Answer:
A.
Explanation:
The β-sheet is a twisted pattern in which the protein strands are laterally linked through hydrogen bonds. These β-sheet motifs are segments of 3 to 10 amino acids that are specially configured to form beta antiparallel strands. In β-sheet regions, the hydrogen bonds are localized among carbonyl and amino groups of the polypeptide backbone, and side chains (i.e., the R groups) are extended up and down in the plane of the β-sheet.
Given that the molar mass of NAOH is 40.00G/MOL, what mass of NAOH is needed to make 2.500 L of a 2.000 M NaOH Solution?
Answer:
200g
Explanation:
n = CV
n = mass/molar mass
mass/molar mass = CV
mass/40 = 2 x 2.5
mass/40 = 5
mass = 5x 40
mass = 200g
The chemical reaction that occurs in a gas grill is the combustion of propane, C3H8. Write a balanced equation for this reaction. (Include states of matter.)
Answer:
[tex]\Large \boxed{\mathrm{C_3 H_8 \ (g)+5O_2 \ (g) \Rightarrow 3CO_2 \ (g)+4 H_2 O \ (l)}}[/tex]
[tex]\rule[225]{225}{2}[/tex]
Explanation:
[tex]\sf C_3 H_8 +O_2 \Rightarrow CO_2 + H_2 O[/tex]
Balancing Carbon atoms on the right side,
[tex]\sf C_3 H_8 +O_2 \Rightarrow 3CO_2 + H_2 O[/tex]
Balancing Hydrogen atoms on the right side,
[tex]\sf C_3 H_8 +O_2 \Rightarrow 3CO_2 +4 H_2 O[/tex]
Balancing Oxygen atoms on the left side,
[tex]\sf C_3 H_8 +5O_2 \Rightarrow 3CO_2 +4 H_2 O[/tex]
[tex]\rule[225]{225}{2}[/tex]
The combustion reaction of propane is :C₃H₈ [tex]_(g)[/tex]+5 O₂ [tex]_(g)[/tex][tex]\rightarrow[/tex]3 CO₂[tex]_(g)[/tex] + 4 H₂O[tex]_(l)[/tex].
What is combustion reaction?Combustion is defined as a high temperature exothermic reaction between a fuel which acts as a reductant and an oxidant which is usually atmospheric oxygen.It does not result in fire as the flame is visible only when substance which undergoes combustion vaporizes.
Activation energy must be overcome so that combustion is initiated.Solid fuels such as wood and coal initially undergo endothermal pyrolysis which results in gaseous fuels. It is widely used in industry and the application is based on concepts of chemistry, physics and mechanics.
It is a complex chemical process involving many steps which depend on properties of combustible material. It is a type of redox reaction.
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What is the concentration (M) of CH3OH in a solution prepared by dissolving 11.7 g of CH3OH in sufficient water to give exactly 100. mL of solution
Answer:
[tex]3.65~M[/tex]
Explanation:
We have to remember the molarity equation:
[tex]M=\frac{mol}{L}[/tex]
So, we have to calculate "mol" and "L". The total volume is 100 mL. So, we can do the conversion:
[tex]100~mL\frac{1~L}{1000~mL}=~0.1~L[/tex]
Now we can calculate the moles. For this we have to calculate the molar mass:
O: 16 g/mol
H: 1 g/mol
C: 12 g/mol
[tex](16*1)+(1*4)+(12*1)=32~g/mol[/tex]
With the molar mass value we can calculate the number of moles:
[tex]1.7~g~of~CH_3OH\frac{1~mol~CH_3OH}{32~g~of~CH_3OH}=0.365~mol~CH_3OH[/tex]
Finally, we can calculate the molarity:
[tex]M=\frac{0.365~mol~CH_3OH}{0.1~L}=3.65~M[/tex]
I hope it helps!
What are the correct formulas and coefficients for the products of the following double-replacement reaction? RbOH + H3PO4→
Answer:
3 RbOH + H₃PO₄ → Rb₃PO₄ + 3 H₂O
Explanation:
Let's consider the double-replacement reaction between rubidium hydroxide and phosphoric acid to form rubidium phosphate and water. The cation rubidium replaces the cation hydrogen and the anion hydroxyl replaces the anion phosphate. The balanced chemical reaction is:
3 RbOH + H₃PO₄ → Rb₃PO₄ + 3 H₂O
A silver cube with an edge length of 2.42 cm and a gold cube with an edge length of 2.75 cm are both heated to 85.4 ∘C and placed in 112.0 mL of water at 20.5 ∘C . What is the final temperature of the water when thermal equilibrium is reached?
Answer:
Explanation:
Volume of silver cube = 2.42³ = 14.17 cm³
mass of silver cube = volume x density
= 14.17 x 10.49 = 148.64 gm
Volume of gold cube = 2.75³ = 20.8 cm³
mass of gold cube = 20.8 x 19.3 = 401.44 gm
specific heat of silver and gold are .24 and .129 J /g°C
mass of 112 mL water = 112 g
Heat absorbed = heat lost = mass x specific heat x temperature fall or rise
Heat lost by metals
= 148.64 x .24 x ( 85.4 -T) + 401.44 x .129 x ( 85.4 - T )
= (35.67 + 51.78 ) x ( 85.4 - T )
87.45 x ( 85.4 - T )
= 7468.23 - 87.45 T
Heat gained by water
= 112 x 1 x ( T - 20.5 )
= 112 T - 2296
Heat lost = heat gained
7468.23 - 87.45 T = 112 T - 2296
199.45 T = 9764.23
T = 48.95° C
4.50 g of a certain Compound X, known to be made of carbon, hydrogen and perhaps oxygen, and to have a molecular molar mass of 128. g/mol, is burned completely in excess oxygen, and the mass of the products carefully measured: product carbon dioxide water mass 15.47 g 2.53 g Use this information to find the molecular formula of X.
Answer:
[tex]\mathbf{C_{10}H_8}[/tex] ( Naphthalene )
Explanation:
Given that:
4.50 g of a Compound X is made up of Carbon , Hydron and Oxygen
It's molecular molar mass = 128 g/mol
Compound X undergoes combustion reaction and the product yield :
CO_2 with mass 15.47g and :
H_2O with mass 2.53 g
The objective is to use this information to determine the molecular formula of X.
We all know that ; number of moles = mass/molar mass
where the molar mass of H_2O is 18 g/mol
number of moles of H_2O product = 2.53 g/18 g/mol
number of moles of H_2O product = 0.1406 moles
Also; the molar mass of CO_2 product = 44 g/mol
number of moles of CO_2 product = 15.47g/ 44 g/mol
number of moles of CO_2 product = 0.3516 moles
number of moles of Compound X in the reactant side= 4.50 g /128 g/mol
number of moles of Compound X n the reactant side= 0.03516 moles
Now; number number of moles of CO_2 in reactant = 0.3516 moles/0.03516 moles
Now; number number of moles of CO_2 in reactant = 10
number of moles of H_2O reactant = 0.1406 moles × 2/0.03516
number of moles of H_2O reactant = 7.997 ≅ 8
Since we said the Compound X is known to be made of Carbon C , Hydrogen H and Oxygen O
Then the molecular formula can be written as :
[tex]\mathbf{C_{10}H_8O_{x}}[/tex]
In order to find the x; we have
128 = (12 × 10 + 1 × 8 + 16 × x)
128 = 120 + 8 + 16x)
128 = 128 + 16 x
128 - 128 = 16 x
0 = 16 x
x = 0/16
x = 0
As x = 0 ; hence there are no oxygen present in the reaction
Thus; the molecular formula of Compound X = [tex]\mathbf{C_{10}H_8}[/tex] which is also known as Naphthalene
The force that opposes drag and is powered by combustion reactions in the
engine is
Answer:
Thrust.
Explanation:
hope this helps you :)
Answer:
thrust
Explanation:
codons.
a- One.
b- Two.
C- Three.
d- Four.
2. the start codon (AUG) binds to a tRNA with
a- Methionine.
b- Glycine.
C-Leucine.
d- Alanine.
3. Ribosomes move along mRNA adding amino acids to a growing peptide chain, this
process is called:
a- Activation.
b- Termination.
C- Initiation.
d- Translocation.
4) The sugar component is made up of what functional group?
a- NH2
b- C=0.
C- OH.
d- COOH.
5. The phosphate is attached to which carbon:
a- 5'.
b-1.
C-4'.
d-3.
6. Where is the (-OH) bonded to:
a- 3' carbon.
b- l' carbon
C-4' carbon
d- 5 carbo
7. Which of the next are the purines?
a- adenine and guanine.
b-adenine and pyrimidine. c- cytosine, uracil, and thy
Answer:
1. C- Three.
2. A- Methionine
3. D- Translocation.
4. C- OH.
5. A - 5'
6. A - 3' carbon
7. A. adenine and guanine
Explanation:
1. A codon is a group of three nucleotide sequence that encodes or specifies an amino acid. This means that, during translation (second stage of gene expression), when a CODON is read, an amino acid is added to the growing peptide chain.
2. The codon that initiates the translation process is called a start codon. It has a sequence: AUG and it specifies Methionine amino acid. Hence, during translation where a tRNA binds to the mRNA codon to read it and add its corresponding amino acid, a tRNA with a complementary sequence of AUG (start codon) binds to it and carries Methionine amino acid.
3. Translocation is a process during translation whereby the mRNA-tRNA moeity moves forward in the ribosome to allow another codon to move into the vacant site for translation process to continue.
4. The sugar component of a nucelotide that makes up the nucleic acid (DNA or RNA) i.e. ribose or deoxyribose, contains an hydroxyll functional group (-OH).
5. A nucleotide consists of a pentose (five carbon) sugar, phosphate group and a nitrogenous base. The phosphate group (PO43-) is attached to the 5' carbon of the sugar molecule.
6. The free hydroxyll group (-OH) of the five carbon sugar molecule in DNA is attached to its 3' carbon.
7. Nitrogenous bases are the third component of a nucleotide, the other two being pentose sugar and phosphate group. The nitrogenous bases are four viz: Adenine, Guanine, Cytosine, and Thymine. These bases are classified into Purines and Pyrimidines based on the similarity in their structure. Adenine (A) and Guanine (G) are Purines because they possess have two carbon-nitrogen rings, as opposed to one possessed by Pyrimidines (Thymine and Cytosine).
Draw structural formulas for the major organic product(s) of the reaction shown below.
• You do not have to consider stereochemistry.
If no reaction occurs, draw the organic starting material.
Remember to include all of the formal charges on the atoms of any nitro groups.
Answer:
3-bromobenzoic acid
Explanation:
In this case, we have to remember that the [tex]Br_2/FeBr_3[/tex] is a reaction in which we add Br into the molecule an electrophilic aromatic substitution. Additionally, we have a carboxylic acid in the benzene. This carboxylic acid is an ortho director because is a deactivating group (it removes electrons from the benzene ring). With this in mind, a "Br" atom would be added in an ortho position respect to the COOH group and we will obtain 3-bromobenzoic acid.
See figure 1.
I hope it helps!
To create 3-bromobenzoic acid, a "Br" atom would be placed at an orthogonal position to the COOH group according to electrophilic aromatic substitution.
Electrophilic aromatic substitution is a type of organic reaction in which an atom or group in an aromatic ring is substituted with an electrophile. It is a fundamental reaction in aromatic chemistry that happens due to the aromatic system's high electron density.
It is an electrophilic aromatic substitution process in which Br is incorporated into the molecule. In addition, the benzene contains a carboxylic acid. Because it removes electrons from the benzene ring, this carboxylic acid functions as an ortho director. To create 3-bromobenzoic acid, a "Br" atom would be placed at an orthogonal position to the COOH group. The product is seen in the photographs below.
