The number of times a player has golfed in one's lifetime is compared to the number of strokes it takes the player to complete 18 holes. The correlation coefficient relating the two variables is -0.26. Which best describes the strength of the correlation and what is true about the causation between the variables?
Answer: It is a weak negative correlation and it is not likely causal.
Step-by-step explanation:
Given: The number of times a player has golfed in one's lifetime is compared to the number of strokes it takes the player to complete 18 holes. The correlation coefficient relating the two variables is -0.26.
Variables : "number of times a player has golfed in one's lifetime" and "number of strokes it takes the player to complete 18 holes".
Since -0.26 is more closer to 0 as compared to 1 , so it describes a weak negative correlation.
Also, it is not likely causal as number of times a player has golfed in one's lifetime not cause number of strokes it takes the player to complete 18 holes.
Answer: B) It is a weak negative correlation, and it is likely casual
Correct on edge 2020!
what song goes whoooooo Iiiiii smoooooooooke
Answer:
Lol yu lateee das "who i smoke by yung ace"
Step-by-step explanation:
Answer:
woogle said woo hoo by rock a teens
Step-by-step explanation:
find the n^th root of z = -2i, n = 6
Answer:
2^(1/6) (cos(-pi/12)+i sin(-pi/12))
2^(1/6) (cos(3pi/12)+i sin(3pi/12))
2^(1/6) (cos(7pi/12)+i sin(7pi/12))
2^(1/6) (cos(11pi/12)+i sin(11pi/12))
2^(1/6) (cos(5pi/4)+i sin(5pi/4))
2^(1/6) (cos(19pi/12)+i sin(19pi/12))
Step-by-step explanation:
Let's convert to polar form.
-2i=2(cos(A)+i sin(A) )
There is no real part so cos(A) has to be zero and since we want -2 and we already have 2 then we need sin(A)=-1 so let's choose A=-pi/2.
So z=2(cos(-pi/2)+i sin(-pi/2)).
There are actually infinitely many ways we can write this polar form which we will need.
z=2(cos(-pi/2+2pi k)+i sin(-pi/2+2pi k))
where k is an integer
Now let's find the 6 6th roots or z.
2^(1/6) (cos(-pi/12+2pi k/6)+i sin(-pi/12+2pi k/6))
Reducing
2^(1/6) (cos(-pi/12+pi k/3)+i sin(-pi/12+pi k/3))
Plug in k=0,1,2,3,4,5 to find the 6 6th roots.
k=0:
2^(1/6) (cos(-pi/12+pi (0)/3)+i sin(-pi/12+pi (0)/3))
=2^(1/6) (cos(-pi/12)+i sin(-pi/12))
k=1:
2^(1/6) (cos(-pi/12+pi/3)+i sin(-pi/12+pi/3))
2^(1/6) (cos(3pi/12)+i sin(3pi/12))
k=2:
2^(1/6) (cos(-pi/12+2pi/3)+i sin(-pi/12+2pi/3))
2^(1/6) (cos(7pi/12)+i sin(7pi/12))
k=3:
2^(1/6) (cos(-pi/12+3pi/3)+i sin(-pi/12+3pi/3))
2^(1/6) (cos(11pi/12)+i sin(11pi/12))
k=4:
2^(1/6) (cos(-pi/12+4pi/3)+i sin(-pi/12+4pi/3))
2^(1/6) (cos(15pi/12)+i sin(15pi/12))
2^(1/6) (cos(5pi/4)+i sin(5pi/4))
k=5:
2^(1/6) (cos(-pi/12+5pi/3)+i sin(-pi/12+5pi/3))
2^(1/6) (cos(19pi/12)+i sin(19pi/12))
A sequence of 1 million iid symbols(+1 and +2), Xi, are transmitted through a channel and summed to produce a new random variable W. Assume that the probability of transmitting a +1 is 0.4. Show your work
a) Determine the expected value for W
b) Determine the variance of W
Answer:
E(w) = 1600000
v(w) = 240000
Step-by-step explanation:
given data
sequence = 1 million iid (+1 and +2)
probability of transmitting a +1 = 0.4
solution
sequence will be here as
P{Xi = k } = 0.4 for k = +1
0.6 for k = +2
and define is
x1 + x2 + ................ + X1000000
so for expected value for W
E(w) = E( x1 + x2 + ................ + X1000000 ) ......................1
as per the linear probability of expectation
E(w) = 1000000 ( 0.4 × 1 + 0.6 × 2)
E(w) = 1600000
and
for variance of W
v(w) = V ( x1 + x2 + ................ + X1000000 ) ..........................2
v(w) = V x1 + V x2 + ................ + V X1000000
here also same as that xi are i.e d so cov(xi, xj ) = 0 and i ≠ j
so
v(w) = 1000000 ( v(x) )
v(w) = 1000000 ( 0.24)
v(w) = 240000
PLEASE gelp me with this, gelp me please oh please gelp me!
