The Kepler's constant for Gliese 357 system in units of s2 / m3 is:k = (4 * pi^2) / (G * 0.3 solar masses * (0.025 AU)^3) = 8.677528872262322 s^2
The steps involved in converting the orbital period of GJ 357 d from days to seconds, calculating Kepler's constant for the Gliese 357 system in units of s2 / m3:
1. Convert the orbital period of GJ 357 d from days to seconds. The orbital period of GJ 357 d is 3.37 days. There are 86,400 seconds in a day. Therefore, the orbital period of GJ 357 d in seconds is 3.37 days * 86,400 seconds/day = 291,167 seconds.
2. Calculate Kepler's constant for the Gliese 357 system in units of s2 / m3.Kepler's constant is a physical constant that relates the orbital period of a planet to the mass of the star it orbits and the distance between the planet and the star.
The value of Kepler's constant is 4 * pi^2 / G, where G is the gravitational constant. The mass of Gliese 357 is 0.3 solar masses. The orbital radius of GJ 357 d is 0.025 AU.
Therefore, Kepler's constant for the Gliese 357 system in units of s2 / m3 is: k = (4 * pi^2) / (G * 0.3 solar masses * (0.025 AU)^3) = 8.677528872262322 s^2 .
Learn more about keplers constant with the given link,
https://brainly.com/question/16705471
#SPJ11
A uniform electric field has a magnitude of 10 N/C and is directed upward. A charge brought into the field experiences a force of 50 N downward. The charge must be A. +50 C. B. - 50 C. C. +0.5 C. D -0.5 C
The charge is B. -50 C because it experiences a force of 50 N downward in a uniform electric field of magnitude 10 N/C directed upward.
When a charge is placed in a uniform electric field, it experiences a force proportional to its charge and the magnitude of the electric field. In this case, the electric field has a magnitude of 10 N/C and is directed upward. The charge, however, experiences a force of 50 N downward.
The force experienced by a charge in an electric field is given by the equation F = qE, where F is the force, q is the charge, and E is the electric field strength. Rearranging the equation, we have q = F / E.
In this scenario, the force is given as 50 N downward, and the electric field is 10 N/C directed upward. Since the force and the electric field have opposite directions, the charge must be negative in order to yield a negative force.
By substituting the values into the equation, we get q = -50 N / 10 N/C = -5 C. Therefore, the correct answer is: B. -50 C.
Learn more about Electric field
brainly.com/question/11482745
#SPJ11
Two balls are side by side initially. At time = 0s, ball A is thrown at an initial angular velocity of pi radians per second and at time = 5s, the second ball is thrown down at the same angular velocity of pi radians per second down identical inclines with negligible friction. Assume the ramp is big enough so that the balls do not reach the bottom in the time values given.
a) Construct the angular velocity vs. time graph of both balls from time = 0 s to 15 seconds. Clearly label which line represent which ball and the time values.
b) The experiment is repeated on the same ramps with the same balls but this time, both balls are thrown down the incline at the same time with the same angular velocity. Ball A has twice the radius of Ball B.
i) Construct the linear velocity vs. time graph of both balls.
ii) Shade in the part of your linear velocity vs. time graph that represent the separation displacement between Ball A and Ball B as time progresses. Does this distance increase, decrease, or remain the same over time? Explain your answer.
a) Ball A: Horizontal line at pi radians per second from 0s to 15s.
Ball B: Horizontal line at pi radians per second from 5s to 15s.
b) i) Ball A: Positive sloped line indicating constant increase in linear velocity.
Ball B: Positive sloped line indicating constant increase in linear velocity.
ii) The separation distance between Ball A and Ball B remains the same over time.
a) The angular velocity vs. time graph for both balls can be represented as follows:
- Ball A: The graph is a horizontal line at the value of pi radians per second starting from time = 0s and continuing until time = 15s.
- Ball B: The graph is also a horizontal line at the value of pi radians per second starting from time = 5s and continuing until time = 15s.
b) i) The linear velocity vs. time graph for both balls can be represented as follows:
- Ball A: The graph is a straight line with a positive slope, indicating a constant increase in linear velocity over time.
- Ball B: The graph is also a straight line with a positive slope, indicating a constant increase in linear velocity over time.
ii) The separation displacement between Ball A and Ball B will remain the same over time. This is because both balls are thrown down the incline at the same time with the same angular velocity, meaning they will have the same linear velocity at any given time. Since they start at the same position, their relative distance or separation will remain constant throughout their motion.
Learn more about angular velocity:
https://brainly.com/question/29342095
#SPJ11
HEAT experiment (2) A stream of water strikes a stationary turbine blade horizontally, as the drawing illustrates. The incident water stream has a velocity of 16.0 m/s, while the exiting water stream has a velocity of -16.0 m/s. The mass of water per second that strikes the blade is 30.0 kg/s. Calculate the magnitude of the average force exerted on the water by the blade. [Answer: 960 N)
The magnitude of the average force exerted on the water by the blade is 960 N.
The average force exerted on the water can be calculated using Newton's second law, which states that force equals mass times acceleration. The change in velocity of the water stream is given as -16.0 m/s (opposite to the initial velocity).
Since the water stream's mass per second is 30.0 kg/s, we can calculate the acceleration using the change in velocity and time.
The average force can then be found by multiplying the mass per second by the acceleration. Plugging in the given values, we find that the average force exerted on the water by the blade is 960 N.
To learn more about Newton's second law
Click here brainly.com/question/31541845
#SPJ11
A hollow square steel tube has a height and width dimension of 5 in and a wall thickness of 0.4 in. and an original length of 8 in. The tube is loaded with 44000 lb. in compression and is shortened by 0.0017 in. as a result of the load. Determine the Modulus of Elasticity of the steel with 1-decimal place accuracy.E= _______ x10^6
(to 1 decimal place)
The Modulus of Elasticity of the steel with 1-decimal place accuracy is 0.0017 in / 8 in
To determine the modulus of elasticity (E) of the steel, we can use Hooke's law, which states that the stress (σ) is directly proportional to the strain (ε) within the elastic limit.
The stress (σ) can be calculated using the formula:
σ = F / A
Where:
F is the force applied (44000 lb in this case)
A is the cross-sectional area of the steel tube.
The strain (ε) can be calculated using the formula:
ε = ΔL / L0
Where:
ΔL is the change in length (0.0017 in)
L0 is the original length (8 in)
The modulus of elasticity (E) can be calculated using the formula:
E = σ / ε
Now, let's calculate the cross-sectional area (A) of the steel tube:
The outer dimensions of the tube can be calculated by adding twice the wall thickness to each side of the inner dimensions:
Outer height = 5 in + 2 × 0.4 in = 5.8 in
Outer width = 5 in + 2 × 0.4 in = 5.8 in
The cross-sectional area (A) is the product of the outer height and outer width:
A = Outer height × Outer width
Substituting the values:
A = 5.8 in × 5.8 in
A = 33.64 in²
Now, we can calculate the stress (σ):
σ = 44000 lb / 33.64 in²
Next, let's calculate the strain (ε):
ε = 0.0017 in / 8 in
Finally, we can calculate the modulus of elasticity (E):
E = σ / ε
To know more about elasticity click on below link :
https://brainly.com/question/17250844#
#SPJ11
billy, a student, sounds two tuning forks that are supposed to be tuned to A 440.0hz. in which one is correct. When sounded with the other tuning ford, he hears a periodic volume change at a rate of 24 times in 6.0s
a) In physics, what is this called?
b) What would be the possible frequencies for the tuning fork that happens to be out of tune?
In physics, the periodic volume change heard when two sound waves with nearly similar frequencies interfere with each other is called beats. The frequency of the out-of-tune tuning fork is 222 Hz.
When two sound waves interfere with each other, the periodic volume change heard when two sound waves with nearly similar frequencies interfere with each other is called beats.
The frequency of the out-of-tune tuning fork can be calculated from the number of beats heard in a given time. Billy hears 24 beats in 6.0 seconds. Therefore, the frequency of the out of tune tuning fork is 24 cycles / 6.0 seconds = 4 cycles per second.
In one cycle, there are two sounds: one of the tuning fork, which is at a frequency of 440.0 Hz, and the other is at the frequency of the out-of-tune tuning fork (f). The frequency of the out-of-tune tuning fork can be calculated by the formula; frequency of the out-of-tune tuning fork (f) = (Beats per second + 440 Hz) / 2.
Substituting the values, we get;
frequency of the out-of-tune tuning fork (f) = (4 Hz + 440 Hz) / 2 = 222 Hz.
Learn more about frequency:
https://brainly.com/question/14567997
#SPJ11
" An object moves (3.5x10^0) metres, stops, and them moves (3.340x10^0) Ý metres. What is the total displacement. Give your answer to 2 sf.
The total displacement of the object is approximately 165.64 meters.
Given
The first movement is (3.5 × 10) meters.
The second movement is (3.34 × 10) [tex]\hat{y}[/tex] meters.
Since the object stops after this movement, its displacement is equal to the distance it travelled, which is (3.5 × 10) meters.
To find the total displacement, we need to consider both movements. Since the movements are in different directions (one in the x-direction and the other in the y-direction), we can use the Pythagorean theorem to calculate the magnitude of the total displacement:
Total displacement = [tex]\sqrt{(displacement_x)^2 + (displacement_y)^2})[/tex]
In this case,
[tex]displacement_x[/tex] = 3.5 × 10 meters and
[tex]displacement_y[/tex] = 3.34 × 10 meters.
Plugging in the values, we get:
Total displacement = ([tex]\sqrt{(3.5 \times 10)^2 + (3.34 \times 10)^2})[/tex]
Total displacement = [tex]\sqrt{(122.5)^2 + (111.556)^2})[/tex]
Total displacement ≈ [tex]\sqrt{(15006.25 + 12432.835936)[/tex]
Total displacement ≈ [tex]\sqrt{27439.085936[/tex])
Total displacement ≈ 165.64 meters (rounded to 2 significant figures)
Therefore, the total displacement of the object is approximately 165.64 meters.
Learn more about Displacement from the given link:
https://brainly.com/question/29769926
#SPJ11
A thermistor is used in a circuit to control a piece of equipment automatically. What might this circuit be used for? A lighting an electric lamp as it becomes darker B ringing an alarm bell if a locked door is opened C switching on a water heater at a pre-determined time D turning on an air conditioner when the temperature rises
A thermistor is used in a circuit to control a piece of equipment automatically, this circuit be used for D. Turn on an air conditioner when the temperature rises.
A thermistor is a type of resistor whose resistance value varies with temperature. In a circuit, it is used as a sensor to detect temperature changes. The thermistor is used to control a piece of equipment automatically in various applications like thermostats, heating, and cooling systems. A circuit with a thermistor may be used to turn on an air conditioner when the temperature rises. In this case, the thermistor is used to sense the increase in temperature, which causes the resistance of the thermistor to decrease.
This change in resistance is then used to trigger the circuit, which turns on the air conditioner to cool the room. A thermistor circuit may also be used to switch on a water heater at a pre-determined time. In this case, the thermistor is used to detect the temperature of the water, and the circuit is programmed to turn on the heater when the water temperature falls below a certain level. This helps to maintain a consistent temperature in the water tank. So therefore the correct answer is D, turn on an air conditioner when the temperature rises.
Learn more about thermistor at:
https://brainly.com/question/31888503
#SPJ11
Part A A1 1-cm-tall object is 17 cm in front of a concave mirror that has a 69 em focal length Calculate the position of the image. Express your answer using two significant figures. ΨΗ ΑΣΦ O ? cm Submit Request Answer Part 8 A 1.1-cm-tall object is 17 cm in front of a concave mirror that has a 69 cm focal length Calculate the height of the image Express your answer using two significant figures. Vo] ΑΣΦ XE Cm
The position of the image is approximately -6.81 cm, and the height of the image is approximately 0.4 cm.The position of the image is approximately -6.81 cm, and the height of the image is approximately 0.4 cm.
To calculate the position of the image formed by a concave mirror and the height of the image, we can use the mirror equation and magnification formula.
Given:
- Object height (h_o) = 1 cm
- Object distance (d_o) = -17 cm (negative because the object is in front of the mirror)
- Focal length (f) = 69 cm
Using the mirror equation:
1/f = 1/d_i + 1/d_o
Since the object distance (d_o) is given as -17 cm, we can rearrange the equation to solve for the image distance (d_i):
1/d_i = 1/f - 1/d_o
Substituting the values:
1/d_i = 1/69 - 1/-17
To calculate the height of the image (h_i), we can use the magnification formula:
h_i / h_o = -d_i / d_o
Rearranging the formula to solve for h_i:
h_i = (h_o * d_i) / d_o
Substituting the given values:
h_i = (1 * d_i) / -17
Now, let's calculate the position of the image (d_i) and the height of the image (h_i):
1/d_i = 1/69 - 1/-17
1/d_i = (17 - 69) / (69 * -17)
1/d_i = 52 / (-69 * 17)
d_i = -1 / (52 / (-69 * 17))
d_i ≈ -6.81 cm
h_i = (1 * -6.81) / -17
h_i ≈ 0.4 cm
Therefore, the position of the image is approximately -6.81 cm from the mirror and the height of the image is approximately 0.4 cm.
To know more about concave mirror, click here:
brainly.com/question/31379461
#SPJ11
The cathodic polarization curve of a nickel electrode is measured in a de-aerated acid solution. The saturated calomel electrode is used as the reference. The working electrode has a surface of 2 cm². The following results are obtained: E (V) (SCE) -0.55 I (mA) 0 -0.64 0.794 -0.69 3.05 -0.71 4.90 -0.73 8.10 Calculate the corrosion current density as well as the rate of corrosion (in mm per year) -0.77 20.0
The corrosion current density is 2.03 x 10⁻⁶ A/cm² and the rate of corrosion is 0.309 mm/year.
The Tafel slope of cathodic reaction is given as :- (dV/d log I) = 2.303 RT/αF
The value of Tafel slope is found to be:
60 mV/decade (take α=0.5 for cathodic reaction)
From the polarisation curve, it is found that Ecorr = -0.69 V vs SCE
The cathodic reaction can be written asN
i2⁺(aq) + 2e⁻ → Ni(s)
The cathodic current density (icorr) can be calculated by Tafel extrapolation, which is given as:
I = Icorr{exp[(b-a)/0.06]}
where b and a are the intercepts of Tafel lines on voltage axis and current axis, respectively.
The value of b is Ecorr and the value of a can be calculated as:
a = Ecorr - (2.303RT/αF) log Icorr
Substituting the values:
0.71 = Icorr {exp[(0.69+2.303x8.314x298)/(0.5x96485x0.06)]} ⇒ Icorr = 4.05 x 10⁻⁶ A/cm²
The corrosion current density can be found by the relationship:icorr = (Icorr)/A
Where A is the surface area of the electrode. Here, A = 2 cm²
icorr = 4.05 x 10⁻⁶ A/cm² / 2 cm² = 2.03 x 10⁻⁶ A/cm²
The rate of corrosion can be found from the relationship:
W = (icorr x T x D) / E
W = corrosion rate (g)
icorr = corrosion current density (A/cm³)
T = time (hours)
D = density (g/cm³)
E = equivalent weight of metal (g/eq)
D of Ni = 8.9 g/cm³
E of Ni = 58.7 g/eq
T = 1 year = 365 days = 8760 hours
Substituting the values, the rate of corrosion comes out to be:
W = 2.03 x 10-6 x 8760 x 8.9 / 58.7 = 0.309 mm/year
Learn more about cathode at
https://brainly.com/question/31491308
#SPJ11
Questions 7.39 Homework. Unanswered ★ A pendulum is fashioned out of a thin bar of length 0.55 m and mass 1.9 kg. The end of the bar is welded to the surface of a sphere of radius 0.11 m and mass 0.86 kg. Find the centre of mass of the composite object as measured in metres from the end of the bar without the sphere. Type your numeric answer and submit
The center of mass of the composite object, consisting of the bar and sphere, is approximately 0.206 meters from the end of the bar. This is calculated by considering the individual centers of mass and their weighted average based on their masses.
To find the center of mass of the composite object, we need to consider the individual center of masses of the bar and the sphere and calculate their weighted average based on their masses.
The center of mass of the bar is located at its midpoint, which is L/2 = 0.55 m / 2 = 0.275 m from the end of the bar.
The center of mass of the sphere is at its geometric center, which is at a distance of R/2 = 0.11 m / 2 = 0.055 m from the end of the bar.
Now we calculate the weighted average:
Center of mass of the composite object = ([tex]m_bar[/tex] * center of mass of the bar + [tex]m_bar[/tex] * center of mass of the sphere) / ([tex]m_bar + m_sphere[/tex])
Center of mass of the composite object = (1.9 kg * 0.275 m + 0.86 kg * 0.055 m) / (1.9 kg + 0.86 kg)
To solve the expression (1.9 kg * 0.275 m + 0.86 kg * 0.055 m) / (1.9 kg + 0.86 kg), we can simplify the numerator and denominator separately and then divide them.
Numerator: (1.9 kg * 0.275 m + 0.86 kg * 0.055 m) = 0.5225 kg⋅m + 0.0473 kg⋅m = 0.5698 kg⋅m
Denominator: (1.9 kg + 0.86 kg) = 2.76 kg
Now we can calculate the expression:
(0.5698 kg⋅m) / (2.76 kg) ≈ 0.206 m
Therefore, the solution to the expression is approximately 0.206 meters.
To know more about the center of mass refer here,
https://brainly.com/question/8662931#
#SPJ11
A sinker of 4 Oz is weighed to be 3 OZ in water. The density of
alcohol used is 0.81 g/cm3. How many Oz will it weigh in the
alcohol?
The sinker will weigh approximately 2.8676 oz in alcohol.
To find the weight of the sinker in alcohol, we need to calculate the buoyant force and subtract it from the weight of the sinker.
Weight of the sinker in water = 3 oz
Density of alcohol = 0.81 g/cm^3
First, let's convert the density of alcohol to ounces per cubic inch to match the units of weight:
Density of alcohol = 0.81 g/cm^3
= (0.81 g/cm^3) × (0.03527396 oz/g) × (1 cm^3 / 0.06102374 in^3)
≈ 0.046708 oz/in^3
The buoyant force is equal to the weight of the liquid displaced by the sinker. The volume of liquid displaced is the difference in volume between the sinker in water and the sinker in alcohol.
To find the weight of the sinker in alcohol, we need to calculate the volume of the sinker in water and the volume of the sinker in alcohol:
Volume of sinker in water = Weight of sinker in water / Density of water
= 3 oz / 1 oz/in^3
= 3 in^3
Volume of sinker in alcohol = Volume of sinker in water - Volume of liquid displaced
= 3 in^3 - 3 in^3 × (Density of alcohol / Density of water)
= 3 in^3 - 3 in^3 × (0.046708 oz/in^3 / 1 oz/in^3)
= 3 in^3 - 3 in^3 × 0.046708
= 3 in^3 - 0.140124 in^3
≈ 2.859876 in^3
Finally, we can calculate the weight of the sinker in alcohol by subtracting the buoyant force from the weight of the sinker:
Weight of the sinker in alcohol = Weight of the sinker in water - Buoyant force
= 3 oz - (Volume of sinker in alcohol × Density of alcohol)
= 3 oz - (2.859876 in^3 × 0.046708 oz/in^3)
≈ 2.867576 oz
Learn more about density at https://brainly.com/question/26364788
#SPJ11
An electron is shot vertically upward through the tiny holes in the center of a parallel-plate capacitor. If the initial speed of the electron at the hole in the bottom plate of the capacitor is 4.00
Given Data: The initial speed of the electron at the hole in the bottom plate of the capacitor is 4.00.What is the final kinetic energy of the electron when it reaches the top plate of the capacitor? Explanation: The potential energy of the electron is given by, PE = q V Where q is the charge of the electron.
V is the potential difference across the capacitor. As the potential difference across the capacitor is constant, the potential energy of the electron will be converted to kinetic energy as the electron moves from the bottom to the top of the capacitor. Thus, the final kinetic energy of the electron is equal to the initial potential energy of the electron. K.E = P.E = qV Thus, K.E = eV Where e is the charge of the electron. K.E = 1.60 × 10-19 × 1000 × 5K.E = 8 × 10-16 Joule, the final kinetic energy of the electron when it reaches the top plate of the capacitor is 8 × 10-16 Joule.
To know more about energy visit:
https://brainly.com/question/1932868
#SPJ11
15) During a 4.50 s time period the magnetic field through a 0.350 m² wire loop changes from 2.30 T to 5.50T (directed straight through the loop), what is the average induced emf in the wire? 4.sos & ang NAER • 6.350m2
Given a change in magnetic field from 2.30 T to 5.50 T over a time period of 4.50 s, and a wire loop with an area of 0.350 m²,The average induced emf in the wire loop is 5.33 V.
According to Faraday's law, the induced emf in a wire loop is equal to the rate of change of magnetic flux through the loop. The magnetic flux (Φ) is given by the product of the magnetic field (B) and the area of the loop (A). In this case, the magnetic field changes from 2.30 T to 5.50 T, so the change in magnetic field (ΔB) is 5.50 T - 2.30 T = 3.20 T.
The average induced emf (ε) can be calculated using the formula:
ε = ΔΦ / Δt
where ΔΦ is the change in magnetic flux and Δt is the change in time. The change in time is given as 4.50 s.
To find the change in magnetic flux, we multiply the change in magnetic field (ΔB) by the area of the loop (A):
ΔΦ = ΔB * A
Plugging in the values, we have:
ΔΦ = 3.20 T * 0.350 m² = 1.12 Wb (weber)
Finally, substituting the values into the formula for average induced emf, we get:
ε = 1.12 Wb / 4.50 s = 5.33 V
Therefore, the average induced emf in the wire loop is 5.33 V.
To learn more about magnetic field click here brainly.com/question/14848188
#SPJ11
(i) Construct linear and quadratic approximations to the function f = x1x2 at the point x0 = (1,2)T. (ii) For the function f = x1x2, determine expressions for f(α) along the line x1 = x2 and also along the line joining (0, 1) to (1, 0).
The linear and quadratic approximations to the function f = x1x2 at the point x0 = (1,2)T have been constructed and the expressions for f(α) along the line x1 = x2 along the line joining (0, 1) to (1, 0).
For the given function f(x1,x2)=x1x2, the linear and quadratic approximations can be determined as follows:
Linear approximation: By taking the partial derivatives of the given function with respect to x1 and x2, we get:
f1(x1,x2) = x2 and f2(x1,x2) = x1
Now, the linear approximation can be expressed as follows:
f(x1,x2) ≈ f(1,2) + f1(1,2)(x1-1) + f2(1,2)(x2-2)
Thus, we have (x1,x2) ≈ 2 + 2(x1-1) + (x2-2) = 2x1 - x2 + 2.
Quadratic approximation:
For the quadratic approximation, we need to take into account the second-order partial derivatives as well.
These are given as follows:
f11(x1,x2) = 0, f12(x1,x2) = 1, f21(x1,x2) = 1, f22(x1,x2) = 0
Now, the quadratic approximation can be expressed as follows
f(x1,x2) ≈ f(1,2) + f1(1,2)(x1-1) + f2(1,2)(x2-2) + (1/2)[f11(1,2)(x1-1)² + 2f12(1,2)(x1-1)(x2-2) + f22(1,2)(x2-2)²]
Thus, we have (x1,x2) ≈ 2 + 2(x1-1) + (x2-2) + (1/2)[0(x1-1)² + 2(x1-1)(x2-2) + 0(x2-2)²] = 2x1 - x2 + 2 + x1(x2-2)
For the function f(x1,x2)=x1x2, we are required to determine the expressions for f(α) along the line x1 = x2 and also along the line joining (0, 1) to (1, 0).
Line x1 = x2:
Along this line, we have x1 = x2 = α.
Thus, we can write the function as f(α,α) = α².
Hence, the expression for f(α) along this line is simply f(α) = α².
The line joining (0,1) and (1,0):
The equation of the line joining (0,1) and (1,0) can be expressed as follows:x1 + x2 = 1Or,x2 = 1 - x1Substituting this value of x2 in the given function, we get
f(x1,x2) = x1(1-x1) = x1 - x1²
Now, we need to express x1 in terms of t where t is a parameter that varies along the line joining (0,1) and (1,0). For this, we can use the parametric equation of a straight line which is given as follows:x1 = t, x2 = 1-t
Substituting these values in the above expression for f(x1,x2), we get
f(t) = t - t²
Thus, we have constructed the linear and quadratic approximations to the function f = x1x2 at the point x0 = (1,2)T, and also determined the expressions for f(α) along the line x1 = x2 and also along the line joining (0, 1) to (1, 0).
To know more about partial derivatives visit
brainly.com/question/28751547
#SPJ11
Any two point charges exert equally strong electric forces on each other. Coulomb's constant is
8.99 × 10° N-m2/C?, and given that an electron has a charge of -1.60 × 10-19 C: What is the electric force (magnitude and direction) between two electrons (-e) separated by a
distance of 15.5 cm?
The magnitude of the electric force between two electrons separated by a distance of 15.5 cm is approximately 2.32 × 10^-8 N. The direction of the force is attractive, as like charges repel each other, and both electrons have a negative charge.
The electric force between two charges can be calculated using Coulomb's law:
F = k * |q1 * q2| / r^2
where F is the electric force, k is Coulomb's constant (8.99 × 10^9 N m^2/C^2), q1 and q2 are the charges, and r is the distance between the charges.
Given that both charges are electrons with a charge of -1.60 × 10^-19 C, and the distance between them is 15.5 cm (which can be converted to meters as 0.155 m), we can substitute the values into the equation:
F = (8.99 × 10^9 N m^2/C^2) * |-1.60 × 10^-19 C * -1.60 × 10^-19 C| / (0.155 m)^2
Calculating the expression inside the absolute value:
|-1.60 × 10^-19 C * -1.60 × 10^-19 C| = (1.60 × 10^-19 C)^2 = 2.56 × 10^-38 C^2
Substituting this value and the distance into the equation:
F = (8.99 × 10^9 N m^2/C^2) * (2.56 × 10^-38 C^2) / (0.155 m)^2
Calculating further:
F ≈ 2.32 × 10^-8 N
Therefore, the magnitude of the electric force between two electrons separated by a distance of 15.5 cm is approximately 2.32 × 10^-8 N. The direction of the force is attractive, as like charges repel each other, and both electrons have a negative charge.
Learn more about magnitude:
https://brainly.com/question/30337362
#SPJ11
50. The angle that a reflected light ray makes with the surface normal A) is smaller B) the same size C) greater than the angle that the incident ray makes with the normal 51. The speed of light in gl
The angle that a reflected light ray makes with the surface normal is smaller.
The law of reflection states that the angle of incidence is equal to the angle of reflection. When light is reflected from a surface, the angle at which it is reflected (angle of reflection) is equal to the angle at which it hits the surface (angle of incidence). The angle that a reflected light ray makes with the surface normal is the angle of reflection. Therefore, the answer is that the angle that a reflected light ray makes with the surface normal is smaller than the angle that the incident ray makes with the normal.
The speed of light in glass is less than the speed of light in a vacuum. This means that the refractive index of glass is greater than 1. When light passes through a medium with a higher refractive index than the medium it was previously in, the light is bent towards the normal. Therefore, the answer is that the speed of light in glass is less than the speed of light in a vacuum, and the refractive index of glass is greater than 1.
The angle that a reflected light ray makes with the surface normal is A) is smaller. The law of reflection states that the angle of incidence is equal to the angle of reflection. When light is reflected from a surface, the angle at which it is reflected (angle of reflection) is equal to the angle at which it hits the surface (angle of incidence). The angle that a reflected light ray makes with the surface normal is the angle of reflection. Therefore, the answer is that the angle that a reflected light ray makes with the surface normal is smaller than the angle that the incident ray makes with the normal.
The speed of light in glass is less than the speed of light in a vacuum. This means that the refractive index of glass is greater than 1. When light passes through a medium with a higher refractive index than the medium it was previously in, the light is bent towards the normal. Therefore, the answer is that the speed of light in glass is less than the speed of light in vacuum, and the refractive index of glass is greater than 1.
When a light wave strikes a surface, it can be either absorbed or reflected. Reflection occurs when light bounces back from a surface. The angle at which the light strikes the surface is known as the angle of incidence, and the angle at which it reflects is known as the angle of reflection. The angle of incidence is always equal to the angle of reflection, as stated by the law of reflection. The angle that a reflected light ray makes with the surface normal is the angle of reflection. It's smaller than the angle of incidence.
When light travels through different mediums, such as air and glass, its speed changes, and it bends. Refraction is the process of bending that occurs when light moves from one medium to another with a different density. The refractive index is a measure of the extent to which a medium slows down light compared to its speed in a vacuum. The refractive index of a vacuum is 1.
When light moves from a medium with a low refractive index to a medium with a high refractive index, it bends toward the normal, which is a line perpendicular to the surface separating the two media.
When light is reflected from a surface, the angle of reflection is always equal to the angle of incidence. The angle of reflection is the angle that a reflected light ray makes with the surface normal, and it is smaller than the angle of incidence. The refractive index of a medium is a measure of how much the medium slows down light compared to its speed in a vacuum. When light moves from a medium with a low refractive index to a medium with a high refractive index, it bends toward the normal.
To know more about refractive index visit
brainly.com/question/30761100
#SPJ11
Review. A small object with mass 4.00kg moves counterclockwise with constant angular speed 1.50rad/s in a circle of radius 3.00m centered at the origin. It starts at the point with position vector 3.00 i^m . It then undergoes an angular displacement of 9.00 rad.(d) In what direction is it moving?
The object is moving counterclockwise along an arc of length 27.00m.
The small object with a mass of 4.00kg moves counterclockwise in a circle with a radius of 3.00m and a constant angular speed of 1.50rad/s. It starts at the point with a position vector of 3.00i^m.
To determine the direction in which the object is moving, we need to consider the angular displacement of 9.00rad. Angular displacement is the change in angle as an object moves along a circular path. In this case, the object moves counterclockwise, so the direction of the angular displacement is also counterclockwise.
To find the direction in which the object is moving, we can look at the change in the position vector. The position vector starts at 3.00i^m and undergoes an angular displacement of 9.00rad. This means that the object moves along an arc of the circle.
The direction of the object's motion can be determined by finding the vector that points from the initial position to the final position. Since the object moves counterclockwise, the vector should also point counterclockwise.
In this case, the magnitude of the angular displacement is 9.00rad, so the object moves along an arc of length equal to the radius multiplied by the angular displacement. The length of the arc is 3.00m * 9.00rad = 27.00m.
To know more about radius visit:
https://brainly.com/question/13449316
#SPJ11
Problem 1: his Water (density equal to 1000 kg/m) flows through a system of pipes that goes up a step. The water pressure is 140 kPa at the bottom of the step (point 1), the cross-sectional area of the pipe at the top of the step (point 2) is half that at the bottom of the step and the speed of the water at the bottom of the step is 1.20 m/s. The pressure at the top of the step is 120 kPa. Find the value of the height h? (10 points) y h 0 11
The value of the height h is 5 meters.
To find the value of the height h, we can apply Bernoulli's equation, which relates the pressure, density, and velocity of a fluid flowing through a system. Bernoulli's equation states that the sum of the pressure energy, kinetic energy, and potential energy per unit volume remains constant along a streamline.
Apply Bernoulli's equation at points 1 and 2:
At point 1 (bottom of the step):
P1 + 1/2 * ρ * v1^2 + ρ * g * h1 = constant
At point 2 (top of the step):
P2 + 1/2 * ρ * v2^2 + ρ * g * h2 = constant
Simplify the equation using the given information:
Since the pressure at point 1 (P1) is 140 kPa and at point 2 (P2) is 120 kPa, and the speed of the water at the bottom (v1) is 1.20 m/s, we can substitute these values into the equation.
140 kPa + 1/2 * 1000 kg/m^3 * (1.20 m/s)^2 + 1000 kg/m^3 * 9.8 m/s^2 * h1 = 120 kPa + 1/2 * 1000 kg/m^3 * v2^2 + 1000 kg/m^3 * 9.8 m/s^2 * h2
Since the cross-sectional area of the pipe at the top (point 2) is half that at the bottom (point 1), the velocity at the top (v2) can be calculated as v2 = 2 * v1.
Solve for the value of h:
Using the given values and the equation from Step 2, we can solve for the value of h.
140 kPa + 1/2 * 1000 kg/m^3 * (1.20 m/s)^2 + 1000 kg/m^3 * 9.8 m/s^2 * h1 = 120 kPa + 1/2 * 1000 kg/m^3 * (2 * 1.20 m/s)^2 + 1000 kg/m^3 * 9.8 m/s^2 * h2
Simplifying the equation and rearranging the terms, we can find that h = 5 meters.
Therefore, the value of the height h is 5 meters.
Learn more about Bernoulli's equation
brainly.com/question/29865910
#SPJ11
On a day when the speed of sound is 345 m/s, the fundamental frequency of a particular stopped organ pipe is 220 Hz. The second overtone of this pipe has the same wavelength as the third harmonic of an open pipe. How long is the open pipe? Express your answer in mm
The length of the open pipe can be determined by comparing the wavelength of the third harmonic of the open pipe to the second overtone of the stopped organ pipe.
The fundamental frequency of a stopped organ pipe is determined by the length of the pipe, while the frequency of a harmonic in an open pipe is determined by the length and speed of sound. In this case, the fundamental frequency of the stopped organ pipe is given as 220 Hz.
The second overtone of the stopped organ pipe is the third harmonic, which has a frequency that is three times the fundamental frequency, resulting in 660 Hz (220 Hz × 3). The wavelength of this second overtone can be calculated by dividing the speed of sound by its frequency: wavelength = speed of sound / frequency = 345 m/s / 660 Hz = 0.5227 meters.
Now, we need to find the length of the open pipe that produces the same wavelength as the third harmonic of the stopped organ pipe. Since the open pipe has a fundamental frequency that corresponds to its first harmonic, the wavelength of the third harmonic in the open pipe is four times the length of the pipe. Therefore, the length of the open pipe can be calculated by multiplying the wavelength by a factor of 1/4: length = (0.5227 meters) / 4 = 0.1307 meters.
Finally, to express the length in millimeters, we convert the length from meters to millimeters by multiplying it by 1000: length = 0.1307 meters × 1000 = 130.7 mm. Hence, the length of the open pipe is 130.7 mm.
To learn more about wavelength.
Click here:brainly.com/question/29548846
#SPJ11
Which graphs could represent CONSTANT VELOCITY MOTION
A constant velocity motion will be represented by a straight line on the position-time graph as in option (c). Therefore, the correct option is C.
An object in constant velocity motion keeps its speed and direction constant throughout. The position-time graph for motion with constant speed is linear. The magnitude and direction of the slope on the line represent the speed and direction of motion, respectively, and the slope itself represents the velocity of the object.
A straight line with a slope greater than zero on a position-time graph indicates that the object is traveling at a constant speed. The velocity of the object is represented by the slope of the line; A steeper slope indicates a higher velocity, while a shallower slope indicates a lower velocity.
Therefore, the correct option is C.
Learn more about Slope, here:
https://brainly.com/question/3605446
#SPJ4
Your question is incomplete, most probably the complete question is:
Which of the following position-time graphs represents a constant velocity motion?
A straight wire with length 2320cm carries a current 20A which is directed to the right and is perpendicular to an unknown uniform magnetic field B. A magnetic
force 31pN acts on a conductor which is directed downwards. A. Determine the magnitude and the direction of the magnetic field in the region
through which the current passes. B. If the angle between the current and the magnetic field is 54 this time, what would
be the new value of the magnitude of the new magnetic force?
a. The magnitude of the magnetic field is [tex]2.84 * 10^(^-^1^1^) Tesla.[/tex]
b. The new value of the magnitude of the magnetic force is [tex]4.49 * 10^(^-^1^1^)[/tex] Newtons.
How do we calculate?a.
F_ = BILsinθ
F_ = magnetic force,
B = magnetic field
I = current,
L = length of the wire,
θ = angle between the current and the magnetic field.
Current (I) = 20 A
Length of wire (L) = 2320 cm = 23.20 m
Magnetic force (F) = 31 pN = 31 x 10^(-12) N
B = F/ (ILsinθ)
B = ([tex]31 * 10^(^-^1^2)[/tex]) N) / (20 A x 23.20 m x sin(90°))
B = [tex]2.84 * 10^(^-^1^1^)[/tex] T
b.
F' = BILsinθ'
F' = ([tex]2.84 * 10^(^-^1^1^)[/tex]T) x (20 A) x (23.20 m) x sin(54°)
F' = 4.49 x 10^(-11) N
Learn more about magnetic field at:
https://brainly.com/question/14411049
#SPJ4
If the period of a 70.0-cm-long simple pendulum is 1.68 s, what
is the value of g at the location of the pendulum?
The value of g at the location of the pendulum is approximately 9.81 m/s², given a period of 1.68 s and a length of 70.0 cm.
The period of a simple pendulum is given by the formula:
T = 2π√(L/g),
where:
T is the period,L is the length of the pendulum, andg is the acceleration due to gravity.Rearranging the formula, we can solve for g:
g = (4π²L) / T².
Substituting the given values:
L = 70.0 cm = 0.70 m, and
T = 1.68 s,
we can calculate the value of g:
g = (4π² * 0.70 m) / (1.68 s)².
g ≈ 9.81 m/s².
Therefore, the value of g at the location of the pendulum is approximately 9.81 m/s².
