Determine whether each function is even, odd, or neither.g(x) = |x-3| g(x) = x + x

Answers

Answer 1

Answer:

Step-by-step explanation:

g(x) = |x-3| is neither even nor odd; the graph is not symmetric about the y-axis (as characterizes even functions), and is not symmetric about the origin either.

g(x) = x + x is actually g(x) = 2x, which is an odd function.  The graph is symmetric about the origin.


Related Questions

Help please!!
What quadrant does the terminal side of this angle lie in?

Answers

Answer:

QIII

Step-by-step explanation:

Which of the following represents a coefficient from the expression given?

9x – 20 + x2

Answers

Answer:

1 or 9.

Step-by-step explanation:

A coefficient is "a numerical or constant quantity placed before and multiplying the variable in an algebraic expression (e.g. 4 in 4xy)".

So, in this case, the coefficient of 9x would be 9.

The coefficient of x^2 would be 1.

Hope this helps!

In the given quadratic expression 9x - 20 + x, 1, 9, and -20 are the coefficients.

What are coefficients in a quadratic expression?

In a quadratic expression of the standard form ax² + bx + c, x is the variable and a, b, and c are the numeric coefficients.

How to solve the given question?

In the question, we are asked to identify the coefficients from the given quadratic expression 9x - 20 + x².

First, we try to express the given quadratic expression, 9x - 20 + x², in the standard form of a quadratic expression, ax² + bx + c.

Therefore, 9x - 20 + x² = x² + 9x - 20.

Comparing the expression x² + 9x - 20 with the standard form of a quadratic expression ax² + bx + c, we get a = 1, b = 9, c = -20.

We know that in a quadratic expression ax² + bx + c, x is the variable and a, b, and c are the numeric coefficients.

Thus, we can say that in the given quadratic expression 9x - 20 + x², 1, 9, and -20 are the coefficients.

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Suppose IQ scores were obtained for 20 randomly selected sets of siblings . The 20 pairs of measurements yield x overbar equals98.26​, y overbar equals99​, requals 0.911​, ​P-valueequals ​0.000, and ModifyingAbove y with caret equals negative 5.9 plus 1.07 x ​, where x represents the IQ score of the older child . Find the best predicted value of ModifyingAbove y with caret given that the older child has an IQ of 102 ​? Use a significance level of 0.05 g

Answers

Answer:

The answer to the best prediction is 115.04

Step-by-step explanation:

We have to:

x = 102

They also tell us that:

y = 5.9 + 1.07 * x

If we replace we have:

y = 5.9 + 1.07 * (102)

y = 115.04

Therefore, the best predicted value of ModifyingAbove and with caret given that the older child has an IQ of 102 is 115.04

If a baseball player has a batting average of 0.375, what is the probability that the player will get the following number of hits in the next four times at bat?
A. Exactly 2 hits(Round to 3 decimal places as needed)
B. At least 2 hits (Round to 3 decimal places as needed)

Answers

Answer:

a) [tex]P(X=2)=(4C2)(0.375)^2 (1-0.375)^{4-2}=0.330[/tex]  

b) [tex]P(X\geq 2)=1-P(X< 2)=1-[P(X=0)+P(X=1)][/tex]

[tex]P(X=0)=(4C0)(0.375)^0 (1-0.375)^{4-0}=0.153[/tex]  

[tex]P(X=1)=(4C1)(0.375)^1 (1-0.375)^{4-1}=0.366[/tex]  

And replacing we got:

[tex]P(X\geq 2)=1-P(X< 2)=1-[0.153+0.366]=0.481[/tex]

Step-by-step explanation:

Let X the random variable of interest, on this case we now that:  

[tex]X \sim Binom(n=4, p=0.375)[/tex]  

The probability mass function for the Binomial distribution is given as:  

[tex]P(X)=(nCx)(p)^x (1-p)^{n-x}[/tex]  

Where (nCx) means combinatory and it's given by this formula:  

[tex]nCx=\frac{n!}{(n-x)! x!}[/tex]  

Part a

[tex]P(X=2)=(4C2)(0.375)^2 (1-0.375)^{4-2}=0.330[/tex]  

Part b

[tex]P(X\geq 2)=1-P(X< 2)=1-[P(X=0)+P(X=1)][/tex]

[tex]P(X=0)=(4C0)(0.375)^0 (1-0.375)^{4-0}=0.153[/tex]  

[tex]P(X=1)=(4C1)(0.375)^1 (1-0.375)^{4-1}=0.366[/tex]  

And replacing we got:

[tex]P(X\geq 2)=1-P(X< 2)=1-[0.153+0.366]=0.481[/tex]

Which angles are pairs of alternate exterior angles

Answers

Answer:

when a straight line cuts two or more parallel lines then the angles forming on the side of transversal line exteriorly opposite to eachother is called exterior alternative angle.

for eg if AB //CD and EF is a transversal line meeting the parallel lines at G abd H then the exterior alternative angle are angle EGB = angle CHF and angle AGE=angle DHF are two pairs of exterior alternative angle .

hope its helpful to uh !!!!!!

