1)I}{\mu_on_2I}[/tex]

[tex]\dfrac{B_2}{B_1} =6[/tex]

Thus the ratio of the magnetic fields in interior 2 to interior 1 will be

[tex]\dfrac{B_2}{B_1} =\dfrac{6}{1}[/tex]

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Answer:

W = - 118.24 J (negative sign shows that work is done on piston)

Explanation:

First, we find the change in internal energy of the diatomic gas by using the following formula:

[tex]\Delta\ U = nC_{v}\Delta\ T[/tex]

where,

ΔU = Change in internal energy of gas = ?

n = no. of moles of gas = 0.0884 mole

Cv = Molar Specific Heat at constant volume = 5R/2 (for diatomic gases)

Cv = 5(8.314 J/mol.K)/2 = 20.785 J/mol.K

ΔT = Rise in Temperature = 18.8 K

Therefore,

[tex]\Delta\ U = (0.0884\ moles)(20.785\ J/mol.K)(18.8\ K)\\\Delta\ U = 34.54\ J[/tex]

Now, we can apply First Law of Thermodynamics as follows:

[tex]\Delta\ Q = \Delta\ U + W[/tex]

where,

ΔQ = Heat flow = - 83.7 J (negative sign due to outflow)

W = Work done = ?

Therefore,

[tex]-83.7\ J = 34.54\ J + W\\W = -83.7\ J - 34.54\ J\\[/tex]

W = - 118.24 J (negative sign shows that work is done on piston)

Answer:

-49.2

Explanation:

Trust me bro

Answer:

[tex]CPD = 80[/tex]

[tex]PCD = 44[/tex]

Explanation:

Given

[tex]AB || CD[/tex]

[tex]BAD = 56[/tex]

[tex]CPA = 100[/tex]

See attachment

Required

Determine PCD and CPD

First, we need to calculate CPD

Since DPA is a straight line and CPA = 100;

We have that:

[tex]CPA + CPD = 180[/tex] --- angle on a straight theorem

Substitute 100 for CPA

[tex]100 + CPD = 180[/tex]

Subtract 100 from both sides

[tex]100-100 + CPD = 180-100[/tex]

[tex]CPD = 80[/tex]

Next, we calculate PCD

We have that:

[tex]DAB= ADC = 56[/tex]  --alternate angle

In triangle PCD

[tex]PCD + CPD + PDC = 180[/tex] --- angles in a triangle

Where

[tex]PDC = ADC = 56[/tex]

So, we have:

[tex]PCD +80 + 56 = 180[/tex]

[tex]PCD +136 = 180[/tex]

Subtract 136 from both sides

[tex]PCD = 180 - 136[/tex]

[tex]PCD = 44[/tex]

Answer:

i believe that they are or there's something out there

Explanation:

:)

Answer:

The PE of the mass increased by 6,972.95 J

Explanation:

Gravitational Potential Energy

It's the energy stored in an object because of its vertical position or height in a gravitational field.

It can be calculated with the equation:

U=m.g.h

Where m is the mass of the object, h is the height with respect to a fixed reference, and g is the acceleration of gravity or 9.8 m/s^2.

We are given the mass of m=16 slug raised by a height h=10 ft. Both units will be converted to SI standard:

1 slug = 14.59 Kg, thus

16 slug = 16*14.59 Kg=233.44 Kg

1 ft = 0.3048 m, thus:

10 ft = 10*0.3048 m = 3.048 m

Thus, the PE of the mass increased by:

U = 233.44 * 9.8 * 3.048 = 6,972.95 J

the PE of the mass increased by 6,972.95 J

The potential energy will be "5120 ft.lb".

According to the question,

Mass,

Height,

As we know the formula,

→ [tex]U = mgh[/tex]

By substituting the values, we get

→     [tex]= 16\times 32\times 10[/tex]

→     [tex]= 5120 \ ft.lb[/tex]

Thus the response above is correct.

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Answer:

The ratio of the new internal energy to the old is 4

Explanation:

let the old pressure of the gas = P₁

let the old volume of the gas = V₁

then, the new pressure of the gas = 2P₁

the new volume of the gas = 2V₁

The internal energy of the gas is given as;

PV = nRT

PV = k

P₁V₁ = P₂V₂

[tex]\frac{P_2V_2}{P_1V_1} = \frac{2P_1\ \times \ 2V_1}{P_1V_1} =\frac{4}{1} = 4[/tex]

The ratio of the new internal energy to the old is 4

Answer:

a. Concave mirror, radius of curvature = 16 cm b. magnification = 2

Explanation:

a. Since the image is upright and larger than the object, we need a concave mirror.

We know image height, h'/object height, h = -image distance, d'/object distance, d

h'/h = -d'/d

Using the real is positive convention,

h'= + 5.4 cm, h = + 2.7 cm and d = + 12 cm.

So, + 5.4 cm/+ 2.7 cm = -d'/+ 12 cm

2 = -d'/12

d' = -2 × 12 cm

= -24 cm

Using the mirror formula 1/d + 1/d' = 2/r where r = radius of curvature of the mirror

1/+12 + 1/- 24 = 2/r

1/12(1 - 1/2) = 2/r

1/12(1/2) = 2/r

1/24 = 2/r

r/2 = 24

r = 2 × 24

r = 48 cm

b.

magnification = image height, h'/object height,h = + 5.4 cm/+ 2.7 cm = 2

Answer:

c.) 10 to 15 minutes

Explanation:

yw :)

Answer:

c.) 10 to 15 minutes

Explanation:

Answer:

0 j

Explanation:

The work done by the employee on the box at the given zero displacement is 0 J.

The given parameters;

The work done by the employee on the box is calculated as follows;

W = Fd

where;

Since the employee sits on the box without moving it, the distance moved by the box = 0

W = 500 x 0

W = 0 J

Thus, the work done by the employee on the box is 0 J.

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Answer:

Image B

Explanation:

although I'm not exactly sure, i've recently gotten this question as well. but model B demonstrates the force- distance trade off because you can see how in that image them distance is increased in the force is decreased with the object being shorter. hopefully this helps in some way

Given that,

Mass of student 1, m₁ = 90 kg

Mass of student 2, m₂ = 60 kg

Speed of student 1, v₁ = 5 m/s

To find,

The velocity of the other student.

Solution,

Using the conservation of momentum to find the velocity of the other student. Let it is v₂.

[tex]m_1v_1=m_2v_2\\\\v_2=\dfrac{m_1v_1}{m_2}\\\\v_2=\dfrac{90\times 5}{60}\\\\=7.5\ m/s[/tex]

So, the velocity of the other student is 7.5 m/s.

Answer:

So we can have energy  for electronics. It limits the flow of electric current

Explanation:

It’s in the answer!

Answer:

Basically, the function of a resistor is always to oppose the flow of current through it and the strength of this opposition is termed as its resistance.

Answer:

E = 5.65 x 10¹⁰ N/C

Explanation:

First we need to find the total charge on the sphere. So, we use the following formula for that purpose:

[tex]q = \sigma V\\[/tex]

where,

q = total charge on sphere

V = Volume of Sphere = [tex]\frac{4}{3} \pi r^3 = \frac{4}{3} \pi (0.08\ m)^3 = 0.335\ m^3[/tex]

σ = volume charge density = 1.5 C/m³

Therefore,

[tex]q = (0.335\ m^3)(1.5\ C/m^3) \\q = 0.502 C[/tex]

Now, we use the following formula to find the electric field due to this charged sphere:

[tex]E = \frac{kq}{r^2}[/tex]

where.

