weight=mass*gravity
w=2959.0*10
w=29590N
The weight of a 2959.0-kg car that is moving at a speed of 21 m / s would be 28998.2 Newtons, here speed of the car is the redundant value that is not used to calculate the weight of the car.
What is gravity?It can be defined as the force by which a body attracts another body toward its center as the result of the gravitational pull of one body and another.
As given in the problem, we have to determine the weight of a 2959.0-kg car that is moving at a speed of 21 m / s .
The weight of the car = mass of the car × acceleration due to gravity
= 2959 × 9.8
= 28998.2 Newtons
Thus, the weight of a 2959.0-kg car that is moving at a speed of 21 m / s would be 28998.2 Newtons.
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A rocket takes off from Earth. It travels 825km in 75 seconds. What is the
speed of the rocket?
0 1 km/s
11 km/s
O 1.1 km/s
O 111 km/s
Answer:
11 km/s
Explanation:
v=s/t
v=825km/75s
v=11km/s
7. Your teacher has mixed salt, pepper, and water. Describe a procedure that you could use to separate this mixture. Be sure to list all of the materials you would need, your set up, and your expected results.
Answer:
hope this could help you
23. A ball is dropped from 215m. How long will it take to reach the ground?
Answer:
6.6 s.
Explanation:
From the question given above, the following data were obtained:
Height (h) = 215 m
Time (t) =..?
Thus, we can obtain the time taken for the ball to get to the ground by applying the following formula:
h = ½gt²
Where:
h is the height.
g is the acceleration due to gravity
t is the time to taken.
With the above formula, the time taken for the ball to get to the ground can be obtained as follow:
Height (h) = 215 m
Acceleration due to gravity (g) = 9.8 m/s²
Time (t) =..?
h = ½gt²
215 = ½ × 9.8 × t²
215 = 4.9 × t²
Divide both side by 4.9
215 / 4.9 = t²
Take the square root of both side.
t = √(215 / 4.9)
t = 6.6 s
Therefore, it will take 6.6 s for the ball to get to the ground.
Carlos gets tired of pushing and instead begins to pull with force Fpull at an angle to the horizontal.
The block slides along the rough horizontal surface at a constant speed. A free-body diagram for the
situation is shown below. Blake makes the following claim about the free-body diagram:
Blake: “The velocity of the block is constant, so the net force exerted on the block must be zero.
Thus, the normal force FN equals the weight Fmg, and the force of friction Ff equals the applied
force Fpull.”
What, if anything, is wrong with this statement? If something is
wrong, identify it and explain how to correct it. If this statement is
correct, explain why.
Answer:
The wrong items are;
1) The normal for FN equals the weight Fmg
2) The force of friction, Ff, equals the applied force Fpull
The corrected statements are;
1) The normal force is weight less the vertical component of the applied force Fpull
FN = Fmg - Fpull × sin(θ)
2) The force of friction equals the horizontal component of the applied force Fpull
Ff = Fpull × cos(θ)
Explanation:
The given statement was;
The velocity of the block is constant, so the net force exerted on the block must be zero. Thus, the normal force FN equals the weight Fmg, and the force of friction Ff equals the applied force Fpull
By the equilibrium of forces actin on the system, given that the applied force acts at an angle, θ, with the horizontal, we have;
The normal force is equal to the weight less the vertical component of the applied force;
That is we have, FN = Fmg - Fpull × sin(θ)
The friction force similarly, is equal to the horizontal component of the applied force;
Ff = Fpull × cos(θ)
The wrong items are therefore as follows;
1) The normal for FN equals the weight Fmg
1 i) The normal force is weight less the vertical component of the applied force Fpull
FN = Fmg - Fpull × sin(θ)
2) The force of friction, Ff, equals the applied force Fpull
2 i) The force of friction equals the horizontal component of the applied force Fpull
Ff = Fpull × cos(θ).
A force of 500 N acts for a time interval of 0.001 second on an object of mass 0.20 kg that was initially at rest. Calculate the final velocity of the object after the force acts
Answer:
100
Explanation:
The final velocity of the object after the force acts is 2.5 meters per second.
To calculate the final velocity of the object after the force acts, we can use Newton's second law of motion, which states that:
Force = Mass × Acceleration
We need to find the acceleration of the object first. Since the object was initially at rest, its initial velocity (u) is 0 m/s.
The force acting on the object is 500 N, and the mass of the object is 0.20 kg. We can rearrange the equation to find the acceleration (a):
Acceleration (a) = Force / Mass
a = 500 N / 0.20 kg
a = 2500 m/s²
Now, we can use the kinematic equation to find the final velocity (v) of the object:
Final velocity (v) = Initial velocity (u) + (Acceleration × Time)
The initial velocity (u) is 0 m/s (since the object was initially at rest), and the time interval (t) is 0.001 second.
Final velocity (v) = 0 m/s + (2500 m/s² × 0.001 s)
v = 0 m/s + 2.5 m/s
v = 2.5 m/s
Hence, the final velocity of the object after the force acts is 2.5 meters per second.
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2
How is acceleration related to force when mass is constant, according to Newton's second law of motion?
A. The acceleration is directly proportional to the net force,
OB
The acceleration is inversely proportional to the net force.
C. The acceleration is inversely proportional to the square root of the net force.
OD
The acceleration is directly proportional to the square root of the net force.
Reset
Next Question
Answer:
A
Explanation:
The acceleration of an object is directly proportional to its net force.
[tex]a = \frac{f}{m} [/tex]
Answer:
Correct choice: A. The acceleration is directly proportional to the net force
Explanation:
Newton's Second Law of Motion
According to Newton's second law of motion, the acceleration of an object is directly proportional to the net force F and inversely proportional to the object's mass m:
[tex]\displaystyle a=\frac{F}{m}[/tex]
Correct choice: A. The acceleration is directly proportional to the net force
Select the correct answer.
Type O negative blood is considered the universal red blood cell donor because it
OA.
Has all 3 types of antigens.
OB.
Has all 3 types of antibodies.
Lacks all 3 types of antigens.
OD
Lacks all 3 types of antibodies.
Answer:
The answer is C.) Lacks all 3 types of antigens.
Which statement is true about magnetic field lines?
O A. They point toward the north pole of a magnet and away from the
south pole.
OB. They point toward the south pole of a magnet and away from the
north pole
O C. They loop from the south pole to the south pole and from the
north pole back to the north pole.
OD. No consistent pattern exists in the lines.
Answer:
It’s option B
Explanation:
Magnetic field lines are defined to have the direction that a small compass points when placed at a location. If small compasses are used to map the magnetic field around a bar magnet, they will point in the directions shown: away from the north pole of the magnet, toward the south pole of the magnet.
The magnetic field lines are the points towards the south pole of magnet and are away from the north pole. Thus, option B is correct.
What are magnetic field lines?A North magnetic pole would move along magnetic field lines, which are lines drawn in a magnetic field. Magnetic lines of force are another name for the magnetic field lines.
The north pole serves as the starting point for magnetic lines of force, which end at the south pole. They won't ever cross over each other.
Small compasses will point away from the magnet's north pole and toward its south pole when used to map the magnetic field surrounding a bar magnet.
Therefore, the magnetic field lines are given to have direct attention away from the north pole of a magnet and toward its south pole.
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21000 km/hr how far will it travel in 5 hours
Answer:
105000 is the answer your welcome
Explanation:
105000
Which event is an example of condensation?
A. Wet clothes are drying on a clothesline.
B. A mirror fogs up when someone takes a hot shower.
C. Water drips from an icicle on the edge of a roof.
O D. Rain turns to sleet as it nears the ground.
Answer:
the answer to your question is b a mirror fogs up when someone takes a hot shower.
The process of conversion of gaseous water to its liquid form is called condensation. The fogs formed on the mirror from the hot shower is an example of condensation.
What is condensation?Condensation is the process of cooling up of water vapor to liquid water. Water vapor condenses when it cools. Condensation can be best understood from the reason behind raining.
