Determine the slope of the line passing through the points (0,-3) and (3,-11).

Answer:

[tex]\frac{x^{\frac{5}{6}} }{x^{\frac{1}{6}} } = x^{(\frac{5}{6} -\frac{1}{6}) }= x^{\frac{4}{6} }\\\sqrt{x} . \sqrt[4]{x} = x^{\frac{1}{2} } . x^{\frac{1}{4} } = x^{(\frac{1}{2} +\frac{1}{4}) } = x^{\frac{3}{4}[/tex]

Answer:

Section I test scores are more dispersed that that of section II.

Step-by-step explanation:

Consider the data collected from the arithmetic test given to two sections of a school.

Section I: Mean = 45, Standard  Deviation = 6.5

Section II: Mean = 45,  Standard deviation = 3.1

The mean of both the sections are same, i.e. 45.

So there is no comparison that can be made from the center of the distribution.

The standard  deviation for section I is 6.5 and the standard  deviation for section II is 3.1.

The standard deviation is a measure of dispersion, i.e. it tells us how dispersed the data is from the mean or how much variability is present in the data.

The standard  deviation for section I is higher than that of section II.

So, this implies that section I test scores are more dispersed that that of section II.

Answer:

0.5*sqrt33

Step-by-step explanation:

A(0,0,0) B(-4,1,-2), c(-4,2,-3)

Vector AB is (-4-0,-1-0, -2-0)= (-4,-1,-2)  The modul of AB is sqrt (4squared+

+(-1) squared+ (-2) squared)= sqrt (16+1+4)=sqrt21

Vector AC is (-4,2,-3) The modul of vector AC is equal to sqrt ((-4)squared+ 2squared+(-3)squared)= sqrt(16+4+9)= sqrt29

Vector BC is equal to (-4-(-4), 2-1, -3-(-2))= (0,1,-1)

The modul of BC is sqrt (1^2+(-1)^2)=sqrt2

Find the angle B

Ac^2= BC^2+AB^2-2*BC*AB*cosB

29= 2+21-2*sqrt2*sqrt21*cosB

29= 2+21-2*sqrt42*cosB

cosB= -3/ sqrt42

sinB= sqrt( 1-(-3/sqrt42)^2)=sqrt33/42= sqrt11/14

s=1/2* (sqrt2*sqrt21*sqrt11/14)=1/2*sqrt(42*11/14)= 0.5*sqrt33

Answer:

hfwhww45 5h wahdaw 5656 adshjdawh bh4 54

Step-by-step explanation:

5767

12345

Sum of digits = 1+2+3+4+5

= 15

Which means divisible by 3

Ends with 0 or 5 = Yes ends with 5

Therefore the number is divisible by 15

12345÷15 = 823

Divisiblity rule of 15 = Any number is divisible by 15 if the sum of the digits is divisible by 3 and the number ends with a 0 or 5.

Must click thanks and mark brainliest

Answer:

20 days

Step-by-step explanation:

Renting a car costs $30 per day.

y = 30x

Renting a car costs $600 per month

y = 600

Set the two equations equal to each other.

30x = 600

(30x)/30 = (600)/30

x = 20

After 20 days, the two options have an equal cost.

Answer:

there are many types of polyhedron.

Basically about which one you want to know?

Step-by-step explanation:

Pentahydron. A polyhedron with 5 faces.

Hexahyderon. A polyhedron with 6 faces.

HeptahyderonA polyhedron with 7 faces.

Octahyderon. A polyhedron with 8 faces.

Similarly there are three more...

Please tell me if it was helpful to you.

If not, then ask me again..

Answer:

11/(x + 1) thus d: is the answer

Step-by-step explanation:

Simplify the following:

(11 (x + 8))/((x + 1) (x + 8))

(11 (x + 8))/((x + 1) (x + 8)) = (x + 8)/(x + 8)×11/(x + 1) = 11/(x + 1):

Answer: 11/(x + 1)

Answer:

345

Step-by-step explanation:

20*3 = 60 there's 60 minutes in one hour

115*3 = 345

Answer:

Need more explation of the question

Step-by-step explanation:

Hello!

Answer:

[tex]\huge\boxed{\frac{12}{20}}[/tex]

To find the numerator and denominator, we can set up a proportion where:

x = denominator

x -8 = numerator

[tex]\frac{3}{5} = \frac{x-8}{x}[/tex]

Cross multiply:

[tex]3(x) = 5(x - 8)[/tex]

[tex]3x = 5x - 40[/tex]

Simplify:

[tex]3x - 5x = -40\\\\-2x = -40\\\\x = 20[/tex]

Substitute in this value of x to find the numerator and denominator:

[tex]\frac{(20) - 8}{(20)} = \frac{12}{20}[/tex]

Hope this helped you! :)

[tex] \LARGE{ \boxed{ \rm{ \orange{ Solution:}}}}[/tex]

Let the numerator be x

It is given that,

Then,

⇛ Denominator- 8 = x

⇛ Denominator = x + 8

According to condition -2)

⇛ Fraction = 3/5

⇛ x/x + 8 = 3/5

Cross multiplying,

⇛ 3(x + 8) = 5x

⇛ 3x + 24 = 5x

⇛ 24 = 5x - 3x

⇛ 24 = 24

Flipping it out,

⇛ 2x = 24

⇛ x = 24/2 = 12

Then,

⇛ x + 8 = 12 + 8 = 20

[tex] \large{ \therefore{ \boxed{ \rm{ \pink{Then, \: the \: fraction = \dfrac{12}{20} }}}}}[/tex]

━━━━━━━━━━━━━━━━━━━━

Hey There!!

The answer to this is: A quadrilateral has vertices A(3, 5), B(2, 0), C(7, 0), and D(8, 5). Which statement about the quadrilateral is true?" Line BC is parallel to line AD because their slopes is equal i.e. (0 - 0) / (7 - 2) = (5 - 5) / (8 - 3) which gives 0 / 5 = 0 / 5 giving that 0 = 0. We check whether line AB is parallel to line CD. Slope of line AB is given by (0 - 5) / (2 - 3) = -5 / -1 = 5. Slope of line CD is given by (5 - 0) / (8 - 7) = 5 / 1 = 5 We have been able to prove that the opposite sides of the quadrilateral are parallel which means that the quadrilateral is not a trapezoid. Next we check whether the length of the sides are equal. Length of line AB is given by sqrt[(0 - 5)^2 + (2 - 3)^2] = sqrt[(-5)^2 + (-1)^2] = sqrt(25 + 1) = sqrt(26) Length of line BC is given by sqrt[(0 - 0)^2 + (7 - 2)^2] = sqrt[0^2 + 5^2] = sqrt(25) = 5 Length of line CD is given by sqrt[(5 - 0)^2 + (8 - 7)^2] = sqrt[5^2 + 1^2] = sqrt(25 + 1) = sqrt(26) Length of line DA is given by sqrt[(5 - 5)^2 + (8 - 3)^2] = sqrt[0^2 + 5^2] = sqrt(25) = 5 Thus, the length of the sides of the quadrilateral are not equal but opposite sides are equal which means that the quadrilateral is not a rhombus. Finally, we check whether adjacent lines are perpendicular. Recall the for perpendicular lines, the product of their slopes is equal to -1. Slope of line AB = 5 while slope of line BC = 0. The product of their slopes = 5 x 0 = 0 which is not -1, thus the adjacent sides of the quadrilateral are not perpendicular which means that the quadrilateral is not a rectangle. Therefore, ABCD is a parallelogram with non-perpendicular adjacent sides. Thus, For (option A).

Hope It Helped!~ ♡

ItsNobody~ ☆

Answer:

A. ABCD is a parallelogram with non-perpendicular adjacent sides.

Hope this helps!

Step-by-step explanation:

Rx=1 means to reflect the given point on the line of x= 1

The mapping for the reflection on line x is x = k

(-2,7) = (-2(1) - -2,7) = (4,7)

The missing value is 7

Answer:

mass = 9a^5

center of mass = [tex]\frac{7a}{12}, \frac{7a}{12}, \frac{7a}{12}[/tex]

Step-by-step explanation:

Finding the mass of the solid E

given density function : p ( x,y,z ) = [tex]9x^2 + 9y^2 + 9z^2[/tex]

Mass =   [tex]\int\limits^a_0 \int\limits^a_0 \int\limits^a_0 {9(x^2+y^2+z^2)} \, dx dydz[/tex]   [tex]= \int\limits^a_0 \int\limits^a_0 {9(\frac{a^3}{3}+ay^2+az^2 )} \, dydz[/tex]

         [tex]= \int\limits^a_0 {9(\frac{a^4}{3}+\frac{a^4}{3} +a^2z^2 )} \, dz[/tex]  [tex]= \int\limits^a_0 {9(\frac{2a^4}{3}+a^2z^2 )} \, dz[/tex]  [tex]= 9 ( \frac{2a^5}{3} + \frac{a^5}{3} )[/tex]  

( taking limits as a and 0 )

hence Mass = 9 [tex](a^5)[/tex]

finding the center of mass

attached below is solution

128Answer:

128

Step-by-step explanation:

vì 4+4=8

8+8=16

16+16=32

32+32=64

64+64=128

Answer:

ZWU ~ WYU

WY = 2.5

UY= 1.5

Step-by-step explanation:

ZUW ~ WUY ~ ZWY

5/3=x+1/x

Cross multiply

5x=3x+3

2x=3

x=3/2 OR 1.5

Answer:

87, which is positive

Step-by-step explanation:

-8 --95

Subtracting a negative is like adding

-8 +95

87

Answer:

I've attached a graph with this, that's your answer

Answer:

80

Step-by-step explanation:

15 percent of 80 is 12

and 12 is 60 percent of 80!

hope this helps :)

Answer:

(-1,-4)

Step-by-step explanation:

The equation of a parabola os written as: ax^2+bx+c

This parabola's equation is x^2+2x-3

● a= 1

● b= 2

● c = -3

The coordinates of the parabola are: ( (-b/2a) ; f(-b/2a) )

● -b/2a = -2/2 = -1

● f(-b/2a) = (-1)^2+2×(-1)-3=1-2-3= -4

So the vertex coordinates are (-1,-4)

Answer:

-1+2X

Step-by-step explanation:

To convert [tex]24.123[/tex] in base 8, also notated with [tex]24.123_8[/tex] into base 10 simply multiply each digit with 8 to the power of its position relative to the decimal point.

So,

[tex]24.123_8=2\cdot8^1+4\cdot8^0+1\cdot8^{-1}+2\cdot8^{-2}+3\cdot8^{-3}=20.162109375_{10}[/tex]

Hope this helps :)

Answer:

The 90 % confidence limits are (-2.09, 8.09).

Since the calculated values do not lie in the critical region we accept our null hypothesis.

Step-by-step explanation:

The null and alternative hypothesis are given by

H0: σ₁²= σ₂² against Ha: σ₁² ≠ σ₂²

Confidence interval for the population mean difference is given by

(x`1- x`2) ± t √S²(1/n1 + 1/n2)

Where S ²= (n1-1)S₁² + S²₂(n2-1)/n1+n2-2

Critical value of t with n1+n2-2= 50+ 35-2= 83 will be -1.633

Now calculating

S ²=34* (12.8)²+ (14.6)²*49/83= 192.96

Now putting the values in the t- test

(75.1 -72.1) ± 1.633 √ 192.96(1/35 +1/50)

=3 ±  5.09

=-2.09, 8.09  is the 90 % confidence interval for the difference

The 90 % confidence limits are (-2.09, 8.09).

Since the calculated values do not lie in the critical region we accept our null hypothesis.

Answer:

[tex]t \: = 3.92 \: sec[/tex]

Step-by-step explanation:

When (t =0)

Height of cliff = 248 feet = 75.5m

Using Newton's equations of motion:

[tex]s = ut + \frac{1}{2} a {t}^{2} [/tex]

75.5 = 0 * t + 4.9 * t^2

Solving further :

[tex]t \: = 3.92 \: sec[/tex]

Answer:

12 feet

BRAINLIEST, PLEASE!

