Could anyone answer this?

Answer:=6x3−9c

Step-by-step explanation:

3x3+4x2+3x3−4x2−9c

=3x3+4x2+3x3+−4x2+−9c

Combine Like Terms:

=3x3+4x2+3x3+−4x2+−9c

=(3x3+3x3)+(4x2+−4x2)+(−9c)

=6x3+−9c

Answer:

Step-by-step explanation:

-4x + 1 = -4x + 1

1 = 1

infinitely many solutions

Answer:

a)  The arithmetic sequence with common difference 2 that has 8 as the first term.

b) The arithmetic sequence of common difference -5 and first term 15.

Step-by-step explanation:

Let's use for example the arithmetic sequence with common difference 2 that has 8 as the first term. Then the first two terms of this sequence are:

8, and (8+2) = 10 Therefore the second term is 10.

Another arithmetic sequence of common difference -5 and first term 15. The firs two terms of this sequence are:

15, and  (15 - 5)  = 10. Therefore again a 10 as second term.

Answer:

a)73

b)27

c)58

d)70

Answer:

A = 60 cm^2

Step-by-step explanation:

The area of a parallelogram is

A = bh

A = 14*5

A = 60 cm^2

[tex] area \: of \: parallelogram \: = \: base \times height[/tex]

[tex] \: \: \: \: \: \: \: \: \: \: \: \: \: \: a \: \: \: \: \: \: \: \: \: \: \: \: = \: \: \: \: \: \: \: \: \: \: \: 14cm \times 5cm[/tex]

[tex]a \: \: \: \: \: \: \: \: \: \: \: \: \: = \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: 70 {cm}^{2} [/tex]

Answer:

The ratio will be 48/109

Step-by-step explanation:

Answer:

Distribute the 3

Step-by-step explanation:

order of operations mate

Answer:2

Step-by-step explanation: 15x5=75

75/26=2.886

Answer:

129

Step-by-step explanation:

120 +9 =129

because it is total and total means add

Answer:

True because there would be more understanding

Step-by-step explanation:

Answer:

                     FALSE

Step-by-step explanation:

                                        Drawing map takes  a while but verbal directions are quite simple and easy to understand

Hope it helps!

Answer:

2/3

Step-by-step explanation:

3/3 = 1 whole

3/3 - 1/3 = 2/3

Answer: 5 21/50

Step-by-step explanation: 5.42 = 271/50 = 521/50 as a fraction

Answer:

0.200

Step-by-step explanation:

∑ₓ₌₁⁴⁰ (1 + i)⁻ˣ = 5

∑ₓ₌₁⁴⁰ ((1 + i)⁻¹)ˣ = 5

This is a geometric series.  The sum of the first n terms of a geometric series is:

S = a₁ (1 − rⁿ) / (1 − r)

where a₁ is the first term and r is the common ratio.

Here, a₁ = (1 + i)⁻¹, r = (1 + i)⁻¹, and n = 40.  For simplicity, let's write both a₁ and r in terms of r.  So a₁ = r and r = r.

5 = r (1 − r⁴⁰) / (1 − r)

5 (1 − r) = r (1 − r⁴⁰)

5 − 5r = r − r⁴¹

r⁴¹ − 6r + 5 = 0

Solving with a calculator, r ≈ 0.8334.

Therefore:

(1 + i)⁻¹ = 0.8334

1 + i = 1.200

i = 0.200

Answer:

A=1.75

Step-by-step explanation:

[tex]10a + 6a = 21 + 7 \\ 16a = 28 \\ divide \: both \: sides \: by \: 16 \\ a = 1.75 \: or 1 \ \frac{3}{4} [/tex]

Answer:

a = 7/4

Step-by-step explanation:

10a -7 = 21 - 6а​

Add 6a to each side

10a+6a -7 = 21 - 6а+6a

16a -7 = 21

Add 7 to each side

16a+7-7=21+7

16a = 28

Divide each side by 16

16a/16 = 28/16

a = 7/4

You cannot divide any number by zero since it is meaningless to say that we are dividing a number or object in zero groups or in 0 size parts

Answer:

203

Step-by-step explanation:

Square of 101 = 101^2= 10201

Square of 102 = 102 ^2=10404

No. of numbers between both of them =10404-10201=203

Answer:

203

Step-by-step explanation:

✓101 kare = 10.201

✓102 kare = 10.404

✓ 10.404- 10.201 = 203

#Başarılar

#Türkiye

Answer:

The formula of area is Pi×R×R

and then you add all sides and answer of your question is 30cm

Answer:

a = 28

Step-by-step explanation: First you would have to multiply 7 x 8 which equals =56. Then you would have to divide 56 by 2 which is =28 and that would be your area if you are solving for a triangle.

Answer:

A. 280degree

B. 137degree

Answer:

on [3, 4] = 0.30

on [4, 5] = 0.18

on [5, 6] = 0.12

Step-by-step explanation:

The average rate of change f, of a function f(x) on an interval [a, b] is given by;

[tex]f = \frac{f(b) - f(a)}{b - a}[/tex]              -------------(i)

In our case,

f(x) = log 2(3x - 6)

Now let's get the average rate of change of f(x) on;

(i) [3, 4]

Here, a = 3 and b = 4

f(a) = f(3)        [This is f(x) at x = 3]

=> f(3) = log[2(3(3) - 6)]

=> f(3) = log[2(9 - 6)]

=> f(3) = log[2(3)]

=> f(3) = log[6]

Also,

f(b) = f(4)        [This is f(x) at x = 4]

=> f(4) = log[2(3(4) - 6)]

=> f(4) = log[2(12 - 6)]

=> f(4) = log[2(6)]

=> f(4) = log[12]

Now substitute the values of a, b, f(a) and f(b) into equation (i) as follows;

[tex]f = \frac{log 12 - log 6}{4 - 3}[/tex]             [Remember that log m - log n = log (m / n)]

[tex]f = \frac{log (12 / 6)}{4 - 3}[/tex]

[tex]f = \frac{log (2)}{1}[/tex]

f = log 2 = 0.3010

f = 0.30          [to two decimal places]

∴ The average rate of change on [3, 4] = 0.30

(ii) [4, 5]

Here, a = 4 and b = 5

f(a) = f(4)        [This is f(x) at x = 4]

=> f(4) = log[2(3(4) - 6)]

=> f(4) = log[2(12 - 6)]

=> f(4) = log[2(6)]

=> f(4) = log[12]

Also,

f(b) = f(5)        [This is f(x) at x = 5]

=> f(5) = log[2(3(5) - 6)]

=> f(5) = log[2(15 - 6)]

=> f(5) = log[2(9)]

=> f(5) = log[18]

Now substitute the values of a, b, f(a) and f(b) into equation (i) as follows;

[tex]f = \frac{log 18 - log 12}{5 - 4}[/tex]             [Remember that log m - log n = log (m / n)]

[tex]f = \frac{log (18 / 12)}{5 - 4}[/tex]

[tex]f = \frac{log (1.5)}{1}[/tex]

f = log 1.5 = 0.176

f = 0.18          [to two decimal places]

∴ The average rate of change on [4, 5] = 0.18

(iii) [5, 6]

Here, a = 5 and b = 6

f(a) = f(5)        [This is f(x) at x = 5]

=> f(5) = log[2(3(5) - 6)]

=> f(5) = log[2(15 - 6)]

=> f(5) = log[2(9)]

=> f(5) = log[18]

Also,

f(b) = f(6)        [This is f(x) at x = 6]

=> f(6) = log[2(3(6) - 6)]

=> f(6) = log[2(18 - 6)]

=> f(6) = log[2(12)]

=> f(6) = log[24]

Now substitute the values of a, b, f(a) and f(b) into equation (i) as follows;

[tex]f = \frac{log 24 - log 18}{6 - 5}[/tex]             [Remember that log m - log n = log (m / n)]

[tex]f = \frac{log (24 / 18)}{6 - 5}[/tex]

[tex]f = \frac{log (1.33)}{1}[/tex]

f = log 1.33 = 0.124

f = 0.12         [to two decimal places]

∴ The average rate of change on [5, 6] = 0.12

Answer:CORRECT ANSWER ON PLATO

[3,4]= 1

[4,5]=0.59

[5,6]= 0.41

Step-by-step explanation:

a · b = (4)(3) + (5)(6)

a · b = 12 + 30

a · b = 42

Answer:

42

Step-by-step explanation:

a*b = 4*3 + 5*6 = 12 + 30 ( where i*i = j*j = 1)

∴ a*b = 42

Answer:

The cordinates are:

y = 3

x = 4

Step-by-step explanation:

If you draw a line in the middle of the triangle

It Will go through the base at point V

point V can be marked at y=3 and x=4 the line drawn will intersect 0

Answer:

The answer is 729

Step-by-step explanation:

to get the next term, the sequence multiples the previous number by -3

1 * -3 = -3

-3 * -3 = 9

and so on.

To get the 7th term:

-27 * -3 = 81 (5th term)

81 * -3 = -243 (6th)

-243 * -3 = 729 (7th)

Answer:

The seventh term in the sequence is -729.

Step-by-step explanation:

Notice that the sequence is not increasing linearly. Therefore, this is a geometric sequence.

Recall that the explicit formula for a geometric sequence is given by:

[tex]x_n=a(r)^{n-1}[/tex]

Where a is the first term, r is the common ratio, and n denotes the nth term.

From the sequence, we can see that our first term a is -1.

Because each term is thrice the previous, our common ratio r is 3.

By substitution:

[tex]x_n=-(3)^{n-1}[/tex]

Hence, the seventh term is:

[tex]\displaystyle \begin{aligned} x_7 & = -(3)^{(7)-1} \\ \\ & = -(3)^{6} \\ \\ & = -729\end{aligned}[/tex]

In conclusion, the seventh term is -729.

Answers: line DB

H

D

Answer:

The line passing through the given points is:

[tex]y=-\frac{4}{3}x+\frac{1}{3}[/tex]

in its slope-intercept form

Step-by-step explanation:

Start by finding the slope of the segment that joins the two given points using the slope formula:

[tex]slope=\frac{y_2-y_1}{x_2-x_1}[/tex]

which for our case renders:

[tex]slope=\frac{3-(-5)}{-2-4}=\frac{8}{-6} =-\frac{4}{3}[/tex]

Now we can find the y-intercept by using any one of the given points in the general slope-intercept form of a line with this slope:

[tex]y=-\frac{4}{3} x+b\\3=-\frac{4}{3} (-2)+b\\3=\frac{8}{3}+b\\b=3-\frac{8}{3} \\b=\frac{9-8}{3} \\b=\frac{1}{3}[/tex]

Therefore, the equation of the line becomes:

[tex]y=-\frac{4}{3}x+\frac{1}{3}[/tex]

Answer:

see below (I hope this helps!)

Step-by-step explanation:

∠VZY and ∠VXW form a linear pair and are supplementary, and since m∠VZY = 90°, m∠VXW = 180 - 90 = 90°. Since m∠WXU + m∠UXV = ∠VXW, we can write the following equation:

44 + 5x - 4 = 90

5x + 40 = 90

5x = 50

x = 10°

Therefore, m∠UXV = 5 * 10 - 4 = 46°

Answer:

x = 10 m(UXV)=46°

Step-by-step explanation:

m(UXV) + m(UXW) = 90° because m(VXY)= 90°

m(UXW) = 44°

m(UXV) + 44° = 90°

m(UXV) = 46°

5x - 4 = 46°

5x = 50

5x/5 = 50/5

x = 10

Hope this helps ^-^

Answer:

[tex]y = \frac{7}{10} e^{3(t - 1)} + \frac{3}{10}e^{-7(t - 1)}[/tex]

Step-by-step explanation:

y′′ + 4y′ − 21y = 0

The auxiliary equation is given by

m² + 4m - 21 = 0

We solve this using the quadratic formula. So

[tex]m = \frac{-4 +/- \sqrt{4^{2} - 4 X 1 X (-21))} }{2 X 1}\\ = \frac{-4 +/- \sqrt{16 + 84} }{2}\\= \frac{-4 +/- \sqrt{100} }{2}\\= \frac{-4 +/- 10 }{2}\\= -2 +/- 5\\= -2 + 5 or -2 -5\\= 3 or -7[/tex]

So, the solution of the equation is

[tex]y = Ae^{m_{1} t} + Be^{m_{2} t}[/tex]

where m₁ = 3 and m₂ = -7.

So,

[tex]y = Ae^{3t} + Be^{-7t}[/tex]

Also,

[tex]y' = 3Ae^{3t} - 7e^{-7t}[/tex]

Since y(1) = 1 and y'(1) = 0, we substitute them into the equations above. So,

[tex]y(1) = Ae^{3X1} + Be^{-7X1}\\1 = Ae^{3} + Be^{-7}\\Ae^{3} + Be^{-7} = 1 (1)[/tex]

[tex]y'(1) = 3Ae^{3X1} - 7Be^{-7X1}\\0 = 3Ae^{3} - 7Be^{-7}\\3Ae^{3} - 7Be^{-7} = 0 \\3Ae^{3} = 7Be^{-7}\\A = \frac{7}{3} Be^{-10}[/tex]

Substituting A into (1) above, we have

[tex]\frac{7}{3}B e^{-10}e^{3} + Be^{-7} = 1 \\\frac{7}{3}B e^{-7} + Be^{-7} = 1\\\frac{10}{3}B e^{-7} = 1\\B = \frac{3}{10} e^{7}[/tex]

Substituting B into A, we have

[tex]A = \frac{7}{3} \frac{3}{10} e^{7}e^{-10}\\A = \frac{7}{10} e^{-3}[/tex]

Substituting A and B into y, we have

[tex]y = Ae^{3t} + Be^{-7t}\\y = \frac{7}{10} e^{-3}e^{3t} + \frac{3}{10} e^{7}e^{-7t}\\y = \frac{7}{10} e^{3(t - 1)} + \frac{3}{10}e^{-7(t - 1)}[/tex]

So the solution to the differential equation is

[tex]y = \frac{7}{10} e^{3(t - 1)} + \frac{3}{10}e^{-7(t - 1)}[/tex]

Answer:

3. it should be positive 3.5

4. (-2,4); (4,2); (6,-9)

Step-by-step explanation: