Describe el tipo de transformación de la siguiente figura y sus coordenadas.

Answer:

7,273 Pesos

Step-by-step explanation:

1 Peso = $0.055

The formula below converts pesos to dollars:

1 Peso x 0.055 = $1

The formula below converts dollars to pesos:

$1/0.055= 1 Pesos

We use the second formula because we are coverting

from dollars to pesos.

$400/0.055=7,273 Pesos

Answer:

22

Step-by-step explanation:

If one Mexican peso is .055 U.S dollars that means it has a greater value than the dollar so we can make the following ratio 1:.055. But if the .055 is a 400 1:400 we just multiply to get 22.

Answer:

95 ft²

Step-by-step explanation:

Given:

regular pyramid with,

Square base of side length (s) = 5 ft

Slant height (l) = 7 ft

Required:

Surface area

Solution:

Surface area of a regular pyramid = ½*P*l + B

Where,

P = perimeter of the square base = 4(s) = 4(5) = 20 ft

l = slant height = 7 ft

B = area of base = s² = 5² = 25 ft²

Surface area = ½*20*7 + 25

= 10*7 + 25

= 70 + 25

Surface area of regular pyramid = 95 ft²

Answer:

CI: {0.4085; 0.6647}

Step-by-step explanation:

The confidence interval for a proportion (p) is given by:

[tex]p \pm z*\sqrt{\frac{(1-p)*p}{n} }[/tex]

Where n is the sample size, and z is the z-score for the desired confidence interval. The score for a 90% confidence interval is 1.645. The proportion of depositors who ask for cash back is:

[tex]p=\frac{22}{41}=0.536585[/tex]

Thus the confidence interval is:

[tex]0.536585 \pm 1.645*\sqrt{\frac{(1-0.536585)*0.536585}{41}}\\0.536585 \pm 0.128109\\L=0.4085\\U=0.6647[/tex]

The confidence interval for the proportion of all depositors who ask for cash back is CI: {0.4085; 0.6647}

Answer:

3

Step-by-step explanation:

Given  

y

=

2

x

2

−

4

x

+

3

The y-intercept is the value of  

y

when  

x

=

0

XXX

y

=

2

(

0

)

2

−

4

(

0

)

+

3

=

3

For a quadratic in the general form:

XXX

y

=

a

x

2

+

b

x

+

c

the determinant  

Δ

=

b

2

−

4

a

c

indicates the number of zeros.

Δ

⎧

⎪

⎨

⎪

⎩

<

0

==⇒  

no solutions

=

0

==⇒  

one solution

>

0

==⇒  

two solutions

In this case

XXX

Δ

=

(

−

4

)

2

−

4

(

2

)

(

3

)

<

0

so there are no solutions (i.e. no values for which the expression is equal to zero).

This can also be seen from a graph of this equation:

graph{2x^2-4x+3 [-6.66, 13.34, -0.64, 9.36]}

Answer link

Vinícius Ferraz

Nov 13, 2015

(

0

,

3

)

Explanation:

x

=

0

⇒

y

=

0

−

0

+

3

y

=

0

⇒

x

=

−

b

±

√

b

2

−

4

a

c

2

a

a

=

2

,

b

=

−

4

,

c

=

3

But  

Δ

< 0, then there is no real root  

(

x

0

,

0

)

.

Answer:

it has 2

Step-by-step explanation:

I hope this helps!

Answer:

The common difference is 1/2

Step-by-step explanation:

Data obtained from the question include:

3rd term (a3) = 0

Common difference (d) =.?

From the question given, we were told that the 7th term (a7) and the 4th term (a4) are related by the following equation:

a7 – 2a4 = 1

Recall:

a7 = a + 6d

a4 = a + 3d

a3 = a + 2d

Note: 'a' is the first term, 'd' is the common difference. a3, a4 and a7 are the 3rd, 4th and 7th term respectively.

But, a3 = 0

a3 = a + 2d

0 = a + 2d

Rearrange

a = – 2d

Now:

a7 – 2a4 = 1

Substituting the value of a7 and a4, we have

a + 6d – 2(a + 3d) = 1

Sustitute the value of 'a' i.e –2d into the above equation, we have:

–2d + 6d – 2(–2d + 3d) = 1

4d –2(d) = 1

4d –2d = 1

2d = 1

Divide both side by 2

d = 1/2

Therefore, the common difference is 1/2

***Check:

d = 1/2

a = –2d = –2 x 1/2 = –1

a3 = 0

a3 = a + 2d

0 = –1 + 2(1/2)

0 = –1 + 1

0 = 0

a7 = a + 6d = –1 + 6(1/2) = –1 + 3 = 2

a4 = a + 3d = –1 + 3(1/2) = –1 + 3/2

= (–2 + 3)/2 = 1/2

a7 – 2a4 = 1

2 – 2(1/2 = 1

2 – 1 = 1

1 = 1

Answer:

We conclude that the true average percentage of organic matter in such soil is something other than 3% at 10% significance level.

We conclude that the true average percentage of organic matter in such soil is 3% at 5% significance level.

Step-by-step explanation:

We are given a random sample of soil specimens was obtained, and the amount of organic matter (%) in the soil was determined for each specimen;

1.10, 5.09, 0.97, 1.59, 4.60, 0.32, 0.55, 1.45, 0.14, 4.47, 1.20, 3.50, 5.02, 4.67, 5.22, 2.69, 3.98, 3.17, 3.03, 2.21, 0.69, 4.47, 3.31, 1.17, 0.76, 1.17, 1.57, 2.62, 1.66, 2.05.

Let [tex]\mu[/tex] = true average percentage of organic matter

So, Null Hypothesis, [tex]H_0[/tex] : [tex]\mu[/tex] = 3%      {means that the true average percentage of organic matter in such soil is 3%}

Alternate Hypothesis, [tex]H_A[/tex] : [tex]\mu \neq[/tex] 3%      {means that the true average percentage of organic matter in such soil is something other than 3%}

The test statistics that will be used here is One-sample t-test statistics because we don't know about the population standard deviation;

                         T.S.  =  [tex]\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }[/tex]  ~ [tex]t_n_-_1[/tex]

where, [tex]\bar X[/tex] = sample mean percentage of organic matter = 2.481%

             s = sample standard deviation = 1.616%

            n = sample of soil specimens = 30

So, the test statistics =  [tex]\frac{2.481-3}{\frac{1.616}{\sqrt{30} } }[/tex]  ~ [tex]t_2_9[/tex]

                                     =  -1.76

The value of t-test statistics is -1.76.

(a) Now, at 10% level of significance the t table gives a critical value of -1.699 and 1.699 at 29 degrees of freedom for the two-tailed test.

Since the value of our test statistics doesn't lie within the range of critical values of t, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region.

Therefore, we conclude that the true average percentage of organic matter in such soil is something other than 3% at 10% significance level.

(b) Now, at 5% level of significance the t table gives a critical value of -2.045 and 2.045 at 29 degrees of freedom for the two-tailed test.

Since the value of our test statistics lies within the range of critical values of t, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region.

Therefore, we conclude that the true average percentage of organic matter in such soil is 3% at 5% significance level.

Answer:

B. [tex]4^2[/tex]

Step-by-step explanation:

[tex]4^7 \times 4^{-5}[/tex]

Apply rule (if bases are same) : [tex]a^b \times a^c = a^{b + c}[/tex]

[tex]4^{7 + -5}[/tex]

Add exponents.

[tex]=4^2[/tex]

Answer:

Step by step explanation

[tex] {4}^{7} \times {4}^{ - 5} [/tex]

Use product law of indices

i.e

[tex] {x}^{m} \times {x}^{n} = {x}^{m + n} [/tex]

( powers are added in multiplication of same base)

[tex] = {4}^{7 + ( - 5)} [/tex]

[tex] = {4}^{7 - 5} [/tex]

[tex] = {4}^{2} [/tex]

Hope this helps...

Best regards!

Answer:

a) 16xy³

Step-by-step explanation:

For a binomial expansion (a + b)ⁿ, the r+1 term is:

nCr aⁿ⁻ʳ bʳ

Here, a = 4x, b = y, and n = 4.

For the fourth term, r = 3.

₄C₃ (4x)⁴⁻³ (y)³

4 (4x) (y)³

16xy³

Answer:

It's (D) 8 cm and 9 cm. Hope this helps you!

Step-by-step explanation:

The other 2 sides added have to be greater than 13.

Answer:

8 and 9

Step-by-step explanation:

The triangle inequality states that the sum of the two shortest sides must be greater than the longest side.

Let's check the first one. 5 + 8 > 13 → 13 > 13 which is false.

6 + 7 > 13 → 13 > 13 which is false.

7 + 2 > 13 → 9 > 13 which is false.

8 + 9 > 13 → 17 > 13 which is true.

Answer:

The probability that at least one of the 5 donors has Group O blood type is 0.9497.

Step-by-step explanation:

We can model this as a binomial random variable, with n=5 (the sample size) and p=0.45.

The probability that exactly k donors have Group O blood type in the sample can be written as:

[tex]P(x=k) = \dbinom{n}{k} p^{k}(1-p)^{n-k}\\\\\\P(x=k) = \dbinom{5}{k} 0.45^{k} 0.55^{5-k}\\\\\\[/tex]

We have to calculate the probability P(x≥1). In this case it easy to substract from 1 the probabitity that x is exactly 0:

[tex]P(X\geq1)=1-P(x=0)\\\\\\P(x=0) = \dbinom{5}{0} p^{0}(1-p)^{5}=0.55^5=0.0503\\\\\\P(x\geq1)=1-0.0503=0.9497[/tex]

Answer:

B. -1.

Step-by-step explanation:

[tex]i^1[/tex] = i

[tex]i^2 = -1[/tex]

[tex]i^3 = -i[/tex]

[tex]i^4 = 1[/tex]

...And it keeps going in a pattern, from i to -1 to -i to 1. And so, we have four values.

34 / 4 = 8 with a remainder of 2. That means that the value of [tex]i^{34}[/tex] is the same thing as [tex]i^2\\[/tex], so it is B. -1.

Hope this helps!

Answer:

Do you have an image because I'm a bit confused with you just asking the measure of PSQ.

Step-by-step explanation:

Answer:

-7

Step-by-step explanation:

4 + (−3 − 8)

PEMDAS

Parentheses first

4 + (-11)

Add and subtract next

-7

Answer:

first I'm using BODMAS

4+(-11)

= -7

hope it helps

Answer:

x > -2

Step-by-step explanation:

2(3x–1)>4x–6

Divide each side by 2

2/2(3x–1)>4x/2–6/2

3x-1 > 2x-3

Subtract 2x from each side

3x-2x-1 > 2x-3-2x

x-1 > -3

Add 1 to each side

x-1+1 > -3+1

x > -2

Answer:

a) The sample mean is M=200.

The sample standard deviation is s=13.19.

b) Right-tailed. The null and alternative hypothesis are:

[tex]H_0: \mu=195\\\\H_a:\mu> 195[/tex]

c) At a significance level of 0.01, there is  notenough evidence to support the claim that the arrival rate is significantly higher than 195.

Step-by-step explanation:

We start by calculating the sample and standard deviation.

The sample size is n=30.

The sample mean is M=200.

The sample standard deviation is s=13.19.

[tex]M=\dfrac{1}{n}\sum_{i=1}^n\,x_i\\\\\\M=\dfrac{1}{30}(210+215+200+. . .+221)\\\\\\M=\dfrac{6000}{30}\\\\\\M=200\\\\\\s=\sqrt{\dfrac{1}{n-1}\sum_{i=1}^n\,(x_i-M)^2}\\\\\\s=\sqrt{\dfrac{1}{29}((210-200)^2+(215-200)^2+(200-200)^2+. . . +(221-200)^2)}\\\\\\s=\sqrt{\dfrac{5048}{29}}\\\\\\s=\sqrt{174.07}=13.19\\\\\\[/tex]

This is a hypothesis test for the population mean.

The claim is that the arrival rate is significantly higher than 195.  As we are interested in only the higher tail for a significant effect, this is a right-tailed test.

Then, the null and alternative hypothesis are:

[tex]H_0: \mu=195\\\\H_a:\mu> 195[/tex]

The significance level is 0.01.

The standard deviation of the population is known and has a value of σ=13.

We can calculate the standard error as:

[tex]\sigma_M=\dfrac{\sigma}{\sqrt{n}}=\dfrac{13}{\sqrt{30}}=2.373[/tex]

Then, we can calculate the z-statistic as:

[tex]z=\dfrac{M-\mu}{\sigma_M}=\dfrac{200-195}{2.373}=\dfrac{5}{2.373}=2.107[/tex]

This test is a right-tailed test, so the P-value for this test is calculated as:

[tex]\text{P-value}=P(z>2.107)=0.018[/tex]

As the P-value (0.018) is bigger than the significance level (0.01), the effect is not significant.

The null hypothesis failed to be rejected.

At a significance level of 0.01, there is  notenough evidence to support the claim that the arrival rate is significantly higher than 195.

Answer:

Domain is all real numbers or (negative infinity, positive infinity)

Step-by-step explanation:

Domain is all values of x (inputs) that will work with the function. Since a parabola has no limits for x, and all numbers work for x, then the domain can be any number. That leaves us with All Real Numbers as our answer.

I'm not sure what exactly you did wrong, but I agree with you that the sample size is too small, so the correct answer will probably be the fourth options. Hope that this gives you some confidence, and 'm sorry not to be able to help you any further...

Answer:

i think this person answered but idrk perseusharrison79

Step-by-step explanation:

For 2 parallelograms, the corresponding side lengths are 1 inch and x inches, and 2 inches and 6 inches.

Not drawn to scale

StartFraction 1 over x EndFraction = StartFraction 2 over 6 EndFraction

StartFraction 1 over x EndFraction = StartFraction 6 over 2 EndFraction

StartFraction 1 over 6 EndFraction = StartFraction 2 over x EndFraction

One-half = StartFraction 6 over x EndFraction

Step-by-step explanation:

Answer:

3/10ths of the money

Step-by-step explanation:

Add together the two numbers to get the total.

Josh gets 30 percent and Lucy gets 70 percent.

3/10

Answer:

3/10

Step-by-step explanation:

3+7=10  

Josh=3

Lucy=7

Answer:

5.33

Step-by-step explanation:

Move your numbers so that they're separate from the variables. You should now have x = -2.67 + 8; x = 5.33

Answer:

x=5.33

Step-by-step explanation:

7+x-15=-2.67

7-15+x=-2.67

Add 7 and -15

-8+x=-2.67

Add 8 on both sides

which equal to 5.33

x=5.33

Answers:

A ' = (-2, -3)

B ' = (0, -3)

C ' = (-1, 1)

=======================================================

Explanation:

To apply an x axis reflection, we simply change the sign of the y coordinate from positive to negative, or vice versa. The x coordinate stays as is.

Algebraically, the reflection rule used can be written as [tex](x,y) \to (x,-y)[/tex]

Applying this rule to the three given points will mean....

The diagram is provided below.

Side note: Any points on the x axis will stay where they are. That isn't the case here, but its for any future problem where it may come up. This only applies to x axis reflections.

Answer:

(-2,-3)...(0,-3)...(-1,1)

Step-by-step explanation:

Answer:

7). y = 140

8). x = 9

Step-by-step explanation:

Question (7).

All-right pencil factory will produce the graphite pencils, table formed will represent a linear graph.

Three points on the graph are (12, 42) and (18, 63), (40, y)

Slope of the line passing through these points = [tex]\frac{y_2-y_1}{x_2-x_1}[/tex]

m = [tex]\frac{63-42}{18-12}[/tex] = [tex]\frac{y-42}{40-12}[/tex]

[tex]\frac{21}{6}[/tex] = [tex]\frac{y-42}{40-12}[/tex]

3.5 = [tex]\frac{y-42}{40-12}[/tex]

98 = y - 42

y = 140

Question (8),

If a bicyclist rides at a constant rate, table formed will represent a linear graph.

Slope of a line passing through three points (2, 25), (5, 62.5) and (x, 112.5) given in the table,

m = [tex]\frac{y_2-y_1}{x_2-x_1}[/tex]

[tex]\frac{62.5-25}{5-2}=\frac{112.5-62.5}{x-5}[/tex]

[tex]\frac{37.5}{3}=\frac{50}{x-5}[/tex]

37.5x - 187.5 = 150

37.5x = 337.5

x = 9

Answer:

  [tex]\dfrac{2y^2 +12y -8}{y^3-3y+2}[/tex]

Step-by-step explanation:

It usually works to factor the denominators, so you can determine the least common denominator.

  [tex]\dfrac{2y}{y^2-2y+1}+\dfrac{8}{y^2+y-2}=\dfrac{2y}{(y-1)^2}+\dfrac{8}{(y-1)(y+2)}\\\\=\dfrac{2y(y+2)}{(y-1)^2(y+2)}+\dfrac{8(y-1)}{(y-1)^2(y+2)}=\dfrac{2y^2+4y+8y-8}{(y-1)^2(y+2)}\\\\=\boxed{\dfrac{2y^2 +12y -8}{y^3-3y+2}}[/tex]

Answer:

1/7

Step-by-step explanation:

There are 7 cards, 1 of which is less than 2. Therefore, P (less then 2) = 1/7

Answer:

1/7

Step-by-step explanation:

The number from the list that is less than 2 is 1.

1 number out of a total of 7 numbers.

= 1/7

8x + 3 > 2x - 15

8x - 2x > -15 - 3

6x > -18

x > -3

Answer:

x > -3

Step-by-step explanation:

8x + 3 > 2x - 15​

Add -3 and -2x on both sides.

8x - 2x > -15 - 3

6x > -18

Divide 6 into both sides.

x > -18/6

x > -3

Answer:

(190-5a)°

Step-by-step explanation:

Sum of internal angles of a triangle equals to 180°

If the third angle is x, then we have:

The third angle is: (190-5a)°

Step-by-step explanation:

yeah,when 15-7=8

the number is 8

Answer:

b. 11 apples; 1 orange

Step-by-step explanation:

We test each option, and see if the total is $3.50(what you spend). If the result is different, it is not a possible solution.

a. 1 apple; 11 oranges

1 apple for $0.20

11 oranges for $0.30 each

0.20 + 11*0.30 = $3.50

Possible solution

b. 11 apples; 1 orange

11 apples for $0.20 each

1 orange for $0.30

11*0.2 + 0.3 = 2.5

Not $3.5, so this is not a possible solution.

This is the answer

c. 7 apples; 7 oranges

7*0.2 + 7*0.3 = $3.5

Possible

d. 4 apples; 9 oranges

4*0.2 + 9*0.3 = $3.5

Possible

Answer:

The original digit is 62

Step-by-step explanation:

Let the Tens be represented with T

Let the Units be represented with U

Given:

Unknown Two digit number

Required:

Determine the number

Since, it's a two digit number, then the number can be represented as;

[tex]T * 10 + U[/tex]

From the first sentence, we have that;

[tex]T = 4 + U[/tex]

[tex]T = 4+U[/tex]

Interchanging the digit, we have the new digit to be [tex]U * 10 + T[/tex]

So;

[tex](U * 10 + T) + (T * 10+ U) = 88[/tex]

[tex]10U + T + 10T + U= 88[/tex]

Collect Like Terms

[tex]10U + U + T + 10T = 88[/tex]

[tex]11U + 11T = 88[/tex]

Divide through by 11

[tex]U + T = 8[/tex]

Recall that [tex]T = 4+U[/tex]

[tex]U + T = 8[/tex] becomes

[tex]U + 4 + U = 8[/tex]

Collect like terms

[tex]U + U = 8 - 4[/tex]

[tex]2U = 4[/tex]

Divide both sides by 2

[tex]U = 2[/tex]

Substitute 2 for U in [tex]T = 4+U[/tex]

[tex]T = 4 + 2[/tex]

[tex]T = 6[/tex]

Recall that the original digit is [tex]T * 10 + U[/tex]

Substitute 6 for T and 2 for U

[tex]T * 10 + U[/tex]

[tex]6 * 10 + 2[/tex]

[tex]60 + 2[/tex]

[tex]62[/tex]

Hence, the original digit is 62

1 - complementary =  90- 30 = 60

    suplementary = 180- 30 = 150

2 - area = hb/2 = 360 = hb/2 =  h = 72

3 - similar

4- see number 3

5 - asa, ssa, sas

6 - polygon that had all equal angle measures and sides (equiangular and equilateral)

7 - length x width = area so

   240 / 24 = 10

8 - line

9 - triangle

10 - 180, as see in question 1

vote me brainliest ):>