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Which of the following does pascal's Principle help to explain?
Answer:
B) hydraulics
Explanation:
Answer:
hydraulics
Explanation:
i got it right the test on apex
:DDDDDDDD
Calculate the number of C atoms in 9.837 x 1024 molecules of CO2.
Please help
Answer:
Explanation:
1 molecule contains 1 carbon atom.
9.837 * 10^24 molecules contains 9.837 * 10^24 atom of carbon.
It's a 1 to 1 ratio.
Brown algae, such as giant kelp and sargassum, are an example of ? A. macroalgae B chemosynthetic algae C Flowering plants D Phytoplankton
Answer:
The answer is option A.
I hope this helps you.
Answer:
Macro Algae
Explanation:
probz
The reaction 2A -> B is first order in A with a rate constant of 8.42 x 10-2 s-1 at 800oC. How long it will take for A to decrease from 5.00 M to 0.153 M?
Answer:
41.4 s
Explanation:
Given data
Rate constant (k): 8.42 × 10⁻² s⁻¹ at 800 °CInitial concentration of A ([A]₀): 5.00 MConcentration of A at a time t ([A]): 0.153 MLet's consider the following reaction of first order with respect to A.
2 A ⇒ B
We can find the time that it will take for A to decrease from 5.00 M to 0.153 M using the following expression.
[tex]ln([A]/[A]_0)=-k.t\\ln(0.153M/5.00M)=-8.42 \times 10^{-2}s^{-1} .t\\t = 41.4 s[/tex]
4.15 Calculate the composition, in weight percent, of an alloy that contains 218.0 kg titanium, 14.6 kg of aluminum, and 9.7 kg of vanadium.
Answer:
The composition of the allow, in weigh percent, is 89.971 % Titanium, 6.026 % Aluminium and 4.003 % Vanadium.
Explanation:
The weight percentage of a element in an allow is equal to the mass of the element divided by the total mass of the allow and multiplied by 100. Then:
Titanium (Ti)
[tex]\% m_{Ti} = \frac{m_{Ti}}{m_{Ti}+m_{Al}+m_{V}}\times 100\,\%[/tex]
[tex]\%m_{Ti} = \frac{218\,kg}{218\,kg+14.6\,kg+9.7\,kg}\times 100\,\%[/tex]
[tex]\%m_{Ti} = 89.971\,\%[/tex]
Aluminium (Al)
[tex]\% m_{Al} = \frac{m_{Al}}{m_{Ti}+m_{Al}+m_{V}}\times 100\,\%[/tex]
[tex]\%m_{Al} = \frac{14.6\,kg}{218\,kg+14.6\,kg+9.7\,kg}\times 100\,\%[/tex]
[tex]\%m_{Al} = 6.026\,\%[/tex]
Vanadium (V)
[tex]\% m_{V} = \frac{m_{V}}{m_{Ti}+m_{Al}+m_{V}}\times 100\,\%[/tex]
[tex]\%m_{V} = \frac{9.7\,kg}{218\,kg+14.6\,kg+9.7\,kg}\times 100\,\%[/tex]
[tex]\%m_{Al} = 4.003\,\%[/tex]
The composition of the allow, in weigh percent, is 89.971 % Titanium, 6.026 % Aluminium and 4.003 % Vanadium.
Suppose the concentration of the NaOH solution was 0.5 M instead of 0.1 M. Would this titration have required more, less, or the same amount of NaOH solution for a complete reaction? Explain
Answer:
Less.
Explanation:
Since there was an increase of concentration of NaOH, there would be more molecules of NaOH present. There would be no need to use the same amount of NaOH because there was already more in the solution.
The titration will require a less amount of the NaOH solution.
I will like to state here that the amount we are talking about is the volume of the NaOH solution.
Concentration is defined as mole per unit volume i.e
Concentration = mole / VolumeWe can see from the formula above that the concentration is inversely proportional to the volume.
This means that a higher concentration requires a lower volume and a lesser concentration requires a higher volume.