Answer:
V = 2143.57 cm^3
Step-by-step explanation:
The volume of a sphere is
V = 4/3 pi r^3
The diameter is 16 so the radius is 1/2 of the diameter or 8
V = 4/3 ( 3.14) (8)^3
V =2143.57333
Rounding to the nearest hundredth
V = 2143.57 cm^3
Answer:
2143.57 cm^3
Step-by-step explanation:
V = 4/3 * 3.14 * r^3
r = 1/2 * 16 = 8
So V = 4/3 * 3.14 * 8^3
= 2143.57 cm^3.
If a system of linear equations has no solution, what does this mean about the two lines?
Answer:
The two lines do not intersect, and are parallel to one another on a graph.
Step-by-step explanation:
A system of equations consists of two or more equations with two or more variables. The solution to these variables must satisfy all of the variables in the equations in the system at the same time. Usually, all the equations in the system are considered and solved simultaneously. A linear equation might have a unique solution, an infinite solution, or no solution at all.
A system with exactly one solution is called a consistent system, and it is said to be independent, and the graph of its lines intersects at the point that is the solution to the equations. A system with an infinite number of solution is said to be dependent and the lines are coincident on a graph.
If a system has no solution, it is said to be inconsistent . The graphs of the lines do not intersect, and the lines are parallel to one another on the graph.
For two lines of linear equations to have no solution, they must be parallel to each other i.e they must have the same slope.
The standard form of writing linear equation is expressed as y = mx + b
m is the slope of the line
b is the y-intercept
For two lines of linear equations to have no solution, they must be parallel to each other i.e they must have the same slope.
For instance, the system of equations y = 2x + 7 and y = 2x - 3 have no solutions because they have the same slope.
Learn more on system of equation here: https://brainly.com/question/12526075
Which option is correct and how would one solve for it?
Answer:
28
Step-by-step explanation:
We need to find the value of [tex]\Sigma_{x=0}^3\ 2x^2[/tex]
We know that,
[tex]\Sigma n^2=\dfrac{n(n+1)(2n+1)}{6}[/tex]
Here, n = 3
So,
[tex]\Sigma n^2=\dfrac{3(3+1)(2(3)+1)}{6}\\\\\Sigma n^2=14[/tex]
So,
[tex]\Sigma_{x=0}^3\ 2x^2=2\times 14\\\\=28[/tex]
So, the value of [tex]\Sigma_{x=0}^3\ 2x^2[/tex] is 28. Hence, the correct option is (d).
A lime passes through the point (5,7) has a slope of 3. Which of the following gives the equation of the line
Answer:
Hey There!! The answer to this is (6, 10) There are no answer choices, so I will just list a few. But first, we need to create the equation.
Plugging in (5,7) into the equation y=mx+b, we can solve for b since all of the other variables are known, with m=3 as the slope.
So, 7=3*5+b
7=15+b
b = -8
y=3x-8 is your equation.
So, you can plug in any value of x you get a certain value of y.
(1,-5), (2,-2), (3,1), (4,4), (5,7), (6,10), (7,13) Thus, for The correct option (6, 10). Hope It Helped!~ ♡
ItsNobody~ ☆
Answer:
y=3x-8
Step-by-step explanation:
We can start by writing the equation of the line in point-slope form.
