decide which of the two given prices is the better deal and explain why. you can buy shampoo in a 5 ounce bottle for $4.89 or in a 15 ounce bottle for $10.29. what is the cost per ounce for each bottle

Answer:  b) Each sold the same number of vehicles

Step-by-step explanation:

This question is only asking for the quantity of vehicles (not the total amount earned) so we can disregard the second matrix and find the sum of each row in the first matrix.

Kelly: 8 + 2 + 6 = 16

Scott: 7 + 8 + 1 = 16

Mark: 10 + 4 + 2 = 16

The total number of vehicles sold by each person is the same

Answer:

[tex]508.68[/tex] [tex]in^{2}[/tex]

Step-by-step explanation:

[tex]\pi r^{2} (1/2)[/tex]

[tex](3.14)(18^{2})(1/2)[/tex]

[tex]12717/25 = 508.68[/tex]

Answer:

12x8+5=101/8

101/8-74/5

40/8=5

5x101=505

40/5=8

8x74=592

therefore 505/40-592/40=

-87/40=-2.175

Answer:

The correct answer would be 2.175

Step-by-step explanation:

i got it right :))

Refer to the provided image.

A triangle with one of its angles to be 90°. That is if a triangle has one right angle then the triangle is a right-angled triangle.

A right-angled triangle's hypotenuse is the longest side. It's the side that's on the opposite side of the right angle.

A leg of a right-angled triangle is the side that is adjacent to the right angle.

The height of the right-angled triangle when the hypotenuse is considered as the base is called the Altitude of the right-angled triangle.

Considering the definitions above label the figure accordingly.

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Answer:

Yes, they are consistent.

A 99​% confidence interval is consistent with a​ two-sided test with significance level alpha=0.01 because if a​ two-sided test with this significance level does not reject the null​ hypothesis, then the confidence interval does contains the value in the null hypothesis.

Step-by-step explanation:

Yes, they are consistent.

A 99​% confidence interval is consistent with a​ two-sided test with significance level alpha=0.01 because if a​ two-sided test with this significance level does not reject the null​ hypothesis, then the confidence interval does contains the value in the null hypothesis.

The critical values of the confidence level are equivalent to the critical values in the hypothesis test. In the case that the conclusion of the test is to not reject the null hypothesis, the test statistic falls within the acceptance region: its value is within the critical values of the two-sided test.

Then, it is also within the critical values of the confidence interval and the sample mean (or other measure) will be within the confidence interval bounds.

Answer:

  1

Step-by-step explanation:

The quadratic relation is a perfect square:

  y = (7x +3)²

so has one zero, where the factor is zero:

  7x +3 = 0

  7x = -3

  x = -3/7

_____

It is useful to have handy reference to the form of the square of a binomial:

  (a +b)² = a² +2ab +b²

Here, your first clue is that 49x² and 9 are both perfect squares: (7x)² and (3)². It is easy to check that the middle term is twice the product of these roots:

  2(7x)(3) = 42x . . . . matches the middle term

So, the given expression is equivalent to ...

  y = (7x +3)²

Answer:

option 2

Step-by-step explanation:

4^2=16/8=2.  4^2=16/16=1.  2-1=1

Answer:

[tex] m=\frac{y_2 -y_1}{x_2 -x_1} =\frac{0-800}{400-0}= -2[/tex]

And then we can find the y intercept using one point for example (0,800) and we have:

[tex] 800= -2*0+ b[/tex]

[tex] b= 800[/tex]

And our model would be:

[tex] y = -2x +800[/tex]

And the x intercept would be if y=0 then

[tex] 0 =-2x +800[/tex]

[tex] x =400[/tex]

x intercept =400 represent the value of x when y =0

y intercept = 800 represent the value of y when x =0

Step-by-step explanation:

We have the following points given:

(0, 800) and (400, 0)

If we want to find the x intercept and y intercept we need to remember that we need to set a linear model given by:

[tex] y=mx +b[/tex]

Where

[tex] m=\frac{y_2 -y_1}{x_2 -x_1} =\frac{0-800}{400-0}= -2[/tex]

And then we can find the y intercept using one point for example (0,800) and we have:

[tex] 800= -2*0+ b[/tex]

[tex] b= 800[/tex]

And our model would be:

[tex] y = -2x +800[/tex]

And the x intercept would be if y=0 then

[tex] 0 =-2x +800[/tex]

[tex] x =400[/tex]

x intercept =400 represent the value of x when y =0

y intercept = 800 represent the value of y when x =0

Answer:

And then we can find the y intercept using one point for example (0,800) and we have:

And our model would be:

And the x intercept would be if y=0 then

x intercept =400 represent the value of x when y =0

y intercept = 800 represent the value of y when x =0

Step-by-step explanation:

We have the following points given:

(0, 800) and (400, 0)

If we want to find the x intercept and y intercept we need to remember that we need to set a linear model given by:

Where

And then we can find the y intercept using one point for example (0,800) and we have:

And our model would be:

And the x intercept would be if y=0 then

x intercept =400 represent the value of x when y =0

y intercept = 800 represent the value of y when x =0

Step-by-step explanation:

Answer:

8,15 and 17 are Pythagorean triplets,the Pythagorean triplets of 15 are: (15,112 and113),(15,8 and 17),(15,20 and 25),(15,9and 12),(15,36 and 39)

Answer:

Step-by-step explanation:

If

[tex]a=m^2-n^2;\ b=2mn;\ c=m^2+n^2[/tex]

for m > n, then a, b, c make a Pythagorean triplet.

[tex]m^2-n^2=15\to(m-n)(m+n)=15\\\\(m-n)(m+n)=(3)(5)\to m-n=3\ \wedge\ m+n=5[/tex]

We have the system of equations:

[tex]\underline{+\left\{\begin{array}{ccc}m-n=3\\m+n=5\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad2m=8\qquad\text{divide both sides by 2}\\.\qquad\boxed{m=4}[/tex]

Substitute to the second equation:

[tex]4+n=5\qquad\text{subtract 4 from both sides}\\\boxed{n=1[/tex]

Therefore we have:

[tex]a=4^2-1^2=16-1=15\\b=2(4)(1)=8\\c=4^2+1^2=16+1=17[/tex]

[tex]2mn=15[/tex]  it's impossible, because 15 is not an even number.

[tex]m^2+n^2=15[/tex]

Let's consider all possible sums of two numbers resulting in 15.

We will check which of the numbers are perfect squares.

1 + 14

2 + 13

3 + 12

4 + 11

5 + 10

6 + 9

7 + 8

(Bold not perfect squares)

There are no two perfect squares among the listed pairs of numbers.

Other:

15, 112, 113

We know the Egyptian triangle with sides of length 3, 4, 5.

By modifying this Pythagorean triplet by multiplying by 3 we get:

(3)(3) = 9; (3)(4) = 12; (3)(5) = 15

By modifying this Pythagorean triplet by multiplying by 5 we get:

(5)(3) = 15; (5)(4) = 20; (5)(5) = 25

She will receive a lot more money because she is already retired from work already and will win as bit more money

Options:

The supplier products have a lower mean than claimed

The supplier is more accurate than they claimed

The supplier products have a higher mean than claimed

The supplier is less accurate than they have claimed

Answer:

The supplier is less accurate than they have claimed

Step-by-step explanation:

Confidence Interval for supplier claim, CI = (20.45, 21.05)

Confidence Interval for your claim, CI = (20.48, 21.02)

Calculate the mean of the Confidence Interval for the supplier's claim:

[tex]\bar{X_s} = \frac{20.45 + 21.05}{2} \\\bar{X_s} = \frac{41.50}{2}\\\bar{X_s} = 20.75[/tex]

Calculate the mean of the Confidence Interval for your claim :

[tex]\bar{X_y} = \frac{20.48 + 21.02}{2} \\\bar{X_y} = \frac{41.50}{2}\\\bar{X_y} = 20.75[/tex]

Both the supplier and you have the equal mean

Margin of Error by the supplier = 21.05 - 20.75 = 0.30

Margin of Error by you = 21.02 - 20.75 = 0.27

Since the margin of error for the supplier is more, you can conclude that the suppler is less accurate than they have claimed.

The question is incomplete! Complete question along with answer and step by step explanation is provided below.

Question:

Supplier claims that they are 95% confident that their products will be in the interval of 20.45 to 21.05. You take samples and find that the 95% confidence interval of what they are sending is 20.48 to 21.02. What conclusion can be made?

The supplier products have a lower mean than claimed

The supplier is more accurate than they claimed

The supplier products have a higher mean than claimed

The supplier is less accurate than they have claimed

Answer:

The margin of error reported by the supplier is greater as compared to the actual margin of error. A greater margin of error results in less accuracy.

Therefore, we can conclude that the supplier is less accurate than they have claimed.

Step-by-step explanation:

Supplier claims that they are 95% confident that their products will be in the interval of 20.45 to 21.05.

The mean is given by

Mean = (Upper limit + Lower limit)/2

Mean = (21.05 + 20.45)/2

Mean = (41.50)/2

Mean = 20.75

The margin of error in this case is

MoE = Upper limit - Mean

MoE = 21.05 - 20.75

MoE = 0.30

You take samples and find that the 95% confidence interval of what they are sending is 20.48 to 21.02.

The mean is given by

Mean = (Upper limit + Lower limit)/2

Mean = (21.02 + 20.48)/2

Mean = (41.50)/2

Mean = 20.75

The margin of error in this case is

MoE = Upper limit - Mean

MoE = 21.02 - 20.75

MoE = 0.27

As you can notice the margin of error reported by the supplier is greater as compared to the actual margin of error. A greater margin of error results in less accuracy.

Therefore, we can conclude that the supplier is less accurate than they have claimed.

Answer:

see below

Step-by-step explanation:

5x - 6y = 21

Let x = 0 and solve for y to find the y intercept

-6y = 21

Divide by -6

y = 21/-6 = -7/2

The y intercept is (0,-7/2)

5x - 6y = 21

Let y = 0 and solve for x to find the x intercept

5x = 21

Divide by 5

y = 21/5 = 21/5

The x intercept is (21/5,0)

Answer:

x=4.2 (x-intercept)

y=-3.5 (y-intercept)

Step-by-step explanation:

To find the x-intercept, we know that y=0. To find the y-intercept, we know that x=0. All we have to do is plug in 0 into either x or y to find the x-intercept and y-intercept.

X-intercept

5x-6(0)=21

5x-0=21

5x=21

x=4.2

Y-intercept

5(0)-6y=21

0-6y=21

-6y=21

y=-3.5

Answer:

Mean = 3x

Step-by-step explanation:

Mean = [tex]\frac{SumOfObservations}{No. OfObservations}[/tex]

Mean = [tex]\frac{x+2x+3x+4x+5x}{5}[/tex]

Mean = [tex]\frac{15x}{5}[/tex]

Mean = 3x

The mean, also known as the average of x, 2x, 3x, 4x, and 5x is 3x as per the concept of Simplifying.

To find the mean of x, 2x, 3x, 4x, and 5x, we need to add up all the values and divide by the total number of values.

In this case, we have five values.

Mean = (x + 2x + 3x + 4x + 5x) / 5

Simplifying the numerator:

Mean = (15x) / 5

Mean = 3x

Therefore, the mean of x, 2x, 3x, 4x, and 5x is 3x.

The mean, also known as the average, represents the central tendency of a set of values. In this case, the mean is 3x, which indicates that on average, the values x, 2x, 3x, 4x, and 5x are three times the value of x.

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Answer:

B and A

Step-by-step explanation:

So based on the facts given, we know that b and a both have the same abasolute value. It does not matter whether a or b is negative or positive.

Answer:

11.42 boxes

Step-by-step explanation:

For the first box bought, there is a 100% chance of getting a unique toy (since you still don't have any). E₁ = 1.

After that, there is a 4 in 5 chance of getting a unique toy from the next box, the expected number of boxes required is:

[tex]E_2 = (\frac{4}{5})^{-1} = 1.25[/tex]

For the next unique toy, there is now a 3 in 5 chance of getting it:

[tex]E_3 = (\frac{3}{5})^{-1} = 1.67[/tex]

Following that logic, there is a 2 in 5 chance of getting the 4th unique toy:

[tex]E_4 = (\frac{2}{5})^{-1} = 2.5[/tex]

Finally, there is a 1 in 5 chance to get the last unique toy:

[tex]E_5 = (\frac{1}{5})^{-1} = 5[/tex]

The expected number of boxes to obtain a full set is:

[tex]E=E_1+E_2+E_3+E_4+E_5\\E=1+1.25+1.67+2.5+5\\E=11.42\ boxes[/tex]

113/32

Step-by-step explanation:

7 squared is 49, 4 cubed is 64, 2 to the 5th power is 32.

49 plus 64 is 113 divided by 32

3.53125

Step-by-step explanation:

7^2+4^3/2^5

= 49+64/32

= 113/32

= 3.53125

Solution,

Radius=2 m

Area =pi r^2

= 3.142*(2)^2

=12.568 m^2

hope it helps

Good luck on your assignment

Options:

(A)x = StartFraction 6 over 4 EndFraction

(B)x = Negative StartFraction 6 over 4 EndFraction

(C)x minus one-fourth = negative StartFraction 5 over 4 EndFraction

(D)x = negative three-halves

(E)x = negative three-fourths

Answer:

(B)x = Negative StartFraction 6 over 4 EndFraction

[tex]-\dfrac{6}{4}[/tex]

(D)x = negative three-halves

[tex]-\dfrac{3}{2}[/tex]

Step-by-step explanation:

We want to determine which fraction is equivalent to

[tex]\dfrac{1}{4}+x=-\dfrac{5}{4}\\$First, we collect like terms$\\x=-\dfrac{5}{4}-\dfrac{1}{4} \\\\=\dfrac{-5-1}{4}\\=-\dfrac{6}{4}\\x=-\dfrac{6}{4}[/tex]

This value of x is the result in Option B.

Reducing [tex]-\dfrac{6}{4}[/tex] to its lowest form:

[tex]-\dfrac{6}{4}=-\dfrac{3}{2}[/tex] which is Option D.

Therefore, the correct options are: B and D

Answer:one lakh....

Step-by-step explanation:I don't say u must have to mark my ans as brainliest but if it has really helped u plz don't forget to thnk me...

Answer:

1 Lakh = 100 Thousands

Step-by-step explanation:

Answer:

The question is not clear.

Step-by-step explanation:

Normally it helps to rewrite 8 as

8 = 2 * 2 * 2 = 2³

However the question is not clear.

There are no following expressions given...

By 2X^2 +8,

do you mean 2*x² + 8, or do you mean 2*x^(2 + 8)

or did you perhaps mean 2^(x+8)

Next time, please add a picture.

Answer:

(2x-4i)(x+2i)

Answer:

The probability that at least 13 flights arrive late is 2.5196 [tex]\times 10^{-6}[/tex].

Step-by-step explanation:

We are given that Southwest Air had the best rate with 80 % of its flights arriving on time.

A test is conducted by randomly selecting 18 Southwest flights and observing whether they arrive on time.

The above situation can be represented through binomial distribution;

[tex]P(X = x) = \binom{n}{r}\times p^{r} \times (1-p)^{n-r} ; x = 0,1,2,3,.........[/tex]

where, n = number of trials (samples) taken = 18 Southwest flights

           r = number of success = at least 13 flights arrive late

          p = probability of success which in our question is probability that

                flights arrive late, i.e. p = 1 - 0.80 = 20%

Let X = Number of flights that arrive late.

So, X ~ Binom(n = 18, p = 0.20)

Now, the probability that at least 13 flights arrive late is given by = P(X [tex]\geq[/tex] 13)

P(X [tex]\geq[/tex] 13) = P(X = 13) + P(X = 14) + P(X = 15) + P(X = 16) + P(X = 17) + P(X = 18)

= [tex]\binom{18}{13}\times 0.20^{13} \times (1-0.20)^{18-13}+ \binom{18}{14}\times 0.20^{14} \times (1-0.20)^{18-14}+ \binom{18}{15}\times 0.20^{15} \times (1-0.20)^{18-15}+ \binom{18}{16}\times 0.20^{16} \times (1-0.20)^{18-16}+ \binom{18}{17}\times 0.20^{17} \times (1-0.20)^{18-17}+ \binom{18}{18}\times 0.20^{18} \times (1-0.20)^{18-18}[/tex]

= [tex]\binom{18}{13}\times 0.20^{13} \times 0.80^{5}+ \binom{18}{14}\times 0.20^{14} \times 0.80^{4}+ \binom{18}{15}\times 0.20^{15} \times 0.80^{3}+ \binom{18}{16}\times 0.20^{16} \times 0.80^{2}+ \binom{18}{17}\times 0.20^{17} \times 0.80^{1}+ \binom{18}{18}\times 0.20^{18} \times 0.80^{0}[/tex]

= 2.5196 [tex]\times 10^{-6}[/tex].

Answer:

[tex] X= v_i t + \frac{1}{2}a t^2 [/tex]

And from this equation we can solve for a like this:

[tex] 205m = 3.5m/s *(28.7s) +\frac{1}{2}a (28.7s)^2[/tex]

And solving for a we got:

[tex] 104.55m = \frac{1}{2}a (28.7s)^2[/tex]

[tex] a = \frac{2*104.55m}{(28.7s)^2)}= 0.254 m/s^2[/tex]

Step-by-step explanation:

For this case we have the velocity , distance and time given:

[tex] v = 3.5 m/s, d=205m, t =28.7s[/tex]

And we know from kinematics that he velocity can be expressed like this:

[tex] v_f = v_i +a t[/tex]

We also know that the distance is given by:

[tex] X= v_i t + \frac{1}{2}a t^2 [/tex]

And from this equation we can solve for a like this:

[tex] 205m = 3.5m/s *(28.7s) +\frac{1}{2}a (28.7s)^2[/tex]

And solving for a we got:

[tex] 104.55m = \frac{1}{2}a (28.7s)^2[/tex]

[tex] a = \frac{2*104.55m}{(28.7s)^2)}= 0.254 m/s^2[/tex]

Answer:

Option (2). None

Step-by-step explanation:

A quadrilateral ABCD has been given with a property,

m∠7 = m∠4

Option (1). AB║ DC

For AB║DC, angle 7 and angle 3 should measure the same.

(By the property of alternate angles)

Therefore, by the given property we can not deduce AB║DC.

Option (3). AD║BC

For AD║BC, angle 7 and angle 3 must be equal in measure.

(By the property of alternate angles)

Therefore, by the given property we can not deduce AD║DC

Option (2). None will be the answer.

Answer:

The probability that at least one of the children get the disease from their mother is 0.7125.

Step-by-step explanation:

We are given that a human gene carries a certain disease from the mother to the child with a probability rate of 34%.

Suppose a female carrier of the gene has three children. Assume that the infections of the three children are independent of one another.

Let Probability that children get the disease from their mother = P(A) = 0.34

SO, Complement of the event "At least one of the children get the disease from their mother"= P(A') = 1 - P(A)

where A' = event that children do not get the disease from mother.

So, P(A') = 1 - P(A) = 1 - 0.34 = 0.66

Now, probability that at least one of the children get the disease from their mother = 1 - Probability that none of the three children get disease from their mother

                     = 1 - P(X = 0)

                     = 1 - (0.66 [tex]\times[/tex] 0.66 [tex]\times[/tex] 0.66)

                     = 1 - 0.2875 = 0.7125

Answer:

Step-by-step explanation:

The objective is to  Show that if the set of images {T(v1)......T(vp)} is linearly dependent, then {v1......vp} is linearly dependent.

Given that:

[tex]\mathbf{[T(v_1) +T(v_2) ...T(v_p)]}[/tex] is linearly dependent set

Thus; there exists scalars [tex]\mathbf{k_1 , k_2 ... k_p}[/tex] ; ( read as "such that")  [tex]\mathbf{k_1 T(v_1) +k_2T(v_2) ...k_pT(v_p)=0}[/tex]

[tex]\mathbf{= T(k_1 v_1 +k_2v_2 ...k_pv_p)=0}[/tex]

T = 0                                  (for the fact that T is linear transformation)

[tex]\mathbf{k_1 v_1 +k_2v_2 ...k_pv_p=0}[/tex]     (due to T is one-one)

NOTE: Not all Ki's are zero;

Thus;

[tex]\mathbf{[v_1,v_2 ...v_p] }[/tex]  is linearly dependent

It negation also illustrates that :

If [tex]\mathbf{[v_1,v_2 ...v_p]}[/tex] is also linearly independent then [tex]\mathbf{[T(v_1),T(v_2) ...T(v_p)]}[/tex] is also linearly independent.

Answer:

Step-by-step explanation:

if N=2.0

4.9 N=4.9×2=9.8

9.8/1.4=7

which is an integer.

so N=2.0

Answer:

252

Step-by-step explanation:

The order of the books isn't important, so we'll use combinations.

The number of ways to choose 5 books from 10 is:

₁₀C₅ = 10! / (5! (10 − 5)!)

₁₀C₅ = 10! / (5! 5!)

₁₀C₅ = 10×9×8×7×6 / (5×4×3×2×1)

₁₀C₅ = 252

Answer:

8.80$

Step-by-step explanation:

Total 20.20. 6.06 x 2=12.12. 20.20-12.12=8.80$

Mathew paid 8.80$

Clarence paid 12.12$

Daniel paid 6.06$

Answer:

w || n and n ⊥ m

Step-by-step explanation:

To find out which statement is true, recall the following:

1. 2 lines are said to be parallel to each other if they do not intersect at any given point and are of the same distant apart. Parallel is denoted by ||

2. 2 lines are said to be perpendicular if both lines intersect at a right angle. It is denoted by ⊥

==>From the diagram given, we can see that w and n are of the same distant apart and they do not intersect at any given point.

Also, we can see that n and m intersect at point X to at right angle.

Therefore, we can conclude that w || n and n ⊥ m