To learn more about acceleration due to gravity, Visit:
https://brainly.com/question/88039
#SPJ11
A loop of wire carrying current I (moving counterclockwise as seen from above) lies in the xy. plane. The loop is placed in a constant magnetic field of magnitude B that points at 30° from the z-axis. If the loop has a radius of 10 meters, carries a current of 2 amps, and the magnitude of the magnetic field is B Tesla, then the magnitude of the torque on the loop is given by am Newton-meters What is the value of a if B=5 Tesla?
The value of a is 100, as it represents the coefficient π in the equation. Therefore, if B = 5 Tesla, the magnitude of the torque on the loop is 500π N·m, or approximately 1570 N·m.
The torque on a current-carrying loop placed in a magnetic field is given by the equation τ = NIABsinθ, where τ is the torque, N is the number of turns in the loop, I is the current, A is the area of the loop, B is the magnitude of the magnetic field, and θ is the angle between the magnetic field and the normal to the loop.
In this case, the loop has a radius of 10 meters, so the area A is πr² = π(10 m)² = 100π m². The current I is 2 amps, and the magnitude of the magnetic field B is 5 Tesla. The angle θ between the magnetic field and the z-axis is 30°.
Plugging in the values into the torque equation, we have: τ = (2)(1)(100π)(5)(sin 30°)
Using the approximation sin 30° = 0.5, the equation simplifies to: τ = 500π N·m
To know more about torque refer here:
https://brainly.com/question/28220969#
#SPJ11
Question 51 1 pts How much heat, in kilo-joules, is required to convert 29 g of ice at -12°C into steam at 119°C, all at atmospheric pressure? (Lice 333 J/g, Lsteam = 2.26 10³ J/g, Cice = 2.090 J/g, Cwater = 4.186 J/g, Csteam = 2.010 J/g).
The amount of heat required to convert 29 g of ice at -12°C to steam at 119°C, at atmospheric pressure, is approximately 290 kJ.
To calculate the total heat required, we need to consider the heat energy for three stages: (1) heating the ice to 0°C, (2) melting the ice at 0°C, and (3) heating the water to 100°C, converting it to steam at 100°C, and further heating the steam to 119°C.
1. Heating the ice to 0°C:
The heat required can be calculated using the formula Q = m * C * ΔT, where m is the mass, C is the specific heat capacity, and ΔT is the change in temperature.
Q₁ = 29 g * 2.090 J/g°C * (0°C - (-12°C))
2. Melting the ice at 0°C:
The heat required for phase change can be calculated using Q = m * L, where L is the latent heat of fusion.
Q₂ = 29 g * 333 J/g
3. Heating the water from 0°C to 100°C, converting it to steam at 100°C, and further heating the steam to 119°C:
Q₃ = Q₄ + Q₅
Q₄ = 29 g * 4.186 J/g°C * (100°C - 0°C)
Q₅ = 29 g * 2.26 × 10³ J/g * (100°C - 100°C) + 29 g * 2.010 J/g°C * (119°C - 100°C)
Finally, the total heat required is the sum of Q₁, Q₂, Q₃:
Total heat = Q₁ + Q₂ + Q₃
By substituting the given values and performing the calculations, we find that the heat required is approximately 290 kJ.
To know more about atmospheric pressure refer here:
https://brainly.com/question/31634228#
#SPJ11
PROBLEM STATEMENT Housewives claims that bulk red label wine is stronger than the Red Label wine found on Supermarket shelves. Plan and design an experiment to prove this claim HYPOTHESIS AM APPARATUS AND MATERIALS DIAGRAM OF APPARATUS (f necessary METHOD On present tense) VARIABLES: manipulated controlled responding EXPECTED RESULTS ASSUMPTION PRECAUTIONS/ POSSIBLE SOURCE OF ERROR
To prove the claim that bulk red label wine is stronger than the Red Label wine found on supermarket shelves, an experiment can be designed to compare the alcohol content of both types of wine.
To investigate the claim, the experiment would involve analyzing the alcohol content of bulk red label wine and the Red Label wine available in supermarkets. The hypothesis assumes that bulk red label wine has a higher alcohol content than the Red Label wine sold in supermarkets.
In order to conduct this experiment, the following apparatus and materials would be required:
1. Samples of bulk red label wine
2. Samples of Red Label wine from a supermarket
3. Alcohol meter or hydrometer
4. Wine glasses or containers for testing
The experiment would proceed as follows:
1. Obtain representative samples of bulk red label wine and Red Label wine from a supermarket.
2. Ensure that the samples are of the same vintage and have been stored under similar conditions.
3. Use the alcohol meter or hydrometer to measure the alcohol content of each wine sample.
4. Pour the wine samples into separate wine glasses or containers.
5. Observe and record any visual differences between the wines, such as color or clarity.
Variables:
- Manipulated variable: Type of wine (bulk red label wine vs. Red Label wine from a supermarket)
- Controlled variables: Vintage of the wine, storage conditions, and volume of wine used for testing
- Responding variable: Alcohol content of the wine
Expected Results:
Based on the hypothesis, it is expected that the bulk red label wine will have a higher alcohol content compared to the Red Label wine from a supermarket.
Assumption:
The assumption is that the bulk red label wine, being purchased in larger quantities, may be sourced from different suppliers or production methods that result in a higher alcohol content compared to the Red Label wine sold in supermarkets.
Precautions/Possible Sources of Error:
1. Ensure that the alcohol meter or hydrometer used for measuring the alcohol content is calibrated properly.
2. Take multiple measurements for each wine sample to ensure accuracy.
3. Avoid cross-contamination between the wine samples during testing.
4. Ensure the wine samples are handled and stored properly to maintain their integrity.
Learn more about alcohol
brainly.com/question/29268872
#SPJ11
A proton (charge +e, mass mp), a deuteron (charge +e, mass 2mp), and an alpha particle (charge +2e, mass 4m) are accelerated from rest through a common potential difference AV. Each of the particles enters a uniform magnetic field B, with its velocity in a direction perpendicular to B. The proton moves in a circular path of radius p (a) In terms of r, determine the radius r of the circular orbit for the deuteron.
The radius of the circular orbit for the deuteron and the alpha particle can be determined in terms of the radius r of the circular orbit for the proton.
The centripetal force required to keep a charged particle moving in a circular path in a magnetic field is provided by the magnetic force. The magnetic force is given by the equation F = qvB, where q is the charge of the particle, v is its velocity, and B is the magnetic field strength.
