Convert each of the ingredient amounts below from ounces to fractions
Example: 8.2 = 8 2/10 *
2 points
Puppy Chow Trail Mix
• Trail Mix:
• 1 (12.65 ounce) can salted peanuts
• 1 (10.5 ounce) package miniature marshmallows
• 1 (3.2 ounce) package sunflower seeds
• 1(1.69 ounce) package candy-coated milk chocolate pieces (such as M&M's(R))
• 1 (1.5 ounce) box raisins
Your answer

Answer:

  66,000 kg·km/hr

Step-by-step explanation:

  p = mass × velocity

  p = (1200 kg) × (55 km/hr) = 66,000 kg·km/hr

_____

Additional comment

Here, we have used the standard metric units for momentum. The units you choose can be any mass·velocity units that meet your needs.

Answer: D: (-∞, ∞)

               R: (-∞, ∞)

Step-by-step explanation:

Since the end points are arrows and have no set stopping point we can assume the answer is all real numbers, also known as infinity

Answer:

Which Restaurant and aquarium

Step-by-step explanation:

If you tell the name I can answer it

Answer:

A

i will go with a. hope to help u

Answer:

1/64

Step-by-step explanation:

Answer: that would be 1/64

Step-by-step explanation:

for this type of question you put it 1/ such as:[tex]\frac{1}{8*8}[/tex] i got 8*8 because of The 8^2

and 8*8=64 therefor the answer is 1/64

*you put it over 1 to get rid of the negative exponents*

Answer:

17.41 Dollars

Step-by-step explanation:

First, you take the discount, which is 2 dollars, so now the cost without any additional costs is 22 dollars. Next, find 8 percent of 22 by multipling 22*0.08 and then you get 1.76. Subtract that from 22 and 20.24. Then take 14 percent of 20.24 by multiplying it by 0.14, which you get 2.8336. Round that down and you get 2.83. Subtract that from that and you get 17.41.

The quantity of excess reserves that the Bank of Cheerton now hold is $210

From the attached table, the amount generated on the reserve is $4,200

If the Fed's reserve requirement is 5 percent, then the quantity of excess reserves that the Bank hold is given as:

Quantity of excess reserves = 5% of $4,200

Quantity of excess reserves = 0.05 * 4200

Quantity of excess reserves = $210

Hence the quantity of excess reserves that the Bank of Cheerton now holds is $210.

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The required angles from smallest to largest are m<M < m<L < m<K

Given the coordinate of the triangle KLM given as K(-2,-2), L(2, 6), M(7, -2)

Get the measure of KL, KM and LM using the distance formula as shown:

[tex]D=\sqrt{(x_2-x_1)^2+(y_2-y)_1)^2}[/tex]

For the length KL with coordinate points K(-2,-2), L(2, 6)

[tex]KL=\sqrt{(2-(-2))^2+(6-(-2))^2}\\KL=\sqrt{4^2+8^2}\\KL=\sqrt{16+64}\\KL=\sqrt{80}\\KL =4\sqrt{5}[/tex]

For the length KM with coordinate points K(-2,-2), M(7, -2)

[tex]KM=\sqrt{(7-(-2))^2+(-2-(-2))^2}\\KM=\sqrt{9^2+0^2}\\KM=\sqrt{81}\\KM=9[/tex]

The length LM with coordinate points L(2,6), M(7, -2)

[tex]LM=\sqrt{(7--2)^2+(-2-6)^2}\\LM=\sqrt{5^2+(-8)^2}\\LM=\sqrt{25+64}\\LM=\sqrt{89}[/tex]

From the distances, we can see that side LM > KM > KL. Hence the required angles from smallest to largest are m<M < m<L < m<K

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Answer:

The answer is B

Answer:

The retail price would be $93.6

Step-by-step explanation:

This is because you can divide 130 by 100 to find 1% of such, and you'll get 1.3. Then, multiply 1.3 by 72, which makes 72% of the original price, to come find your answer, $93.6. Hope this helps!

Answer:

5 m, 2 m, 2.5 m, 2 m, 2.5 m, 4 m.

Step-by-step explanation:

First find the length of the 2 missing sides. Remember that the picture is WAY out of proportion, so the sides won't be what they look like.

Since the left side is 4 and the right side is 8 cm, the missing left side is 4 cm.

Since the top side is 5 and the bottom side is 10 cm, the missing top piece is 5 cm.

So the sides starting at the bottom right and going clockwise are 10, 4, 5, 4, 5, 8 cm. Multiply each of these * 0.5 and call them meters.

5 m, 2 m, 2.5 m, 2 m, 2.5 m, 4 m.