Therefore, we can conclude that the titration will require a less amount (i.e volume) of the 0.5 M NaOH solution.
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Name the following alkanes. Please need help last assignment. The questions in the picture.
Answer:
Hydrogen, carbon reaction
What is the main type of energy conversion that happens as a skier goes
down a hill?
A. Gravitational potential energy to kinetic energy
B. Heat energy to kinetic energy
C. Kinetic energy to gravitational potential energy
D. Kinetic energy to heat energy
As a skier goes down the hill:
A. Gravitational potential energy to kinetic energy
What volume (mL) of 0.0855 M phosphoric acid can be neutralized with 119 mL of 0.315 M sodium hydroxide? A 1320 B 438 C 9.61 D 146 E 1470
Answer:
146 mL
Explanation:
Step 1: Write the balanced equation
H₃PO₄ + 3 NaOH ⇒ Na₃PO₄ + 3 H₂O
Step 2: Calculate the reacting moles of sodium hydroxide
119 mL of 0.315 M NaOH react.
[tex]0.119L \times \frac{0.315mol}{L} = 0.0375mol[/tex]
Step 3: Calculate the reacting moles of phosphoric acid
The molar ratio of H₃PO₄ to NaOH is 1:3. The reacting moles of H₃PO₄ are 1/3 × 0.0375 mol = 0.0125 mol.
Step 4: Calculate the reacting volume of phosphoric acid
0.0125 moles of H₃PO₄ are in a 0.0855 M solution.
[tex]0.0125 mol \times \frac{1L}{0.0855mol} \times \frac{1,000mL}{1L} =146 mL[/tex]
An ion of a single pure element always has an oxidation number of ________.
Answer: An ion of a single pure element always has an oxidation number of
zero.
Explanation:
A saturated solution of NaCl is formed by adding 500.g of NaCl to 0.500L of water. The excess solid NaCl is filtered from the solution, and after being dried in an oven, the mass was determined to be 346.8g.
Required:
What is the solubility of NaCl?
Answer:
4.96 mol/dm³
Explanation:
From the question,
Mass of NaCl that dissolved in 0.5L of water = 500-346.8 = 153.2 g.
Therefore, 145.2(1/0.5)g of NaCl will dissolve in 1 L of water
mass of NaCl that will dissolve in 1 L of water = 290.4 g/dm³
Molar mass of NaCl = 58.5 g/mol.
Solubility is the amount of substance in mol that will dissolve in 1 L or 1 dm³ Solution.
solubility in (mol/dm³) = solubility in (g/dm³)/molar mass.
solubility in (mol/dm³) = 290.4/58.5
solubility in (mol/dm³) = 4.96 mol/dm³
what is required on a chemical label
Answer: What is required on a chemical label includes pictograms, a signal word, hazard and precautionary statements, the product identifier, and supplier identification.
Explanation:
According to Occupational Safety and Health Administration (OSHA), the following are required on the label of a chemical;
pictograms a signal word hazard and precautionary statementsproduct identifiersupplier identificationAll these requirements on a chemical label helps to minimize the risk associated with such chemical substance especially if it has been marked as hazardous.
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4. A puddle of coastal seawater, caught in a depression formed by some coastal rocks at high tide, begins to evaporate as the tide goes out. If the volume of a puddle decreases to 23% of its original volume, what is the sodium chloride concentration if it was initially 0.449 M?
Answer:
0.583M NaCl
Explanation:
Molarity is an unit of concentration defined as the ratio between moles of solute and liters of solution.
In the puddle, the solute is sodium chloride that is dissolved in water and you have 0.449 moles of NaCl per liter of water
When the solution begins to evaporate, amount of water decreases whereas moles of NaCl remain constant.
As 23% of the water evaporates, amount of water that remains is 100-23 = 77%, that means now you have 0.449 moles of NaCl per 77% of a liter, 0.770L. The new concentration is:
0.449 moles NaCl / 0.770L =
0.583M NaClAccording to solubility rules, which of the following compounds is insoluble in water?
A.Cal
2
B.NA SO
2 4
C.AgF
D.AI(OH)
3
Answer:
The correct answer is - Al(OH)3
Explanation:
At the point when a substance is blended in with a soluble, there are a few potential outcomes. The deciding variable for the outcome is the solubility of the substance, which is characterized as the maximum concentration of the solute. These rules help figure out which substances are solvent, and how much.
According to the 11 rules of solubility rules, the insoluble compound in water is - Al(OH)3
Answer:
Na2So4
Explanation:
If you consult a table of solubility rules, like the one below, you will see that sodium sulfate (Na2SO4) is soluble in water.
4. In which pair of substances does the first underlined atom have a lower oxidation number than the second? A. NH3OH+ NH4– B. H2O H2O2 C. SO3 SO42– D. HCHO C
Answer:
Option B is correct.
Only this option has the first underlined element with a lower oxidation number than the second amongst the options.
Explanation:
Complete Question
In which pair of substances does the first underlined atom have a lower oxidation number than the second?
A. NH₃OH⁺, NH₄⁻ (N is underlined)
B. H₂O, H₂O₂ (O is underlined)
C. SO₃, SO₄²⁻ (S is underlined)
D. HCHO, C (C is underlined)
Solution
In determination of the oxidation number of an atom in a compound, we first name the unknown oxidation number x.
Then, the total oxidation number of the atoms in the compound is equal to the charge of on the compound (or radical).
So, elements in their neutral state have no charge and no oxidation number.
A. NH₃OH⁺, NH₄⁻ (N is underlined)
N in NH₃OH⁺
Oxidation number of N = x
Oxidation number of H = +1
Oxidation number of O = -2
x + (3×+1) + (-2) + (+1) = +1
x - 3 - 2 + 1 = 1
x = +5
N in NH₄⁻
Oxidation number of N = x
Oxidation number of H = +1
x + (4×1) = -1
x + 4 = -1
x = -1 - 4 = -5
First underlined element has a greater oxidation number than the second. So, this doesn't qualify.
B. H₂O, H₂O₂ (O is underlined)
O in H₂O
Oxidation number of H = +1
Oxidation number of O = x
(2×1) + x = 0
2 + x = 0
x = -2
H₂O₂
Oxidation number of H = +1
Oxidation number of O = x
(2×1) + (2×x) = 0
2 + 2x = 0
2x = -2
x = (-2/2) = -1.
First underlined element has a lower oxidation number than the second. So, this qualifies.
C. SO₃, SO₄²⁻ (S is underlined)
S in SO₃
Oxidation number of S = x
Oxidation number of O = -2
x + (3×-2) = 0
x - 6 = 0
x = +6
SO₄²⁻
Oxidation number of S = x
Oxidation number of O = -2
x + (4×-2) = -2
x - 8 = -2
x = 8 - 2 = +6
First underlined element has the same oxidation number as the second. So, this doesn't qualify.
D. HCHO, C (C is underlined)
C in HCHO
Oxidation number of H = +1
Oxidation number of C = x
Oxidation number of O = -2
+1 + x + 1 - 2 = 0
x = 0
C in C
Oxidation number of C = x
x = 0
First underlined element has the same oxidation number as the second. So, this doesn't qualify.
Hope this Helps!!!
Explain with examples following characteristics of chemical reactions: a. Change of colour b. Evolution of gas c. Change of smell d. Change of state
Answer:
Explanation:
a. change of colour:
A chemical reaction rearranges the constituent atoms of the reactants to create different substances as products. The products have different molecular structures than the reactants. Different atoms and molecules radiate different colours of light. Hence, there usually is a change in colour during a chemical reaction.
Eg: copper reactions with the elements
b. Evolution of gas:
A gas evolution reaction is a chemical reaction in which one of the end products is a gas such as oxygen or carbon dioxide.
Eg: ammonium hydroxide breaks down to water and ammonia gas.
c. Change of smell :
Production of an Odor Some chemical changes produce new smells. ... The formation of gas bubbles is another indicator that a chemical change may have occured.
