Answer:
3.24×10¯² nN
Explanation:
From the question given above, the following data were obtained:
Mass of girl (M₁) = 61.6 kg
Mass of boy (M₂) = 71.2 kg
Distance apart (r) = 95 m
Gravitational constant (G) = 6.67×10¯¹¹ Nm²/Kg²
Force (F) =?
The force of attraction between the girl and the boy can be obtained as follow:
F = GM₁M₂ /r²
F = 6.67×10¯¹¹ × 61.6 × 71.2 / 95²
F = 6.67×10¯¹¹ × 61.6 × 71.2 / 9025
F = 3.24×10¯¹¹ N
Finally, we shall convert 3.24×10¯¹¹ N to nN. This can be obtained as follow:
1 N = 10⁹ nN
Therefore,
3.24×10¯¹¹ N = 3.24×10¯¹¹ N × 10⁹ nN / 1 N
3.24×10¯¹¹ N = 3.24×10¯² nN
Thus, the force attraction between the girl and the boy is 3.24×10¯² nN
REAL ANSWER OR REPORTED, REAL GETS BRAINLIST
2. What is the weight of:
A 32 kg child
An 82 kg linebacker
A 1000 kg car
3. What is the mass of:
A student who weighs 524 Newtons
A table that weighs 441 Newtons
A hammer that weighs 51 Newtons
4. A 15 kg box sits motionless on the floor.
Draw a force diagram for the box.
Write a vertical Fnet equation for the box.
Determine the weight of the box.
What is the magnitude of the normal force?
Answer:
32kg = 313.6N
82kg = 803.6N
1000kg = 9800N
524N = 53.47kg
441N = 45kg
51N = 5.20kg
for the box diagram the weight of the 15kg box is 147N
the net force will be equal to zero because the box is motionless
Fg goes downward arrow of box 147N
Fnorm goes upward arrow of box 147N
Francine is dragging a heavy toolbox across a rough, cement floor.
What is a contact force that is acting on the box as Francine pulls it.
A.
static electricity
B.
gravity
C.
magnetism
D.
friction
Answer:
D. Friction
Explanation:
Answer:
d. friction
I took it on study island and got it correct thanks to the other guy that has answered
Explanation:
While sliding a couch across a floor, Hannah and Andrea exerts forces FH and FA on the couch. Hannah's force is due north with a magnitude of FH = 59 N and Andrea's force is θ = 22° east of north with a magnitude of FA = 155 N. In this problem, use a coordinate system with y directed north and x directed east.
Part (a) Find the net force in the y-direction in Newtons.
Part (b) Find the net force in the x-direction in Newtons.
Part (c) Calculate the angle in degrees north of east of the net force exerted on the couch by Hannah and Andrea, F HAF→HA.
Part (d) Hannah and Andrea's housemates, David and Stephanie disagree with the move and want to prevent its relocation. Their combined force F DSF→DS must be equal and opposite to that of FHAF→HA. What is the magnitude in Newtons of the force F DSF→DS which will prevent the relocation?
Answer:
a) 202.7 N
b) 58.1 N
c) 74.1º N of E.
d) 210.9 N
Explanation:
a)
The net force exerted in the y-direction, will be the sum of FH (which is directed northwards) and the y-component of FA.Since the magnitude of FA is 155 N and the angle of FA with the y-axis, is 22º (E of N), we can find the N-S component of FA, just applying the the definition of cosine, to the triangle defined by FA, the y- axis and a segment parallel to the x- axis between FA and the y-axis, as follows:[tex]F_{Ay} = F_{A} * cos \theta = 155 N* cos 22 = 143.7 N (1)[/tex]
⇒ Fy = FH + FAy = 59 N + 143.7 N = 202.7 N (2)
b)
We can proceed exactly in the same way for the x-axis. Since FH is directed due North, it has no component along the x-axis.So, Fx is directly the component of FA along the x-axis, which can be found applying the definition of sine to the same triangle than in a) as follows:[tex]F_{x} = F_{A} * sin \theta = 155 N* sin 22 = 58.1 N (3)[/tex]
c)
Taking the same triangle than in a) and b), we can apply the definition of tangent, in order to find the angle between F and the x-axis, as follows:[tex]tg \theta = \frac{F_{y}}{F_{x}} = \frac{202.7N}{58.1N} = 3.5 (4)[/tex]
⇒ θ = tg⁻¹ (3.5) = 74.1º N of E. (5)
d)
In order to be equal and opposite to the combined force FH+FA, it must have the same magnitude.This magnitude can be found applying the Pythagorean Theorem to the same triangle that we used in a), b) and c):[tex]F_{DS} = \sqrt{(F_{x} ^{2} +F_{y} ^{2})} = \sqrt{(58.1N)^{2}) + (202.7N)^{2} } = 210.9 N (6)[/tex]
Which two options are homogeneous mixtures?
A. Sand
B. A wet sponge
C. Liquid dishwashing soap
O D. Vinegar
Answer:
Liquid dishwashing soap
Vinegar
What is a measure of how much matter an object is made of?
Answer:
grams
Explanation:
According to the law of conservation of energy, how will the sum of the kinetic
and potential energies compare at the four points?
Can you also answer questions 1-5
Answer:
I think that this ans may help you
Calculate the amount of potential difference in a capacitor of 0.9 MF , If the amount of charge is 1.4x10^-4 C .(Show all the work)
Answer:
1.56×10¯¹⁰ V.
Explanation:
From the question given above, the following data were obtained:
Capicitance (C) = 0.9 MF
Quantity of electricity (Q) = 1.4x10¯⁴ C
Potential difference (V) =?
Next, we shall convert 0.9 MF to farad (F). This can be obtained as follow:
1 MF = 10⁶ F
Therefore,
0.9 MF = 0.9 MF × 10⁶ F / 1 MF
0.9 MF = 9×10⁵ F
Finally, we shall determine the potential difference. This can be obtained as follow:
Capicitance (C) = 9×10⁵ F
Quantity of electricity (Q) = 1.4x10¯⁴ C
Potential difference (V) =?
Q = CV
1.4x10¯⁴ = 9×10⁵ × V
Divide both side by 9×10⁵
V = 1.4x10¯⁴ / 9×10⁵
V = 1.56×10¯¹⁰ V
Therefore, the potential difference is 1.56×10¯¹⁰ V.
A car completes a journey in 2 hours. Its average speed over this journey was 45 mph. Calculate the distance travelled by the car in miles.
g A boat is anchored 2000 ft from shore anddirects its searchlight towards an automobile travelingdown the straight road. At the particular moment whenthe distance rfrom the searchlight to the automobile is3000 ft, the automobile has speed 80 ft/s and increasesits speed at a rate of 15 ft/s2 down the road.Find the required angular velocity and angularacceleration of the boat's searchlight to track the automobile at this instant.(Answers: 0.018 rad/s CCW, 0.004 rad/s2 CCW)
Answer:
Explanation:
The distance of searchlight will act as radius R and velocity of car may be supposed to be tangential velocity v . We are required to calculate angular velocity ω .
v = 80 ft /s
R = 3000 ft
ω = v / R
= 80 / 3000 = .027 rad / s
For angular acceleration the formula is
angular acceleration α = a / R
a is linear acceleration = 15 ft / s²
α = 15 / 3000 = .005 rad / s².
A 1.0 C charged object and a 2.0 C charged object are separated by 100 m. Where should a -1.0x10-3 C charged object be placed on a line between the positively charged objects so that the net electrical force exerted on the negatively charged object is zero
Answer:
x = 41.2 m
Explanation:
The electric force is a vector magnitude, so it must be added as vectors, remember that the force for charges of the same sign is repulsive and for charges of different sign it is negative.
