Cyclohexane (C6H12) is found in gasoline. It is burned for fuel in a combustion reaction. The unbalanced combustion reaction for octane is shown below. C6H12 + O2 + CO2 + H2O + heat When the reaction is balanced, how many carbon dioxide molecules are produced for every cyclohexane molecule burned? O A1 O B. 9 O c. 6 O D. 3​

Answer:

14.4g

Explanation:

Answer:

The molecular formula for Potassium Carbonate is K2CO3. The SI base unit for amount of substance is the mole. 1 grams Potassium Carbonate is equal to 0.0072356020563581 mole. Note that rounding errors may occur, so always check the results.

Explanation:

The molecular formula for Potassium Carbonate is K2CO3. The SI base unit for amount of substance is the mole. 1 grams Potassium Carbonate is equal to 0.0072356020563581 mole.

Answer:

Explanation:

The number of molecules can be found by using the formula

N = n × L

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

We have

N = 4.67 × 6.02 × 10²³

We have the final answer as

Hope this helps you

Answer:

2.13 M

Explanation:

To solve this problem we need to keep in mind the definition of molarity:

As the problem gives us both the number of moles and the volume of solution, we can proceed to calculate the molarity:

The answer is 2.13 M.

Answer:

Relative atomic mass

Explanation:

The heat of reaction for the reaction 2H₂O₂ → 2H₂O +O₂ is -196 KJ

From the question, we are to calculate the heat of reaction for the reaction

2H₂O₂ → 2H₂O +O₂               ∆H=?

Using Hess's law

Hess's Law of constant heat summation states that regardless of the multiple stages or steps of a reaction, the total enthalpy change for the reaction is the sum of all changes

From the given equations,

2H₂ +O₂ → 2H₂O                   ∆H= -572 KJ ---------- (1)

2H₂O₂ → 2H₂ + 2O₂              ∆H= 376 KJ ----------- (2)

Adding equations (1) and (2), we get

2H₂O₂ → 2H₂O +O₂               ∆H= -572 KJ + 376 KJ

2H₂O₂ → 2H₂O +O₂               ∆H= -196 KJ

Hence, the heat of reaction for the reaction 2H₂O₂ → 2H₂O +O₂ is -196 KJ.

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The elemental particles like the atoms, molecules and compounds present in a given substance is called an Avogadro's number. This number is expressed as [tex]N_{A}[/tex] and is equal to [tex]6.022 \times 10^{23} \;\rm mol^{-1}[/tex].

[tex]8.06 \times 10 ^{23}[/tex] molecules are present in 135 g of Teflon [tex]\rm C_{2}F_{4}[/tex].

Given,

We have 135 g, so moles will be:

[tex]\begin{aligned}\rm Moles (n) &=\dfrac{ \rm Mass }{\;\rm Molar \;\rm mass}\\\\\rm n &= \dfrac{135 \rm g }{100.02 \rm g/mol} \\\\\rm n &= 1.34 \;\rm mole\end{aligned}[/tex]

Hence,

1 mole contains [tex]6.022140857 \times 10^{23}[/tex] (Avogadro's number)

So 1.34 moles will contain,

[tex]\begin{aligned}&=1.34 \times 6.022140857 \times 10^{23}\\\\&= 8.06 \times 10 ^{23}\;\rm molecules\end{aligned}[/tex]

Therefore, [tex]8.06 \times 10 ^{23}[/tex] molecules are present in 135 g of Teflon [tex]\rm C_{2}F_{4}[/tex].

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Explanation:

HCL you can do it yourself .try again

Answer:

4NH3 + 3O2 → 2N2 + 6H2O

a. 2 moles

b. 4 moles

c. 3 moles

Explanation:

a. 4 mol NH3

4NH3 + 3O2 → 2N2 + 6H2O

  4      :     3    :    2     :    6

  4                                        (mol)

⇒[tex]n_{N2}[/tex] = 4 × 2 ÷ 4 = 2

b. 4 mol N2

c. 4.5 mol O2

4NH3 + 3O2 → 2N2 + 6H2O

4      :     3    :    2     :    6

           4.5                          (mol)

⇒[tex]n_{N2}[/tex] = 4.5 × 2 ÷ 3 = 3

Answer:

Potassium phosphide (K3P)

[tex]\text{N}_{2}\text{O}_{3}=\text{nitrogen trioxide}\\\text{N}_{2}=\text{nitrogen}\\\text{O}_{2}=\text{oxygen}[/tex]

Answer:

108 g

Explanation:

First we convert 6.00 moles of H₂ into moles of H₂O, using the stoichiometric coefficients of the reaction:

Then we can convert 6.00 moles of H₂O into grams, using the molar mass of water:

The answer is 108 grams of water.

Answer:

Explanation:

The atomic number of uranium (see periodic table) is 92, and the mass number of the isotope is given as 238. Therefore, it has 92 protons, 92 electrons, and 238 — 92 : 146 neutrons

Uranium has an atomic number of 92. There are 146 neutrons, 92 protons, and 92 electrons in 238U+5. The number of neutrons can vary from 141 to 146.

Chemical element uranium has the atomic number 92 and the letter U. It is an actinide metal in the periodic table's silvery-gray series. There are 92 protons and 92 electrons in an atom of uranium, of which 6 are valence electrons.

Since uranium has an atomic number of 92, its atomic structure consists of 92 protons and 92 electrons. The nucleus of U-238 contains 146 neutrons, but this number can range from 141 to 146.

With 92 protons and 146 neutrons, Uranium-238 is the heaviest element in nature. The overall mass and charge of the nucleus are 238 nucleons, or +92.

Thus, Uranium has an atomic number of 92. There are 146 neutrons, 92 protons, and 92 electrons in 238U+5.

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b. a positive cation and a negative anion

✏ Anions are negative in nature while cations are positive in nature. Together they come together by an attractive electrostatic force to form an ionic bond.

ʰᵒᵖᵉ ⁱᵗ ʰᵉˡᵖˢ

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Answer: Element is P, phosphor

Explanation:  Phosphor has oxidation number -III and it has 15 protons. So it is possible to have 16 neutrons. Other elements having oxidation number -III are N and As which can not have an isotope with 16 neutrons.

Answer:

mass of chlorine = 10.4 grams

Explanation:

Mass of the solution = 5.20 × 10⁶ g

ppm chlorine by mass = 2.00

Recall that:

[tex]ppm = \dfrac{mass \ of \ chorine \ gas (solute)}{ mass of the solution }\times 10^6[/tex]

[tex]2 = \dfrac{mass \ of \ chorine \ gas (solute)}{ 5.20\times 10^6}\times 10^6[/tex]

mass of chlorine = 5.20 × 2.0

mass of chlorine = 10.4 grams

Answer: 114.22852 grams

HOPE THIS HELPS

Answer:

-846 kJ

Explanation:

Using Henderson Hasselbach's law,

2Al + 3/2 O2 -> Al2O3    H = -1670 kJ

-(2Fe + 3/2 O2 -> Fe2O3) = Fe2O3 -> 2Fe + 3/2 O2    H = 824 kJ

-1670 kJ + 824kJ = -846 kJ

Answer: The element B will have ONE unpaired electron in the p orbital.

Explanation:

The electronic configuration of each given element is as follows.

Atomic number of calcium (Ca) is 20.

Ca: [tex]1s^{2} 2s^{2} 2p^{6} 3s^{2} 3p^{6} 4s^{2}[/tex]

Atomic number of nitrogen (N) is 7.

N: [tex]1s^{2} 2s^{2} 2p^{3}[/tex]

Atomic number of boron (B) is 5.

B: [tex]1s^{2} 2s^{2} 2p^{1}[/tex]

Atomic number of argon (Ar) is 18.

Ar: [tex]1s^{2} 2s^{2} 2p^{6} 3s^{2} 3p^{6}[/tex]

Atomic number of bromine (Br) is 35.

Br: [tex][Ar] 4s^{2} 3d^{10} 4p^{5}[/tex]

Therefore, boron is the only element that have one unpaired electron in the p-orbital.

Thus, we can conclude that element B will have ONE unpaired electron in the p orbital.

Answer:

No

Explanation:

Rust is an iron oxide, a usually reddish-brown oxide formed by the reaction of iron and oxygen in the catalytic presence of water or air moisture.

Solution :

Compound                      Ksp

[tex]$PbF_2$[/tex]                               [tex]$3.3 \times 10^{-8}$[/tex]

[tex]$Ni(CN)_2$[/tex]                        [tex]$3 \times 10^{-23}$[/tex]

FeS                                [tex]$8 \times 10^{-19}$[/tex]

[tex]$CaSO_4$[/tex]                           [tex]$4.93 \times 10^{-5}$[/tex]

[tex]$Mg(OH)_2$[/tex]                      [tex]$5.61 \times 10^{-12}$[/tex]

Ksp of [tex]$Ni(CN)_2 << Ksp \text{ of}\ \ Mg(OH)_2$[/tex] and both compounds dissociate the same way. Hence [tex]$Mg(OH)_2$[/tex] is more soluble than [tex]$(B). \ Ni(CN)_2$[/tex]

[tex]$Mg(OH)_2$[/tex]  is less soluble than [tex]$(A). \ \ PbF_2 \ ()Ksp \ PbF_2 > Ksp \ \text{ of } \ Mg(OH)_2$[/tex]

It is not possible to determine CD - [tex]$FeS \text{ or} \ CaSO_4$[/tex]  is more or less soluble than [tex]$Mg(OH)_2$[/tex]  as though they have a different Ksp values their molecular dissociation is also different and they may have a close solubility values.

[tex]$Ni(OH)_2$[/tex]  can be directly compared with PbS, [tex]$AlPO_4, MnS$[/tex]

[tex]$\text{For } \ Ni(OH)_2$[/tex]

[tex]$AB_2(s) \rightarrow A^{2+} + 2B^{-}$[/tex]

[tex]$Ni(OH)_2(s) \rightarrow Ni^{2+} + 2OH^-$[/tex]

100

1-s s 2s

Ksp = [tex][A2+][B-]^2 = s \times (2s)^2 = 4s^3[/tex]

Hence they can be directly compared by Ksp values, smaller the Ksp, smaller the solubility.

For Silver Chloride

[tex]$AB(s) \rightarrow A^{x+}+B^{x-}$[/tex]

[tex]$AgCl(s) \rightarrow Ag^+ + Cl^-$[/tex]

1 0 0

1 - s s s

Ksp [tex]$=[A^{x+}][B^{x-}]=s \times s = s^2$[/tex]

Hence, they can be directly compared by Ksp values, smaller the Ksp, smaller the solubility.

Answer:

1) some of the gas maybe metal but non metal directly refers it self to not begin metal

2) gases are present in only air . non metals are available in solid form too

Explanation:

Ionic product of water, Kw

[tex]Kw = [OH {}^{ - } ][H _{3} O {}^{ + } ] \\ 1.0 \times {10}^{ - 14} = (1 \times {10}^{ - 11} )[H _{3} O {}^{ + } ] \\ [H _{3} O {}^{ + } ] = \frac{(1.0 \times {10}^{ - 14}) }{(1 \times 10 {}^{ - 11}) } \\ ][H _{3} O {}^{ + } ] = 0.001 \: M[/tex]