E  = Electric Field Magnitude = ?

k = Coulomb's Constant = 9 x 10⁹ N.m²/C²

r = radius of sphere = 8 cm = 0.08 m

Therefore,

[tex]E = \frac{(9\ x\ 10^9\ Nm^2/C^2)(0.502 C)}{(0.08\ m)^2}\\\\[/tex]

E = 5.65 x 10¹⁰ N/C

Answer:

D mass of the iron rod

Explanation:

A) the length of the iron rod.

B) the thermal conductivity of iron.

C) the temperature difference between the ends of the rod.

D) the mass of the iron rod.

E) the duration of the time interval

The amount of heat that will flow through an iron rod whose two ends are maintained at different temperatures would depend on the thermal conductivity of the iron, the temperature difference between the two ends, the length of the iron rod, and the duration of flow of heat.

The thermal conductivity of any material is an indication of the ability of the materials to conduct heat. The higher the thermal conductivity, the higher the amount of heat a material can conduct within a specified period. Hence, the amount of heat that will flow through the iron rod depends on its thermal conductivity.

The temperature difference between two solid materials depends on the amount of heat that will flow across the materials by conduction. The higher the difference, the more the amount of heat that will flow. Hence, the amount of heat that would be conducted depends on the temperature difference between the two ends of the iron rod

The amount of heat that would move my conduction also depends on the distance that would be traveled by the heat. Due to heat loss to the surrounding, the shorter the distance, the more the heat and vice versa. Hence, the amount of heat that will flow through an iron rod depends on the length of the iron rod.

The duration of flow also dictates the amount of heat that will flow between two regions by conduction. The more the duration, the more the heat, provided that other conditions remain constant.

The only option that the amount of heat that would be conducted does not depend on is the mass of the iron rod.

The correct option is D.

Answer:

178.5 Hz

Explanation:

Given that a  car approaches a train station with a speed of 24 m/s. A stationary train at the station sounds its horn which has a frequency of 166 Hz. What frequency of sound is heard by the car's driver ?

Solution

Using doppler effect formula

F = f ( V/ V- v)

Where F = frequency of sound heard by the car

f = train frequency

V = speed of sound

v = car speed

F = 166 ( 343 ÷ ( 343 - 24 ) )

F = 166 ( 343 / 319 )

F = 166 × 1.0752

F = 178.489 Hz

F = 178.5 Hz

Therefore, the frequency of sound heard by the observer in the car is 178.5 Hz approximately.

Answer:

[tex]velocity(x)=15\,\frac{\pi}{4}\,cos(\frac{\pi}{4}x)[/tex]

Max speed = [tex]\frac{15\, \pi}{4} \,\, \frac{m}{s}[/tex]

Max acceleration = [tex]\frac{15\,\pi^2}{16} \,\,\frac{m}{s^2}[/tex]

Explanation:

Given the description of period and amplitude, the SHM could be described by:

[tex]f(x)=5\,sin(\frac{\pi}{4}x)[/tex]

and its angular velocity can be calculated doing the derivative:

[tex]f(x)=5\, \,sin(\frac{\pi}{4}x)\\f'(x)=5\,\frac{\pi}{4}\,cos(\frac{\pi}{4}x)[/tex]

And therefore, the tangential velocity is calculated by multiplying this expression times the radius of the movement (3 m):

[tex]velocity(x)=15\,\frac{\pi}{4}\,cos(\frac{\pi}{4}x)[/tex]  and is given in m/s.

Then the maximum speed is obtained when the cosine function becomes "1", and that gives:

Max speed = [tex]\frac{15\, \pi}{4} \,\, \frac{m}{s}[/tex]

The acceleration is found from the derivative of the velocity expression, and therefore given by:

[tex]acceleraton(x)=-15\,\frac{\pi^2}{16}\,sin(\frac{\pi}{4}x)[/tex]

and the maximum of the function will be obtained when the sine expression becomes "-1", which will render:

Max acceleration = [tex]\frac{15\,\pi^2}{16} \,\,\frac{m}{s^2}[/tex]

Answer:

The total momentum is zero.

Explanation:

This problem can be solved by applying the momentum conservation theorem and the amount of motion. This theorem tells us that the amount of motion is conserved before and after a collision.

In the next equation, we will write to the left of the equal sign the amount of motion before the collision and to the right the amount of motion after the collision.

[tex](P_{1})-(P_{2})=P_{3}[/tex]

where:

P₁ = momentum of the ball moving to the right, before the collision = 85 [kg*m/s]

P₂ = momentum of the ball moving to the left, before the collision = - 85 [kg*m/s]

P₃ = Final momentum after the collision [kg*m/s]

[tex](85) - 85 = P_{3}\\P_{3}= 0[/tex]

There is no movement of any of the balls, they remain at rest after the impact.

Answer:

The number of crate to be lifted is 27

Explanation:

Given;

mass of the crates, m = 25 kg

height in which the crate is lifted, h = 1.0 m

power output, P = 110 W

time to complete the task, t = 1 minutes = 60 s

The input energy is equal to the gravitational energy due to height the crate is lifted is given as;

E(input) = mgh

E(input)  = 25 x 9.8 x 1

E(input)  = 245 J

Output energy is given as;

E(output) = P x t

E(output) = 110 x 60

E(output) = 6600 J

Let the number of crate to be lifted = n

n x E(input)  = E(output)

n x 245 = 6600

n = 6600 / 245

n = 27 crates

Answer:

The value is [tex]L = 0.0073 \ H[/tex]      

Explanation:

From the question we are told that

    The number of turns is  [tex]N = 650 \ turns[/tex]

     The length is  [tex]l = 28 \ cm = 0.28 \ m[/tex]

      The radius of the cross-section is [tex]r = 3.5 \ cm = 0.035 \ m[/tex]

Generally the cross-sectional area  is mathematically represented as

       [tex]A = \pi * r^2[/tex]

=>    [tex]A = 3.142 * 0.035^2[/tex]

=>    [tex]A = 0.00384 \ m^2[/tex]

Generally the inductance is mathematically represented as

      [tex]L = \frac{N^2 * \mu _o * A }{ l}[/tex]

Here  [tex]\mu_o[/tex] is the permeability of free space with value [tex]\mu_o = 4\pi * 10^{-7} N/A^2[/tex]

=>    [tex]L = \frac{ 650^2 * 4\pi * 10^{-7} * 0.00384 }{0.28}[/tex]

=>    [tex]L = 0.0073 \ H[/tex]      

Answer:

10 Pa

Explanation:

Pressure is defined as force per unit area.

Mathematically, P= F/A where  P is pressure, F is force and A is area.

Force, F = 60 N

Area, A = 2*3 = 6m²

P = 60/6 = 10 Pa

Answer:

CELL DIVISION THAT INVOLVES MITOSIS AND CELL GROWTH DUE TO TAKING IN NUTRIENTS

Explanation:

Answer: Cell growth due to taking in nutrients and Cell growth due to fertilization​.

Explanation:

Explanation:

Single slit diffraction

Diffraction is the phenomenon of spreading out of waves as they pass through an aperture or around objects. Diffraction occurs when the size of the aperture or obstacle is of the same order of magnitude as the wavelength of the incident wave. For very small aperture sizes, the vast majority of the wave is blocked. in case of  large apertures the wave passes by or through the obstacle without any significant diffraction.

Ranking Earthquake Intensity

Magnitude Average number per year Modified Mercalli Intensity

2.0 – 2.9 >1 million I

3.0 – 3.9 about 100,000 II – III

4.0 – 4.9 about 10,000 IV – V

5.0 – 5.9 about 1,000 VI – VII

Explanation:

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Answer:

Yes it is matter

Explanation:

In physics, usually the word "electricity" isn't really used. "Electric current" is more common, and is defined as the flow of charges, where the charges are held by particles (electrons). Electrons have mass, so they are definitely matter.