Point-slope form is y-y1=m(x-x1)
This is where:
y1= y-coordinate of a given point on the line
m= slope of the line
x1= x-coordinate of a given point on the line
The given point in this example is (5,7)
A point is (x-coordinate, y-coordinate)
Therefore,
y1=7
m=3
x1=5
Plug that into the form.
y-7=3(x-5)
We can now simplify that to slope-intercept form,since that is most standard.
y-7=3(x-5)
Start by distributing the right side.
y-7=3x-15
Add 7 to both sides.
y=3x-8
How many odd numbers with 4 different digits, can be formed using the digits 1, 2, 3, 4, 5, 6, 7, 8? (No repetition is allowed)
A. 71
B. 200
C. 210
D. 840
E.1680
Answer:
840 ( D )
Step-by-step explanation:
GIVEN DIGITS : 1,2,3,4,5,6,7,8
Number of odd numbers = 4
Number of even numbers = 4
therefore the number of odd numbers with 4 different digits can be formed by the same way the number of even numbers ( without repetition )
Hence the number of ways odd numbers with 4 different digits = Total number of ways of forming 4 digit numbers / 2
8*7*6*5 = 1680 / 2 = 840 ways
A hunter shot 7 ducks. The hunter's dog recovered 5/7 of the ducks. How many ducks were recover
Answer:
5
Step-by-step explanation:
Just multiply 5/7 by 7 since his dog retrieved 5/7 out of the 7 ducks he shot.
Answer:
5
Step-by-step explanation:
7*5/7
7 represents the # of ducks
5/7 represents the # of ducks that were recovered
The question asks the number of ducks that were recovered so you should multiply the total # of ducks there are by the fraction that were recovered.
PLEASE HELP!!! (1/5) - 50 POINTS-
Answer:
consistent independent
Step-by-step explanation:
This is a graph of consistent independent equations
The lines cross and there is one solution
Inconsistent equations never cross and there is no solutions
Consistent dependent equations are equations of the same line
Answer:
Linear
Step-by-step explanation:
This is a graph of linear system of equation.
The two lines represent different equations connected with each other.
They intersect at a common point showing the solution to the system of equation.
Find the first, second, third and fourth order Maclaurin polynomials of f(x) =
arctan(x). Draw the graph of f(x) and the four polynomials on the same
diagram. (Sketch by hand or use software.)
#urgent please give me this answer and help me#
The first, second, third and fourth order Maclaurin polynomials of f(x)=arctan(x) are:
The first order Maclaurin polynomial is f(x)=xThe second order Maclaurin polynomial is also f(x)=xThe third order Maclaurin polynomial is [tex]f(x)=x-\frac{1}{3}x^{3}[/tex]The fourth order Maclaurin polynomial is also [tex]f(x)=x-\frac{1}{3}x^{3}[/tex]You can see the graph on the attached picture.So let's start by finding the first order maclaurin polynomial:
f(x)=f(0)+f'(0)x
so let's find each part of the function:
f(0)=arctan(0)
f(0)=0
now, let's find the first derivative of f(x)
f(x)=arctan(x)
This is a usual derivative so there is a rule we can use here:
[tex]f'(x)=\frac{1}{x^{2}+1}[/tex]
so now we can find f'(0)
[tex]f'(0)=\frac{1}{(0)^{2}+1}[/tex]
f'(0)=1
So we can now complete the first order Maclaurin Polynomial:
f(x)=0+1x
which simplifies to:
f(x)=x
Now let's find the second order polynomial, for which we will need to get the second derivative of the function:
[tex]f(x)=f(0)+f'(0)x+\frac{f''(0)}{2!}x^{2}[/tex]
so:
[tex]f'(x)=\frac{1}{x^{2}+1}[/tex]
we can rewrite this derivative as:
[tex]f'(x)=(x^{2}+1)^{-1}[/tex]
and use the chain rule to get:
[tex]f''(x)=-1(x^{2}+1)^{-2}(2x)[/tex]
which simplifies to:
[tex]f''(x)=-\frac{2x}{(x^{2}+1)^{2}}[/tex]
now, we can find f''(0):
[tex]f''(0)=-\frac{2(0)}{((0)^{2}+1)^{2}}[/tex]
which yields:
f''(0)=0
so now we can complete the second order Maclaurin polynomial:
[tex]f(x)=0+1x+\frac{0}{2!}x^{2}[/tex]
which simplifies to:
f(x)=x
Now let's find the third order polynomial, for which we will need to get the third derivative of the function:
[tex]f(x)=f(0)+f'(0)x+\frac{f''(0)}{2!}x^{2}+\frac{f'''(0)}{3!}x^{3}[/tex]
so:
[tex]f''(x)=-\frac{2x}{(x^{2}+1)^{2}}[/tex]
In this case we can use the quotient rule to solve this:
Quotient rule: Whenever you have a function in the form , then it's derivative is:
[tex]f'(x)=\frac{p'q-pq'}{q^{2}}[/tex]
in this case:
p=2x
p'=2
[tex]q=(x^{2}+1)^{2}[/tex]
[tex]q'=2(x^{2}+1)(2x)[/tex]
[tex]q'=4x(x^{2}+1)[/tex]
So when using the quotient rule we get:
[tex]f'(x)=\frac{p'q-pq'}{q^{2}}[/tex]
[tex]f'''(x)=\frac{(2)(x^{2}+1)^{2}-(2x)(4x)(x^{2}+1)}{((x^{2}+1)^{2})^{2}}[/tex]
which simplifies to:
[tex]f'''(x)=\frac{-2x^{2}-2+8x^{2}}{(x^{2}+1)^{3}}[/tex]
[tex]f'''(x)=\frac{6x^{2}-2}{(x^{2}+1)^{3}}[/tex]
now, we can find f'''(0):
[tex]f'''(0)=\frac{6(0)^{2}-2}{((0)^{2}+1)^{3}}[/tex]
which yields:
f'''(0)=-2
so now we can complete the third order Maclaurin polynomial:
[tex]f(x)=0+1x+\frac{0}{2!}x^{2}-\frac{2}{3!}x^{3}[/tex]
which simplifies to:
[tex]f(x)=x-\frac{1}{3}x^{3}[/tex]
Now let's find the fourth order polynomial, for which we will need to get the fourth derivative of the function:
[tex]f(x)=f(0)+f'(0)x+\frac{f''(0)}{2!}x^{2}+\frac{f'''(0)}{3!}x^{3}+\frac{f^{(4)}(0)}{4!}x^{4}[/tex]
so:
[tex]f'''(x)=\frac{6x^{2}-2}{(x^{2}+1)^{3}}[/tex]
In this case we can use the quotient rule to solve this:
[tex]f'(x)=\frac{p'q-pq'}{q^{2}}[/tex]
in this case:
[tex]p=6x^{2}-2[/tex]
p'=12x
[tex]q=(x^{2}+1)^{3}[/tex]
[tex]q'=3(x^{2}+1)^{2}(2x)[/tex]
[tex]q'=6x(x^{2}+1)^{2}[/tex]
So when using the quotient rule we get:
[tex]f'(x)=\frac{p'q-pq'}{q^{2}}[/tex]
[tex]f^{4}(x)=\frac{(12x)(x^{2}+1)^{3}-(6x^{2}-2)(6x)(x^{2}+1)^{2}}{((x^{2}+1)^{3})^{2}}[/tex]
which simplifies to:
[tex]f^{4}(x)=\frac{12x^{3}+12x-6x^{3}+12x}{(x^{2}+1)^{4}}[/tex]
[tex]f^{4}(x)=\frac{6x^{3}+24x}{(x^{2}+1)^{4}}[/tex]
now, we can find f^{4}(0):
[tex]f^{4}(x)=\frac{6(0)^{3}+24(0)}{((0)^{2}+1)^{4}}[/tex]
which yields:
[tex]f^{4}(0)=0[/tex]
so now we can complete the fourth order Maclaurin polynomial:
[tex]f(x)=0+1x+\frac{0}{2!}x^{2}-\frac{2}{3!}x^{3}+\frac{0}{4!}x^{4}[/tex]
which simplifies to:
[tex]f(x)=x-\frac{1}{3}x^{3}[/tex]
you can find the graph of the four polynomials in the attached picture.
So the first, second, third and fourth order Maclaurin polynomials of f(x)=arctan(x) are:
The first order Maclaurin polynomial is f(x)=xThe second order Maclaurin polynomial is also f(x)=xThe third order Maclaurin polynomial is [tex]f(x)=x-\frac{1}{3}x^{3}[/tex]The fourth order Maclaurin polynomial is also [tex]f(x)=x-\frac{1}{3}x^{3}[/tex]You can find further information on the following link:
https://brainly.com/question/17440012?referrer=searchResults
In a class of 70 pupils, 36 like tasty time , 34 like ice-
cream, 6 like both tasty time }
draw a Venn diagram to show the data.
find how
many
like neither tasty time nor ice-cream
Step-by-step explanation:
I think this might be the correct answer
The number of pupils that like neither tasty-time nor ice cream is 6 if in a class of 70 pupils, 36 like tasty time, 34 like ice cream, 6 like both tasty times.