Step-by-step explanation:

Area = base x height

60 = base x 5

base = 60/5

base = 12

Step-by-step explanation:

Ellen - 115/23

Classmates and Ellen got = 5 each

Answer:

p = 5

Step-by-step explanation:

hopefully it is clear and understandable :)

Answer:

The numbers that are at a distance of 2 from the number 8 can be expressed using absolute value notation as:

|x - 8| = 2

Step-by-step explanation:

The numbers that are at a distance of 2 from the number 8 are the numbers that are satisfied by the equation:

|x - 8| = 2

The equation is written in the notation of absolute value as required.

Answer and Step-by-step explanation: Spherical coordinate describes a location of a point in space: one distance (ρ) and two angles (Ф,θ).To transform cartesian coordinates into spherical coordinates:

[tex]\rho = \sqrt{x^{2}+y^{2}+z^{2}}[/tex]

[tex]\phi = cos^{-1}\frac{z}{\rho}[/tex]

For angle θ:

Calculating:

a) (4,2,-4)

[tex]\rho = \sqrt{4^{2}+2^{2}+(-4)^{2}}[/tex] = 6

[tex]\phi = cos^{-1}(\frac{-4}{6})[/tex]

[tex]\phi = cos^{-1}(\frac{-2}{3})[/tex]

For θ, choose 1st option:

[tex]\theta = tan^{-1}(\frac{2}{4})[/tex]

[tex]\theta = tan^{-1}(\frac{1}{2})[/tex]

b) (0,8,15)

[tex]\rho = \sqrt{0^{2}+8^{2}+(15)^{2}}[/tex] = 17

[tex]\phi = cos^{-1}(\frac{15}{17})[/tex]

[tex]\theta = tan^{-1}\frac{y}{x}[/tex]

The angle θ gives a tangent that doesn't exist. Analysing table of sine, cosine and tangent: θ = [tex]\frac{\pi}{2}[/tex]

c) (√2,1,1)

[tex]\rho = \sqrt{(\sqrt{2} )^{2}+1^{2}+1^{2}}[/tex] = 2

[tex]\phi = cos^{-1}(\frac{1}{2})[/tex]

[tex]\phi[/tex] = [tex]\frac{\pi}{3}[/tex]

[tex]\theta = tan^{-1}\frac{1}{\sqrt{2} }[/tex]

d) (−2√3,−2,3)

[tex]\rho = \sqrt{(-2\sqrt{3} )^{2}+(-2)^{2}+3^{2}}[/tex] = 5

[tex]\phi = cos^{-1}(\frac{3}{5})[/tex]

Since x < 0, use 2nd option:

[tex]\theta = \pi + tan^{-1}\frac{1}{\sqrt{3} }[/tex]

[tex]\theta = \pi + \frac{\pi}{6}[/tex]

[tex]\theta = \frac{7\pi}{6}[/tex]

Cilindrical coordinate describes a 3 dimension space: 2 distances (r and z) and 1 angle (θ). To express cartesian coordinates into cilindrical:

[tex]r=\sqrt{x^{2}+y^{2}}[/tex]

Angle θ is the same as spherical coordinate;

z = z

Calculating:

a) (4,2,-4)

[tex]r=\sqrt{4^{2}+2^{2}}[/tex] = [tex]\sqrt{20}[/tex]

[tex]\theta = tan^{-1}\frac{1}{2}[/tex]

z = -4

b) (0, 8, 15)

[tex]r=\sqrt{0^{2}+8^{2}}[/tex] = 8

[tex]\theta = \frac{\pi}{2}[/tex]

z = 15

c) (√2,1,1)

[tex]r=\sqrt{(\sqrt{2} )^{2}+1^{2}}[/tex] = [tex]\sqrt{3}[/tex]

[tex]\theta = \frac{\pi}{3}[/tex]

z = 1

d) (−2√3,−2,3)

[tex]r=\sqrt{(-2\sqrt{3} )^{2}+(-2)^{2}}[/tex] = 4

[tex]\theta = \frac{7\pi}{6}[/tex]

z = 3