Complete the sentence with the word "element" or "compound." O is a(n) and H2O2 is a(n)

Answers

Answer 1

Answer:

O is an element whilst H2O2 is a compound.

Explanation:

O is an element. You can find it on the periodic table. H2O2 is composed of both H and O. Thus, H2O2 is a compound.

Answer 2

The O is a(n) element and [tex]H_{2} O_{2}[/tex] is a(n) compound.

What is element?

All facets of a species of atoms with a specific count of protons in its nuclei are referred to as chemical elements, such as the pure substance made exclusively of the that species.

What is compound?

A compound comprises a substance created by the chemical fusion of two or more components.

Therefore, the O is a(n) element and [tex]H_{2} O_{2}[/tex] is a(n) compound.

To know more about compound and element.

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Related Questions

Enunciado: Una bola se lanza verticalmente de la parte superior de un edificio con una velocidad inicial de 25 m/s. La bola impacta al suelo en la base del edificio 7 segundos después de ser lanzada. (Marque la respuesta correcta)

¿Qué altura subió la bola (medida desde la parte superior del edificio)? a) 19.6 m b) 12.75 m c) 31.88 m d) 40 m e) 20 m

Answers

Responder:

Explicación:

Usaremos la ecuación de movimiento para determinar la altura de la bola medida desde la parte superior del edificio.

Usando la ecuación para obtener la altura de caída

S = ut + 1 / 2gt²

u es la velocidad inicial = 25 m / s

g es la aceleración debida a la gravedad = 9,81 m / s²

t es el tiempo = 7 segundos

S es la altura de la caída

S = 25 (7) +1/2 (9,81) × 7²

S = 175 + 4,905 (49)

S = 175 + 240,345

S = 415,35 m

Esto significa que la pelota se elevó a 415,35 m de altura

La altura vertical máxima alcanzada es de 31,88 m.

Tenemos la siguiente información de la pregunta;

Velocidad inicial = 25 m/s

Velocidad final = 0 m/s (a la altura máxima)

tiempo empleado = 3,5 minutos (el tiempo empleado para subir y bajar es igual).

Usando la ecuación;

v^2 = u^2 - 2gh

Dado que v = 0

u^2 = 2gh

h = tu^2/2g

h = (25)^2/2 *9.8

h = 31,88 m

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What is the kinetic energy when the pendulum is at the halfway point
(height=1 m) when the total mechanical energy is 4 J

Answers

The answer is 0 , hope this helps

lol
idk what this is​

Answers

Answer:

I know

Explanation:

Physics= hard

lol‍♀️‍♀️‍♀️‍♀️‍♀️‍♀️‍♀️‍♀️‍♀️‍♀️‍♀️‍♀️‍♀️‍♀️‍♀️‍♀️‍♀️‍♀️‍♀️‍♀️‍♀️‍♀️

the force which slow down a paper aeroplane moving through the air is called​

Answers

Explanation:

The paper plane slows down when flying in the air due to air resistance or the friction due to the air around it. As the paper plane have flat surfaces and more surface area, the air resists it's motion more than before. If the paper plane is moving towards left, then friction acts towards left.

The friction always act opposite to the direction of paper plane and resists its motion. Hence, we can say that paper plane slows due to Frictional Force [tex]\red{\bullet}[/tex]

#CarryOnLearning

━━━━━━━━━━━━━━━━━━━━

Air resistance - due to friction in the air

6
Following an inelastic collision, what can kinetic energy be converted into? Check all that apply.
heat
impulse
momentum
potential energy
sound
Mark this and return
Save and Exit
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Submit

Answers

Answer:

Heat, potential energy, and sound.

Explanation:

Edgenuity says so

The characteristics of the inelastic shocks allow to find the correct answers of in which the kinetic energy can be transformed are:

Heat Potential energy Sound.

In a collision the total momentum of the system is conserved, this is an important principle of physics, we have two types of collisions:

Elastic. In this case the kinetic energy of the system is conserved. Inelastic. In this case the initial kinetic energy is not conserved.

In inelastic collision, part of the energy of the movement is transformed into potential energy of configuration of the system.

Let's analyze the different answers:

a) Heat.

True. Heat is a form of energy that, due to the change in the relative friction motion of bodies, is one of the greatest sources of transformation of energy into configuration power energy.

b) Impulse.

False. The impulse is the change of the momentum of the system and this is conserved, therefore the momentum is also conserved.

c) Momentum

False. Momentum is preserved in all crashes.

d) Potential energy.

