Complete the statement. Explain your
reasoning
7
3
26
8 4 15 C

Answer:

4350

Step-by-step explanation:

Linda's net and first term of the expression is correct and the surface area of the attic is 4425 square feet.

The area of a three dimensional object on it's outer surface is called the surface area of the object.

Given the attic of Linda's home.

Attic is in the shape of triangular prism.

The net that Linda drawn is correct since she expresses all the measurements right in the net.

So, the net Linda drew is correct.

We can find the surface area from the net of the prism.

Net of the prism consists of 2 identical triangles, 2 identical rectangles and a rectangle.

Area of triangle is  [tex]\frac{1}{2}[/tex] × base × height and that of rectangle = length × width

Area of 2 triangles = 2 × [tex]\frac{1}{2}[/tex] × 25 × 15 = 25 × 15

Area of rectangles = (45 × 40) + (45 × 25) + (45 × 25)

                               = 45(40 + 25 + 25)

Total surface area = 45(40 + 25 + 25) + (25 × 15)

The first term of Linda's expression, 45(40 + 25 + 25) is correct.

The second term of Linda's expression, ([tex]\frac{1}{2}[/tex] × 25 × 15) is not correct.

Surface area of the attic = 45(40 + 25 + 25) + (25 × 15)

                                        = 4425 square feet

Hence the surface area of the attic is 4425 square feet.

Learn more about Surface Area here :

https://brainly.com/question/28307440

#SPJ7

The complete question is given below.

Answer:

Is this in a different language?

Step-by-step explanation:ok:)

Answer:

Exact form: 157/20

Decimal Form: 7.85

Mixed Number Form: 7/17/20

Step-by-step explanation:

Answer: Add 11 to the other side of the equation, giving you 81. Then, since x is square you are going to need to square root both sides ([tex]\sqrt{x}[/tex] this symbol). When you do that, you should get what x is! Let me know if you still need help!

Answer:

he will fill 6 pitchers

Step-by-step explanation:

4.8÷0.8=6

Answer:

The instantaneous rate of change as x approaches 3 is 18.

Step-by-step explanation:

From Differential Calculus and Geometry we remember that instantaneous rate of change of the function is represented by a tangent line, whose slope is determined by the first derivative of the curve. Let [tex]f(x) = 3\cdot x^{2}[/tex], the instantaneous rate of change of the function when x approaches 3 is deducted from the definition of derivative:

[tex]f'(x) = \lim_{h \to 0} \frac{f(x+h)-f(x)}{h}[/tex] (1)

[tex]f'(x) = \lim_{h\to 0} \frac{3\cdot (x+h)^{2}-3\cdot x^{2}}{h}[/tex]

[tex]f'(x) = \lim_{h\to 0} \frac{3\cdot (x^{2}+2\cdot x\cdot h +h^{2})-3\cdot x^{2}}{h}[/tex]

[tex]f'(x) = \lim_{h\to 0} \frac{3\cdot x^{2}+6\cdot x\cdot h+3\cdot h^{2}-3\cdot x^{2}}{h}[/tex]

[tex]f'(x) = \lim_{h\to 0} \frac{6\cdot x\cdot h +3\cdot h^{2}}{h}[/tex]

[tex]f'(x) = \lim _{h\to 0} (6\cdot x+3\cdot h)[/tex]

[tex]f'(x) = 6\cdot x \cdot \lim_{h\to 0} 1 + 3\cdot \lim_{h\to 0} h[/tex]

[tex]f'(x) = 6\cdot x[/tex] (2)

If we know that [tex]x = 3[/tex], then the instantaneous rate of change as x approaches 3 is:

[tex]f'(3) = 6\cdot (3)[/tex]

[tex]f'(3) = 18[/tex]

The instantaneous rate of change as x approaches 3 is 18.

Answer:

 [tex]y= -\frac{1}{3}x -6[/tex]

Step-by-step explanation:

Using the slope formula, you can form this equation! The slope of any equation would replace the m, and the y intercept would replace b!

I added in the slope formula at the bottom, just in case, so you'll see what I mean!

I hope this helps, and I explained enough! Have a great day c:

Answer:

so what is the question?

