Momentum = (mass) x (velocity)
Momentum m₁ = (6 kg) x (13 m/s east) = 78 kg-m/s east
Momentum m₂ = (14 kg) x (7 m/s east) = 98 kg-m/s east
Since they're both in exactly the same direction you can simply addum up to get their total momentum. It's 176 kg-m/s east .
The momentum of a system that consists of two objects should be 176 kg m/s on east hand side.
Calculation of the momentum:Since we know that
Momentum = (mass) x (velocity)
So,
Momentum m₁ = (6 kg) x (13 m/s east) = 78 kg-m/s east
Momentum m₂ = (14 kg) x (7 m/s east) = 98 kg-m/s east
Since they are on same direction so the total momentum should be
= 78 + 98
= 176 kg-m/s east
hence, The momentum of a system that consists of two objects should be 176 kg m/s on east hand side.
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Two identical conducting spheres are charged with a net charge of +5.0 q on the first sphere and a net charge of −8.0 q on the second sphere. The spheres are brought together, allowed to touch, and then separated. What is the net charge on each sphere now?
Answer:
The net charge on each sphere is -1.5 q
Explanation:
Conductors are materials that allow the electrons which are the carriers of the charges to move between them, and when two conductors come in contact, the available charge is shared by the two conductors and the resultant like charges will spread on the surface of the conductor due to the repellent effect between similar charges such that if the conductors are identical, the resultant charge becomes evenly shared by the conductors when they become separated again
The given parameters of the conducting spheres meant to touch are;
The net charge on the first sphere, Q₁ = +5.0 q
The net charge on the second sphere, Q₂ = -8.0 q
The net charge on each sphere after touching and then separated, 'Q', is given as follows;
[tex]Q = \dfrac{Q_1 + Q_2}{2}[/tex]
Therefore, by substituting the known values of the variables, we have;
[tex]Q = \dfrac{5 \ q+ (-8 \ q)}{2} = -\dfrac{3 \ q}{2} = -1.5 \ q[/tex]
The net charge on each sphere, Q = -1.5 q.
The net charge on each sphere after spheres are brought together, allowed to touch is -1.5 q
What is charge?Conductors are materials that allow the electrons which are the carriers of the charges to move between them, and when two conductors come in contact, the available charge is shared by the two conductors and the resultant like charges will spread on the surface of the conductor due to the repellent effect between similar charges such that if the conductors are identical, the resultant charge becomes evenly shared by the conductors when they become separated again
The given parameters of the conducting spheres meant to touch are;
The net charge on the first sphere, Q₁ = +5.0 q
The net charge on the second sphere, Q₂ = -8.0 q
The net charge on each sphere after touching and then separated, 'Q', is given as follows;
[tex]Q=\dfrac{Q_1+Q_2}{2}[/tex]
Therefore, by substituting the known values of the variables, we have;
[tex]\dfrac{5q+(-8q)}{2}=-1.5q[/tex]
Hence the net charge on each sphere after spheres are brought together, allowed to touch is -1.5 q
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There is a current of 2.95 A in one of the copper wires for 60 seconds. Calculate the charge flow through the wire.
Answer:
177 coulomb
Explanation:
Given data
I=2.95A
T=60
The relationship between current I and quantity of charge Q.
Q=IT
Substitute
Q=2.95*60
Q=177 coulomb
Suman with a mass of 45kg climbs in 3m heigh ladder in 10 seconds. Calculate her power. Plz help me
Answer:
work done=fdcosø
f=mg=450N
d=+3m
ø=180
450×3×cos(180°) power=work done/
time taken
1350×-1 p=135watts
John slides down a hill at a 4 m height initially at rest. If all energy is conserved and friction is excluded, what is John's velocity at the bottom of the ramp?
The velocity at the bottom : v = 8.85 m/s
Further explanationGiven
height of the hill = 4 m
Required
The velocity at the bottom
Solution
The law of conservation energy :
ME₁=ME₂
(PE+KE)₁ = (PE+KE)₂
initially at rest⇒vo=0⇒KE₁=0
At the bottom⇒h=0⇒PE₂=0
So the equation becomes :
PE₁=KE₂
mgh=1/2.mv²
gh = 1/2v²
[tex]\tt v=\sqrt{2gh}[/tex]
v = √2x9.8x4
v = 8.85 m/s
Hell it’s due soon??
Explanation:
don't know don't know don't know
Sometimes, a crackling sound is heard while taking off a sweater during winters. Explain
Answer:
it is somewhat frozen
Explanation: