Define a method printAll() for class PetData that prints output as follows with inputs "Fluffy", 5, and 4444. Hint: Make use of the base class' printAll() method. Name: Fluffy, Age: 5, ID: 4444

Answer:

Enterprise software/system

Explanation:

Enterprise software which is also known as Enterprise Application Software (EAS) is computer software that its primary function is to meet the needs of an organization rather than that of an individual.

EAS or Enterprise System is the software development management tool that easily integrates into a business' enterprise software system.

Answer:

Here is the C program :

#include<stdio.h>  // to use input output functions

   int main(){  //start of main() function body

   int n;  //to store the number of tests taken

   int test_scores[n], i;  //a variable length array test_score

   float sum=0,average;  //to store the sum and average of test scores

   int lowest;   //to store the lowest test score

   printf("Enter the number of tests taken :");//prompts user to enter number of test scores

   scanf("%d",&n); /  / reads the value of n from user

   printf("Enter test scores: ");  //prompts user to enter test scores

for(i=0; i<n; i++)  {  

 scanf("%d",&test_scores[i]);  //read the values of input test scores

 sum = sum + test_scores[i];   } //calculates the sum of the test scores by adding the values of test scores

        average=sum/n;  // compute the average by dividing sum of all test scores with the total number of test scores

               printf("Average is %.2f",average);  //displays the average

    printf("\nGrade is ");  // prints Grade is

    if (average >= 90) {  //if value of average is greater than or equal to 90

       printf("A");     }  //print the grade letter A

else if(average >= 80 && average < 90)  { //if value of average is greater than or equal to 80 and less than 90

 printf("B");  }   //print the grade letter B

else if(average>60 && average<80){ //if value of average is between 60 and 80

 printf("C");  }  //print the grade letter C

else if(average>40 && average<=60) {  //if value of average is greater than 40 and less than or equals to 60

 printf("D");  }  //print the grade letter D

else  {  //if the value of average is below 40

 printf("F");  }   //print the grade letter F

   lowest = test_scores[0];     //lowest points to the 1st element of test scores means the first input test score

   for (int j = 1; j < n;j++)     {  //loop iterates through the scores

       if (test_scores[j] < lowest)   {  // if the element at j-th index position of test_scores array is less than the element stored in the lowest variable

          lowest = test_scores[j];     }     } //then assign that element value of test_score to the lowest

     printf("\nLowest test score is:  %d.\n", lowest); } //displays the lowest test score

Explanation:

The program is well explained in the comments mentioned with each statement of the code.

The program prompts the user to enter the number of test scores as they are not already specified in the array because array test_scores is a variable length array which means its length is not fixed. The program then prompts the user to enter the test scores. The program then adds all the test scores and store the result in sum variable. Then it computes the average by dividing the value in sum variable to the number of test scores n. Then in order to determine the letter Grade the average value is used. The if else conditions are used to specify conditions in order to determine the Grade. Next the lowest score is determined by setting the value of lowest variable to the first element of the test_scores array. Then using for loop, the index variable j moves to each array element i.e. score and determines if the the value of element is less than that stored in the lowest variable. If the value positioned at j-th index of test_scores is less than that of lowest than this value is assigned to lowest. At last the lowest holds the minimum of the test scores.

Answer:

2500 kb

Explanation:

Here, we are to calculate the bandwidth delay product

From the question, we are given that

band width = 500 Mbps

The bandwidth-delay product is = 500 x 10^6 x 25 x 10^-3

= 2500 Kbits

Answer and Explanation:

A BST is the short form for Binary Search Tree. It is a special type of binary tree data structure in which nodes are arranged in a particular order such that;

i. the left subtree of a particular node should always contain nodes whose key values are less than that of the key value of the node itself.

ii. the right subtree of a particular node should always contain nodes whose key values are greater than that of the key value of the node itself.

iii. the right and left subtrees should also be a binary search tree.

For the given set of data:

36,22,10,44,42,16,25,3,23,24;

The equivalent binary search tree is attached to this response.

As shown in the attachment:

i. the first data value (36) is the root node value.

ii. the second value (22) is less than the root node value (36), therefore, 22 goes to the left of the root node.

iii. the third value is 10. This is less than 36 and then also less than 22, so 10 goes to the left of 22.

iv. the fourth value is 44. This is greater than the root node value (36), therefore, 44 goes to the right of the root node.

v. the fifth value is 42. This is greater than the root value (36) so it is going to be positioned somewhere at the right of the root node. But it is less than the value (44) of the direct right node of the root node. Therefore, 42 goes to the left of the direct right (44) of the root node.

vi. the sixth value is 16. This is less than the root node value (36). So it is going to be positioned somewhere at the left of the root node. It is also less than the value (22) of the direct left node of the root node. So it is going to be positioned somewhere at the left of the node with 22. But it is greater than the node with 10. Therefore, 16 is going to be to the right of the node with 10.

This trend continues until all data values have been rightly positioned.

PS: A binary tree is a data structure in which each node cannot have more than two nodes directly attached to it.

Answer:

10 minutes

Explanation:

Answer:

I am writing a Python program.

def concordance(filename):  # function that takes a file name as parameter and returns the concordance for that file

   file = open(filename,"r")  #opens file in read mode

   unique={}  #creates and empty list

   for word in file.read().split():  #loops through every word in the file

       if word in unique:  # if words is already present in the list

           unique[word] += 1  #add 1 to the count of the existing word

       else:    #if word is not present in the list

           unique[word] = 1 #add the word to the list and add 1 to the count of word

           file.close();  # close the file

   for x in sorted(unique):  #sort the list and displays words with frequencies

       print(x, unique[x]);  #prints the unique words and their frequencies in alphabetical order

#prompts user to enter the name of the file

file_name=input('Enter the input file name: ')

concordance(file_name)  #calls concordance method by passing file name to it

Explanation:

The program has a function concordance that takes a text file name as parameter and returns a list of unique words and their frequencies.

The program first uses open() method to open the file in read mode. Here "r" represents the mode. Then creates an empty list named unique. Then the for loop iterates through each word in the file. Here the method read() is used to read the contents of file and split() is used to return these contents as a list of strings. The if condition inside the loop body checks each word if it is already present in the list unique. If the word is present then it adds 1 to the count of that word and if the word is not already present then it adds that unique word to the list and assign 1 as a count to that word. close() method then closes the file. The second for loop for x in sorted(unique):  is used to display the list of unique words with their frequencies. sorted() method is used to sort the list and then the loop iterates through each word in the list, through x, which acts like an index variable, and the loop displays each word along with its frequency.

Answer:

System.gc()

Explanation:

System.gc() can be defined as the method which can be used to effectively request for garbage collection because they runs the garbage collector, which in turn enables JMV which is fully known as JAVA VIRTUAL MACHINE to claim back the already unused memory space of the objects that was discarded for quick reuse of the memory space , although Java virtual machine often perform garbage collection automatically.

Answer:

Baselines

Explanation:

The idea of software configuration management is that of monitoring and controlling changes in the software. The baseline is the standard and formally accepted form of a software item that is meant to be configured. It is like a generally accepted reference point, which could be applied in effecting incremental changes in the software.

There are three types of baselines which are the functional, developmental, and product baselines. Functional baselines provide an overview of the functionality and specifications of a system. The product baseline encompasses both the functional and physical details of the system.

Answer:

The program written in Python is as follows

def fibonac(N):

    series = ""

    for i in range(0,N+1):

         series = series + str(i) + ","

   return series[:-1]

N = int(input("Number: "))

print(fibonac(N))

Explanation:

This line defines the function fibonac

def fibonac(N):

This line initializes variable "series" to an empty string

    series = ""

This line iterates through the passed argument, N

    for i in range(0,N+1):

This line determines the Fibonacci sequence

         series = series + str(i) + ","

Lastly, this line returns the Fibonacci sequence

   return series[:-1]

The main starts here

The firs line prompts user for input

N = int(input("Number: "))

This line prints the Fibonacci sequence

print(fibonac(N))

Answer:

The correct answer will be "Virtual networks".

Explanation:

Explanation:

bottom [20, 20, 17, 11, 8, 8, 3, 21 top the following stack is not sorted (the 15 is out of place), so passing it to your method should return a result of false: bottom [18, 12, 15, 6, 11 top an empty or one-element stack is considered to be sorted. when your method returns, the stack should be in the same state as when it was passed in. in other words, if your method modifies the stack, you must restore it before returning.

Answer:

c. rear = (rear + 1) % elements.length; elements[rear] = element;

Explanation:

In the above statement:

Name of the array is elements.

rear holds current index of elements array where current rear element of queue is stored. Front are rear are two open ends of the queue and the end from which the element is inserted into the queue is called rear.

element is the element that is required to enqueue into the queue

Enqueue basically mean to add an element to a queue.

Here it is assumed that the queue is not full. This means an element can be added to the queue.

It is also assumed that code also correctly increments numElements.

rear = (rear + 1) % elements.length; This statement adds 1 to the rear and takes the modulus of rear+1 to the length of the array elements[]. This statement specifies the new position of the rear.

Now that the new position of rear is found using the above statement. Next the element can be enqueued to that new rear position using the following statement:

elements[rear] = element; this statement sets the element at the rear-th (new position) index of elements[] array.

For example we have a queue of length 5 and there are already 4 elements inserted into this queue. We have to add a new element i.e. 6 to the queue. There are four elements in elements[] array and length of the array is 5 so this means the queue is not full. Lets say that rear = 3

elements.length = 5

rear = 3

Using above two statements we get.

rear = (rear + 1) % elements.length;

       = 3 + 1 % 5

       = 4%5

      =  4

This computes the new position of rear. So the new position of rear is the 4-th index of elements[]. Now next statement:

elements[rear] = element;

elements[4] = 6

This statement adds element 6 to the 4-th index of elements[] array.

Thus the above statement enqueues element (element 6 in above example) into the queue.

Answer:

Following are the answer to this question:

Explanation:

The server would be generally a powerful processor instead of a desktop pc. It must choose the Dell server browser to choose a server for industrial applications.

Answer:

I am writing  a JAVA program. Let me know if you want this program in some other programming language.

import java.util.Scanner;  // class to take input from user

class EvenOddNum{  //class name

   static void EvenOdd(int array[]) {  //function that takes an array as input and displays number of even numbers and odd numbers

       int even = 0;  // counts even numbers      

       int odd = 0;   //counts odd numbers

       for(int i = 0 ; i < array.length-1 ; i++){  //loop through the array elements till the second last array element

           if ((array[i] % 2) == 1) {  // if the element of array is not completely divisible by 2 then this means its an odd  number

               System.out.println(array[i]+" = odd");  //display that element to be odd

               odd++ ; }  //adds 1 to the count of odd every time the program reads an odd number

           else{  // if above IF condition evaluates to false then the number is an even number

                System.out.println(array[i]+" = even"); //display that element to be odd

                even++ ; } }  //adds 1 to the count of odd every time the program reads an odd number

       System.out.println( "Number of even numbers = " + even);  //counts the total number of even integers in the array

       System.out.println( "Number of odd numbers = " + odd);    }   //counts the total number of odd integers in the array      

   public static void main (String[] args){  //start of main function body

       Scanner scan= new Scanner(System.in); //creates Scanner class object

       int [] integers = new int[10];  //declares an array named integers that stores 10 integers

       System.out.print("Enter numbers: ");  //prompts user to enter the integers

       for(int i = 0;i<integers.length;i++){  //loops to read the input integers

           integers[i] = scan.nextInt(); }  //scans and reads each integer value

       EvenOdd(integers);    } }  //calls function EvenOdd to display number of even and odd numbers

Explanation:

The program has a method EvenOdd that takes an array of integers as its parameter. It has two counter variables even and odd. even counts the number of even input integers and odd counts the number of odd input integers. The for loop iterates through each element (integer) of the array except for the last one. The reason is that it is assumed that the input ends with 0 so the last element i.e. 0 is not counted. So the loop iterates to length-1 of the array. The number is odd or even is determined by this if condition: if ((array[i] % 2) == 1) A number is even if it is divisible by 2 otherwise its odd. If the element of array is not completely divisible by 2 i.e. the remainder of the division is not 0 then the number is odd. The modulo operator is used which returns the remainder of the division of number by 2. Each time when an odd or even number is determined, the array[i]+" = even" or  array[i]+" = odd" is displayed on the output screen for each integer in the array. Here array[i] is the element of the array and even or odd depicts if that element is even or odd. The last two print statement display the total number of even and odd numbers in the array.

Answer:

nxlskshwhhwwlqlqoejebx znznxjslaa

Answer:

Please see below

Explanation:

Suppose N = 10. And you have these dots equidistant from each other, and probability = 0.3. According to the data provided in the question statement, we will then have forty-five pairs of points. The task is to draw lines amongst these pairs, all 45 of them, with a 30% probability. Keep in mind that every one of the 45 lines are independent.

A few lines of simple code (just some for loops) needed to run this is attached in the image herewith, .

Answer: DIDN'T UNDERSTAND

Answer:

x(t) = −2 cos ( [tex]\frac{\pi }{4}t[/tex]  − [tex]\frac{\pi }{2}[/tex] ) + 4 cos ( [tex]\frac{5\pi }{4}t[/tex] )

Explanation:

Given:

Fundamental period of real valued continuous-time periodic signal x(t) = T = 8

Non-zero Fourier series coefficients for x(t) :

a₁ = [tex]a^{*}_{-1}[/tex] = j

a₅ = [tex]a_{-5}[/tex] = 2  

To find:

Express x(t) in the form

               ∞

x(t) =        ∑    A[tex]_{k}[/tex] cos ( w[tex]_{k}[/tex] t + φ[tex]_{k}[/tex] )

              [tex]_{k=0}[/tex]  

Solution:

Compute fundamental frequency of the signal:

w₀ = 2 π / T

     = 2 π / 8               Since T = 8

w₀  = π / 4

                   ∞

                    ∑ [tex]a_{k}e^{jw_{0}t }[/tex]

x(t) =          k=⁻∞

     =  [tex]a_{1}e^{jw_{0} t} + a_{-1}e^{-jw_{0} t} + a_{5}e^{5jw_{0} t}+a_{-5}e^{-5jw_{0} t}[/tex]  

     =  [tex]je^{j(\pi/4)t} - je^{-j(\pi/4)t} +2e^{(5\pi/4)t}+2e^{-(5\pi/4) t}[/tex]

     = −2 sin ( [tex]\frac{\pi }{4}t[/tex] ) + 4 cos ( [tex]\frac{5\pi }{4}t[/tex] )

     = −2 cos ( [tex]\frac{\pi }{4}t[/tex]  − [tex]\frac{\pi }{2}[/tex] ) + 4 cos ( [tex]\frac{5\pi }{4}t[/tex] )

Answer:

All team members

Explanation:

In respect of the question, the or those responsible for tracking the tasks in an agile team comprises of all the team members.

Agile in relation to task or project management, can be refer to an act of of division of project or breaking down of project or tasks into smaller unit. In my opinion, these is carried out so that all team members can be duly involved in the tasks or project.

Answer:

Decommission/Recycle

Explanation:

This specific scenario that is being described belongs to the final stage of the hardware lifecycle known as Decommission/Recycle. This is when the asset in question has completed its function for an extended period of time and is no longer functioning at maximum efficiency and/or newer hardware has hit the market. Once in this stage, the hardware in question is either repaired or scrapped for resources that can be used to create newer products.

Answer:

RAM is used to store programs and data the CPU needs. ROM has prerecorded data and is used to boot the computer

Explanation:

Answer:

sports = ["football", "basketball", "volleyball", "baseball", "swimming"]

last = sports[-3:]

print(last)

Explanation:

*The code is in Python.

Create a list called sports

Create a variable called last and set it to the last three elements of the sports list using slicing

Print the last

Answer:

customer service and support

Explanation:

-Loyalty programs for current customers refer to incentives companies provide to existing customers to encourage them to keep buying their products or services.

-Customer service and support refers to the assistance companies provide to their existing customers to help them solve issues or provide information about their current products or services and other options.

-Profitability for the company refers to actions that will increase the financial gains of the company.

-Acquisition of new customers refers to actions implemented to attract clients.

According to this, the answer is that this is a typical example of CRM that focuses on customer service and support because you call the company to get assistance with options to change your current products.

The other options are not right because the situation is not about incentives for the customer or actions the company implements to increase its revenue. Also, you are not a new customer.

Answer:

int ComputeFibonacci(int N) {

   if(N == 0)

       return 0;

   else if (N == 1)

       return 1;

   else

       return ComputeFibonacci(N-1) + ComputeFibonacci(N-2);

}

Explanation:

Inside the function ComputeFibonacci that takes one parameter, N, check the base cases first. If N is eqaul to 0, return 0. If N is eqaul to 1, return 1. Otherwise, call the ComputeFibonacci function with parameter N-1 and N-2 and sum these and return the result.

For example,

If N = 4 as in the main part:

ComputeFibonacci(4) → ComputeFibonacci(3) + ComputeFibonacci(2) = 2 + 1 = 3

ComputeFibonacci(3) → ComputeFibonacci(2) + ComputeFibonacci(1) = 1 + 1 = 2

ComputeFibonacci(2) → ComputeFibonacci(1) + ComputeFibonacci(0) = 1 + 0  = 1

*Note that you need to insert values from the bottom. Insert the values for ComputeFibonacci(1) and  ComputeFibonacci(0) to find ComputeFibonacci(2) and repeat the process.

Answer:

(A) Injection

Explanation:

SQL injection is one of the most common web attacks used by attackers to steal data or compromise a web application (especially the database) by inserting or "injecting" SQL queries or commands through the input data from the web application.

In web applications, form inputs are used to make requests to the database either for validation or submission of data by executing queries in the database. If these queries are interfered with by passing query like commands into the form input fields rather than some regular alphanumeric characters, then we have an SQL injection.

When this happens;

i. the attackers can modify an SQL query to return additional results from the database

ii. the attackers can change a query to interfere with the application's regular logic flow.

iii. the attackers can extract sensitive information about the database such as its version and structure.

Answer:

Following are the code to this question:

#include<stdio.h>//defining header file

int AND(int x,int y) //defining a method AND that hold two variable in its parameter

{

if(x==1 && y==1)//defining if block to check x and y value is equal to 1

{

return 1;//return value 1

}

else //defining else block

{

   return 0;//return value 0

}

}

int OR(int x,int y)//defining method OR that hold two variable in its parameter

{

if(x==0&&y==0)//defining if block to check x and y value is equal to 1

{

return 0;//return value 0

}

else //defining else block

{

   return 1;//return value 1

}

}

int main()//defining main method

{

int a,b,c;//defining integer variable  

int k=1;//defining integer variable k that holds a value 1

while(k<=8)//defining while loop for 8 time input

{

printf("Please insert 3 numbers in (0 0r 1):\n ");//print message

scanf("%d%d%d", &a, &b, &c);//input value

k++;//increment the value of k by 1

printf("value: %d\n",AND(OR(a,b),c));

}

return 0;

}

Output:

please find the attachment.

Explanation:

In the above-given C language code two methods "AND and OR" is declared, holds two integer variable "x and y" in its parameters, inside the method a conditional it used that can be defined as follows:

Answer:

The start menu in windows 10 has similarities.

Explanation:The windows 10 is start menu and start screen. Installed windows 10 on a PC, the start button after windows appear start menu.Windows app you can access windows apps right the menu. click the left display all apps installed your personal computer. click right to open a window app NEWS,MAIL, or CALENDAR. POWER button at the bottom of the left side, and display the to shut down and restart.

Right click your account name at the top the menu.You add files explorer to taskbar.Simply click the option you needed

Answer:

Here is the next_number method:

def next_number(self): #method to return next number in the sequence

    temporary = self.back1 + self.back2 # adds previous number to next number and stores the result in a temporary variable

    self.back2 = self.back1 #Updates back2 with the former value of back1,

    self.back1 = temporary #update back1 with the new next item in the sequence.

    return temporary #

Explanation:

I will explain the working of the above method.

back1 = 1

back2 = 0

At first call to next_number()  method:

temporary = back1 + back2

                 = 1 + 0

temporary = 1

self.back2 = self.back1

self.back2 = 1

self.back1 = temporary

self.back1 = 1

return temporary

This return statement returns the value stored in temporary variable i.e. 1

Output: 1

back1 = 1

back2 = 1

At second call to next_number()  method:

temporary = back1 + back2

                 = 1 + 1

temporary = 2

self.back2 = self.back1

self.back2 = 1

self.back1 = temporary

self.back1 = 2

return temporary

This return statement returns the value stored in temporary variable i.e. 2

output: 2

back1 = 2

back2 = 1

At second call to next_number()  method:

temporary = back1 + back2

                 = 2 + 1

temporary = 3

self.back2 = self.back1

self.back2 = 2

self.back1 = temporary

self.back1 = 3

return temporary

This return statement returns the value stored in temporary variable i.e. 3

Output: 3

back1 = 3

back2 = 2

At second call to next_number()  method:

temporary = back1 + back2

                 = 3 + 2

temporary = 5

self.back2 = self.back1

self.back2 = 3

self.back1 = temporary

self.back1 = 5

return temporary

This return statement returns the value stored in temporary variable i.e. 5

Output: 5

back1 = 5

back2 = 3

At second call to next_number()  method:

temporary = back1 + back2

                 = 5 + 3

temporary = 8

self.back2 = self.back1

self.back2 = 5

self.back1 = temporary

self.back1 = 8

return temporary

This return statement returns the value stored in temporary variable i.e. 8

Output: 8

Calling next_number 5 times would print 1, 2, 3, 5, and 8.

The complete program along with its output is attached.