The two triangles are similar. What is the value of x? Enter your answer in the box. x =

Answers

Answer:

the value of x=12

Step-by-step explanation:

d) the answer is d on edg.

the answer is D..........

HELP PLEASE!!What method can you use to find the area of the composite figure. Check ALL that apply.

Answers

Answer:

C

Step-by-step explanation:

The reason we can use this method is because we are given a composite figure with a house shape with one triangle on top. We can use the guidance of the dotted lines to make out that a rectangle can be used to find the figure. We can see that apart from the figure, there are two congruent triangles. To find the area we would do -

First find the missing height of the smaller triangles. We would use the pythagorean theorem to find that the missing height is√5

We could do 8(4) = 32 to find the area of the rectangle.

Then, we could do 2√5/2 to find one missing triangle. We could then add the triangles to find the measures of the combined triangles as 2√5. Then, we could do 32 - 2√5 to find the area as 27.5.

Hope this helps :)

Answer:

it is A,B,D

Step-by-step explanation:

i got it right on edge

What is the complete factorization of x^2+4x-45?​

Answers

Answer:(x-5)(x+9)

Step-by-step explanation:

You want two numbers that can give you -45 in multiplication and two numbers that can add to 4 and that is -5 and 9.

Answer:  (x - 5)(x + 9)

If you have to solve, x=5 or x= -9

Step-by-step explanation: You need two numbers that multiply to be 45.

(could be 3 × 15 or 5 × 9) . The difference between the two factors needs to be 4, the coefficient of the middle term.

9 - 5 =4, so use those.  -45 has a negative sign, so one of the factors must be + and the other -  Since the 4 has the + sign, the larger factor has to be + so the difference will be positive.

So (x -5)(x + 9) are your factors. You can FOIL to be sure

x × x +=. x × 9 = 9x .  -5 ×  x = -5x . -5 × 9 = -45 .

Combine the x terms: 9x -5x = +4x  

In a Classroom, 1/6 of the students are wearing blue shirts, and 2/3 are wearing white shirts. There are 12 students in the classroom. How many students are wearing shirt other than blue shirts or white shirts?

Answers

Answer:

2

Step-by-step explanation:

firstly...you have to find the number of students wearing blue and white shirt and subtract from the total number of students to get the number if students that neither wears blue or white shirt as follows :

no wearing blue = 1/6 × 12 = 2

no.wearing white = 2/3 × 12 = 8

total number wearing blue and white = 8+2 =10

number of students not putting on either of the two colours include...= 12-10 = 2

.....

.....

.....

MARK BRAINLIEST will be appreciated please...thanks in advance

if p+4/p-4, what is the value of p

Answers

Answer:

p = 2

Step-by-step explanation:

p + 4/p - 4

multiplying through by p,

p×p + 4/p ×p - 4×p

p² + 4 - 4p = 0

p² - 4p + 4 = 0

factorizing,

p(p - 2) -2(p - 2) =0

(p -2)(p -2) =0

p-2 =0

p=2

PLEASE HELP. FINAL TEST QUESTION!!!!

Devon is having difficulty determining if the relation given in an input-output table is a function. Explain why he is correct or incorrect.

Answers

Step-by-step explanation:

input x , output y

if x= x1 then y=y1 and y1 is the only value then it is a function

if we get multiple values of y then it is not a function

20% of city employees ride the bus to work. This is up 10% from last year. What percent of employees rode the bus to work last year?

Answers

Answer:

18.18% of employees rode the bus to work last year

Step-by-step explanation:

This question can be solved using a rule of three.

Last year, a proportion of x employees riding the bus was 100% = 1.

This year, 20% = 0.2 ride the bus, which is 100 + 10 = 110% = 1.1 of last year.

So

0.2 - 1.1

x - 1

[tex]1.1x = 0.2[/tex]

[tex]x = \frac{0.2}{1.1}[/tex]

[tex]x = 0.1818[/tex]

0.1818*100 = 18.18%

18.18% of employees rode the bus to work last year

which point is a solution to the inequality shown in the graph? (3,2) (-3,-6)

Answers

The point that is a solution to the inequality shown in the graph is:

A. (0,5).

Which points are solutions to the inequality?

The points that are on the region shaded in blue are solutions to the inequality.

(3,2) and (-3,-6) are on the dashed line, hence they are not solutions. Point (5,0) is to the right of the line, hence it is not a solution, and point (0,5) is a solution, meaning that option A is correct.

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How to solve the exponential equation for 3^k2 • 3^-k+2 = 81

Answers

Answer:

k=2

Step-by-step explanation:

3^k*2 * 3^-k+2 = 81

Factor out 81 to be : 3^4

Rewrite the equation:

k*2 - k+2 = 4

k^2 - 2k = 4

Simplify : k+2 = 4

               - 2   - 2

             k = 2

An election ballot asks voters to select six city commissioners from a group of 24 candidates in how many ways can this be done? Six city commissioners can be selected from a group of 24 candidates in blank different ways

Answers

Answer:

134,596 diffrent ways.

Step-by-step explanation:

Combination has to do with selection. When n object is to be selected from n objects, this can be achieved using the combination formula as shown; \

nCr = n!/(n-r)!r!

If an election ballot asks voters to select six city commissioners from a group of 24 candidates, then the selection can be done in 24C6 different ways.

Applying the formula above:

24C6 = 24!/(24-6)!6!

24C6 = 24!/18!6!

24C6 = 24*23*22*21*20*19*18!/18!*6*5*4*3*2

24C6 = 24*23*22*21*20*19/24*30

24C6 = 23*22*21*20*19/30

24C6 = 134,596 different ways.

Hence, Six city commissioners can be selected from a group of 24 candidates in 134,596 different ways

a dense fog advisory means visibility is less than 1/8 of a mile

-true
-false

Answers

it’s true
Good luck

ANSWER ASAP! PLEASE HELP!

Answers

The one under the question is correct

I got the answer but I really don’t know if it’s correct or not, please help this is due today

Answers

Answer: x=2

Explanation: 180-52 = 128

So we have an equation:

2^3x+1=128 ( cuz they are in the same position)

Now we need to find what number that 2 raise to the power of that number is 128

And the answer is 2^7=128

Let’s go back to our equation:

2^3x+1=128
And we know that 2^7=128
Now we just have to make 3x+1=7:
3x+1=7
x=(7-1)/3
x=2

And there you have it x=2

In the DBE 122 class, there are 350 possible points. These points come from 5 homework sets that are worth 10 points each and 3 tests that are worth 100 points each. A student has received homework scores of 7, 8, 7, 5, and 8 and the first two test scores are 81 and 80. Assuming that grades are assigned according to the standard scale, where if the grade percentage is 0.9 or higher the student will get an A, and if the grade percentage is between 0.8 and 0.9 the student will get a B, and there are no weights assigned to any of the grades, is it possible for the student to receive an A in the class? What is the minimum score on the third test that will give an A? What about a B?

Answers

Answer:

hey mate how r u I am good I am new to this app

Each side of a square is increasing at a rate of 3 cm/s. At what rate is the area of the square increasing when the area of the square is 36 cm2?

Answers

Each side of the square would have to be 6 cm to have an area of 36 cm^2.  However, as a side can never be 0, and you never gave a starting size for the square, the question is unanswerable.

Evaluate the expression.........

Answers

Answer:

9

Step-by-step explanation:

p^2 -4p +4

Let p = -1

(-1)^1 -4(-1) +4

1 +4+4

9

Find the domain of the graphed function.
10
-10
10
10
O A. -45x39
B. -43x8
C. X2-4
0
D. x is all real numbers.

Answers

Dddddddddddddddddddddd

show that 7 1/2 - 4 2/3 = 2 5/6

Answers

You have to make the denominator common before subtracting 2 fractions.

Since the end fraction has a denominator of 6 try and multiply both of the ones on the LHS to get 6 as a denominator.

First though convert the improper fractions into fractions solely.

7 1/2 goes to 15/2

While

4 2/3 goes to 14/3

Now

15/2 multiply both numerator and denominator by 3 gives you 45/6

14/3 multiply both numerator and denominator by 2 gives you 28/6

Subtract 45/6 by 28/6= 17/6

Highest multiple of 6 in 17 is 12
12/6 + 5/6 = 2 5/6

Equation is [tex]7\frac{1}{2} -4\frac{2}{3}=2\frac{5}{6}[/tex] is true.

What is Equation?

Two or more expressions with an Equal sign is called as Equation.

The given equation is [tex]7\frac{1}{2} -4\frac{2}{3}=2\frac{5}{6}[/tex]

We need to check whether the left hand side is equal to right hand side.

These are in the form pf mixed fraction we can convert them to the improper fraction.

[tex]7\frac{1}{2}=15/2[/tex]

[tex]4\frac{2}{3}=\frac{14}{3}[/tex]

So Let us subtract 24/3 from 15/2

15/2-14/3

LCM of 2 and 3 is 6

45-28/6

17/6

This can be written as mixed fraction [tex]2\frac{5}{6}[/tex]

Hence, equation is [tex]7\frac{1}{2} -4\frac{2}{3}=2\frac{5}{6}[/tex] is true.

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The mean monthly car payment for 123 residents of the local apartment complex is $624. What is the best point estimate for the mean monthly car payment for all residents of the local apartment complex?

Answers

Answer:

The best point estimate for the mean monthly car payment for all residents of the local apartment complex is $624.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

In this question:

We apply the inverse Central Limit Theorem.

The mean monthy car payment for 123 residents of the local apartment complex is $624.

So, for all residents of the local apartment complex, the best point estimate for the mean monthly car payment is $624.

The amount of pollutants that are found in waterways near large cities is normally distributed with mean 8.6 ppm and standard deviation 1.3 ppm. 38 randomly selected large cities are studied. Round all answers to 4 decimal places where possible
a. What is the distribution of X?
b. What is the distribution of a?
c. What is the probability that one randomly selected city's waterway will have more than 8.5 ppm pollutants?
d. For the 38 cities, find the probability that the average amount of pollutants is more than 8.5 ppm.
e. For part d), is the assumption that the distribution is normal necessary?
f. Find the IQR for the average of 38 cities.
Q1=__________ ppm
Q3 =_________ ppm
IQR=_________ ppm

Answers

We assume that question b is asking for the distribution of [tex] \\ \overline{x}[/tex], that is, the distribution for the average amount of pollutants.

Answer:

a. The distribution of X is a normal distribution [tex] \\ X \sim N(8.6, 1.3)[/tex].

b. The distribution for the average amount of pollutants is [tex] \\ \overline{X} \sim N(8.6, \frac{1.3}{\sqrt{38}})[/tex].

c. [tex] \\ P(z>-0.08) = 0.5319[/tex].

d. [tex] \\ P(z>-0.47) = 0.6808[/tex].

e. We do not need to assume that the distribution from we take the sample is normal. We already know that the distribution for X is normally distributed. Moreover, the distribution for [tex] \\ \overline{X}[/tex] is also normal because the sample was taken from a normal distribution.

f. [tex] \\ IQR = 0.2868[/tex] ppm. [tex] \\ Q1 = 8.4566[/tex] ppm and [tex] \\ Q3 = 8.7434[/tex] ppm.

Step-by-step explanation:

First, we have all this information from the question:

The random variable here, X, is the number of pollutants that are found in waterways near large cities.This variable is normally distributed, with parameters:[tex] \\ \mu = 8.6[/tex] ppm.[tex] \\ \sigma = 1.3[/tex] ppm.There is a sample of size, [tex] \\ n = 38[/tex] taken from this normal distribution.

a. What is the distribution of X?

The distribution of X is the normal (or Gaussian) distribution. X (uppercase) is the random variable, and follows a normal distribution with [tex] \\ \mu = 8.6[/tex] ppm and [tex] \\ \sigma =1.3[/tex] ppm or [tex] \\ X \sim N(8.6, 1.3)[/tex].

b. What is the distribution of [tex] \\ \overline{x}[/tex]?

The distribution for [tex] \\ \overline{x}[/tex] is [tex] \\ N(\mu, \frac{\sigma}{\sqrt{n}})[/tex], i.e., the distribution for the sampling distribution of the means follows a normal distribution:

[tex] \\ \overline{X} \sim N(8.6, \frac{1.3}{\sqrt{38}})[/tex].

c. What is the probability that one randomly selected city's waterway will have more than 8.5 ppm pollutants?

Notice that the question is asking for the random variable X (and not [tex] \\ \overline{x}[/tex]). Then, we can use a standardized value or z-score so that we can consult the standard normal table.

[tex] \\ z = \frac{x - \mu}{\sigma}[/tex] [1]

x = 8.5 ppm and the question is about [tex] \\ P(x>8.5)[/tex]=?  

Using [1]

[tex] \\ z = \frac{8.5 - 8.6}{1.3}[/tex]

[tex] \\ z = \frac{-0.1}{1.3}[/tex]

[tex] \\ z = -0.07692 \approx -0.08[/tex] (standard normal table has entries for two decimals places for z).

For [tex] \\ z = -0.08[/tex], is [tex] \\ P(z<-0.08) = 0.46812 \approx 0.4681[/tex].

But, we are asked for [tex] \\ P(z>-0.08) \approx P(x>8.5)[/tex].

[tex] \\ P(z<-0.08) + P(z>-0.08) = 1[/tex]

[tex] \\ P(z>-0.08) = 1 - P(z<-0.08)[/tex]

[tex] \\ P(z>-0.08) = 0.5319[/tex]

Thus, "the probability that one randomly selected city's waterway will have more than 8.5 ppm pollutants" is [tex] \\ P(z>-0.08) = 0.5319[/tex].

d. For the 38 cities, find the probability that the average amount of pollutants is more than 8.5 ppm.

Or [tex] \\ P(\overline{x} > 8.5)[/tex]ppm?

This random variable follows a standardized random variable normally distributed, i.e. [tex] \\ Z \sim N(0, 1)[/tex]:

[tex] \\ Z = \frac{\overline{X} - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex] [2]

[tex] \\ z = \frac{\overline{8.5} - 8.6}{\frac{1.3}{\sqrt{38}}}[/tex]

[tex] \\ z = \frac{-0.1}{0.21088}[/tex]

[tex] \\ z = \frac{-0.1}{0.21088} \approx -0.47420 \approx -0.47[/tex]

[tex] \\ P(z<-0.47) = 0.31918 \approx 0.3192[/tex]

Again, we are asked for [tex] \\ P(z>-0.47)[/tex], then

[tex] \\ P(z>-0.47) = 1 - P(z<-0.47)[/tex]

[tex] \\ P(z>-0.47) = 1 - 0.3192[/tex]

[tex] \\ P(z>-0.47) = 0.6808[/tex]

Then, the probability that the average amount of pollutants is more than 8.5 ppm for the 38 cities is [tex] \\ P(z>-0.47) = 0.6808[/tex].

e. For part d), is the assumption that the distribution is normal necessary?

For this question, we do not need to assume that the distribution from we take the sample is normal. We already know that the distribution for X is normally distributed. Moreover, the distribution for [tex] \\ \overline{X}[/tex] is also normal because the sample was taken from a normal distribution. Additionally, the sample size is large enough to show a bell-shaped distribution.  

f. Find the IQR for the average of 38 cities.

We must find the first quartile (25th percentile), and the third quartile (75th percentile). For [tex]\\ P(z<0.25)[/tex], [tex] \\ z \approx -0.68[/tex], then, using [2]:

[tex] \\ -0.68 = \frac{\overline{X} - 8.6}{\frac{1.3}{\sqrt{38}}}[/tex]

[tex] \\ (-0.68 *0.21088) + 8.6 = \overline{X}[/tex]

[tex] \\ \overline{x} =8.4566[/tex]

[tex] \\ Q1 = 8.4566[/tex] ppm.

For Q3

[tex] \\ 0.68 = \frac{\overline{X} - 8.6}{\frac{1.3}{\sqrt{38}}}[/tex]

[tex] \\ (0.68 *0.21088) + 8.6 = \overline{X}[/tex]

[tex] \\ \overline{x} =8.7434[/tex]

[tex] \\ Q3 = 8.7434[/tex] ppm.

[tex] \\ IQR = Q3-Q1 = 8.7434 - 8.4566 = 0.2868[/tex] ppm

Therefore, the IQR for the average of 38 cities is [tex] \\ IQR = 0.2868[/tex] ppm. [tex] \\ Q1 = 8.4566[/tex] ppm and [tex] \\ Q3 = 8.7434[/tex] ppm.