Answer:

[tex]T_n = 8+ 4n[/tex]

[tex]T_{11} = 52[/tex]

Step-by-step explanation:

Given

[tex]Sequence: 12, 16, 20, 24[/tex]

Solving (a): Write a formula

The above sequence shows an arithmetic progression

Hence:

The formula can be calculated using:

[tex]T_n = a + (n - 1) d[/tex]

In this case:

[tex]a = First\ Term = 12[/tex]

Difference (d) is difference of 2 successive terms

So:

[tex]d = 16 - 12 = 20 - 16 = 24 - 20[/tex]

[tex]d = 4[/tex]

Substitute 4 for d and 12 for a in [tex]T_n = a + (n - 1) d[/tex]

[tex]T_n = 12 + (n - 1) * 4[/tex]

Open Bracket

[tex]T_n = 12 + 4n - 4[/tex]

Collect Like Terms

[tex]T_n = 12 - 4+ 4n[/tex]

[tex]T_n = 8+ 4n[/tex]

Hence, the explicit formula is: [tex]T_n = 8+ 4n[/tex]

Solving (b): 11th term

This implies that n = 11

Substitute 11 for n in: [tex]T_n = 8+ 4n[/tex]

[tex]T_{11} = 8+ 4 * 11[/tex]

[tex]T_{11} = 8+ 44[/tex]

[tex]T_{11} = 52[/tex]

Answer:

A) The explicit formula for the sequence is [tex]f(n) = 12+4\cdot n[/tex], [tex]n \in \mathbb{N}_{O}[/tex].

B) The 11th term of the sequence is 62.

Step-by-step explanation:

A) Let [tex]f(0) = 12[/tex], we notice that sequence observes an arithmetic progression, in which there is a difference of 4 between two consecutive elements. The formula for arithmetic progression is:

[tex]f(n) = f(0) +r\cdot n[/tex] (1)

Where:

[tex]f(0)[/tex] - First value of the sequence, dimensionless.

[tex]r[/tex] - Arithmetic increase rate, dimensionless.

[tex]n[/tex] - Term of the value in the sequence, dimensionless.

If we know that [tex]f(0) = 12[/tex] and [tex]r = 4[/tex], then the explicit formula for the sequence is:

[tex]f(n) = 12+4\cdot n[/tex], [tex]n \in \mathbb{N}_{O}[/tex]

B) If we know that [tex]f(n) = 12+4\cdot n[/tex] and [tex]n = 10[/tex], the 11th term of the sequence is:

[tex]f(10) = 12+4\cdot (10)[/tex]

[tex]f(10) = 62[/tex]

The 11th term of the sequence is 62.

Answer:

A) None of the above

Step-by-step explanation

it's distributive property

Answer:

the answer is there should be another digit in the quotient

Answer:

No, because there should be another digit in the quotient

Answer:

Step-by-step explanation:

4x^3 + 7x^3 - 5x + 9x + 3 + 11 = 11x^3 + 4x + 14

Answer:

2a^2 b^3(3a^2 b^3 - 4ab^2 + 6)

Answer:

S(-2, -3)

Step-by-step explanation:

Find the diagram attached below,=. Frim the diagram, the coordinate of R and T are (-5, 3) and (-1, -5) respectively. If the ratio of RS to ST is 3:1, the coordinate of S can be gotten using the midpoint segment formula as shown;

S(X, Y) = {(ax1+bx2/a+b), (ay1+by1/a+b)} where;

x1 = -5, y1 = 3, x2 = -1, y2 = -5, a = 3 and b =1

Substitute the values into the formula;

X = ax2+bx1/a+b

X = 3(-1)+1(-5)/3+1

X = -3-5/4

X = -8/4

X = -2

Similarly;

Y = ay2+by1/a+b

Y = 3(-5)+1(3)/3+1

Y = -15+3/4

Y = -12/4

Y = -3

Hence the coordinate of the point (X, Y) is (-2, -3)

Answer:

y = 4/5x

Step-by-step explanation:

Her ya go!

Answer:

x=5

Both are vertical lines and parallel to each other.

Answer:

1.2

Step-by-step explanation:

0.3 * 4

= 3 * 0.1  * 4

= 3 * 4 * 0.1

= 12 * 0.1

= 1.2

Answer:

Two complex (imaginary) solutions.

Step-by-step explanation:

To determine the number/type of solutions for a quadratic, we can evaluate its discriminant.

The discriminant formula for a quadratic in standard form is:

[tex]\Delta=b^2-4ac[/tex]

We have:

[tex]3x^2+7x+5[/tex]

Hence, a=3; b=7; and c=5.

Substitute the values into our formula and evaluate. Therefore:

[tex]\Delta=(7)^2-4(3)(5) \\ =49-60\\=-11[/tex]

Hence, the result is a negative value.

If:

Since our discriminant is negative, this means that for our equation, there exists two complex (imaginary) solutions.

Answer:

$14.4

Step-by-step explanation:

I don't quite understand this question, but this is what I think

Answer:

280

Step-by-step explanation:

Month 1: 100 + 30 = 150

Month 2: +30

Month 3: +30

Month 4: +30

Month 5: +30

Month 6: +30

Total: 280

Hope this helps!

Answer:

$280

Step-by-step explanation:

For this problem, we simply need to take the initial cost of membership and add that to the reoccurring cost from a time period, in this case, 6 months.  So let's make an equation to represent this.

