Answer:
Please see explanations below
Explanation:
Goals; These are the outcomes that a website planning intends to achieve within a stipulated time, i.e weeks, months or years.
Objectives; These are the methods taken, through which the website planning goals will be achieved.
Target audience; These are the specific group of people that are intended to be reached for the website planning. The targeted audience could be identified based on age range, academic background or qualification, gender or marital status.
Purpose statement; This refers to an explanation of the website's planning goals, which is formally written and also shows the main objectives identified with the goals.
The Influence on society of inexpensive internet access and access to the web are numerous; yet it provide information that are not readily accessible by individuals before using the internet. For information to be accessed through internet access by all and sundry, it must come at little or no cost, which is what is currently obtainable in most part of the world.
Moreover, inexpensive access to the internet and web also improve quality of knowledge in addition to the existing ones through research, which is mostly done through the internet.
However, there are also downside of inexpensive access to the internet and web which now depends on whichever individuals want. For instance not every information on the website are true or correct. The right thing to be done is to further search and compare several ones until the right one is found.
Assign True to the variable is_ascending if the list numbers is in ascending order (that is, if each element of the list is greater than or equal to the previous element in the list). Otherwise, assign False with is_ascending.
Answer:
The question seem incomplete as the list is not given and the programming language is not stated;
To answer this question, I'll answer this question using Python programming language and the program will allow user input.
Input will stop until user enters 0
The program is as follows
newlist = []
print("Input into the list; Press 0 to stop")
userinput = int(input("User Input:"))
while not userinput == 0:
newlist.append(userinput)
userinput = int(input("User Input:"))
is_ascending = "True"
i = 1
while i < len(newlist):
if(newlist[i] < newlist[i - 1]):
is_ascending = "False"
i += 1
print(newlist)
print(is_ascending)
Explanation:
This line declares an empty list
newlist = []
This line prompts gives instruction to user on how to stop input
print("Input into the list; Press 0 to stop")
This line prompts user for input
userinput = int(input("User Input:"))
This next three lines takes input from the user until the user enters 0
while not userinput == 0:
newlist.append(userinput)
userinput = int(input("User Input:"))
The next line initialized "True" to variable is_ascending
is_ascending = "True"
The next 5 line iterates from the index element of the list till the last to check if the list is sorted
i = 1
while i < len(newlist):
if(newlist[i] < newlist[i - 1]):
is_ascending = "False"
i += 1
The next line prints the list
print(newlist)
The next line prints the value of is_ascending
print(is_ascending)
In this lab, you declare and initialize constants in a C++ program. The program, which is saved in a file named NewAge2.cpp, calculates your age in the year 2050.
Answer:
#include <iostream>
using namespace std;
int main()
{
const int YEAR = 2050;
int currentYear = 2020;
int currentAge = 38;
cout<<"You will be " << currentAge + (YEAR - currentYear) << " years old in " << YEAR;
return 0;
}
Explanation:
Initialize the YEAR as a constant and set it to 2050
Initialize the currentYear as 2020, and currentAge as 38
Calculate and print the age in 2050 (Subtract the currentYear from the YEAR and add it to the currentAge)
Type a statement using srand() to seed random number generation using variable seedVal. Then type two statements using rand() to print two random integers between (and including) 0 and 9. End with a newline. Ex: #include < iostream > #include < cstdlib > // Enables use of rand() #include < ctime > // Enables use of time() using namespace std: int main() { int seedVal = 0 /* Your solution goes here */ return 0: }
Answer:
Replace /* Your solution goes here */ with the following code segment
srand(seedVal);
cout<<rand()%(int)(9 - 0 + 1) + 0<<endl;
cout<<rand()%(int)(9 - 0 + 1) + 0<<endl;
Explanation:
From the code segment, the seedVal has already been declared and initialized to 0; The next step is to seed it as random number using srand.
The first line of the code segment in the Answer section "srand(seedVal); " is used to achieve that task.
Having done that, the next step is to write statements to generate the two random numbers using rand();
When generating random numbers, two things are to be noted;
The lower bound; LThe upper bound; UHere, the lower bound is 0 and the upper bound is 9;
C rand() function uses the following syntax to generate random numbers
rand()%(int)(U - L + 1) + L
Where U = 9 and L = 0
Replacing U and L with there respective values; the syntax becomes
rand()%(int)(9 - 0 + 1) + 0
So, the two print statements will be written as
cout<<rand()%(int)(9 - 0 + 1) + 0;
Also, the question states that, each print statement be ended with a new line;
So, the print statements will be
cout<<rand()%(int)(9 - 0 + 1) + 0<<endl;
Alternatively, by solving (9 - 0 + 1) + 0; the statements can be written as
cout<<rand()%(int)(10)<<endl;
Conclusively, the complete statements is as follows;
srand(seedVal);
cout<<rand()%(int)(9 - 0 + 1) + 0<<endl;
cout<<rand()%(int)(9 - 0 + 1) + 0<<endl;
or
srand(seedVal);
cout<<rand()%(int)(10)<<endl;
cout<<rand()%(int)(10)<<endl;
if you want to exclude a portion of an image which option should be chosen?? A. Arrange B. Position C. Crop D. Delete
All of the following are true about hacksaws except: a. A hacksaw only cuts on the forward stroke. b. A coarse hacksaw blade (one with fewer teeth) is better for cutting thick steel than a fine blade. c. A fine hacksaw blade (one with many teeth) is better for cutting sheet metal. d. A hacksaw blade is hardened in the center, so it is best to saw only with the center portion of the blade.
All of the following are true about hacksaws, except a coarse hacksaw blade (one with fewer teeth) is better for cutting thick steel than a fine blade. The correct option is b.
What is a hacksaw?A hacksaw is a saw with fine teeth that were originally and primarily used to cut metal. Typically, a bow saw is used to cut wood and is the corresponding saw.
Hacksaw is used by hand, it is a small tool for cutting pipes rods wood etc that is very common and homes and in shops. The different types of hacksaws. The main three types of hacksaws are course-grade hacksaws, medium-grade hacksaws, and fine-grade hacks. The difference is just for the quality, and the design of the blade.
Therefore, the correct option is b. Cutting thick steel is easier with a coarse hacksaw blade (one with fewer teeth) than a fine one.
To learn more about hacksaw, refer to the below link:
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If i wanted to change my phones simcard, does anything need transferring, or is it an easy swap?
Write a python program that asks the user to enter a student's name and 8 numeric tests scores (out of 100 for each test). The name will be a local variable. The program should display a letter grade for each score, and the average test score, along with the student's name. There are 12 students in the class.
Write the following functions in the program:
calc_average - this function should accept 8 test scores as arguments and return the average of the scores per student
determine_grade - this function should accept a test score average as an argument and return a letter grade for the score based on the following grading scale:
90-100 A
80-89 B
70-79 C
60-69 D
Below 60 F
Answer:
The program doesn't make use of comments (See Explanation)
Also the source code is attached as image to enable you see the proper format and indexing of the source code
The program using python is as follows
def calc_average(name):
score = []
sum = 0
for j in range(8):
inp = int(input("Test Score"+str(j+1)+": "))
score.append(inp)
sum = sum + inp
if inp>=90 and inp<=100:
print("A")
elif inp>=80 and inp<90:
print("B")
elif inp>=70 and inp<80:
print("C")
elif inp>=60 and inp<70:
print("D")
else:
print("F")
avg = sum/8
print("Result Details of "+name)
print("Average Score: "+str(avg))
return avg
def determine_grade(result):
if float(result) >= 90.0 and float(result) <= 100.0:
print("Letter Grade: A")
elif float(result) >= 80.0 and float(result) <90.0:
print("Letter Grade: B")
elif float(result) >= 70.0 and float(result) < 80.0:
print("Letter Grade: C")
elif float(result) >= 60.0 and float(result) < 70.0:
print("Letter Grade: D")
else:
print("Letter Grade: F")
print(" ")
for i in range(2):
name = input("Student Name: ")
result = calc_average(name)
determine_grade(result)
Explanation:
def calc_average(name): -> Declares the function calc_average(name); It accepts local variable name from the main function
score = []
-> Initialize an empty list to hold test scores
sum = 0
-> Initialize sum of scores to 0
for j in range(8):
-> Iterate from test score 1 to 8
inp = int(input("Test Score"+str(j+1)+": "))
-> This line accepts test score from the user
score.append(inp)
-> The user input is then saved in a lisy
sum = sum + inp
-> Add test scores
The following lines determine the letter grade of each test score
if inp>=90 and inp<=100:
print("A")
---
else:
print("F")
avg = sum/8 -> Calculate average of the test score
The next two lines prints the name and average test score of the student
print("Result Details of "+name)
print("Average Score: "+str(avg))
return avg
-> This line returns average to the main method
The following is the determine_grade method; it takes it parameter from the main method and it determines the letter grade depending on the calculated average
def determine_grade(result):
if float(result) >= 90.0 and float(result) <= 100.0:
print("Letter Grade: A")
elif float(result) >= 80.0 and float(result) <90.0:
print("Letter Grade: B")
elif float(result) >= 70.0 and float(result) < 80.0:
print("Letter Grade: C")
elif float(result) >= 60.0 and float(result) < 70.0:
print("Letter Grade: D")
else:
print("Letter Grade: F")
print(" ")
for i in range(2):
-> This is the main method
name = input("Student Name: ") -> A local variable stores name of the student
result = calc_average(name) -> store average of scores in variable results
determine_grade(result)-> Call the determine_grade function
In this exercise we have to use the computer language knowledge in python to write the code as:
the code is in the attached image.