What is the Venn diagram?It is defined as the diagram that shows a logical relation between sets.
The Venn diagram consists of circles to show the logical relation.
We have:
In a class of 70 pupils, 36 like tasty time, 34 like ice cream, 6 like both tasty time.
Total = 70 pupils
Number of like tasty time = 36
Number of like ice cream = 34
Number of like both = 6
Let x be the total number of pupils that like neither tasty-time nor ice cream
The number of pupils that like ice cream only = 34 - 6 = 28
The number of pupils that like tasty-time only = 36 - 6 = 30
From the Venn diagram:
28 + 30 + 6 + x = 70
x = 70 - 64
x = 6
Thus, the number of pupils that like neither tasty-time nor ice cream is 6 if in a class of 70 pupils, 36 like tasty time, 34 like ice cream, 6 like both tasty times.
Learn more about the Venn diagram here:
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#SPJ2
Find
two consecutive numbers
odd numbers such that the
sum of the
greater number
and 5 times the smaller
number is 92. Please give detailed step by step answer
Answer:
The two odd numbers are 15 and 17
Step-by-step explanation:
Given
Let the odd numbers be represented with x and y
Let x be the greater number
[tex]x + 5y = 92[/tex]
Required
Find x and y
Since x and y are consecutive odd numbers and x is greater, then
[tex]x = y + 2[/tex]
Substitute y + 2 for x in [tex]x + 5y = 92[/tex]
[tex]y + 2 + 5y = 92[/tex]
Collect Like Terms
[tex]y + 5y = 92 - 2[/tex]
[tex]6y = 90[/tex]
Divide both sides by 6
[tex]\frac{6y}{6} = \frac{90}{6}[/tex]
[tex]y = \frac{90}{6}[/tex]
[tex]y = 15[/tex]
Substitute 15 for y in [tex]x = y + 2[/tex]
[tex]x = 15 + 2[/tex]
[tex]x = 17[/tex]
Hence; the two odd numbers are 15 and 17
Answer:
Maths
Step-by-step explanation:
Answer:
The two odd numbers are 15 and 17
Step-by-step explanation:
Given
Let the odd numbers be represented with x and y
Let x be the greater number
Required
Find x and y
Since x and y are consecutive odd numbers and x is greater, then
Substitute y + 2 for x in
Collect Like Terms
Divide both sides by 6
Substitute 15 for y in
Hence; the two odd numbers are 15 and 17
GIVING OUT BRAINLIEST TO THE FIRST PERSON WHO ANSWERS!! I would appreciate if if you do answer though! <3
Also, include ALL work!
Answer:
The answer is option BStep-by-step explanation:
Total number of people = 800
To find the number of unemployed people we must first find the total percentage of the pie chart
That's
25 + 10 + 5 + 60 = 100%
5 % out of the 100% are unemployed
To find the number of unemployed people divide 5 % by the total percentage that's 100% and multiply them by the total number of people
That's
[tex] \frac{5}{100} \times 800[/tex]
5 × 8
We have the final answer as
40 peopleHope this helps you
A number to be multiplied is called a?
Answer:
The number to be multiplied is the "multiplicand"
Step-by-step explanation:
a base when it is written in exponential notation
Simplify your answer as much as possible.
Find the area of the triangle with the following measurements: B = 67°, a = 13 cm, c = 21 cm
9514 1404 393
Answer:
125.6 cm²
Step-by-step explanation:
The relevant area formula is ...
