Consider the reaction: mg(oh)₂ (s) ⇌ mg²⁺ (aq) + 2 oh⁻ (aq) at equilibrium, a 1. 0 l reaction vessel contains 5. 3 moles of mg(oh)₂ and concentrations of 0. 0080 m and 0. 010 m of mg²⁺ and oh⁻ respectively. What is kc for this equilibrium? note kc is sometimes called k

The system's Kc is 8 10-7,The relationship between the equilibrium concentrations of products and reactants.

Finding KC in equilibrium: how do you accomplish it?

Kc Formula: Kc=[C]c[D]d[A]a[B]b] is the formula for calculating Kc. K c = [C] c [D] d [A] a [B] b, where [C] and [D] are the equilibrium molar concentrations of the products and [A] and [B] are the equilibrium molar concentrations of the reactants.

The relationship between the equilibrium concentrations of products and reactants, each raised to the power of their respective stoichiometric coefficients, is known as the equilibrium constant, or Kc.

The reaction's equation is Mg(OH)2 (s) = Mg2+ (aq) + 2 OH (aq)

The question instructs us to look for the Kc of the reaction.

Kc = [Mg2+] [OH]

Remember that since Mg(OH)2 is a pure solid, it is not included in the equilibrium expression.

substituting values;

[Mg²⁺] = 0.0080 M

[ OH⁻ ] = 0.010 M

Kc = [0.0080 M] [0.010 M ]^2

Kc = 8 × 10^-7.

To learn more about KC in equilibrium refer to:

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