Consider these functions:
х
g(x)
h(x)
0
0 0
NO
6
What is the value of x when gh(x)) = 4?
O A 0
OB. 2
OC. 4
OD 5

Answer:

1,390 I think that's the answer

Step-by-step explanation:

hope that helps

The expression equivalent to 40x + 30y are 5(8x + 6y), 10(4x + 3y) and 2(20x + 15y).

Expressions are mathematical statements which consist of two or more terms and terms are connected to each other using mathematical operators like addition, multiplication, subtraction and so on.

Given are some expressions in the options.

Distributive rule says that,

a ( b + c ) = (a b) + (a c), where a, b and c are any numbers.

5x(8 + 6) = 5x(14) = 70x

5(8x + 6y) = 40x + 30y

10(40x + 30y) = 400x + 300y

10(4x + 3y) = 40x + 30y

2y(20x + 15) = 40xy + 30y

2(20x + 15y) = 40x + 30y

Hence the expressions which are equivalent to 40x + 30y are 5(8x + 6y), 10(4x + 3y) and 2(20x + 15y).

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The complete question is :

Which of the following expressions are equivalent to 40x+30y. Choose all that apply.

5x(8 + 6)

5(8x + 6y)

10(40x + 30y)

10(4x + 3y)

2y(20x + 15)

2(20x + 15y)

Answer:

77

Step-by-step explanation:

6x2 = 12

13x5 = 65

65+12 = 77

The answer is 77.

Answer:

A

Step-by-step explanation:

Answer:

Step-by-step explanation:

The prime factor representation of 150 is 2 x 3 x 5^2

Using the Central Limit Theorem, it is found that the mean of the sampling distribution of sample proportions is 0.37.

The Central Limit Theorem establishes that, for a proportion p in a sample of size n, the sampling distribution of sample proportions has:

For this problem, about 37% of high school seniors have vaped in the past year, hence [tex]p = 0.37[/tex].

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The given ratios expresses the number of time a value is larger or smaller

than another value.

The correct responses are;

Reasons:

3. Given that the perimeter of the rectangle = 72

The ratio of the lengths of the sides = 1:2

Let a and b represent the sides, we have;

2·a + 2·b = 72

[tex]\displaystyle \frac{a}{b} = \mathbf{\frac{1}{2}}[/tex]

Which gives;

2·a = b

2·a + 2·(2·a) = 72

6·a = 72

a = 72 ÷ 6 = 12

b = 2·a = 2 × 12 = 24

The lengths of the sides are; (B) 12 and 24

4. Extended ratio = 2:3:7

The perimeter = 36

The lengths of the sides are;

[tex]\displaystyle \frac{2}{2 + 3 + 7} \times 36 = \mathbf{6}[/tex]

[tex]\displaystyle \frac{3}{2 + 3 + 7} \times 36 = \mathbf{9}[/tex]

[tex]\displaystyle \frac{7}{2 + 3 + 7} \times 36 = \mathbf{21}[/tex]

The lengths are; (D) 6, 9, 21

5. The given equation is presented as follows;

[tex]\displaystyle \frac{5}{x + 7} = \mathbf{\frac{3}{x + 2}}[/tex]

5 × (x + 2) = 3 × (x + 7)

5·x + 10 = 3·x + 21

5·x - 3·x  = 21 - 10

2·x = 11

[tex]\displaystyle x = \mathbf{ \frac{11}{2}}[/tex]

The correct option is; [tex]\displaystyle \underline{(E) \ \frac{11}{2}}[/tex]

6. The width to length ratio is [tex]\displaystyle \mathbf{\frac{2.5}{7.0}}[/tex]

The simplified ratio is therefore;

[tex]\displaystyle \frac{2.5}{7.0} = \frac{2 \times 2.5}{2 \times 7.0} = \mathbf{\frac{5}{14}}[/tex]

The correct option is (E) [tex]\displaystyle \underline{(E) \ \frac{5}{14}}[/tex]

7. The given ratio of the lengths is 3:1

Therefore;

[tex]\overline{BC}[/tex]:[tex]\overline{EF}[/tex] = 3:1

Which gives;

[tex]\displaystyle \mathbf{\frac{\overline{BC}}{\overline{EF}}} = \frac{3}{1}[/tex]