Area = (1/2)ac·sin(B)
Area = (1/2)(13 cm)(21 cm)·sin(67°) ≈ 125.6 cm²
The line perpendicular to y=3/4x+7 containing (3,-4)
Answer:
y = - [tex]\frac{4}{3}[/tex] x
Step-by-step explanation:
1). [tex]y_{1}[/tex] = [tex]m_{1}[/tex] [tex]x_{1}[/tex] + [tex]b_{1}[/tex]
[tex]y_{2}[/tex] = [tex]m_{2}[/tex] [tex]x_{2}[/tex] + [tex]b_{2}[/tex]
[tex]y_{1}[/tex] ⊥ [tex]y_{2}[/tex] if [tex]m_{2}[/tex] = - [tex]\frac{1}{m_{1} }[/tex]
2). ( [tex]x_{3}[/tex] , [tex]y_{3}[/tex] )
y - [tex]y_{3}[/tex] = m( x - [tex]x_{3}[/tex] )
~~~~~~~~~~~~~~~~~~
y = [tex]\frac{3}{4}[/tex] x + 7
[tex]m_{1}[/tex] = [tex]\frac{3}{4}[/tex]
[tex]m_{2}[/tex] = - [tex]\frac{4}{3}[/tex]
( 3, - 4 )
y - ( - 4) = - [tex]\frac{4}{3}[/tex] ( x - 3 )
y + 4 = - [tex]\frac{4}{3}[/tex] x + 4
y = - [tex]\frac{4}{3}[/tex] x
Give the domain and range.
x –2 0 2 y –1 0 1
a. domain: {2, 0, 2}, range: {1, 0, 1} b. domain: {–2, 0, 2}, range: {–1, 0, 1} c. domain: {–1, 0, 1}, range: {–2, 0, 2} d. domain: {1, 0, 1}, range: {2, 0, 2}
Answer:
B. domain {-2, 0, 2}, range {-1, 0, 1}
Step-by-step explanation:
The x values and y values as ordered pairs would be: (-2,-1), (0,0), (2,1)
The domain is the all of the values of x and the range is all the values of y.
Find the largest integer which belongs to the following interval: (−∞, 8)
Answer:
7
Step-by-step explanation:
The following range includes numbers from negative infinity to 8. But, 8 isn't included, because there is a parentheses not a bracket. So, basically you can have 7.9999999. But, it asks for an integer, so it is 7.
The largest integer which belongs to the interval: (−∞, 8) is 7
To determine the largest integer, we will first ascertain what the use of parentheses and brackets denote.
The use of parentheses ( ) stands for open interval, that is, the extreme numbers of the set are not included.
If the brackets [ ] were used instead, that will be closed interval, that is, the extreme numbers of the set are included.
Since ( ) were used in the question, that means the extreme numbers −∞ and 8 are NOT included in the set.
Now, let us define an integer.
An integer is a positive or negative whole number or zero.
Hence, the integers in the set will include: −∞+1, −∞ + 2, ... 5, 6, and 7.
The largest integer here is 7
Hence, the largest integer which belongs to the interval: (−∞, 8) is 7
Learn more in the link below:
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Nicole ordered a volleyball for $9.75
Answer:
the other person is right
you should try putting the WHOLE question
Step-by-step explanation:
Using Normal Distribution, what is the area to the right of 0.72 under the
standard normal curve?
Answer: 0.2358
Step-by-step explanation:
Using Normal Distribution, under the standard normal curve
The area to the right of z is given by P(Z>z)=1-P(Z<z)
So, the area to the right of z= 0.72 under the standard normal curve would be:
P(Z>0.72)=1-P(z<0.72)
=1-0.7642 [By using p-value table]
= 0.2358
Hence, the area to the right of z= 0.72 under the standard normal curve is 0.2358 .
Line l has a slope of −6/13. The line through which of the following pair of points is perpendicular to l? A. (13,−4),(−7,2) B. (6,−4),(−7,2) C. (2,6),(−4,−7) D. (6,9),(−4,−4)
=========================================================
Explanation:
The original line has a given slope of -6/13. The opposite reciprocal is 13/6. We flip the fraction and the sign from negative to positive.
With any two perpendicular slopes, they always multiply to -1
(-6/13)*(13/6) = (-6*13)/(13*6) = -78/78 = -1
--------------------
Since the perpendicular slope is 13/6, we need to see which of the four answer choices produces a slope of 13/6. Use the slope formula.
This is something you do through trial and error. You could start with A and work your way to D, or just pick at random. I'll go through each one by one starting at choice A.
---------------------
Let's try choice A
m = (y2 - y1)/(x2 - x1)
m = (2 - (-4))/(-7 - 13)
m = (2 + 4)/(-7 - 13)
m = 6/(-20)
m = -3/10, we can see that choice A is not the answer, since we want m = 13/6 instead.
