Deshaun is fertilizing his garden. The garden is in the shape of a rectangle. Its length is 14 feet and its width is 11 feet. Suppose each bag of fertilizer covers 22 square feet. How many bags will he need to cover the garden?

Answer:

Step-by-step explanation:

surface area of cylinder=2 πr²+2πrh

=2πr(r+h)

=2π×12(12+18)

=24π×30

=720π

≈2261.9 cm²

Answer:

1620

Step-by-step explanation:

If a number decreased by 95% is 81, then

5% is 81.

So, the number = 100/5 x 81= 20 x 81 = 1620

Hope this helps

Answer:

the answer is 1620

Step-by-step explanation:

Answer: 5/55

Step-by-step explanation:

1/11 x 5 = 5/55

So, the fifth equivalent fraction to 1/11 is 5/55.

The 5th equivalent fraction should be [tex]5\div 55[/tex]

Since the fraction is [tex]1\div 11[/tex]

So here the 5th equivalent should be

[tex]= 1\div 11 \times 5\div 5[/tex]

= [tex]5\div 55[/tex]

Here 5 represent the numerator and 55 represent the denominator.

Therefore, we can concluded that The 5th equivalent fraction should be [tex]5\div 55[/tex]

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Answer:

-7, -4, 3

Step-by-step explanation:

Tn = 2n² - 3n - 6

Answer:

6) g = 11p

7) This equation is an example of direct variaction because it is proportional because can make a slanted line with the equation C = 6g + 15

Step-by-step explanation:

Well to find g we seperate g and combine like terms,

[tex]81 = 6g + 15[/tex]

So we subtract 15 from both sides 66 = 6g,

66/6 = 11.

So g = 11.

Answer:

Step-by-step explanation:

We can use the intercept form of the equation of a line, then solve for y.

Intercept form

  x/(x-intercept) +y/(y-intercept) = 1

  x/-4 +y/8 = 1

__

Solving for y, we have ...

  -2x +y = 8 . . . . multiply by 8

  y = 2x +8 . . . .  add 2x

The coefficient of x is 2, so the slope is 2.

__

The graph shows you the rise is 8 for a run of 4, so ...

  slope = rise/run = 8/4

  slope = 2

Answer:

1080

Step-by-step explanation:

Answer:

0.

Step-by-step explanation:

Fair dice are dice that have 6 sides, and the probability of rolling a side is the same as rolling another.

Since each die has 6 sides, the most you can get from the two dice are 6 + 6 = 12. Therefore, getting a 13 is impossible. So, there is a probability of 0.

Hope this helps!

Answer:

x=23/3

Step-by-step explanation:

x=c+ay

7=c+3a     | *(-1)

9=c+6a

-7=-c-3a

9=c+6a

------------

9-7=c-c+6a-3a

2=3a

a=2/3

7=c+3*2/3

7=c+2

-2   -2

5=c

so   x=5+2/3*y

when y=4 then  x=5+2/3*4=5+8/3

x=15/3+8/3

x=23/3

Answer: A. Only A

Step-by-step explanation:

A has exactly one output for every input but B has different outputs for an input.

Answer:

proof

Step-by-step explanation:

Statements

Reasons

<2 is congruent to <5; Segment AB is congruent to Segment DE

Given

<3≅<4

Vertical angle theorem

ΔCDB≅ΔCAE

AAS

Segment BC is congruent to Segment EC

CPCTC

The segment BC is congruent to segment EC and this can be proven by using the properties of a triangle and the given data.

Given :

The following steps can be used in order to prove that segment BC is congruent to segment EC:

Step 1 - Using the triangle properties it can be proven that segment BC is congruent to segment EC.

Step 2 - According to the vertical angle theorem, angle 3 is congruent to angle 4.

Step 3 - Now, according to the AAS (Angle Angle Side) postulate, triangle CDB is similar to triangle CAE.

Step 4 - So, according to the CPCTC, segment BC is congruent to segment EC.

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Answer:

There are 1000 millimeters in a meter.

Step-by-step explanation:

I really hope this helps in any way.

Answer:

1,000

Step-by-step explanation:

The word millimeter has the prefix of 'milli-'.

'Milli-' means a thousand.

Applying the prefix meaning to the word, a millimeter would be a thousandth of a meter.

There are 1,000 millimeters in a meter.

Brainilest Appreciated.

Answer:

\the zeroes are (2√3)/ 3, (√3)/4,

or -1.15, 0.43 to the nearest hundredth.

Step-by-step explanation:

I am assuming you want to find the zeroes of this function:

4√3 x^2+5x-2√3 = 0

Using the quadratic formula:

x = [ -5 +/- √((5)^2 - 4 * 4√3  * -2√3) ]  / (2 * 4√3 )

=  ( - 5 +/- √(25 - (-32*3)) / 8√3

= (-5 +/- √ 121) / 8√3

= (-5 - 11) / 8√3 or  (-5 + 11) / 8√3

=  -16/8√3 or 6/8√3

= -16√3/ 24 or  6√3 / 24

= -2√3/ 3 or √3/4.

Answer:

The correct option is;

D) x² + 72·x - 7920 = 0

Step-by-step explanation:

The time it takes the car to stop = x/24 seconds

the average speed during stopping = x/2 feet per second

Given that the car was initially travelling at x feet per second and it takes the car 165 feet to stop after the driver takes 1.5 seconds at the initial speed x before the break is applied, we have;

Total distance traveled = (x/24)×(x/2) + x×1.5 = 165

= x²/48 + 1.5·x = 165

Multiply through by 48, we have;

x² + 72·x = 7920

Which gives the equation as follows;

x² + 72·x - 7920 = 0.

Answer:

first option

Step-by-step explanation:

Using the rules of logarithms

log x - log y = log ([tex]\frac{x}{y}[/tex] )

log[tex]x^{n}[/tex] ⇔ n log x

ln e = 1

Given

4 + 5[tex]e^{x+2}[/tex] = 11 ( subtract 4 from both sides )

5[tex]e^{x+2}[/tex] = 7 ( divide both sides by 5 )

[tex]e^{x+2}[/tex] = [tex]\frac{7}{5}[/tex] ( take ln of both sides )

ln [tex]e^{x+2}[/tex] = ln ([tex]\frac{7}{5}[/tex] )

(x + 2) lne = ln ([tex]\frac{7}{5}[/tex] )

x + 2 = ln ([tex]\frac{7}{5}[/tex] ) ( subtract 2 from both sides )

x = ln([tex]\frac{7}{5}[/tex] ) - 2

Answer:

114.96 pounds at angle 81.76°

Step-by-step explanation:

Let i be the component along x-axis and j be the component along y-axis.

First force that is given is 150 acting at angle 40; [tex]F1 = 150cos170i + 150sin40j = 114.91i +96.42j[/tex]

The second force 100 is acting at angle 170;

[tex]F2 = 100cos170i + 100sin170j = -98.48i + 17.36j[/tex]

We now have the resultant force, which is: [tex]114.91i + 96.42j + (-98.48i + 17.36j) = 16.43i + 113.78j[/tex]

Magnitude of resultant:

[tex]\sqrt{16.43^{2} + 113.78^{2} }[/tex] = 114.96 pounds

Angle it makes with horizontal; inverse tangent of [tex]\frac{(113.78)}{(16.43)}[/tex] = 81.76 degrees

Hope this helps; Brainliest appreciated!

Answer:

c)    [tex]2\frac{23}{30}[/tex]     d)[tex]1\frac{23}{24}[/tex]

7)    a.   [tex]6\frac{3}{11}[/tex]  kg                  b.   [tex]6 \frac{2}{3}[/tex]  cm               c. 20 cm

d.  [tex]9\frac{9}{10}[/tex] kg                  e. 10 g             f. [tex]23 \frac{1}{4}[/tex]  kg

Step-by-step explanation:

c)  [tex]8\frac{2}{3}[/tex]   -   [tex]5\frac{9}{10}[/tex]

First we will change to improper fraction and then solve

[tex]\frac{26}{3} - \frac{59}{10}[/tex]

=  [tex]\frac{260 - 177}{30}[/tex]

= [tex]\frac{83}{30}[/tex]

we will now change to mixed number

= [tex]2\frac{23}{30}[/tex]

d)  [tex]8\frac{1}{8} - 6\frac{1}{6}[/tex]

we will first change it to improper fraction and then solve

= [tex]\frac{65}{8} - \frac{37}{6}[/tex]

= [tex]\frac{390 - 296}{48}[/tex]

= [tex]\frac{94}{48}[/tex]

we can reduce the fraction

=[tex]\frac{47}{24}[/tex]

we will change it mixed number

=[tex]1\frac{23}{24}[/tex]

7)  

a.   [tex]\frac{3}{11}[/tex]   of 23

=  [tex]\frac{3}{11}[/tex]   × 23

=  [tex]\frac{69}{11}[/tex]

=[tex]6\frac{3}{11}[/tex]  kg

b. [tex]\frac{2}{3}[/tex]   of 10 cm

= [tex]\frac{2}{3}[/tex]   × 10 cm

= [tex]\frac{20}{3}[/tex]  cm

=[tex]6 \frac{2}{3}[/tex]  cm

c. [tex]\frac{5}{6}[/tex]   of 24cm

=    [tex]\frac{5}{6}[/tex]   × 24 cm

6 will divide 24

=5 × 4 cm

= 20 cm

d.  [tex]\frac{3}{10}[/tex]  of  33 kg

=  [tex]\frac{3}{10}[/tex]  ×  33 kg

=[tex]\frac{99}{10}[/tex]  kg

=[tex]9\frac{9}{10}[/tex] kg

e. [tex]\frac{2}{7}[/tex]   of  35 g

=  [tex]\frac{2}{7}[/tex]   ×  35 g

7 will go into 35

=2×5 g

=10 g

f. [tex]\frac{3}{4}[/tex]  of  31 kg

= [tex]\frac{3}{4}[/tex]  ×  31 kg

=[tex]\frac{93}{4}[/tex] kg

=[tex]23 \frac{1}{4}[/tex]  kg

Answer:

1) For [tex]x^2 + y^2 - 4x + 12y - 20 = 0[/tex], the standard form is [tex](x-2)^2 + (y+6)^2 = 60\\[/tex]

2) For [tex]x^2 + y^2 + 6x - 8y - 10 = 0[/tex], the standard form is [tex](x + 3)^2 + (y - 4)^2 = 35\\[/tex]

3) For [tex]3x^2 + 3y^2 + 12x + 18y - 15 = 0[/tex],  the standard form is [tex](x + 2)^2 + (y+ 3)^2 = 18\\[/tex]

4) For [tex]5x^2 + 5y^2 - 10x + 20y - 30 = 0[/tex],  the standard form is [tex](x - 1)^2 + (y+ 2)^2 = 11\\[/tex]

5) For [tex]2x^2 + 2y^2 - 24x - 16y - 8 = 0[/tex],  the standard form is [tex](x - 6)^2 + (y+ 4)^2 = 56\\[/tex]

6) For[tex]x^2 + y^2 + 2x - 12y - 9 = 0[/tex], the standard form is [tex](x+1)^2 + (y-6)^2 = 46\\\\[/tex]

Step-by-step explanation:

This can be done using the completing the square method.

The standard equation of a circle is given by [tex](x - a)^2 + (y-b)^2 = r^2[/tex]

1) For [tex]x^2 + y^2 - 4x + 12y - 20 = 0[/tex]

[tex]x^2 - 4x + y^2 + 12y = 20\\x^2 - 4x + 2^2 + y^2 + 12y + 6^2 = 20 + 4 + 36\\(x-2)^2 + (y+6)^2 = 60\\[/tex]

Therefore, for [tex]x^2 + y^2 - 4x + 12y - 20 = 0[/tex], the standard form is [tex](x-2)^2 + (y+6)^2 = 60\\[/tex]

2) For [tex]x^2 + y^2 + 6x - 8y - 10 = 0[/tex]

[tex]x^2 + 6x + y^2 - 8y = 10\\x^2 + 6x + 3^2 + y^2 - 8y + 4^2 = 10 + 9 + 16\\(x + 3)^2 + (y- 4)^2 = 35\\[/tex]

Therefore, for [tex]x^2 + y^2 + 6x - 8y - 10 = 0[/tex], the standard form is [tex](x + 3)^2 + (y - 4)^2 = 35\\[/tex]

3)  For [tex]3x^2 + 3y^2 + 12x + 18y - 15 = 0[/tex]

Divide through by 3

[tex]x^2 + y^2 + 4x + 6y = 5[/tex]

[tex]x^2 + y^2 + 4x + 6y = 5\\x^2 + 4x + 2^2 + y^2 + 6y + 3^2 = 5 + 4 + 9\\(x + 2)^2 + (y+ 3)^2 = 18\\[/tex]

Therefore, for [tex]3x^2 + 3y^2 + 12x + 18y - 15 = 0[/tex],  the standard form is [tex](x + 2)^2 + (y+ 3)^2 = 18\\[/tex]

4)  For [tex]5x^2 + 5y^2 - 10x + 20y - 30 = 0[/tex]

Divide through by 5

[tex]x^2 + y^2 - 2x + 4y = 6[/tex]

[tex]x^2 + y^2 -2x + 4y = 6\\x^2 - 2x + 1^2 + y^2 + 4y + 2^2 = 6 + 1 + 4\\(x - 1)^2 + (y+ 2)^2 = 11\\[/tex]

Therefore, for [tex]5x^2 + 5y^2 - 10x + 20y - 30 = 0[/tex],  the standard form is [tex](x - 1)^2 + (y+ 2)^2 = 11\\[/tex]

5) For [tex]2x^2 + 2y^2 - 24x - 16y - 8 = 0[/tex]

Divide through by 2

[tex]x^2 + y^2 - 12x - 8y = 4[/tex]

[tex]x^2 + y^2 - 12x - 8y = 4\\x^2 - 12x + 6^2 + y^2 - 8y + 4^2 = 4 + 36 + 16\\(x - 6)^2 + (y+ 4)^2 = 56\\[/tex]

Therefore, for [tex]2x^2 + 2y^2 - 24x - 16y - 8 = 0[/tex],  the standard form is [tex](x - 6)^2 + (y+ 4)^2 = 56\\[/tex]

6) For [tex]x^2 + y^2 + 2x - 12y - 9 = 0[/tex]

[tex]x^2 + 2x + y^2 - 12y = 9\\x^2 + 2x + 1^2 + y^2 - 12y + 6^2 = 9 + 1 + 36\\(x+1)^2 + (y-6)^2 = 46\\[/tex]

Therefore, for[tex]x^2 + y^2 + 2x - 12y - 9 = 0[/tex], the standard form is [tex](x+1)^2 + (y-6)^2 = 46\\\\[/tex]

For Plato / Edmentum

Just to the test and got it right ✅

Answer:

Point used by Harold was:

(7, 0)

Step-by-step explanation:

Given that

Equation of linear function used by Harold:

[tex]y = 3(x - 7)[/tex]

We know that linear equation in point slope form can be represented as:

[tex]y - y_1 = m(x - x_1)[/tex]

Where [tex](x_1,y_1)[/tex] are the coordinates of a given point.

[tex]m[/tex] is the slope of line.

Formula for Slope, m is given as:

[tex]m = \dfrac{y_2-y_1}{x_2-x_1}[/tex]

Where [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex] are the two points on the line.

If slope and a point with coordinates [tex](x_1,y_1)[/tex] is know, the equation of a line can be represented in linear form as:

[tex]y - y_1 = m(x - x_1)[/tex] ....... (1)

Now, the given equation is:

[tex]y = 3(x - 7)[/tex]

Re-writing the equation with a slight modification:

[tex]y-0 = 3(x - 7)[/tex]

Now, comparing the above equation with equation (1):

We get that:

[tex]x_1=7\\y_1=0[/tex]

So, the point used by Harold is (7, 0).

Answer:

(7,0)

Step-by-step explanation:

Answer:

y = csc (x) + 2

Step-by-step explanation:

From the graph, we can derive the parent function y = csc(x). Notice how there are asymptotes at x = 2πk and x = π + 2πk, which is where csc(x) is undefined.

Finally, we can see a vertical shift of 2 which we can see from the mid-line of the graph which is at y = 3.

Answer:

c

Step-by-step explanation:

edg 2021

Answer:

Option C

Step-by-step explanation:

Answer:

B.

You need to subtract 1 term because you don't include the starting 5

4^10 - 1 =  4^9

You multiply 5 by 4 each time for 9 times so it is 5 x 4^9

Hope this helps

Step-by-step explanation:

Answer:

1/3000

Step-by-step explanation:

3 meters to centimeters:

3 × 100 = 300

= 1/10 ÷ 300

= 1/10/300

= 1/(10×300)

= 1/3000

Answer: k ≥ 50

Step-by-step explanation:

From the question, we are informed that Derek will get a bonus if he sells at least 50 sets of knives in a month. We are further told to us k to represent the number of knives he can sell to receive his bonus.

Since we are told that Derek will get a bonus if he sells at least 50 sets of knives in a month, this means that k will be greater than or equal to 50. Therefore,

k ≥ 50

Answer:

Step-by-step explanation:

Total marbles = 5  + 6 + 2 = 13

P( getting blue ball from first draw) = 5/13

The marble is not replaced. So, Now total marbles will be 12 & number blue marbles will be 4

P( getting blue ball from second draw) = 4/12 = 1/3

P(getting two blues) = [tex]\frac{5}{13}*\frac{1}{3}\\[/tex]

                                  = 5/39

Answer:

Rectangular area attached to the back of the building

two sides of legth 7 m and one side of 14 m

Step-by-step explanation:

We need to compare quantity of fencing material to be used in both cases

1.Option

A = 100 m²          dimensions of storage area  "x"    and "y"

x*y = 100     y = 100/x

The perimeter of the storage area is

p = 2*x + 2*y       ⇒ p = 2*x + 2*100/x

p(x) = 2*x + 200/x

Taking drivatives on both sides of the equation

p´(x) = 2 - 200/x²

p´(x) = 0         ⇒        2 - 200/x² = 0

2*x² - 200 = 0       x² = 100

x = 10 m

and  y = 100/10      

y = 10 m

Required fencing material in first option

2*10 + 2*10  =  40 m

2.-Option

Following the same procedure

A = 98 m²       y = A/x         y = 98/x

p = 2*x + y             p(x) =  2*x  +  98/x

p´(x)  = 2 - 98/x²             p ´(x) = 0

2 - 98/x²  = 0

2*x²  = 98           x² =  49

x = 7 m       and        y   =  98/ 7         y  = 14 m

Total quantity of fencing material

p = 2* 7 + 14         p = 28

Therefore option 2 is more convinient from economic point of view

Optimal design rectangular storage area with two sides of 7 m and one side of 14 m

Answer:

  B. 5 seconds

Step-by-step explanation:

A graphing calculator shows the answer easily.

__

h(t) = 0 = -16t^2 +400

t = √(400/16) = 5

It will take 5 seconds for the sandbag to hit the ground.

Answer:

the 2nd

Step-by-step explanation:

Answer:

5pi/3

Step-by-step explanation:

For two angles to be co-terminal, one must differ from the other by a multiple of 2pi.

The angle of consideration is 5pi/3

Let us consider the options one by one and see if they differ from the angle of consideration by a multiple of 2pi.

5pi/3 - pi/3 = 4pi/3

5pi/3 - 2pi/3 = 3pi/3 = pi

5pi/3 - 4pi/3 = pi/3

5pi/3 - 5pi/3 = 0 = 0(2pi)

5pi/3 is co-terminal with itself

Answer:

C) line b and line c

Step-by-step explanation:

On edge

A line is a one-dimensional shape that is straight, has no thickness, and extends in both directions indefinitely. The system of equations that do not have any solution is line b and line c. Hence, the correct option is C.

A line is a one-dimensional shape that is straight, has no thickness, and extends in both directions indefinitely. The equation of a line is given by,

y =mx + c

where,

x is the coordinate of the x-axis,

y is the coordinate of the y-axis,

m is the slope of the line, and

c is the y-intercept.

The equation of line a passing through (-1,0) and (1,2) are,

m = (0-2)/(-1-1) = -2/-2 = 1

y= x + c

0 = -1 + c

c = 1

Equation of line 1, y=x+1

The equation of line b passing through (-2,2) and (-1,-1) are,

m = (2+1)/(-2+1) = 3/-1 = -3

y= -3x + c

-1 = -3(-1) + c

c = -4

Equation of line 1, y=-3x-4

The equation of line c passing through (0,3) and (1,0) are,

m = (3-0)/(0-1) = 3/-1 = -3

y= -3x + c

3 = -3(0) + c

c = 3

Equation of line 1, y=-3x+3

Also, the equation of line d is y=1

The solution of two-equation is the point at which the two equations are not intersecting. Therefore, the system of equations that do not have any solution is line b and line c.

Hence, the correct option is C.

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Answer:

[tex]\boxed{\mathrm{view \: explanation}}[/tex]

Step-by-step explanation:

2)

a) elimination method

b) substitution method

c) substitution method

For the first part we can elimate the y variable by subtracting the equations. We can then find the value of x.

For the second part we can substitute y as 2x+5 in the second equation and solve for x.

For the third part we can substitute y as 4x+3 in the first equation and solve for x.

3)

[tex]\boxed{\mathrm{view \: attachment}}[/tex]