Eg: The chemical change that occurs when an egg is rotting produces the smell of sulfur.
d. Change of state:
A chemical reaction is a process in which one or more substances, also called reactants, are converted to one or more different substances, known as products.
Eg: candle wax (solid) melts initially to produce molten wax (liquid)
plz mark as brainliest!!!!
In what ways are solid solid mixture categorised
Mixtures can be classified as homogeneous or heterogeneous . Mixtures are composed of substances that are not chemically combined.
Homogeneous mixtures are solutions. The components of a solution are evenly distributed throughout, so that every part of the solution is the same. The components that make up a solution include one or more solutes dissolved in a solvent. Solutes can be solids, liquids, or gases, and solvents can also be solids, liquids or gases.
Brass is an example of a solid/solid solution, saline solution is an example of a solid/liquid solution, diluted ethanol is an example of a liquid/liquid solution. There are many examples of solutions. The components of a solution can be separated by physical means, such as distillation, evaporation, and chromatography, among others.
a soluation of acetone in water has a molarity of 2.422M and a density of 0.970 g/mL. Calculate the mole fraction
Answer:
[tex]x_{acetone}=7.970x10^{-3}[/tex]
Explanation:
Hello,
In this case, for the given molarity, we can assume a volume of 1 L of solution, to obtain the following moles of acetone:
[tex]n=0.422mol/L*1L=0.422mol[/tex]
Then, with the density of solution, we can compute the mass of the solution for the selected 1-L volume basis:
[tex]m_{solution}=1L*\frac{1000mL}{1L}*\frac{0.970g}{1mL}=970g[/tex]
After that, we compute the mass of water in the solution, considering the mass of acetone (molar mass = 58.08 g/mol):
[tex]m_{H_2O}=970g-0.422molAcetone*\frac{58.08g\ Acetone}{1mol\ Acetone} =945.49gH_2O[/tex]
Next, the moles of water:
[tex]n_{H_2O}=945.49g*\frac{1molH_2O}{18gH_2O} =52.53molH_2O[/tex]
Finally, the mole fraction:
[tex]x_{acetone}=\frac{n_{acetone}}{n_{acetone}+n_{H_2O}}=\frac{0.422mol}{0.422mol+52.53mol}\\ \\x_{acetone}=7.970x10^{-3}[/tex]
Regards.
Consider the following reaction: C2H4(g)+H2(g)→C2H6(g) ΔH=−137.5kJ; ΔS=−120.5J/K Calculate ΔG at 25 ∘C and determine whether the reaction is spontaneous. Express the free energy change in joules to four significant figures.
Answer:
* [tex]\Delta G=-101.6kJ[/tex]
* Spontaneous reaction.
Explanation:
Hello,
In this case, for the given reaction, we can compute the Gibbs free energy by using the shown below equation:
[tex]\Delta G=\Delta H-T\Delta S[/tex]
In such a way, we proceed as follows with the proper units:
[tex]\Delta G=-137.5kJ-(25+273.15)K*(-120.5\frac{J}{K}*\frac{1kJ}{1000J} )\\\\\Delta G=-101.6kJ[/tex]
Therefore, since the Gibbs free energy of reaction is less than 0, the reaction is said to be spontaneous.
Best regards.
The value of ΔG should be -101.6KJ.
The reaction should be Spontaneous.
Calculation of the value of ΔG and reaction:Here the Gibbs free energy by using the below equation:
So,
=-137.5K - (25 + 273.15)K * (-120.5J/K * 1KH/1000J)
= -101.6KJ
As we can see that the Gibbs free energy of reaction is less than 0, the reaction is said to be spontaneous.
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what is the value of the equilibrium constant at 500k for a chemical equilivrium that has a delta h value of 250kj mol and s value of 48 j mol k
CH3-CHCl-CH2-CH2-CH2CHCl-CH3 +concentrated KCN
Answer:
what is the question is it