Answer: 3. Test the prototype against the design criteria.
Explanation: Dovnovan should test his prototype before anything eles to work out any kinks in the design and write down the problems, and build another one before telling others about the project
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Engineering Design:Question 10
Which option describes the engineering design process?
Select one:
1. A series of steps engineers use to identify constraints.
2. A series of steps engineers use to decide which solution is best.
3. A series of steps engineers use to test what they build.
4. A series of steps engineers use to solve problems.
Answer:
4. A series of steps engineers use to solve problems.
Explanation:
The process of engineering design is a sequence of procedures that engineers pursue to arrive at a solution to a specific problem. Most times the solution includes creating a product such as a computer code, which fulfills certain conditions or performs a function. If the project in-hand includes designing, constructing, and testing it, then engineers probably adopt the design process. Steps of the process include defining the problem, doing background research, specifying requirements, brainstorming solutions, etc.
When x = 10 ft, the crate has a speed of 20 ft/s which is increasing at 6 ft/s^2. Determine the direction of the crate's velocity and the magnitude of the crate's acceleration at this instant.
Answer:
The direction will be "39.8°". The further explanation is given below.
Explanation:
The equation will be:
⇒ [tex]y=\frac{x^2}{24}[/tex]
On differentiating the above, we get
⇒ [tex]\frac{dy}{dx}=\frac{2x}{24}[/tex]
[tex]=\frac{x}{12}[/tex]
On differentiating again, we get
⇒ [tex]\frac{d^2y}{dx^2}=\frac{1}{12}[/tex]
Demonstrate the radius of the path curvature .
⇒ [tex]\rho=\frac{[1+(\frac{dy}{dx})^2]^{\frac{3}{2}}}{\left | \frac{d^2y}{dx^2} \right |}[/tex]
[tex]=\frac{[1+(\frac{x}{12} )^2]^{\frac{3}{2}}}{\left |\frac{1}{12} \right |}[/tex]
[tex]=\frac{[1+(\frac{10}{12})^2]^{\frac{3}{2}}}{\frac{1}{12} }[/tex]
[tex]=26.4 \ ft[/tex]
On calculating the acceleration's normal component, we get
⇒ [tex]a_{n}=\frac{v^2}{\rho}[/tex]
[tex]=\frac{20}{26.4}[/tex]
[tex]=15.15 \ ft/s^2[/tex]
Magnitude,
⇒ [tex]a=\sqrt{a_{n}^2+a_{t}^2}[/tex]
[tex]=\sqrt{(15.15)^2+(6)^2}[/tex]
[tex]=16.29 \ ft/s^2[/tex]
The direction of crate velocity will be:
⇒ [tex]\phi=tan^{-1}(\frac{dy}{dx} )[/tex]
On putting the values, we get
[tex]=tan^{-1}(\frac{x}{12})[/tex]
[tex]=tan^{-1}(\frac{10}{12} )[/tex]
[tex]=39.8^{\circ}[/tex]
BE-40 What is a characteristic of a catamaran hull?
Planes at low speed
Tends to pitch in waves
A stable ride
Only recommended on calm inland waters
Answer:
A stable ride
Explanation:
A Catamaran hull is a form of sea craft invented by the Austronesian peoples, the invention of the Catamaran hull enabled these people to sail across the sea in their expansion to the islands of the Indian and Pacific Oceans. Catamaran has multiple hulls, usually two parallel hulls of equal size. This geometric feature gives the craft an increased stability because, it derives extra stability from its wide beam, in the place of a ballasted keel employed in a regular monohull sailboat. A Catamaran hull will require four times the force needed to capsize it, when compared to an equivalent monohull.
How a single force is resolved along the perpendicular axis acting an angle theta with horizontal?
Answer:
A single force, which is acting at angle θ from a horizontal axis, can be resolved into components which act along the perpendicular axis.
Consider the perpendicular axis x and y, where x represents the horizontal axis and y represents vertical axis.
The Force is resolved into 2 parts, one acts along x-axis and is represent by X. The other acts along y-axis and is represented by Y.
From the diagram we can see that the Force and its components X and Y makes up a right angles triangle, where θ is the angle from the x-axis
Find X:We know that:
cosθ = Base/Hypotenuse
cosθ = X/F
X = Fcosθ
Find Y:
We know that:
sinθ = Perpendicular/Hypotenuse
sinθ = Y/F
Y = Fsinθ
Relation of Force and its Components:
Force F can be represent by:
F = Fcosθ (along x-axis) + Fsinθ (along y-axis)
As they form a right angled triangle, we can use Pythagoras Theorem to show the relation between Force and its components.
Hypotenuse² = Base² + Perpendicular²
F² = X² + Y²
F² = (Fcosθ)² + (Fsinθ)²
[tex]F = \sqrt{(F\cos\theta)^2+(Fsin\theta)^2}[/tex]
Where θ can be found by using any of the trignometric functions.