[tex]\overline{BC}[/tex] = 18

Therefore;

[tex]\displaystyle \frac{18}{\overline{EF}} = \frac{3}{1}[/tex]

18 × 1 = 3 × [tex]\overline{EF}[/tex]

[tex]\displaystyle \overline{EF} = \frac{18 \times 1}{3} = 6[/tex]

[tex]\overline{EF}[/tex] = 6

By Pythagorean theorem, we have;

[tex]\overline{DF}[/tex]² = [tex]\mathbf{\overline{DE}}[/tex]² + [tex]\mathbf{\overline{EF}}[/tex]²

Which gives;

[tex]\overline{DF}[/tex]² = 3² + 6² = 45

[tex]\overline{DF}[/tex] = √(45) = 3·√5

Using the given ratio, we have;

[tex]\overline{AC}[/tex] = 3 × [tex]\mathbf{\overline{DF}}[/tex]

Which gives;

[tex]\overline{AC}[/tex] = 3 × 3·√5 = 9·√5

[tex]\overline{AC}[/tex] = 9·√5

The correct option is; (B) [tex]\overline{EF}[/tex] = 6, [tex]\overline{AC}[/tex] = 9·√5

8. EF = 1, AB = 2

CD = 2, CE = 4

Therefore;

[tex]\displaystyle \mathbf{\frac{EF}{AB}} =\frac{1}{2}[/tex]

[tex]\displaystyle \mathbf{\frac{CD}{CE}} =\frac{2}{4} = \frac{1}{2}[/tex]

Which gives;

[tex]\displaystyle \frac{EF}{AB} =\displaystyle \mathbf{\frac{CD}{CE}}[/tex]

(C) The values are equal

9. AC = 6, BE = 8

DF = 3, BD = 6

Column A

[tex]\displaystyle \frac{AC}{BE} =\displaystyle \mathbf{\frac{6}{8}} = \frac{3}{4}[/tex]

Column B

[tex]\displaystyle \frac{DF}{BD} =\displaystyle \mathbf{\frac{3}{6}} = \frac{1}{2}[/tex]

[tex]\displaystyle \frac{3}{4} > \mathbf{\frac{1}{2}}[/tex]

Therefore;

Column A is greater than column B

(A) The value in column A is greater

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Answer:

-17

Step-by-step explanation:

it's telling you to replace x with -3.

You have to replace all the x's with -3.

(-3)2 + (-3) - 8 = -17

Answer:

48

Step-by-step explanation:

75/100 = 36/x

x = 48

Answer:

UP THE DOWN THAT WHAT I GOT

Step-by-step explanation:

A. - 7x² + 7x + 1 + 8 = 0

- 7x² + 7x + 9 = 0

x = - b ± √b² - 4ac / 2a

= - 7 ± √7² - 4 (-7) (9) / 2 (-7)

= - 7 ± √49 + 252 / - 14

= - 7 ± √ 301 / - 14

x = - 7 + 17.349 / - 14 x = - 7 - 17.349 / - 14

= 10.349 / - 14 = - 24.349 / - 14

= - 0.739 = - 1.739

B. 8x² - 5x² + 6x + 1 = 0

3x² + 6x + 1 = 0

x = - b ± √b² - 4ac / 2a

= - (-5) ± √-5² - 4 (3) (1) / 2 (3)

= 5 ± √25 - 12 / 6

= 5 ± √ 13 / 6

x = 5 + 3.606 /6 x = - 5 - 3.606 / 6

= 8.606/6 = - 8.606/6

= 1.434. = - 1.434

please re-check the answers hope this helps

Answer:

Coordinate  form is [tex](x,y)=(2,3)[/tex]

Step-by-step explanation:

Usually the form is

[tex]f(x)=y[/tex]

Here

We have [tex]f(2)=3[/tex]

Hence [tex](x,y)=(2,3)[/tex]

Let m = slope of the line.

m = delta y/delta x

m = (-70 -(-44)/(-1 -(-2)

m = (-70 + 44)/(-1 + 2)

m = -26/1

m = -26

Understand?

[tex](9+7i)(6+3i)\\\\=54+27i + 42i + 21i^2\\\\=54+69i -21~~~;[i^2 =-1]\\\\=33+69i[/tex]

The domain of the function to know the number of cars remaining on any day during the month is [0, 40]. The maximum and minimum values are 120 and 0 respectively.

The domain is the all inputted value for which the function is defined. All the x values are domain of a function.

Now, finding the domain of the function,

We know that, the number of cars cannot be negative, so

[tex]f(x)\geq0\\120-3x\geq0\\3x\leq120\\x\leq40[/tex]

The number of cars should be greater than 0, so x > 0.

So, the domain will be [0, 40].

The maximum value is given by putting x = 0,

[tex]f(0)=120-3(0)\\=120[/tex]

The minimum value is given by putting x = 40,

[tex]f(40)=120-3\times40\\=120-120\\=0[/tex]

Therefore, the domain of the function f(x)=120-3x to know the number of cars remaining on any day during the month is [0, 40]. The maximum and minimum values are 120 and 0 respectively.

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Answer: 21

Step-by-step explanation:

Answer:

b=(r/5)-a

Step-by-step explanation:

To solve, you do the mathematics.

r=5(b+a)

r=5b+5a

5b=r-5a

b=(r/5)-a

Using translation concepts, the equation will be given by:

[tex]g(x) = (x + 8)^3 + 3[/tex]

The parent function is:

[tex]f(x) = x^3[/tex]

Shifting a function left 8 units means that [tex]g(x) = f(x + 8)[/tex], hence:

[tex]g(x) = f(x + 8) = (x + 8)^3[/tex]

Shifting a function up 3 units means that 3 is added to the function, that is, [tex]g(x) = f(x + 8) + 3[/tex], hence:

[tex]g(x) = f(x + 8) + 3 = (x + 8)^3 + 3[/tex]

Which is the desired equation.

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Answer:

52

Step-by-step explanation:

Answer:

52

Step-by-step explanation:

The top has 6 faces, so 6 x 2 = 12

The bottom has the same, 12

The left side has 3, 3 x 2 = 6

The front and inside has 6, x 2 = 12

The right side has 2 x 2 = 4

The back has 3 x 2 = 6

12 + 12 + 6 + 12 + 4 + 6 = 52

Kind of, Market day as in make stuff and then sell it or Market day as in Sell food, I remember this in elementary school 2 Different Kind of Market day :)

This is right answer because option d only shows that y are multiples in sequence but this answer shows the correct sequence

A is correct! Our base number is 9 since it's at x = 0. The number gets smaller as x increases, so it will be 1/3 instead of 3.

Hope this helps :)

if their corresponding angles are congruent and the corresponding sides are in proportion ...so it will be similar triangle

Answer:

48 and 32 6 hours clearing tables and 2 hours tutoring

Step-by-step explanation:

we can rewrite this as a fraction. we will use 1/10s because 80 can be divided by 8 which is in the problem. we then have to find out what two numbers add up to 8 but one is 3 times the other. 6 and 2 fit into this problem so we plug it into the equation and we write it as this 6x+4x=80 where x is 8. we get 48 and 32.

Answer:

4/8 = 1/2 = 0.5 is your answer

Answer:

The distance formula is 22.360679775

if you round it to the nearest tenth, then the answer is 22.4

Step-by-step explanation:

(-6, -12) and (4,8)

(x2 - x1)² + (y2 - y1)²

Place the x and y values

(4 - - 6)² + (8 - - 12)²

= 10² + 20²

= 100 + 400 = 500

√500 = 22.360679775

Round it to the nearest tenth and you will get 22.4

Hope this helps!

please mark me as the brainliest

The formula in finding the distance between two points is given below:

where:

Substitute the given values into the distance formula and solve for d:

Therefore, the distance between the two points is 22.4 units (nearest tenth).

Cheers!

Step-by-step explanation:

this is a rectangle. so, all things are symmetric.

EI = IG = FI = IH

IGF = IFG = IEH = IHE

therefore, since EI = FI

2x + 8 = 6x - 20

28 = 4x

x = 7

now,

EG = EI + IG = 2×EI = 2×(2×7 + 8) = 2×22 = 44

IFE is a complementary angle to IFG (together they have 90°).

and because IFG = IGF = 30°

IFE = 90 - 30 = 60°