The initial cost is $100

The per month cost is $30

Total cost after 6 months = Inital cost + Per Month Cost * 6 months

Total cost = $100 + $30 * 6

Total cost = $100 + $180

Total cost = $280

Thus, a member will spend $280 after 6 months on the membership.

Cheers.

Answer:

5

Step-by-step explanation:

Answer:

Less Than :)

Step-by-step explanation:

Answer:

a) 2260 cm³

b) 3390 grams

Step-by-step explanation:

3.

a)The radius of the solid cylinder = 6cm

The height of the cylinder is =20 cm

The volume = π*r²*h

The volume = 3.14 * 6²*20 =2260 cm³

b) Density of the material = 1.5 g/cm³

  Volume of the cylinder = 2261 cm³

  Mass of the cylinder = Density * Volume

  Mass of the cylinder = 1.5 * 2261 = 3390 grams

Answer:

a. 50 - 4h < 32

Step-by-step explanation:

The question is "When will the temperature be below 32F?" so it can't be less than or equal to (≤), it has to be less than (<).

If the temperature is decreasing every hour you have to decrease 4 for each hour.

hope that helps!

Answer:

The anti-derivative of f(x) will be:

[tex]\int \:10x^4+12.5dx=2x^5+12.5x+C[/tex]

Step-by-step explanation:

Given the function

[tex]\:f\left(x\right)=10x^4\:+\:12.5[/tex]

Taking the anti-derivative of f(x)

[tex]\int \left(10x^4\:+\:12.5\right)\:dx\:[/tex]

[tex]\mathrm{Apply\:the\:Sum\:Rule}:\quad \int f\left(x\right)\pm g\left(x\right)dx=\int f\left(x\right)dx\pm \int g\left(x\right)dx[/tex]

[tex]\int \left(10x^4\:+\:12.5\right)\:dx\:=\int \:10x^4dx+\int \:12.5dx[/tex]

Solving

[tex]\int 10x^4dx[/tex]

[tex]\mathrm{Take\:the\:constant\:out}:\quad \int a\cdot f\left(x\right)dx=a\cdot \int f\left(x\right)dx[/tex]

[tex]=10\cdot \int \:x^4dx[/tex]

[tex]\mathrm{Apply\:the\:Power\:Rule}:\quad \int x^adx=\frac{x^{a+1}}{a+1},\:\quad \:a\ne -1[/tex]

[tex]=2x^5[/tex]

similarly,

[tex]\int 12.5dx[/tex]

[tex]\mathrm{Integral\:of\:a\:constant}:\quad \int adx=ax[/tex]

[tex]=12.5x[/tex]

so substituting these values

[tex]\int \left(10x^4\:+\:12.5\right)\:dx\:=\int \:10x^4dx+\int \:12.5dx[/tex]

                                [tex]=2x^5+12.5x[/tex]

                               [tex]=2x^5+12.5x+C[/tex]   ∵ Add constant to the solution

Therefore, the anti-derivative of f(x) will be:

[tex]\int \:10x^4+12.5dx=2x^5+12.5x+C[/tex]

Answer:

HP=11

Step-by-step explanation:

Now that we have \blueE{HP}HPstart color #0c7f99, H, P, end color #0c7f99, we can find HDHDH, D.

\begin{aligned} HD&=\blueE{HP}+DP \\\\ &=\blueE{2}+9 \\\\ &=11 \end{aligned}

HD

​

=HP+DP

=2+9

=11

​

Using the AAA similarity theorem, the length of segment HD in the diagram given is: 11 units.

If all corresponding angles of two  triangles are congruent, then, they are similar triangles, based on the AAA similarity theorem.

ΔPOH ~ ΔPID by AAA similarity theorem.

Therefore, their corresponding sides would be proportional. Thus:

PH/PD = PO/PI

Substitute

PH/9 = 6/27

PH = (9 × 6)/27

PH = 2

HD = 2 + 9

HD = 11 units.

Learn more about the AAA similarity theorem on:

https://brainly.com/question/2063552

#SPJ2

Answer:

8.033

Step-by-step explanation:

9514 1404 393

Answer:

  see attached

Step-by-step explanation:

A right turn represents a clockwise rotation of the direction vector by 90°. It is equivalent to multiplying the complex number representation by -i.

A left turn represents a counterclockwise rotation of the direction vector by 90°. It is equivalent to multiplying the complex number representation by i.

The attached table shows the desired values and expressions.

Step-by-step explanation:

[tex]\boxed{\begin{array}{c|c|c} \underline{Intial -d} & \underline {Left-turn} & \underline{Right-turn} \\ -1 & -i & i \\ 1 & i & -i \\ i & -1 & 1\\ -i & 1 & -1 \\ d & di & -di \end{array}}[/tex]

Answer:

66 2/3

Step-by-step explanation:

(2/3)(100) = 66 2/3

[tex]\huge\text{Hey there!}[/tex]

[tex]\huge\textbf{Question reads....}[/tex]

[tex]\large\textbf{What percent is equivalent to }\rm{\bf \dfrac{2}{3}}\large\textbf{ ?}[/tex]

[tex]\huge\textbf{Let's simplify the current fraction}\\\huge\textbf{to find the overall result to this question.}[/tex]

[tex]\mathbf{\dfrac{2}{3}}[/tex]

[tex]\mathbf{= 2\div3}[/tex]

[tex]\mathbf{= 0.66666667}[/tex]

[tex]\mathbf{= 0.66666667 \times 100}[/tex]

[tex]\mathbf{= 66.6666667\%}[/tex]

[tex]\mathbf{\approx 66.67\%}[/tex]

[tex]\huge\textbf{Let's do process of elimination to find}\\\huge\textbf{the fraction that is equivalent to yours.}[/tex]

[tex]\huge\textsf{Option A.}[/tex]

[tex]\mathbf{66 \dfrac{1}{3}}[/tex]

[tex]\mathbf{= \dfrac{66\times3+1}{3}}[/tex]

[tex]\mathbf{= \dfrac{198 +1}{3}}[/tex]

[tex]\mathbf{= \dfrac{199}{3}}[/tex]

[tex]\mathbf{= 199\div3}[/tex]

[tex]\mathbf{= 66.3333333}[/tex]

[tex]\mathbf{= 66.3333333 \times100}[/tex]

[tex]\mathbf{= 6,633.33333\%}[/tex]

[tex]\mathbf{\approx 6,633.33\%}[/tex]

[tex]\huge\textsf{This eliminates Option A. as your result.}[/tex]

[tex]\huge\textsf{Option B.}[/tex]

[tex]\mathbf{66 \dfrac{3}{5}}[/tex]

[tex]\mathbf{= \dfrac{66\times5 + 3}{5}}[/tex]

[tex]\mathbf{= \dfrac{330 + 3}{5}}[/tex]

[tex]\mathbf{= \dfrac{333}{5}}[/tex]

[tex]\mathbf{= 333\div5}[/tex]

[tex]\mathbf{= 66.6}[/tex]

[tex]\mathbf{= 66.6 \times 100}[/tex]

[tex]\mathbf{= 6,660}[/tex]

[tex]\mathbf{\approx 6,660\%}[/tex]

[tex]\huge\textsf{This eliminates Option B. as your result.}[/tex]

[tex]\huge\textsf{Option C.}[/tex]

[tex]\mathbf{66 \dfrac{2}{3}}[/tex]

[tex]\mathbf{= \dfrac{66\times3+2}{3}}[/tex]

[tex]\mathbf{= \dfrac{198 + 2}{3}}[/tex]

[tex]\mathbf{= \dfrac{200}{3}}[/tex]

[tex]\mathbf{= 200\div3}[/tex]

[tex]\mathbf{= 66.6666667}[/tex]

[tex]\mathbf{= 66.6666667\times100}[/tex]

[tex]\mathbf{= 6,666.66667}[/tex]

[tex]\mathbf{\approx 6,666.67\%}[/tex]

[tex]\huge\textsf{This eliminates Option C. as your result.}[/tex]

[tex]\huge\textsf{Option D.}[/tex]

[tex]\mathbf{66\dfrac{7}{10}}[/tex]

[tex]\mathbf{= \dfrac{66\times10 +7}{10}}[/tex]

[tex]\mathbf{= \dfrac{660 + 7}{10}}[/tex]

[tex]\mathbf{= \dfrac{667}{10}}[/tex]

[tex]\mathbf{= 667\div10}[/tex]

[tex]\mathbf{= 6.67}[/tex]

[tex]\mathbf{= 6.67\times100}[/tex]

[tex]\mathbf{= 6,670}[/tex]

[tex]\mathbf{\approx 6,670\%}[/tex]

[tex]\huge\textsf{This eliminates Option D. as your result.}[/tex]

[tex]\huge\textbf{It seems like none of the above matches }\\\huge\textbf{the original fraction, so we will use the}\\\huge\textbf{that is close to the original answer.}[/tex]

[tex]\huge\textbf{The closest answer was:}[/tex]

[tex]\mathbf{66 \dfrac{2}{3}}[/tex]

[tex]\huge\textbf{Therefore the answer MIGHT be:}[/tex]

[tex]\huge\boxed{\mathsf{Option\ C. \ 66 \dfrac{2}{3}}}\huge\checkmark[/tex]

[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]