When water vaporizers from resources and cools from the sky, and the vapor condenses to form liquid droplets. Similarly we can observe water droplets in the window pane due to the similar effect.
The water vapor arises from the hot shower condenses in the atmosphere and forms the drops on the mirror. Therefore, the mirror fogs up by the hot shower is an example of condensation.
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write about any five form of energy with example
Answer:
The different types of energy include thermal energy, radiant energy, chemical energy, nuclear energy, electrical energy, motion energy, sound energy, elastic energy and gravitational energy.
Answer:
Chemical energy
Explanation:
Ex. gasoline, chemical batteries, and wood
The moon euphoria is in a circular orbit around Jupiter. Which of the following describes the direction of the centripetal force acting on euphoria.
A) pointing hand into the path of its orbit
B) pointing towards the sun
C)Pointing away from Jupiter
D) pointing towards Jupiter
conversion
18230 mJ to kJ?
Answer:
0.01823
Explanation:
big brain
lily took 57 seconds to walk from schoolroom to library. if the distance between the classroom and library was 38m, at what average speed did lily walk in m/min?
Answer:
7mph
Explanation:
At a race car driving event, a staff member notices that the skid marks left by the race car are 9.06 m long. The very experienced staff member knows that the deceleration of a car when skidding is -40.52 m/s2. What can the staff member estimate for the original speed of the race car if it came to a stop during the skid?
Answer:
27.1 m/s
Explanation:
Given that at a race car driving event, a staff member notices that the skid marks left by the race car are 9.06 m long. The very experienced staff member knows that the deceleration of a car when skidding is -40.52 m/s2.
Using third equation of motion,
V^2 = U^2 + 2aS
Since the car is decelerating, the final velocity V = 0
Substitute all the parameter into the equation above,
0 = U^2 - 2 * 40.52 * 9.06
U^2 = 734.22
U = [tex]\sqrt{734.22}[/tex]
U = 27.096
U = 27.1 m/s approximately
Therefore, the staff member can estimate for the original speed of the race car to be 27.1 m/s if it came to a stop during the skid
please help im dying
A moving car skids to a stop with the wheels locked across a level roadway. Of the forces listed, identify which act on the car.
Normal
Gravity
Applied
Friction
Tension
Air resistance
Answer:
Normal, Gravity, Friction, and Air Resistance.
Explanation:
When a moving car skid to stop and its wheels are locked across, then the following forces will be applied on the car:
Normal force: It will act counter to gravity that pushes an object against a surface and acts perpendicular to the contact surface.
Gravity: Gravity force acts in each and every object having mass and it can not be avoidable. So, the gravity force will also apply to the car and attract it to the earth's surface.
Friction: Friction is a force that acts opposite to the motion and stops or slows motion. Friction will be applied to the car that will oppose the motion of the car and stop it.
Air resistance: air resistance is defined as the forces exerted by air that acts opposite to the relative motion of an object. Air resistance will also be applied to the car when it will skid to stop as we are always surrounded by the air.
Hence, the correct answers are "Normal, Gravity, Friction, and Air Resistance."
How many meters did the car go in the first 4 seconds?
1. According to Newton's third law of motion, how are action
and reaction forces related?
2. How is momentum conserved?
3. Suppose you and a friend, who has exactly twice your mass,
are on skates. You push away from your friend. How does the
force with which you push your friend compare to the force
with which your friend
pushes you? How do your
accelerations compare?
4. Thinking Critical be ly comparing and Contrasting
Which has more momentum, a 250-kg dolphin swimming
at 6 m/s, or a 450-kg manatee swimming at 2 m/s?
(need 1-4 answered ASAP)
Answer:
you couldn't do this on your own or search it up on google
A neutral atom of alluminum has 13 protons and how many electrons
Answer: also 13
Explanation: because there have to be an equal number of protons,neutrons,and electrons to make the atom stable.
which of the following is the same as 1 second
Answer:
theres no
Explanation:
picture or anything so... ur question doesnt make sense
protons are present in sodium atom.
a 11
b 10
C 12
d 9
11
Explanation:
There are 11 protons in a sodium atom
For the past few days, the weather in Miami has been cool. When the temperature did warm up, the meteorologists noticed that it was also very windy. How could winds influence the temperature?
A. Winds carry energy in the form of heat around Earth.
B. Winds are caused by the energy of the sun.
C. Winds move because of differential heating.
D. Winds transfer energy in the form of heat from the air to the ground.
can we add 2 atoms together? 3? How do particles combine to form the variety of matter one observes?
To change from one unit to another in the metric system multiply or divide by multiples of what number?
A. 2
B. 5
C. 10
D. 15
Answer:
10
Explanation:
Answer:
answer-10 change from one unit to another in the metric system, multiply or divide by multiples of what number?
2
5
10
15
Explanation:
Will was riding his bike when a dog ran out in front of him. He slammed on his brakes. During this quick stop, some of the mechanical energy (his motion) was changed into
A) heat energy.
B) light energy.
C) kinetic energy.
D) gravitational energy.
Answer:
A
Explanation:
big brain
During this quick stop, some of the mechanical energy (his motion) was changed into heat energy.
What is energy?Energy is the ability to do work. There are different types of energy such as Heat energy, light energy, kinetic energy, and gravitational energy.
Heat is the energy that moves from one body to another when temperatures are different. Heat passes from the hotter to the colder body when two bodies with differing temperatures are brought together.
The joule is a unit of energy that serves as the SI unit for heat (J). The calorie (cal), which is defined as "the amount of heat necessary to raise the temperature of one gram of water from 14.5 degrees Celsius to 15.5 degrees Celsius," is another common unit of heat measurement.
Therefore, During this quick stop, some of the mechanical energy (his motion) was changed into heat energy.
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A student fires a cannonball vertically upwards. The cannonball returns to the
ground after a 4.60s flight. Determine all unknowns and answer the following
questions. Neglect drag and the initial height and horizontal motion of the
cannonball. Use regular metric units (ie. meters).
How long did the cannonball rise?
unit
What was the cannonball's initial speed?
unit
What was the cannonball's maximum height?
unit
V
Answer:
(a). The distance is 207 m.
(b). The initial velocity is 45.0 m/s
(c). The maximum height is 103.3 m
Explanation:
Given that,
Time = 4.60 s
We need to calculate the initial velocity
Using equation of motion
[tex]v=u-gt[/tex]
Put the value into the formula
[tex]0=u-9.8\times4.60[/tex]
[tex]u=45.0\ m/s[/tex]
We need to calculate the distance
Using formula of distance
[tex]d=v\times t[/tex]
Put the value into the formula
[tex]d=45\times4.60[/tex]
[tex]d=207\ m[/tex]
We need to calculate the maximum height
Using equation of motion
[tex]v^2=u^2-2gh[/tex]
Put the value into the formula
[tex]0=(45.0)^2-2\times9.8\times h[/tex]
[tex]h=\dfrac{(45.0)^2}{2\times9.8}[/tex]
[tex]h=103.3\ m[/tex]
Hence, (a). The distance is 207 m.
(b). The initial velocity is 45.0 m/s
(c). The maximum height is 103.3 m
A water skier is towing by motorboat at a constant velocity of magnitude 15 km /h. The boat speed up, and after a short interval the skier is towed at a new constant velocity of magnitude 20 km/h. What is the net force on the skier when she is moving at 15 km/h? And at 20 km/h?
Answer:
The skier is experimenting a net force of 0 newtons in both cases. ([tex]v_{1} = 15\,\frac{km}{h}[/tex], [tex]v_{2} = 20\,\frac{km}{h}[/tex])
Explanation:
According to Newton's First Law, an object is in equilibrium when it is either at rest or moving at constant velocity, which means that net force is equal to 0 newtons.
Therefore, the skier is experimenting a net force of 0 newtons in both cases.
What 2 gases make up most of the atmosphere?
Answer:
nitrogen oxygen carbon dioxideand argon
Explanation:
A moving object with a decreasing velocity covers distance during
each new second than it covered in the previous second.
A.the same
B.more
C.less