A stone dropped freely from 72m height of
the tower and reaches the "ground on 6 seconds
calculate acceleration due to gravity of that stone
At what condition does the acceleration due to
gravity becomes Zero
When the initial velcity is 12 m/sec in that condition the acceleration due to gravity becomes Zero.
What is acceleration?The rate of change of velocity with respect to time is known as acceleration. According to Newton's second law, the eventual effect of all forces applied to a body is its acceleration.
The height from the stone drop,h= 72 m
t is the time period=6 sec
From Newton's second equation of motion;
[tex]\rm h = ut +\frac{1}{2} gt^2\\\\[/tex]
The condition does the acceleration due to gravity becomes Zero will be;
The gravitational acceleration is zero;
[tex]\rm h = ut +\frac{1}{2} \times 0t^2\\\\h=ut \\\\ 72 =6u \\\\ u= 12 m/sec[/tex]
Hence when the initial velcity is 12 m/sec in that condition the acceleration due to gravity becomes Zero.
To learn more about the acceleration refer to the link;
https://brainly.com/question/2437624