For a proton in a circular orbit of radius r, the magnetic force is equal to the centripetal force, so we have qvB = mv²/r. Rearranging this equation, we find that v = rB/m.
Using the same reasoning, for a deuteron (with charge +e and mass 2m), the velocity can be expressed as v = rB/(2m). Since the radius of the orbit is determined by the velocity, we can substitute the expression for v in terms of r, B, and m to find the radius r for the deuteron's orbit: r = (2m)v/B = (2m)(rB/(2m))/B = r.
Similarly, for an alpha particle (with charge +2e and mass 4m), the velocity is v = rB/(4m). Substituting this into the expression for v, we get r = (4m)v/B = (4m)(rB/(4m))/B = r.
Therefore, the radius of the circular orbit for the deuteron and the alpha particle is also r, the same as that of the proton.
Learn more about velocity here ;
brainly.com/question/30540135
#SPJ4
In terms of r, the radius of the circular orbit for the deuteron is r.
The magnetic field B that each of the particles enters is uniform. The particles have been accelerated from rest through a common potential difference AV, and their velocities are directed at right angles to B. Given that the proton moves in a circular path of radius p. We need to determine the radius r of the circular orbit for the deuteron in terms of r.
Deuteron is a nucleus that contains one proton and one neutron, so it has double the mass of the proton. Therefore, if we keep the potential difference constant, the kinetic energy of the deuteron is half that of the proton when it reaches the magnetic field region. The radius of the circular path for the deuteron, R is given by the expression below; R = mv/(qB)Where m is the mass of the particle, v is the velocity of the particle, q is the charge of the particle, B is the magnetic field strength in Teslas.
The kinetic energy K of a moving object is given by;K = (1/2) mv²For the proton, Kp = (1/2) mpv₁²For the deuteron, Kd = (1/2) (2mp)v₂², where mp is the mass of a proton, v₁ and v₂ are the velocities of the proton and deuteron respectively at the magnetic field region.
Since AV is common to all particles, we can equate their kinetic energy at the magnetic field region; Kp = Kd(1/2) mpv₁² = (1/2) (2mp)v₂²4v₁² = v₂²From the definition of circular motion, centripetal force, Fc of a charged particle of mass m with charge q moving at velocity v in a magnetic field B is given by;Fc = (mv²)/r
Where r is the radius of the circular path. The centripetal force is provided by the magnetic force experienced by the particle, so we can equate the magnetic force and the centripetal force;qvB = (mv²)/rV = (qrB)/m
Substitute for v₂ and v₁ in terms of B,m, and r;(qrB)/mp = 2(qrB)/md² = 2pThe radius of the deuteron's circular path in terms of the radius of the proton's circular path is;d = 2p(radius of proton's circular path)r = (d/2p)p = r/2pSo, r = 2pd.
Learn more about deuteron
https://brainly.com/question/31978176
#SPJ11
Write a x; in a form that includes the Kronecker delta. Now show that V.r=3.
x; = Σn=1 to ∞ δn,x vn,
where δn,x is the Kronecker delta and vn is a vector in the basis of x.
Kronecker delta is a mathematical symbol that is named after Leopold Kronecker. It is also known as the Kronecker's delta or Kronecker's symbol. It is represented by the symbol δ and is defined as δij = 1 when i = j, and 0 otherwise. Here, i and j can be any two indices in the vector x. The vector x can be expressed as a sum of vectors in the basis of x as follows: x = Σn=1 to ∞ vn, where vn is a vector in the basis of x.
Using the Kronecker delta, we can express this sum in the following form:
x; = Σn=1 to ∞ δn,x vn, where δn,x is the Kronecker delta. Now, if we take the dot product of the vector V and x, we get the following:
V·x = V·(Σn=1 to ∞ vn) = Σn=1 to ∞ (V·vn)
Since V is a 3-dimensional vector, the dot product V·vn will be zero for all but the third term, where it will be equal to 3. So, V·x = Σn=1 to ∞ (V·vn) = 3, which proves that V·x = 3.
Learn more about Kronecker delta here:
https://brainly.com/question/30894460
#SPJ11
How does the voltage across two circuit elements in parallel
compare to one another? Explain.
PLEASE TYPE
When two circuit elements are connected in parallel, the voltage across each element is equal to one another.
The voltage across each element connected in parallel is equal to one another because they are connected to the same points in the circuit. Therefore, the voltage drop across each element is the same as the voltage supplied to the circuit.
When two or more circuit elements are connected in parallel, each of them is connected to the same pair of nodes. This implies that the voltage across every element is the same. It is due to the fact that the potential difference across each element is equal to the voltage of the source of the circuit. Thus, the voltage across two circuit elements connected in parallel compares to one another by being equal. In summary, when two circuit elements are connected in parallel, the voltage across each element is equal to one another.
To know more about circuit visit:
https://brainly.com/question/31426793
#SPJ11
Part A What percentage of all the molecules in the glass are water? Express your answer using six significant figures. D | ΑΣΦ VO ? MAREH nwater Submit Request Answer % Assume the total number of molecules in a glass of liquid is about 1,000,000 million trillion. One million trillion of these are molecules of some poison, while 999,999 million trillion of these are water molecules.
Assuming the total number of molecules in a glass of liquid is about 1,000,000 million trillion.
One million trillion of these are molecules of some poison, while 999,999 million trillion of these are water molecules.
Express your answer using six significant figures. To determine the percentage of all the molecules in the glass that are water, we need to use the following formula: % of water = (number of water molecules/total number of molecules) × 100.
To know more about liquid visit:
https://brainly.com/question/20922015
#SPJ11
(a) Find the distance of the image from a thin diverging lens of focal length 30 cm if the object is placed 20 cm to the right of the lens. Include the correct sign. cm (b) Where is the image formed?
The image is formed on the same side of the object.
Focal length, f = -30 cm
Distance of object from the lens, u = -20 cm
Distance of the image from the lens, v = ?
Now, using the lens formula, we have:
1/f = 1/v - 1/u
Or, 1/-30 = 1/v - 1/-20
Or, v = -60 cm (distance of image from the lens)
The negative sign of the image distance indicates that the image formed is virtual, erect, and diminished.
The image is formed on the same side of the object. So, the image is formed 60 cm to the left of the lens.
To learn more about image, refer below:
https://brainly.com/question/30725545
#SPJ11