In this case the fixed charges (q₁ and q₂) are positive and separated by a distance (d = 100m), the charge (q₃ = -1.0 10⁻³ C)) is negative so the forces are attractive, such as loads q₃ must be placed between the other two forces subtract
F = F₁₃ - F₂₃
let's write the expression for each force, let's set a reference frame on the charge q1
F₁₃ = [tex]k \frac{q_1 q_3}{x^2}[/tex]
F₂₃ = [tex]k \frac{q_2 q_3}{(d-x)^2}[/tex]
they ask us that the net force be zero
F = 0
0 = F₁₃ - F₂₃
F₁₃ = F₂₃
k \frac{q_1 q_3}{x^2} =k \frac{q_2 q_3}{(d-x)^2}
[tex]\frac{q_1}{x^2} = \frac{q_2}{(d-x)^2 }[/tex]q1 / x2 = q2 / (d-x) 2
(d-x)² = [tex]\frac{q_2}{q_1}[/tex] x²
we substitute
(100 - x)² = 2/1 x²
100- x = √2 x
100 = 2.41 x
x = 41.2 m
Imagine that I have a ping-pong ball and a bowling ball resting on the floor of our classroom. I go up to the bowling ball and give it a push so that it starts rolling. If I give a push of the exact same strength to the ping-pong ball, how will the resulting motion of the ping-pong ball be different
Answer:
the speed and aceleration of the ping pong ball is greater than that of the bowling ball.
Explanation:
We can analyze this exercise from several points of view, if we use Newton's second law
Bowling ball
F = M a₁
pingpongg ball
F = m a₂
as the forces the same
M a₁ = m a₂
a₂ = [tex]\frac{M}{m}[/tex] a₁
Since the mass of the bowling ball is much greater than the ping pong ball,
a₂ »a₁
so the acceleration of the ping pong ball is much greater than the acceleration of the bowling ball.
If we use the relationship of momentum and momentum, assuming that the time for the two cases is the same and that both start from rest
Bowling ball
I = F t = Δp
I = M (v₁ - v₀)
Ping pong ball
I = F t = Δp
I = m (v₂ -v₀)
the impulse itself
M v₁ = m v₂
v₂ = [tex]\frac{M }{ m}[/tex] v₁
so we conclude that the speed of the ping pong ball is much greater than the speed of the bowling ball.
In conclusion the speed and aceleration of the ping pong ball is greater than that of the bowling ball.
Billy is trying to shine a laser off a mirror at the end of a basketball court into Sam's eyes to distract him (Billy is evil). Sam is at a 38 degree reflection angle from the mirror. At what angle does Billy need to shine the laser at the mirror to get it in Sam's eyes.
Answer:
When we have a plane interface, the angle of incidence of the ray is the same as the angle of reflection.
In this case, we have a mirror (we assume that it is plane) and we know that we need to have an angle of reflection equal to 38° in order to reach Sam.
Then the angle of incidence of the ray must also be exactly 38°.
Then Billy needs to shine his laser at an angle of 38° at the mirror.
(where the angle is measured between the normal line to the surface of the mirror and the incident ray)
Billy needs to shine the laser at an incident angle of 38 degrees.
LASER is an acronym that stands for “light amplification by the stimulated emission of radiation.” We know that according to the laws of reflection, the angle of incidence is equal to the angle of reflection.
As such, knowing that Sam is at a 38 degree reflection angle from the mirror, Billy needs to shine the laser at an incident angle of 38 degrees.
Learn more: https://brainly.com/question/8592296?
A ball player catches a ball 3.10 s after throwing it vertically upward. a) with what speed did he throw it? b) what height did it reach?
Answer:
speed=30.41, height=94.27
Explanation:
since the motion is vertical upward means the motion is against gravitational force and the initial velocity of the ball was zero.
1. State the law of conservation of energy and what it means for you as a human considering how energy works.
2. Explain how different forms of energy are related.
PLEASE I NEED HELP!! I NEED IT NOW!! AND PLEASE DO IT IN YOUR OWN WORDS!! THANK YOU!
Answer: 1. The law of consevation of energy sates that energy can neither be created nor destroyed. It can only be transformed or transfered from one form to another. The law of conservation of energy is found everywhere for example, Water falls from the sky, converting potential energy to kinetic energy.
2. Different forms of energy are related because energy cannot be created or destroyed. they can all be transformed into from one form to another.
Explanation:
A crane is used to lower weights into a lake for an underwater construction project. Determine the tension in the cable of the crane due to a concrete sphere with a radius of 2 m when the sphere is lowered into the water. The concrete has a specific gravity of 2.8.
Answer:
Tension in the cable = 591292.8 N or 591.3 kN
Explanation:
Tension in the cable = Weight of object in air - upthrust/bouyancy due to the liquid
Weight of object in air = mass * acceleration due to gravity, g
Since mass is not given, it is obtained from the formula, mass = density * volume
Volume of the sphere = 4/3πr³ where r, radius = 2 m; π = 22/7
volume = 4/3 * 22/7 * (2m)³
volume of sphere = 33.52 m³
Density of concrete sphere = specific gravity * density of water
where, specific gravity = 2.8, density of water = 1000 kg/m³
density of concrete = 2.8 * 1000 kg/m³
density of concrete = 2800 kg/m³
acceleration due to gravity, g = 9.8 m/s²
Thus, weight of concrete = 2800 kg/m³ * 33.52 m³ * 9.8 m/s² = 919788.8 N
Upthrust = density of water * volume of sphere * g
Upthrust = 1000 kg/m³ * 33.52 m³ * 9.8 m/s² = 328496 N
The tension in the cable is the calculated as below;
Tension in the cable = Weight of object in air - upthrust/bouyancy due to the liquid
Tension in cable = 919788.8 N - 328.496 N = 591292.8 N
Therefore, tension in the cable is 591292.8 N or 591.3 kN
Explain why objects in water appear to be a different size then the same objects above the water.
Answer:
the answer is the third one since water reflects it
Explanation:
What is light? Let's tallk about anything
Describe how global context (scientific and technical innovation) is connected with force, friction,energy and motion in 200 words.
What three factors determine the amount of potential energy in a object are ______,______,and ______.
Answer:
It should be Mass, Gravity and Height
Explanation:
Given that the frequency of an EM wave is 4THz,what is the wavelength?
a) 75,000um
b) 75,000nm
c) 75,000pm
d) 75,000A
Answer:
B. 75,000nm
Explanation:
The wavelength of a wave can be calculated thus;
λ = v/f
Where;
λ = wavelength (m)
v = velocity of light = 3 × 10^8m/s
f = frequency (Hz)
According to this question, the EM wave has a frequency of 4THz i.e. 4 Terahertz = 4 × 10^12Hz
λ = 3 × 10^8 ÷ 4 × 10^12
λ = 3/4 × 10^(8-12)
λ = 0.75 × 10^-4
λ = 0.000075m
Based on the options given, this value is equivalent to 75,000nm, which means 75000 × 10^-9m.
A boat moves up and down as water waves pass under the boat. If the amplitude of the wave gets bigger, then
A)
the boat will rise up higher.
B)
the boat will not rise up as high.
C)
the boat will go up and down more often.
D)
the boat will continue to move the same way.
Answer: The Boat will rise
Explanation: Because high amplitude means high in heights.
Mae puts on her new winter scarf. Signals are sent to her brain telling her that the scarf is soft. Which sense provides her brain with this information?
Answer:
Touch
Explanation:
The membrane that surrounds a certain type of living cell has a surface area of 4.7 x 10-9 m2 and a thickness of 1.3 x 10-8 m. Assume that the membrane behaves like a parallel plate capacitor and has a dielectric constant of 4.7. (a) The potential on the outer surface of the membrane is 79.5 mV greater than that on the inside surface. How much charge resides on the outer surface
Answer:
Q = 1.2*10⁻¹² C
Explanation:
For any capacitor, by definition the capacitance C is equal to the relationship between the charge on one of the conductors and the potential difference between them, as follows:[tex]C = \frac{Q}{V} (1)[/tex]
For the special case of a parallel plate capacitor, just by application of Gauss' law to a rectangular surface half out of the outer surface, and half inside it, it can be showed that the value of the capacitance C is a parameter defined only by geometric constants, as follows:[tex]C = \frac{\epsilon_{0}*\epsilon _{r} * A}{d} (2)[/tex]
So, due to the left sides in (1) and (2) are equal each other, right sides must be equal too.Replacing ε₀, εr (dielectric constant), A, d and V by their values, we can solve for Q, as follows:[tex]Q =\frac{\epsilon_{0} * \epsilon_{r} *A* V}{d} = \frac{(8.85*(4.7)^{2}*79.5)e-24 (F/m*m2*V)}{1.3e-8m} = 1.2e-12 C = 1.2 pC (3)[/tex]
You are driving up a long, inclined road. After 1.50mi you notice that signs along the roadside indicate that your elevation has increased by 510ft . b) How far do you have to drive to gain an additional 110ft of elevation
Answer:
1.825 miles
Explanation:
Given that :
Distance driven = hypotenus = 1.5 miles
Elevation at distance of 1.5 miles = 510 feets
Converting miles to feets for the hypotenus :
1 mile = 5280 feets
1.5 miles = (5280 * 1.5) = 7920 feets
To obtain the angle of inclination :
Using Pythagoras rule :
Sinθ = opposite / hypotenus
θ = Sin^-1(510 / 7920)
θ = 3.692°
For an additional elevation of 110 ft ; new height = 110 + 510 = 620 feets
Distance driven, d =?
Sin 3.69 = (620 / d)
0.0643581 * d = 620
d = 620 / 0.0643581
d = 9633.5970 feets
Converting to feets :
9633.5970 / 5280 = 1.8245448
= 1.825 miles
Consider a collection of charges in a given region and suppose all other charges are distant and have a negligible effect. Further, the electric potential is taken to be zero at infinity. If the electric potential at a given point in the region is zero, which of the following statements must be true?
A. The electric field is zero at that point.
B. The charges have the same sign and are symmetrically arranged around the given point.
C. The electric potential energy is a minimum at that point.
D. There is no net charge in the region.
E. Some charges in the region are positive, and some are negative.
Answer:
E. Some charges in the region are positive, and some are negative.
Explanation:
Electric potential is given as;
[tex]V = \frac{W}{Q}[/tex]
where;
W is the work done in moving a charge between two points which have a difference in potential
Q is quantity of charge in the given region
If the electric potential at a given point in the region is zero, then sum of the charges in the given region must be equal to zero. For the charges to sum to zero, some will be positive while some will be negative,.
Therefore, the correct statement in the given options is "E"
E. Some charges in the region are positive, and some are negative.
Someone help me with this PE question?
Answer:
Your abdominals
Explanation:
Does light travel faster in seawater or in fresh water? Does light travel faster in seawater or in fresh water? Light travels faster in seawater, because the index of refraction is smaller in seawater. Light travels faster in fresh water, because the index of refraction is smaller in fresh water. Light travels faster in fresh water, because the index of refraction is larger in fresh water. Light travels faster in seawater, because the index of refraction is larger in seawater.
No
because that is a light
The light travel faster in fresh water as compare to sea water.
When light goes from denser to rare medium the speed of light is increases.When light travel from rare to denser medium the speed of light is decreases.The reflective index of denser medium is more as compare to rare medium.The reflective index of sea water is more as compare to fresh water.Hence, the light travel faster in fresh water as compare to sea water.
Learn more:
https://brainly.com/question/10769980
What recreational drug does an alcopop contain?
An "alcopop" is a term used to describe a flavored alcoholic beverage that typically resembles a soft drink or a fruit juice in appearance and taste. It is also referred to as a "ready-to-drink" (RTD) beverage.
Alcopops are often targeted toward younger consumers and are known for their sweet and fruity flavors, which can mask the taste of alcohol.
The specific recreational drug that an alcopop contains is alcohol itself. Alcohol, or ethanol, is a psychoactive substance that can have intoxicating effects when consumed.
It is considered a recreational drug because of its ability to alter consciousness, impair judgment and coordination, and produce pleasurable or mood-altering effects.
The alcohol content in alcopops can vary, but it is typically lower than in pure spirits or liquors. This is often achieved through dilution with other ingredients, such as carbonated water or fruit juices, to create a milder alcoholic beverage.
Alcopops may also contain additional flavorings, sweeteners, and additives to enhance their taste and appeal.
Know more about alcopop:
https://brainly.com/question/33750456
#SPJ4
7. (a) At a distance of d/5 from a positive charge, by what factor is the electric potential changed: (1) 1/5, (2) 5, (3) 1/25 or (4) 25? Why? (b) How far from a +2.0 uC charge is a point with an electric potential value of 15KV? (c) How much of a change in potential would occur if the point were moved to three times the distance?
Answer:
it would change and the points would be off because of the change
A 20.0 N force is necessary to stretch a spring 0.500 m. What is the spring constant of this spring?
The spring constant : k = 40 N/m
Further explanationGiven
Force = 20 N
The displacement of the spring=x=0.5 m
Required
The spring constant = k
Solution
Hooke's Law
F = k.x
k = F/x
Input the value :
k = 20/0.5
k = 40 N/m