Answer:

16 and 2

Step-by-step explanation:

16+2=18

16-2=14

Answer:

B.3/7

Step-by-step explanation:

The value of a in the equation is 10

The root of the equation is determined using the equation shown below:

[tex]x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}[/tex]

Given the quadratic equation ax^2+x-24=0;

The product of the quadratic equation is c/a

Product = c/a

- 2 2/5 = -24/a

-12/5 = -24/a

-12a = 5 * -24

-12a = -120

a = 10

Hence the value of a in the equation is 10

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Compare to ax^2+bx+c

Product of roots=c/a

ATQ

[tex]\\ \tt\hookrightarrow \dfrac{c}{a}=-2\dfrac{2}{5}[/tex]

[tex]\\ \tt\hookrightarrow \dfrac{-24}{a}=\dfrac{-12}{5}[/tex]

[tex]\\ \tt\hookrightarrow \dfrac{24}{a}=\dfrac{12}{5}[/tex]

[tex]\\ \tt\hookrightarrow 12a=120[/tex]

[tex]\\ \tt\hookrightarrow a=10[/tex]

Answer:

a) 4cd²

b) 3a²b³

Step-by-step explanation:

a) 8c⁴d⁵/2c³d³

1: you would divide the 8 by 2

2: subtract the exponents on c so it would be 4-3 = 1

3: subtract the exponents on d so it would br 5-3 = 2

4: put it all together so it would be 4c¹d² but you dont need the 1 above c

b) 1: divide 9 by 3

2: subtract exponents on a so it would be 3-1 = 2

3: subtract exponents on b so it would be 5-2 = 3

4: put it all together so it would be 3a²b³

hope this helped!! :)

                              Answer:

a.   4cd²       b.  3a²b³

Step-by-step explanation:

        [tex]\frac{8c^4d^5}{2c^3d^3}[/tex]

 =    [tex]\frac{8}{2} ( \frac{c^4}{c^3} )(\frac{d^5}{d^3})[/tex]  

  =     [tex]\frac{4}{1} (\frac{c}{1}) (\frac{d^2}{1} )[/tex]    Reduce number.  Substract exponent largest power

                           smallest power  

   =   4cd²  

b.    [tex]\frac{9a^3b^5}{3ab^2}[/tex]

        [tex]\frac{9}{3} (\frac{a^3}{a} ) (\frac{b^5}{b^2} )[/tex]

        [tex]\frac{3}{1} (\frac{a^2}{1}) (\frac{b^3}{1} )[/tex]       Reduce number.  Substract exponent largest power

                              smallest power  

    = 3a²b³

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b

Answer:

x=3

Step-by-step explanation:

Answer:

the top right box

Step-by-step explanation:

Answer:

-g-8≥9

Step-by-step explanation:

Just ask.

Hope this helps. :)

Answer:

  15π/2 ft

Step-by-step explanation:

Arc length is given by the formula ...

  s = rθ . . . . . r = radius; θ = central angle in radians

A 135° arc has a radian measure of (135)(π/180) = 3π/4. The radius of a circle with a 20 ft diameter is (20 ft/2) = 10 ft. So, the arc length is ...

  s = (10 ft)(3π/4) = 30π/4 ft = 15π/2 ft

Answer:

Step-by-step explanation:

4*4*__=48

16*__=48

48/16=3

3*4=12

Answer:

12 boxes on the right side

Step-by-step explanation:

4 going across and 3 rows so 12 boxes

48 divided by 3 is 16 but divided by 4 is 12

since there are 16 boxes at the top its a good inference that there's

only 3 flat rows meaning per every flat there would be 4 boxes and 3 rows

there would be 12 boxes on the right side.

Answer: I Think you will make 100 time 2 divide 3

Step-by-step explanation:

i'm not sure, have a nice day

Answer:

x = 33

Step-by-step explanation:

11 - 4 = 7

You need to make that fraction equal 11

33/3 = 11

I hope this helps!

Applying the required rule or theorem, it can be concluded that the second biker is farther from the parking lot. The distance of the bikers to the parking lot are:

i. First biker = 17.0 km

ii. Second biker = 20.22 km

The path of travel of both bikers would form a triangle. Applying the Pythagoras theorem to the path of the first biker would give his distance from the starting point. While applying the cosine rule to the path of second rider would gives his distance to the starting point.

Thus,

a. To determine the distance of the first biker from the parking lot.

Let the required distance be represented by x. Applying the Pythagoras theorem, we have:

[tex]hyp^{2}[/tex] = [tex]adj 1^{2}[/tex] + [tex]adj 2^{2}[/tex]

[tex]x^{2}[/tex] = [tex]8^{2}[/tex] + [tex]15^{2}[/tex]

   = 64 + 225

   = 289

x = [tex]\sqrt{289}[/tex]

  = 17

x = 17 km

Thus, the first biker is 17.0 km from the starting point.

b. To determine the distance of the second biker from the parking lot.

Let the required distance be represented by x. So that applying the cosine rule, we have:

[tex]c^{2}[/tex] = [tex]a^{2}[/tex] + [tex]b^{2}[/tex] - 2ab Cos θ

[tex]x^{2}[/tex] = [tex]8^{2}[/tex] + [tex]15^{2}[/tex] - 2(15*8) Cos (180 - 20)

    = 64 + 225 - 240 Cos 160

    = 289 - 240 * -0.5

[tex]x^{2}[/tex] = 289 + 120

   = 409

x = [tex]\sqrt{409}[/tex]

 = 20.2237

x = 20.22 km

Thus, the second biker is 20.22 km from the starting point.

Therefore, the second biker is farther from the parking lot.

A sketch of the path of travel for the two bikers is attached for more clarifications.

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Answer: 2,343.3333 repeating, or just 2,343 1/3

Step-by-step explanation:

If you divide, your answer comes out to be 2,343.3333 repeating or 2,343 1/3.

Answer:

71.8

Step-by-step explanation: