Answer:
the data that is shown represents a function
Step-by-step explanation:
the easiest way to know is by looking at the x-variable. Each y-variable needs one x-variable. the x-variable should not be seen paired with another y-variable.
The radioactive compound 14CO2 may be used as a tracer to study metabolism in plants. Suppose that a compound isolated from a plant exhibited 28, 32, 27, 39 and 40 counts of radioactive decays per minute. A blank sample used to measure the background counts of the radiation counter gave 28,21, 28 and 20 counts per minute. It appears that the isolated compound gives more counts than those from background. Can we be 95% confident that the compound is indeed radioactive?
Using the t-distribution, it is found that since the test statistic is more than the critical value for the right-tailed test, it can be conclude that the isolated compound gives more counts than those from background, and hence, we can be 95% confident that the compound is indeed radioactive.
At the null hypothesis, it is tested if isolated compounds do not give more counts than those from background, that is:
[tex]H_0: \mu_1 - \mu_2 \leq 0[/tex]
At the alternative hypothesis, it is tested if the give more counts, that is:
[tex]H_1: \mu_1 - \mu_2 > 0[/tex]
Using a calculator, the mean and the standard deviation for each sample are given by:
[tex]\mu_1 = 33.2, s_1 = 6.058[/tex]
[tex]\mu_2 = 24.25, s_2 = 4.35[/tex]
Considering the sample sizes of 5 and 4, respectively, the standard errors are given by:
[tex]s_1 = \frac{6.058}{\sqrt{5}} = 2.71[/tex]
[tex]s_2 = \frac{4.35}{\sqrt{4}} = 2.175[/tex]
For the distribution of differences, the mean and standard error are given by:
[tex]\overline{x} = \mu_1 - \mu_2 = 33.2 - 24.25 = 8.95[/tex]
[tex]s = \sqrt{s_1^2 + s_2^2} = \sqrt{2.71^2 + 2.175^2} = 3.4749[/tex]
The standard error was found from the standard deviation for each sample, hence, the t-distribution is used.
The test statistic is given by:
[tex]t = \frac{\overline{x} - \mu}{s}[/tex]
In which [tex]\mu = 0[/tex] is the value tested at the null hypothesis, hence:
[tex]t = \frac{\overline{x} - \mu}{s}[/tex]
[tex]t = \frac{8.95 - 0}{3.4749}[/tex]
[tex]t = 2.58[/tex]
The critical value for a right-tailed test, as we are testing if the mean is greater than a value, with 5 + 4 - 2 = 7 df and a 0.05 significance level is of [tex]t^{\ast} = 1.895[/tex]
Since the test statistic is more than the critical value for the right-tailed test, it can be conclude that the isolated compound gives more counts than those from background, and hence, we can be 95% confident that the compound is indeed radioactive.
A similar problem is given at brainly.com/question/24826023
Wheel Fun offers rentals of paddle boats that can be enjoyed by 2 or 3 riders. The price for renting a paddle boat is $15 for each hour. Customers must also pay a $20 deposit on the rental. Write an equation that can be used to determine the price, y for renting a paddle boat for x, hours?
Answer:
15+20=35+15 And then add an additional plus 15 for each hour
Step-by-step explanation:
At a local movie theatre, sodas cost$4.50 and bags of popcorn cost &1.50. Kirk buys three times as many bags of popcorn as sodas and pays a total of $36. Write a system of equations and solve it using any method to determine how many of each item Kirk bought.
Answer:
this might help
Step-by-step explanation:
this might be kinda similar
Chickens and rabbits
In the yard were chickens and rabbits. Together they had 18 heads and 56 legs. How many chickens and how many rabbits were in the yard?
Correct answer:
chickens: 8
rabbits: 10
Step-by-step explanation:
a+b=18
2a+4b=56
a=8
b=10
a+b = 18
2•a+4•b=56
a+b = 18
2a+4b = 56
a = 8
b = 10
What are the domain and range of the function below? (In picture)
Answer:
Domain: [0 , ∞)
Range: (-∞ , 4]
Step-by-step explanation:
I) DOMAIN:For domain, look along the x axis.
The graph starts from x = 0 and it's ending point isn't given in the graph as it continues moving along the positive x axis.
Hence, it's ending point must be ∞
Domain of a function is:
[minimum point in x, maximum point in x]
=> [0, ∞)
"),(" is used for infinity.
"],[" for points that lie within the domain of the function.
II) RANGEFor range, look along the y axis.
The graph starts at y = 4, and continues moving downwards till infinity.
Range:
[minimum in y, maximum in y]
=> (-∞, 4]
For parenthesis, same rule as domain will be applied. 4 is naturally greater than all values in negative. Hence, maximum point will be 4 and minimum will be -∞.From a hot-air balloon, Guadalupe measures a 31^{\circ} ∘ angle of depression to a landmark that’s 316 feet away, measuring horizontally. What’s the balloon’s vertical distance above the ground?
Check the picture below.
What is 10% of 75? Use the double number line below to label your work and answer.
Answer: the answer is 7.5
Step-by-step explanation:
Question
Bill needs to mow his yard which has the dimensions in the shape below. What is the area of yard he needs to mow?
Note: Round your answer to one decimal place.
12 m
5 m
15 m
Answer:
Step-by-step explanation:
imagine you chop off a right triangle from the left side
now you have a rectangle and a right triangle
the rectangle
height 5
width 12
5 x 12 = 60
triangle
height 5
width 3
3 x 5 = 15
15 / 2 = 7.5
60 + 7.5 = 67.5 m^2
Answer: 67.5 m^2
Step-by-step explanation:
To find out the area of the yard, we split the shape up into a triangle and rectangle. The area of the triangle is,
A = 1 × b × h/2 = 1 × 3 × 5/2 = 7.5 m^2.
And the area of the rectangle is,
A = 12 × 5 = 60 m^2.
We then add the area of the triangle and the area of the rectangle.
A = 7.5 + 60 =67.5 m^2
Rounded to one decimal place, the area of the yard is 67.5 square meters.
128x^2-162
How do you factor this
If any doubt leave a comment
Please explain how you got to the answer. I am trying to understand the concept that went into it.
Solve for x in the equation x squared + 11 x + StartFraction 121 Over 4 EndFraction = StartFraction 125 Over 4 EndFraction.
A. x = negative 11 plus-or-minus StartFraction 25 Over 2 EndFraction
B. x = negative eleven-halves plus-or-minus StartFraction 25 Over 2 EndFraction
C. x = negative 11 plus-or-minus StartFraction 5 StartRoot 5 EndRoot Over 2 EndFraction
D.x = negative eleven-halves plus-or-minus StartFraction 5 StartRoot 5 EndRoot Over 2 EndFraction
Answer:
D. x = negative eleven-halves plus-or-minus StartFraction 5 StartRoot 5 EndRoot Over 2 EndFraction
Step-by-step explanation:
Evaluate 0 and 1 (xe+ex)Dx
please helppppppppppppp ASAP. please ensure to use step by step explanation. thanks.
I'll do the first two parts to get you started.
=====================================================
Part (i)
We can show that the operation [tex]\nabla[/tex] is not commutative by picking two random and different real numbers for a,b. In other words, I'm using a counter-example.
Let's say we go for a = 1 and b = 2
[tex]a \nabla b = \frac{3a+b}{5} - 1\\\\1 \nabla 2 = \frac{3*1+2}{5} - 1\\\\1 \nabla 2 = \frac{5}{5} - 1\\\\1 \nabla 2 = 1 - 1\\\\1 \nabla 2 = 0\\\\[/tex]
Now let's swap the values. We'll try a = 2 and b = 1
[tex]a \nabla b = \frac{3a+b}{5} - 1\\\\2 \nabla 1 = \frac{3*2+1}{5} - 1\\\\2 \nabla 1 = \frac{7}{5} - 1\\\\2 \nabla 1 = 1.4 - 1\\\\2 \nabla 1 = 0.4\\\\[/tex]
We can see that [tex]1 \nabla 2[/tex] and [tex]2 \nabla 1[/tex] are not the same value. In general, [tex]a \nabla b \ne b \nabla a[/tex] Therefore, the operation [tex]\nabla[/tex] is not commutative.
The only time [tex]a \nabla b = b \nabla a\\\\[/tex] is true is when [tex]a = b[/tex], since,
[tex]\frac{3a+b}{5}-1 = \frac{3b+a}{5}-1\\\\\frac{3a+a}{5}-1 = \frac{3a+a}{5}-1\\\\\frac{4a}{5}-1 = \frac{4a}{5}-1\\\\[/tex]
It's when [tex]a \ne b[/tex] is where the operation becomes noncommutative.
Another way to arrive at the [tex]a = b[/tex] condition is to solve the original equation for either 'a' or b.
=====================================================
Part (ii)
Using the previous part as inspiration, we'll do a counter-example to show that the operation is not associative. Pick 3 random values for a,b,c. Here are the values I'll pick.
a = 1b = 2c = 3Then,
[tex]d = b \nabla c = \frac{3b+c}{5}-1 = \frac{3*2+3}{5}-1 = 0.8\\\\a \nabla (b \nabla c) = a \nabla d = \frac{3a+d}{5}-1 = \frac{3*1+0.8}{5}-1 = -0.24\\[/tex]
Next, we can say:
[tex]d = a \nabla b = \frac{3a+b}{5}-1 = \frac{3*1+2}{5}-1 = 0\\\\(a \nabla b) \nabla c = d \ \nabla c = \frac{3d+c}{5}-1 = \frac{3*0+3}{5}-1 = -0.4[/tex]
Let's compare the two outputs:
[tex]a \nabla (b \nabla c) = -0.24\\\\(a \nabla b) \nabla c = -0.4[/tex]
They don't match up, so [tex]a \nabla (b \nabla c) \ne (a \nabla b) \nabla c[/tex] when (a,b,c) = (1,2,3).
In general, the operation is not associative in R.
Troy is buying a car that costs $15,000. He
plans to get a 5-year loan to pay for it. He
can get a loan for $15,000 or he can pay
$3,000 from his savings and get a loan
for the rest. The savings account pays 2%
simple interest per year. The simple interest
rate for the loan is 0.5% per year.
a. How much interest over a 5-year
Answer:
300/75
Step-by-step explanation:
Cost of the Car = $15,000
a) Rate of interest received on savings(r) = 2%
Amount in savings account(p) =$3000
Time period(t) = 5 years
simple intrest.
Interest received on savings account = $300
b) Rate of interest on loan = 0.5%
IF P= 15000
intrest.
Difference between the interest = $75
c) Taking loan of the whole amount that is of $15,000 is more reasonable because though the interest is more but Troy will receive interest($300) from his savings account as well. But if he withdraws $3000 from savings and takes the loan for the rest of the amount, he would have no earnings.
2 with the radical of 32
Which equation describes the line shown in the graph?
Answer:
D
Step-by-step explanation:
:)
What does Point P on the number line represent? (Use the hyphen for negative numbers, such as −9)
Number line from negative 8 to positive 10 in increments of 1 is shown. Only the even numbers are labeled. A point labeled P is placed at the third tick mark to the left of 0.
(5 points)
Answer:
P = -3, each line in the negative direction is 1 number
so you would have -1, -2, -3 , -4, etc.
P is on the -3 line.
See attached picture.
Step-by-step explanation:
HELP ASAP Match each division expression to its quotient.
Answer:
2=-12.2/(-6.1
-2=16/(-8)
-3= -2 2/5/4/5
3= 3 3/7 / 1 1/7
Step-by-step explanation:
Find the area of the figure.
7cm
8cm
11cm
Area is ___ square cm?
Answer:
616cm³
Step-by-step explanation:
you just need to multiply those numbers
7 x 8 x 11= 616
[tex]\text{Perimeter of the triangle,}\\\\ 2s = 7 + 8 +11 =26}\\\\\\\implies s = \dfrac{26}2 = 13\\\\\\\text{Apply Heron's formula to find the area of the triangle,}\\\\A = \sqrt{s(s-8)(s-7)(s-11)}\\\\\implies A = \sqrt{13(13-8)(13-7)(13-11)}\\\\\implies A = \sqrt{780} \\\\\implies A = 27.93~~ \text{cm}^2[/tex]
Pls help stuck on it
Answer:
4,-1
Step-by-step explanation:
Please like!♥
x squared+ y squared = 2 y = 2x squared – 3 Which of the following describes the system?
Answer:
[tex]x=-1,1,-\sqrt{\frac{7}{4} },\sqrt{\frac{7}{4}}[/tex] and [tex]y=-1,\frac{1}{2}[/tex]
The ordered pair solutions are [tex](-\sqrt{\frac{7}{4}},0.5)[/tex], [tex](\sqrt{\frac{7}{4}},0.5)[/tex], [tex](-1,-1)[/tex], and [tex](1,-1)[/tex].
Step-by-step explanation:
I'm assuming the system is [tex]\left \{ {x^2+y^2=2} \atop {y=2x^2-3}} \right.[/tex]:
[tex]x^2+y^2=2[/tex]
[tex]x^2+(2x^2-3)^2=2[/tex]
[tex]x^2+(4x^4-12x^2+9)=2[/tex]
[tex]x^2+4x^4-12x^2+9=2[/tex]
[tex]4x^4-11x^2+9=2[/tex]
[tex]4x^4-11x^2+7=0[/tex]
[tex]x^4-11x^2+28=0[/tex]
[tex](x^2-7)(x^2-4)=0[/tex]
[tex](4x^2-7)(x^2-1)=0[/tex]
[tex]4x^2-7=0[/tex]
[tex]4x^2=7[/tex]
[tex]x^2=\frac{7}{4}[/tex]
[tex]x=\pm\sqrt{\frac{7}{4}}[/tex]
[tex]x^2-1=0[/tex]
[tex]x^2=1[/tex]
[tex]x=\pm1[/tex]
[tex]y=2x^2-3[/tex]
[tex]y=2(\pm\sqrt{\frac{7}{4}})^2-3[/tex]
[tex]y=2({\frac{7}{4}})-3[/tex]
[tex]y=\frac{7}{2}-3[/tex]
[tex]y=\frac{1}{2}[/tex]
[tex]y=2x^2-3[/tex]
[tex]y=2(\pm1)^2-3[/tex]
[tex]y=2(1)-3[/tex]
[tex]y=2-3[/tex]
[tex]y=-1[/tex]
Therefore, [tex]x=-1,1,-\sqrt{\frac{7}{4} },\sqrt{\frac{7}{4}}[/tex] and [tex]y=-1,\frac{1}{2}[/tex]
The ordered pair solutions are [tex](-\sqrt{\frac{7}{4}},0.5)[/tex], [tex](\sqrt{\frac{7}{4}},0.5)[/tex], [tex](-1,-1)[/tex], and [tex](1,-1)[/tex].
Need help on True or False PLEASE answer!!!!
Answer:
Step-by-step explanation:
1. False
2. False
3. True
4. True
5. True
6. True
7. True
8. True
9. True
Can anyone help with this?
please help me out on this one
Answer:
6/6 or 1
Step-by-step explanation:
bow tie method
What are the coordinates of the point (-4, 2) after a translation 2 units left and 2 units up?
A (-2, 0)
B (-6,0)
C (-2, 4)
D (-6, 4)
Answer:
the answer you're looking for is D. when you move to the left the -4 becomes -6 and when you move up 2 becomes 4.
OMG HELP RN I MARK BARINLIST
Which of the following correctly describes the solutions to the inequality?
A.
There are an infinite number of solutions. The solutions are all numbers less than 2.
B.
There are an infinite number of solutions. The solutions are all numbers greater than 2.
C.
There are 7 solutions. The solutions are the numbers between 2 and 8.
D.
There are 4 solutions. The solutions are the numbers between -2 and 1.
Answer:
B
Step-by-step explanation:
The dot on 2 is an open spot, so 2 isn't part of the solution. the arrow points towards +∞ so, yeah. b
A bag with 6 marbles has 2 blue marbles, 1 red marble, and 3 yellow marbles. A marble is chosen from the bag at random. What is the probability that it
is not blue?
There are 2 blue marbles out of 6 total marbles.
6-2 = 4 marbles are not blue.
Probability of not being blue = 4/6 which reduces to 2/3
Answer: 2/3
The constraints of a problem are listed below. What are the vertices of the feasible region?
x+3y<=6
4x+6y>=9
x>=0
y>=0
The vertices of the feasible region of the constraints is (0,2.5)
How to determine the vertices?The constraints are given as:
x + 3y ≤ 6
4x + 6y ≥ 9
x ≥ 0, y ≥ 0
Express the inequalities as equations
x + 3y = 6
4x + 6y = 9
Make x the subject in x + 3y = 6
x = 6 - 3y
Substitute x = 6 - 3y in 4x + 6y = 9
4(6 - 3y) + 6y = 9
Expand
24 - 12y + 6y = 9
Evaluate the like terms
-6y = -15
Divide by 6
y = 2.5
Substitute y = 2.5 in x = 6 - 3y
x = 6 - 3 * 2.5
Evaluate
x = -1.5
So, we have:
(x,y) = (-1.5, 2.5)
Recall that: x ≥ 0, y ≥ 0
This means that the feasible region must have positive coordinates or zero
So, we set x = 0
(x,y) = (0, 2.5)
Hence, the vertices of the feasible region of the constraints is (0,2.5)
Read more about feasible region at:
https://brainly.com/question/14381991
#SPJ1
Little help? Ill give 5 stars and brainly (If correct)
Answer:
C
Step-by-step explanation:
Slope is rise over run. Pick two points and then count the rise and run. The rise in this case is one and the run is 2 and one over 2 is 1/2
[tex]Hiya![/tex]
Sokka is here to help!
ANSWER:[tex]C.[/tex]
Because, All you need to do is.. Find the slope of proportional graph, by y and x, Which the line is [tex]\frac{4}{2}[/tex].
[tex]And, \frac{4}{2} =\frac{1}{2} .[/tex]
Hopefully, this helps you!!
[tex]Sokka[/tex]
what do i do for the 2 boxes circled in purple? help!
Which of the following best describes the slope of the line below?
Answer:
Negative
Step-by-step explanation:
The slope of the line is negative because when looking at the graph, you can see that the line starts in the 2nd quadrant and ends in the 4th.
i need help plz
thanks
(2+√3)+(4-√3)
[tex] [/tex]
Explanation :
________________________________
Given:
(2+√3)+(4-√3)
To Find:
Evaluate the expression
Solution:
⇨Step 1:
Remove the parentheses
(2+√3)+(4-√3)
When there is + or no sign in front of an expression in parentheses, the expression remains the same
= 2 + √3+ 4-√3
⇨Step 2:
Cancel the opposite terms √3 and -√3
"Two numbers are opposites if they have the same absolute value but different signs"
= 2 + 4
⇨Step 3:
Add the numbers
= 6
Hence (2+√3)+(4-√3) = 6.