In a more easy way we have that the code will be:
def calc_average(name):
score = []
sum = 0
for j in range(8):
inp = int(input("Test Score"+str(j+1)+": "))
score.append(inp)
sum = sum + inp
if inp>=90 and inp<=100:
print("A")
elif inp>=80 and inp<90:
print("B")
elif inp>=70 and inp<80:
print("C")
elif inp>=60 and inp<70:
print("D")
else:
print("F")
avg = sum/8
print("Result Details of "+name)
print("Average Score: "+str(avg))
return avg
def determine_grade(result):
if float(result) >= 90.0 and float(result) <= 100.0:
print("Letter Grade: A")
elif float(result) >= 80.0 and float(result) <90.0:
print("Letter Grade: B")
elif float(result) >= 70.0 and float(result) < 80.0:
print("Letter Grade: C")
elif float(result) >= 60.0 and float(result) < 70.0:
print("Letter Grade: D")
else:
print("Letter Grade: F")
print(" ")
for i in range(2):
name = input("Student Name: ")
result = calc_average(name)
determine_grade(result)
See more about python at brainly.com/question/26104476
DEF is a small consulting firm with ten on-site employees and 10 to 12 part-time (off-site) software consultants. Currently, the network consists of 2 servers for internal business processes, 1 server that handles the call-in connections; 10 on-site wireless workstations/devices, and 2 printers. Respond to the following in a minimum of 175 words: Identify one network security strategy that would help this organization. Why did you choose this strategy over others
Answer:
What i would suggest for the organization is to use the Testing Infrastructure strategy. it is good for your consulting firm because it is less costly and provide security.
Explanation:
Solution
There are different network security strategy which is listed below:
Segment the network:
Segmentation in network is very useful for providing security.If any threat is occur only one segment is effected remaining are safe and it is less cost process. very useful for small organizations.
Test your infrastructure :
Testing infrastructure also very good technique.
Always we have to test our infrastructure whether threat is occur or not.
If any threat is happen we can detect that easily by testing our infrastructure.
Regularly update anti-virus software :
This is very useful for small organizations and it is less cost.with less cost we can provide security for all devices like computer,server,modems etc.
Frequently backup your critical data :
This is very good technique for crucial data.If we backup important data any time that will be useful if any attack is happen.
This is less costs and simple.
Change router default security settings :
Changing router password and settings also helpful for providing security.If we maintain same password and same settings for a long time that may lead to data hacking.It is cost less process very useful for small organizations.
The performance of a client-server system is strongly influenced by two major network characteristics: the bandwidth of the network (how many bits/sec it can transport) and the latency (how many seconds it takes for the first bit to get from the client to the server). Give an example of a network that exhibits high bandwidth but also high latency. Also give an example of one that has both low bandwidth and low latency. Justify/explain your answers. (
Answer:
A bandwidth is the maximum rate of transfer of data across a given path
Latency refers to the delay of data to travel or move between a source and destination
An example of a high bandwidth and high latency network is the Satellite Internet connectivity.
An example of a low bandwidth and latency network is the telephone system connection.
Explanation:
Solution
Bandwidth: Bandwidth determines how fast data can be transferred for example, how many bits/sec it can transport.
Latency: It refers to the delay or how long it takes for data to travel between it's source and destination.
An example of a high bandwidth and high latency network is the Satellite internet connection.
Satellite internet connection: This is responsible for the connectivity of several systems, it has a high bandwidth, since satellite are in space, due to distance it has a high latency.
So, satellite internet connection is compensated with high latency and high bandwidth.
An example of a low bandwidth and low latency network is the Telephony network.
Telephone/telephony internet connection: This connection does not have much data for transfer. it has low size audio files of which a low bandwidth range. also for both end or end users to understand and talk to each other, it has low latency.
An example of a network that exhibits high bandwidth but also high latency is Satellite internet connection.
An example of one that has both low bandwidth and low latency is telephony internet connection.
Based on the provided information, we can say that Satellite internet connection posses high bandwidth but also high latency because, the fastness of data transfer is based on the bandwidth and how the data to travel between it's source and destination is based on its latency.
We can conclude that telephony internet connection has low bandwidth and low latency because of low data transfer is required.
Learn more about bandwidth at;
https://brainly.com/question/11408596
Describe any five GSM PLMN basic services?
Answer:
Your answer can be found in the explanation below.
Explanation:
GSM is the abbreviation for Global System for Mobile communication. Its purpose is to transmit voice and data services over a range. It is a digital cellular technology.
PLMN is the abbreviation for Public Land Mobile network. It is defined as the wireless communication service or combination of services rendered by a telecommunication operator.
The plmn consists of technologies that range from Egde to 3G to 4G/LTE.
PLMN consists of different services to its mobile subscribers or users but for the purpose of this question, i will be pointing out just 5 of them alongside its definitions.
1. Emergency calls services to fire or police: Plmn provides us with the option to make emergency calls in the event of any accident or fire incident, etc.It is available on devices either when locked or unlocked.
2. Voice calls to/from other PLMN: This entails the putting of calls across to persons we cannot reach very quickly. PLMN helps to connect persons through its network of from other networks thus making communication easier.
3. Internet connectivity: PLMN provieds us with internet services through wifi or bundles that enable us have access to the internet as well as help us communicate with people and loved ones over a distance. Internet service are possble either on GPRS or 3G or 4G networks.
4. SMS service: SMS means short messaging service. This is also know as text messages. PLMN allows us to be able to send short messages to people as oppposed to mails. It is mostly instant and can be sent or recieved from the same PLMN or others.
5. MMS service: Multimedia messaging service whose short form is MMS ccan be descibed as the exchange of heavier messages such as a picture or music or document but not from an email. It is availabel for use from one PLMN to another.
Cheers.
Given positive integer numInsects, write a while loop that prints that number doubled without reaching 100. Follow each number with a space. After the loop, print a newline. Ex: If numInsects = 8, print:
8 16 32 64
#include
using namespace std;
int main() {
int numInsects = 0;
numInsects = 8; // Must be >= 1
while (numInsects < 100) {
numInsects = numInsects * 2;
cout << numInsects << " ";
}
cout << endl;
return 0;
}
So my question is what am I doing wrong?
Answer:
The cout<<numInsects<<""; statement should be placed before numInsects = numInsects * 2; in the while loop.
Explanation:
Your program gives the following output:
16 32 64 128
However it should give the following output:
8 16 32 64
Lets see while loop to check what you did wrong in your program:
The while loop checks if numInsects is less than 100. It is true as numInsects =8 which is less than 100.
So the body of while loop executes. numInsects = numInsects * 2; statement in the body multiplies the value of numInsects i.e 8 with 2 and then cout << numInsects << " "; prints the value of numInsects AFTER the multiplication with 2 is performed. So 8 is not printed in output but instead 16 (the result of 8*2=16) is printed as the result of first iteration.
So lets change the while loop as follows:
while (numInsects < 100) {
cout << numInsects << " ";
numInsects = numInsects * 2;
Now lets see how it works.
The while loop checks if numInsects is less than 100. It is true as numInsects =8 which is less than 100
So the body of while loop executes. cout << numInsects << " "; first prints the value of numInsects i.e. 8. Next numInsects = numInsects * 2; multiplies the value of numInsects i.e 8 with 2. So first 8 is printed on the output screen. Then the multiplication i.e. 8*2=16 is performed as the result of first iteration. So now value of numInsects becomes 16.
Next the while loop condition numInsects < 100 is again checked. It is true again as 16<100. Now cout << numInsects << " "; is executed which prints 16. After this, the multiplication is again performed and new value of numInsects becomes 32 at second iteration. This is how while loops continues to execute.
So this while loop stops when the value of numInsects exceeds 100.