-----------------------
Let's try choice B
m = (y2 - y1)/(x2 - x1)
m = (2 - (-4))/(-7 - 6)
m = (2 + 4)/(-7 - 6)
m = 6/(-13)
m = -6/13, that doesn't work either
------------------------
Let's try choice C
m = (y2 - y1)/(x2 - x1)
m = (-7 - 6)/(-4 - 2)
m = -13/(-6)
m = 13/6, we found the answer
------------------------
For the sake of completeness, here is what choice D would look like
m = (y2 - y1)/(x2 - x1)
m = (-4 - 9)/(-4 - 6)
m = -13/(-10)
m = 13/10, which isn't the slope we want
Given the function f(x) = 3x - 1, explain how to find the average rate of change between x = 1 and x = 4.
Step-by-step explanation:
f(1) = 3×1 - 1 = 2
f(4) = 3×4 - 1 = 12-1 = 11
so, the functional value changes 11-2=9 units on an x interval of 4-1=3 units length.
the average change rate is the total change across the x interval relative to the interval length.
that is
9/3 = 3
which is the slope (= the factor of x) in the line equation.
for a line its change rate for any point is the same constant. and that is therefore automatically also the average change rate across an interval of x values.
if the change rate would be different for different parts of the function, it would not be a straight line.
Answer:
3
Step-by-step explanation:
The average rate of f(x) in the closed interval [ a, b ] is
[tex]\frac{f(b)-f(a)}{b-a}[/tex]
Here [ a, b ] = [ 1, 4 ] , then
f(b) = f(4) = 3(4) - 1 = 12 - 1 = 11
f(a) = f(1) = 3(1) - 1 = 3 - 1 = 2
average rate of change = [tex]\frac{11-2}{4-1}[/tex] = [tex]\frac{9}{3}[/tex] = 3
find the length of the arc . round your answers to the nearest tenth PLEASE HURRY
Answer:
10.2
Step-by-step explanation:
Length of arc=(2*pi*r)*(theta/360)
Length of arc=(2*pi*3)*(195/360)=10.2
What is the domain of f(x) = 5^x - 7?
O {x|x>-7)
O {XIX<-7}
O {x|x>0}
O {x | x is a real number}
Step-by-step explanation:
{ x| x all real numbers}
The domain of f(x) = 5x – 7 will be all real numbers, as the function is a straight line, with no discontinuities, thus undefined at no value of x.
The domain of the function f(x) = 5ˣ - 7 is {x | x is a real number}.
What is Function?A function is a relation from a set A to a set B where the elements in set A only maps to one and only one image in set B. No elements in set A has more than one image in set B.
Given function is,
f(x) = 5ˣ - 7
The domain of the function is the set of all values of x such that the function is defined.
If we use any number for x, the function will be defined.
So the domain is the set of all real numbers.
So the correct option is last one {x | x is a real number}.
Hence the domain of the given function is {x | x is a real number}.
Learn more about Domain here :
https://brainly.com/question/13113489
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[tex]log(x) * log(2)[/tex]
Why can't this problem be solved?
Answer:
Because it is not an equation.
Step-by-step explanation:
[tex] log(x) \times log(2) \\ = log(x + 2) [/tex]
Please find the answer !
Answer:
ring volume is 12cm3
Step-by-step explanation:
Lr ccm=volume of water and ring - Volume of water
ring cubic centimeters =x
x=9.2cm*4.5cm*7cm - 8.8cm*4.5cm*7cm
x=289.2cm3 - 277.2cm3
x=12cm3
Question
Consider this expression.
4/2² - 6²
Type the correct answer in the box. Use numerals instead of words. For help, see this worked example e.
When a =
-5 and b = 3, the value of the expression is
Submit
Answer:
16
Step-by-step explanation:
4 * sqrt( a^2 - b^2)
Let a = -5 and b =3
4 * sqrt( (-5)^2 - 3^2)
Do the squaring first
4 * sqrt( 25 - 9)
Subtract inside the square root
4 * sqrt( 16)
Take the square root
4 * 4
Multiply 16
Answer:
[tex]\Large \boxed{16}[/tex]
Step-by-step explanation:
[tex]4\sqrt{a^2-b^2 }[/tex]
[tex]\sf Plug \ in \ the \ values \ for \ a \ and \ b.[/tex]
[tex]4\sqrt{-5^2-3^2 }[/tex]
[tex]4\sqrt{25-9 }[/tex]
[tex]4\sqrt{16}[/tex]
[tex]4 \times 4=16[/tex]