Determine the length of side QS
Question 14 options:

A)

2.4

B)

5.7

C)

3.4

D)

1.9

Required data:

Before 6.4 2.6 7.7 10.5 11.7 5.8 4.3 2.8

After 6.7 2.4 7.4 8.1 8.6 6.4 3.9 2.7

Answer:

Confidence interval = (-0.404 ; 1.804)

Pvalue = 0.178

Step-by-step explanation:

H0: μd = 0

H1 : μd ≠ 0

Difference, d = (x - y)

d = - 0.3, 0.2, 0.3, 2.4, 3.1, - 0.6, 0.4, 0.1

Using calculator :

μd = 0.7

Sd = 1.32

Confidence interval :

Mean ± margin of error

Margin of Error =Tcritical * Sd/√n

Tcritical at df = 7, 0.5, 2 - tailed = 2.365

Margin of Error = 2.365 * 1.32/√8

Margin of Error = 1.104

Lower boundary :

(0.7 - 1.104) = - 0.404

Upper boundary :

(0.7 + 1.104) = 1.804

(-0.404 ; 1.804)

Test statistic, = μd / (Sd ÷ √n)

Test statistic = 0.7 / (1.32 ÷ √8)

Test statistic = 1.499

From the test statistic score ; using a Pvalue calculator :

Pvalue = 0.178 ( 3 decimal places)

Answer:

What is that

Step-by-step explanation:

I am scared of math

Answer:

1 = 58°

2 = 32°

3 = 32°

Step-by-step explanation:

Answer:

[tex]18 \times 1000 \: metres[/tex]

[tex]18000 \: metres[/tex]

Step-by-step explanation:

[tex]hope \: it \: helps \: don't \: to \: \\ like \: and \: mark \: me[/tex]

Answer:

864 cm

Step-by-step explanation:

Answer:

9M + 8!

Step-by-step explanation:

Brainliest Please!

Answer:

Teachers are idiots that's why :)

Answer:

The Answer to that is pretty simple..

Step-by-step explanation:

We learn stuff that we typically don't need in the real world you would think but when it comes to getting a job thats were that information comes in. Like Science about fossils - You might work at a museum?

But some of this stuff is not really needed so I get your point.

Answer:

6 there are 6 motorcycles

Step-by-step explanation:

Answer:

2. 5x+8

3.5a+2b+2-b

4.15+10y

5.8+9x+5y

6.  9+w(to the fourth power)

7. i cant figure out how to do the last

Answer:

(a) [tex]Pr = 0.3024[/tex]

(b) [tex]Pr = 0.6976[/tex]

(c) [tex]Pr = \frac{^9P_{n-1}}{10^{n-1}}[/tex]

Step-by-step explanation:

Given

[tex]Start = \{5,6,7,8\}[/tex] i.e. between 4 and 9

[tex]n(Start) =4[/tex]

[tex]Digits = 5[/tex]

Solving (a): Probability that each of the 5 digit are different

Since there is no restriction;

The total possible selection is as follows:

[tex]First\ digit = 4[/tex] (i.e. any of the 4 start digits)

[tex]Second\ digit = 10\\[/tex] (i.e. any of the 10 digits 0 - 9)

[tex]Third\ digit = 10[/tex] (i.e. any of the 10 digits 0 - 9)

[tex]Fourth\ digit = 10[/tex] (i.e. any of the 10 digits 0 - 9)

[tex]Fifth\ digit = 10[/tex] (i.e. any of the 10 digits 0 - 9)

So, the total is:

[tex]Total = 4 * 10 * 10 * 10 * 10[/tex]

[tex]Total = 40000[/tex]

For selection that all digits are different, the selection is:

[tex]First\ digit = 4[/tex] (i.e. any of the 4 start digits)

[tex]Second\ digit = 9[/tex] (i.e. any of the remaining 9)

[tex]Third\ digit = 8[/tex] (i.e. any of the remaining 8)

[tex]Fourth\ digit = 7[/tex] (i.e. any of the remaining 7)

[tex]Fifth\ digit = 6[/tex] (i.e. any of the remaining 6)

So:

[tex]Selection =4 * 9 * 8 * 7 * 6[/tex]

[tex]Selection =12096[/tex]

So, the probability is:

[tex]Pr = \frac{Selection}{Total}[/tex]

[tex]Pr = \frac{12096}{40000}[/tex]

[tex]Pr = 0.3024[/tex]

Solving (b): At least 1 repeated digit

The probability calculated in (a) is the all digits are different i.e. P(None)

So, using laws of complement

We have:

[tex]P(At\ least\ 1) = 1 - P(None)[/tex]

So, we have:

[tex]Pr= 1 - 0.3024[/tex]

[tex]Pr = 0.6976[/tex]

Solving (c): An expression to model the probability.

Using (a) as a point of reference, we have;

[tex]Pr = \frac{Selection}{Total}[/tex]

Where

[tex]Selection =4 * 9 * 8 * 7 * 6[/tex] ---- for selection of 5 i.e. n = 5

[tex]Total = 4 * 10 * 10 * 10 * 10[/tex]

[tex]Selection =4 * 9 * 8 * 7 * 6[/tex]

This can be rewritten as:

[tex]Selection = 4 * ^9P_4[/tex]

4 can be expressed as: 5 - 1

So, we have:

[tex]Selection = (5-1) *^9P_{5-1}[/tex]

Substitute n for 5

[tex]Selection = (n-1) *^9P_{n-1}[/tex]

[tex]Selection = (n-1)^9P_{n-1}[/tex]

[tex]Total = 4 * 10 * 10 * 10 * 10[/tex]

This can be rewritten as:

[tex]Total = 4 * 10^4[/tex]

[tex]Total = (5-1) * 10^{5-1}[/tex]

[tex]Total = (n-1) * 10^{n-1}[/tex]

[tex]Total = (n-1) 10^{n-1}[/tex]

So, the expression is:

[tex]Pr = \frac{(n-1)^9P_{n-1}}{(n-1)10^{n-1}}[/tex]

[tex]Pr = \frac{^9P_{n-1}}{10^{n-1}}[/tex]

Where n represents the digit number

Step-by-step explanation:

Real numbers include:

Rational numbers include

Fractions, Integers

Integers include

Negative Integers, Whole numbers

Whole numbers include

Zero, Natural number

Irrational numbers

Answer:

Step-by-step explanation:

Simplifying

5(2x + -6) + 20 = 10

Reorder the terms:

5(-6 + 2x) + 20 = 10

(-6 * 5 + 2x * 5) + 20 = 10

(-30 + 10x) + 20 = 10

Reorder the terms:

-30 + 20 + 10x = 10

Combine like terms: -30 + 20 = -10

-10 + 10x = 10

Solving

-10 + 10x = 10

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '10' to each side of the equation.

-10 + 10 + 10x = 10 + 10

Combine like terms: -10 + 10 = 0

0 + 10x = 10 + 10

10x = 10 + 10

Combine like terms: 10 + 10 = 20

10x = 20

Divide each side by '10'.

x = 2

Simplifying

x = 2

Answer:

x=2

Step-by-step explanation:

Let's solve your equation step-by-step.

5(2x−6)+20=10

Step 1: Simplify both sides of the equation.

5(2x−6)+20=10

(5)(2x)+(5)(−6)+20=10(Distribute)

10x+−30+20=10

(10x)+(−30+20)=10(Combine Like Terms)

10x+−10=10

10x−10=10

Step 2: Add 10 to both sides.

10x−10+10=10+10

10x=20

Step 3: Divide both sides by 10.

10x

10

=

20

10

x=2

Answer:

x=2

Answer:

NO

Step-by-step explanation:

Let h(t) represent the distance the pack is located above the ground at time t.  Then h(t) = 20 ft - 16t^2 ft.  Notice how h = 20 ft (the initial height) and that it decreases as t increases.

How long does it take for the pack tohit the ground?  Set h(t) = 0 and solve for t:

0 ft = 20 ft - 16t^2 ft yields 16t^2 ft = 20, or t^2 ft = 20/16, which is greater than 1.  So the question "Will the backpack hit the ground in 1 second" is answered by NO.

In both triangles Be ABC and RQS

[tex]\because\sf \begin{cases}\sf <B=<Q=90°\\ \sf <\alpha\sim <alpha\end{cases}[/tex]

Hence

[tex]\\ \qquad\quad\sf\longmapsto \Delta ABC\cong \Delta PQR(AA)[/tex]

Answer:

|6|-|1|=5

|6|=6

Step-by-step explanation:

Answer:

3 cups of Chicken Broth remains

Step-by-step explanation:

Answer:

No, it is not.

Step-by-step explanation:

1/5 is equal to 0.2

5/1 is equal to 5 because there are 5 ones.

Answer:

1. C

2.G' is (8,-2) and H' is (14,8)

Step-by-step explanation:

Sorry if im wrong!

Answer:

7/9²=49/81

Step-by-step explanation:

soskssjshsgsgsgsgsgs

Answer:

1, 3, 3, 6, 10, 10, 11, 14

(6,10)  6+10= 16  

16/2= 8

median is = 8

Step-by-step explanation:

Answer:

4. 72 m

5. 42 m

6. 66 yd

8. 18 yd

9. 200 cm

Step-by-step explanation:

3) 1 × 3 × 8 + [5 × 8 × (4-3)] = 24 + 40 = 64 yd³

4) 9 × 1 × 8 = 72 m³

5) 3 × 7 × 2 = 42 m³

6) 3 × 3 × (6 - 2) + 2 × 5 × 3 = 36 + 30 = 66 yd³

7) (7 - 5) × 7 × 3 + 8 × 7 × 5 = 42 + 280 = 322 mm³

8) 3 × 3 × 2 = 18 yd³

9) 8 × 5 × 5 = 200 cm³

Answer:

$ ( 3 x  + 75000 / x )

Step-by-step explanation:

Function that models the total inventory cost as a function of x

holding cost = $6

ordering cost ( fixed cost ) = $30

cost of a pair = $6

Total demand = 2500

∴The total inventory cost ( TIC ) is represented as

holding cost + Ordering cost

= 1 / 2 ( x ) ($6 )  + 2500 / x  ( $30 )

= $ ( 3 x  + 75000 / x )

while total cost  = $ ( 3x + 75000 /x + ( 2500 * 6 ) )

Answer:

look up desmos graphing calculator! you're welcome x

Step-by-step explanation:

Answer:

Depreciation rate is 8%

Car is worth $12127.10

Step-by-step explanation: