The scope of petName is local to the class pet.
The scope of color is accessible by all parts of the program.
How to interpret programming variables?The variable petName is local to the class; This isdue to the fact that the variable was created in a function whose name begins with two underscores.
The variable color; This is created in the petCarrier class and is accessible to the entire function. This was not created in a function whose name begins with an underscore.
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Answer:
The scope of petName limited to the pet class
The scope of color is accessible to the entire program
Explanation:
edge
Which technique will you use to make listening to audio a pleasant experience?
Audio _____ is the smooth shift of one audio file into another.
Don't quote me on this, but I *think* the answer is "Audio transition/transitioning is the smooth shift of one audio file into another." I hope I was able to help and I apologize if I was wrong. ♡♡
Answer:
Sample response: Good thriller has beginning, middle, and end. Reader has to care about the characters. A character should be mysterious so readers are interested. Crime is a good way to talk about human condition. Good thrillers change people’s point of view in some way.
Explanation:
Eric would like to have a callout text box that makes it look as if the character in an image is speaking. Which object should he insert into the Word document?
standard text box
WordArt
callout
shape
picture
Answer:
C: Callout shape
Explanation:
The object that should he insert into the Word document is the callout function. The correct option is b.
What is Microsoft Word?A component of Microsoft Office is Microsoft Word. The office is a collection of Microsoft products that can be used on Windows or macOS and contains Word, PowerPoint, Excel, Outlook, and numerous other tools for both private and professional usage. They aren't the same thing; Microsoft Word is merely one of such app.
A callout function is one of the functions that specifies a callout and is implemented by a callout driver.
The following collection of callout functions makes up a callout: a notification processing notifying function. A function called classifying handles classifications.
Therefore, the correct option is b. callout.
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Which loop prints the numbers 1, 2...100?
c = 1
while (c <= 100):
c = c + 1
print (c)
c = 1
while (c < 100):
c = c + 1
print (c)
c = 1
while (c <= 100):
print (c)
c = c + 1
c = 1
while (c < 101):
c = c + 1
print (c)
Answer:
while (c <= 100):
print (c)
c = c + 1
Explanation:
We can cancel out the while loops with ' < ' because then it won't print when C is 100.
while (c <= 100):
print (c)
c = c + 1
Is probably right because unlike the other while loop with ' <= ' it has a print statement before the C = C + 1 which means look at this:
C = 1
print(c)
C = C + 1
So when it's run 1 is printed
But when doing the other while loop:
c = 1
while (c <= 100):
print (c)
c = c + 1
C = 1
c = c + 1
print(c)
It prints 2 because it added 1 to C first before actually printing it.
The loop that prints the numbers 1, 2...100 is
c = 1
while (c <= 100):
print (c)
c = c + 1
We are to find the loop that prints the numbers 1 , 2 …100.
Therefore, the loop that print 1 to 100 can be represented as follows:
c = 1
while (c <= 100):
print (c)
c = c + 1
c is a variable initialize with zero.
The while loop is used to check if c is less than or equals to 100.
If c is less than or equal to 100 we print the value of c .
Then we add 1 to c and go back to the loop again.
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