Duran Manufacturing uses a process costing system and manufactures its product in three departments. Which of the following is NOT a way in which Duran can use the cost per unit of each process? A) Duran can look for ways to cut the costs when actual process costs are more than planned process costs. B) Duran needs to set the selling price to cover the costs of making the product and provide a profit. C) Duran can only use the cost per unit of each process if all units are fully completed at the end of the accounting period. D) Duran needs to know the ending balances in the following accounts: Work-In-Process Inventory, Finished Goods Inventory, and Cost of Goods Sold.

Answers

Answer:

C) Duran can only use the cost per unit of each process if all units are fully completed at the end of the accounting period.

Step-by-step explanation:

Duran uses cost accounting technique to identify cost per unit for its products. The costing techniques allows us to identify the cost of unit that are not completely finished. It is not necessary that all unit must be completed in order to find out the cost per unit of the product. The process costing is the best method to identify cost per unit for products that are in process.

if jonny has 3 × 6 amounts of dish soap, how much dish soap does he have?!

a(I dont know)

b(18)

c(12)

d(6)
look up a skit called what's 6×3 before answering. ​

Answers

Answer: 18 (b)

Step-by-step explanation:

3x6=18

Answer:

18

Step-by-step explanation:

you can use a visual for a short answer or organize 3 dots in six groups, count in total

What is the solution to the system of equations x+y=10 and x+2y=4 using the linear combination method?

Answers

Answer:

The solution:

X = 16 and Y = -6

Step-by-step explanation:

The equations to be solved are:

x+y = 10 ------- equation 1

x+2y = 4 ----------- equation 2

we can multiply equation 1 by -1 to make the value of x and y negative.

This will give us

-x- y = - 10 ------- equation 3

x+2y = 4 ----------- equation 2

We will now add equations 3 and 2 together so that x will cancel itself out.

this will give us

y = -10 +4 = -6

hence, we have the value of y as -6.

To get the value of x, we can put this value of y into any of the equations above.  (I will use equation 1)

x - 6 = 10

from this, we have that x = 4

Therefore, we have our answer as

X = 16 and Y = -6

Let x=−1−5i and y=5−i. Find x⋅y.

Answers

Answer:

-10 -24i

Step-by-step explanation:

Note : i=√-1 (imaginary number)

i² = -1

xy

= (−1−5i)(5−i)

= -5 +i -25i +5i²

=-5 +i -25i + 5(-1)

= -5 +i -25i -5

= -5 -5 +i -25i

= -10 -24i

A complex number is a number system that extends the real numbers with a particular element labelled "i" known as the imaginary unit. The value of x·y is (−10 −24i).

What is a complex number?

A complex number is a number system that extends the real numbers with a particular element labelled "i" known as the imaginary unit, and satisfies the equation i² = -1; every complex number may be represented as a + bi, where a and b are real numbers.

Given that x=−1−5i and y=5−i. Therefore, the value of x·y is,

x·y = (−1 −5i)(5-i)

     = −5 + i −25i +5i²

     = −5 −24i − 5

      = −10 −24i

Hence, the value of x·y is (−10 −24i).

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A superintendent of a school district conducted a survey to find out the level of job satisfaction among teachers. Out of 53 teachers who replied to the survey, 13 claim they are satisfied with their job.
z equals fraction numerator p with hat on top minus p over denominator square root of begin display style fraction numerator p q over denominator n end fraction end style end root end fraction
The superintendent wishes to construct a significance test for her data. She find that the proportion of satisfied teachers nationally is 18.4%.
What is the z-statistic for this data? Answer choices are rounded to the hundredths place.
a. 2.90
b. 1.15
c. 1.24
d. 0.61

Answers

Answer:

b. 1.15

Step-by-step explanation:

The z statistics is given by:

[tex]Z = \frac{X - p}{s}[/tex]

In which X is the found proportion, p is the expected proportion, and s, which is the standard error is [tex]s = \sqrt{\frac{p(1-p)}{n}}[/tex]

Out of 53 teachers who replied to the survey, 13 claim they are satisfied with their job.

This means that [tex]X = \frac{13}{53} = 0.2453[/tex]

She find that the proportion of satisfied teachers nationally is 18.4%.

This means that [tex]p = 0.184[/tex]

Standard error:

p = 0.184, n = 53.

So

[tex]s = \sqrt{\frac{0.184*0.816}{53}} = 0.0532[/tex]

Z-statistic:

[tex]Z = \frac{X - p}{s}[/tex]

[tex]Z = \frac{0.2453 - 0.184}{0.0532}[/tex]

[tex]Z = 1.15[/tex]

The correct answer is:

b. 1.15

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