Consider Functions F and G

Answer:

A

Step-by-step explanation:

We are given two functions:

[tex]\displaystyle f(x)=\frac{x-16}{x^2+6x-40}\text{ and } g(x)=\frac{1}{x+10}[/tex]

And we want to find:

[tex]f(x)+g(x)[/tex]

Thus:

[tex]\displaystyle =\frac{x-16}{x^2+6x-40}+\frac{1}{x+10}[/tex]

We can factor the denominator of the first term:

[tex]\displaystyle =\frac{x-16}{(x+10)(x-4)}+\frac{1}{x+10}[/tex]

In order to add the two terms, we must have a common denominator. To achieve this, we can multiply to second term by (x - 4). Therefore:

[tex]\displaystyle =\frac{x-16}{(x+10)(x-4)}+\frac{1}{x+10}\Big(\frac{x-4}{x-4}\Big)[/tex]

Multiply:

[tex]\displaystyle =\frac{x-16}{(x+10)(x-4)}+\frac{x-4}{(x+10)(x-4)}[/tex]

Combine:

[tex]\displaystyle =\frac{(x-16)+(x-4)}{(x+10)(x-4)}[/tex]

Simplify:

[tex]\displaystyle =\frac{2x-20}{(x+10)(x-4)}[/tex]

We can expand the denominator:

[tex]\displaystyle =\frac{2x-20}{x^2+6x-40}[/tex]

Therefore, our answer is A.

Answer:

A

Step-by-step explanation:

Solve for x by completing the square. Round ur answer to the nearest thousandth. X^2+6x-3=0

5x+8 = 18
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