True. Power energy is a configuration energy, therefore kinetic energy can be transformed into potential energy.

e) The sound.

True. Sound is a wave that carries energy, therefore kinetic energy can be transformed into traveling sound waves.

In conclusion, using the characteristics of inelastic shocks, we can find the correct answers that the kinetic energy can be transformed into are:

Heat Potential energy Sound.

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Please help me slow this I don't understand how this works

Answers

Answer:

[tex]A=90^0-B\\B+C=180^0-90^0=90^0\\C=90^0-B\\A=C[/tex]

Explanation:

An excited squirrel starts from rest and accelerates towards a nut at 1.0 m/s2 for 2.0 seconds. What is the squirrel’s displacement?

Answers

Answer:

[tex]x=8m[/tex]

Explanation:

Hello,

In this case, the most suitable kinematic equation for the calculation of the squirrel's displacement is:

[tex]x=v_ot+\frac{1}{2}at^2[/tex]

Whereas the initial velocity is zero as it starts from rest, thus, we obtain:

[tex]x=\frac{1}{2}*1.0\frac{m}{s^2}*(2.0s)^2\\ \\x=8m[/tex]

Best regards.

Earth's atmosphere is constantly bombarded by cosmic ray protons that originate somewhere in space. If the protons all passed through the atmosphere, each square meter of Earth's surface would intercept protons at the average rate of 1800 protons per second. What would be the electric current in amperes intercepted by a 41 × 107 km2 area on the planet

Answers

Answer:

Electric current in amperes = 1.1808 A

Explanation:

Given:

Intercept protons rate = 1800 protons per second

Area = 41 × 10⁷ km²

Find:

Electric current in amperes

Computation:

Current density = Intercept protons rate × 1.6 × 10⁻¹⁹

Current density = 1800 × 1.6 × 10⁻¹⁹

Current density = 2.88 × 10⁻¹⁶

1 km² = 10⁶m²

So,

Electric current in amperes =  2.88 × 10⁻¹⁶ × 41 × 10⁷ × 10⁶

Electric current in amperes = 1.1808 A

It takes you 9.5 min to walk with an average velocity of 1.2 m/s to the north
from the bus stop to the museum entrance. What is your displacement?

Answers

you have your velocity in m/s you need your total time in seconds and multiply the two to get displacement
1hr =60 sec
so at 1.2m/s traveling (9.5*60(60 seconds in a minute)= 570 seconds is 570*1.2= 684 meters

The direction of movement of the body or item is defined by velocity. Your total displacement will be 684 meters.

What is Velocity?

The direction of movement of the body or item is defined by velocity. Speed is fundamentally a scalar number. Velocity is, in essence, a vector quantity. It is the pace at which distance changes. It is the displacement rate of change.

Given that It takes you 9.5 min to walk with an average velocity of 1.2 m/s to the north from the bus stop to the museum entrance.

Time = 9.5 minutes = 9.5 × 60 seconds = 570 seconds

Average Velocity = 1.2 m/s

Now, the displacement made by you can be written as,

Velocity = Displacement / Time

1.2 m/sec = Displacement / 570 seconds

Displacement = 1.2 m/sec × 570 seconds

Displacement = 684 meter

Hence, your total displacement will be 684 meters.

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Which are best examples of projectile motion

Answers

Answer:

Please add the multiple choice awensers too then I'll get back to you when I can

Answer:

Answer is D

Explanation:

You walk 20 m north then 30 m west for a total timer four minutes what is the magnitude of your average velocity in (m/s)

Answers

Answer:

The average velocity is 0.15 m/s

Explanation:

Use the definition of average velocity as the distance traveled divided the time it took.

Since the movement was on the plane from the origin (0, 0) to the point (-30, 20) corresponding to 30 m west and 20 m north, we calculate the distance using the distance between two points on the plane:

[tex]distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} = \sqrt{(-30)^2+20^2} =\sqrt{1300} \approx 36.06\,\,m[/tex]

Then the magnitude of the average velocity can be estimated via the quotient between distance divided time, but since the units required are meters per second, we first convert the four minute time into seconds: 4 * 60 = 240 seconds.

Then the average velocity becomes:

[tex]v_{ave}=\frac{distance}{time} =\frac{36.06}{240} =0.15\,\,m/s[/tex]

a steel ball bearing will sink in water but a large ship floats because​

Answers

Answer:

water displacement.

the bigger the item means more water displacement meaning bouyance

If two tug boats are towing a ship with force of 5 tons each and the angle between the two ropes is 60 degrees, what is the resultant force on the ship? Explain how to use a force table to verify answer.

Answers

Answer:

8.6602 tons

Explanation:

We first draw the known vector forces.

2fcos30⁰

We have f to be equal to 5tons

Inserting into formula

Σfx = 2(5)cos30⁰

= 8.6602 tons

Σfy is equal to 0, this is because in the y direction, the forces cancel themselves out.

Therefore the resultant force on the ship is equal to 8.6602 tons

I hope this helps!

Please check attachment for diagram.

A basketball leaves a player's hands at a height of 2.20 m above the floor. The basket is 2.70 m above the floor. The player likes to shoot the ball at a 36.0 ∘ angle. Of the shot is made from a horizontal distance of 9.10 m and must be accurate to ±0.23m (horizontally), what is the range of initial speeds allowed to make the basket

Answers

Answer:

The range of initial speeds allowed to make the basket is: [tex]9.954\,\frac{m}{s}\leq v \leq 10.185\,\frac{m}{s}[/tex].

Explanation:

We must notice that basketball depicts a parabolic motion, which consists of combining a constant speed motion in x-direction and free fall motion in the y-direction. The motion is described by the following kinematic formulas:

x-Direction

[tex]x = x_{o} + v_{o}\cdot t \cdot \cos \alpha[/tex]

y-Direction

[tex]y = y_{o} + v_{o}\cdot t\cdot \sin \alpha +\frac{1}{2}\cdot g\cdot t^{2}[/tex]

Where:

[tex]x_{o}[/tex], [tex]y_{o}[/tex] - Initial position of the basketball, measured in meters.

[tex]x[/tex], [tex]y[/tex] - Final position of the basketball, measured in meters.

[tex]v_{o}[/tex] - Initial speed of the basketball, measured in meters per second.

[tex]t[/tex] - Time, measured in seconds.

[tex]\alpha[/tex] - Tilt angle, measured in sexagesimal degrees.

[tex]g[/tex] - Gravitational acceleration, measured in meters per square second.

If we know that [tex]x_{o} = 0\,m[/tex], [tex]y_{o} = 2.20\,m[/tex], [tex]\alpha = 36^{\circ}[/tex], [tex]g = -9.807\,\frac{m}{s^{2}}[/tex], [tex]x = (9.10\pm0.23)\,m[/tex] and [tex]y = 2.70\,m[/tex], the system of equation is reduce to this:

[tex](9.10\pm 0.23)\,m = 0\,m + v_{o}\cdot t \cdot \cos 36^{\circ}[/tex]

[tex]9.10\pm 0.23 = 0.809\cdot v_{o}\cdot t[/tex] (Ec. 1)

[tex]2.70\,m = 2.20\,m + v_{o}\cdot t \cdot \sin 36^{\circ} + \frac{1}{2}\cdot \left(-9.807\,\frac{m}{s^{2}} \right) \cdot t^{2}[/tex]

[tex]0.50 = 0.588\cdot v_{o}\cdot t-4.904\cdot t^{2}[/tex] (Ec. 2)

At first we clear [tex]v_{o}\cdot t[/tex] in (Ec. 1):

[tex]v_{o}\cdot t = \frac{9.10\pm 0.23}{0.809}[/tex]

[tex]v_{o}\cdot t = 11.248\pm 0.284[/tex]

(Ec. 1) in (Ec. 2):

[tex]0.5 = 0.588\cdot (11.248\pm 0.284)-4.904\cdot t^{2}[/tex]

Now we clear the time in the resulting expression:

[tex]4.904\cdot t^{2} = 0.588\cdot (11.248\pm 0.284)-0.5[/tex]

[tex]t = \sqrt{\frac{0.588\cdot (11.248\pm 0.284)-0.5}{4.904} }[/tex]

There are two solutions:

[tex]t_{1} = \sqrt{\frac{0.588\cdot (11.248- 0.284)-0.5}{4.904} }[/tex]

[tex]t_{1} \approx 1.101\,s[/tex]

[tex]t_{2} = \sqrt{\frac{0.588\cdot (11.248+ 0.284)-0.5}{4.904} }[/tex]

[tex]t_{2}\approx 1.131\,s[/tex]

The initial velocity is cleared within (Ec. 2):

[tex]v_{o}=\frac{0.50+4.904\cdot t^{2}}{0.588\cdot t}[/tex]

The bounds of the range of initial speed is determined hereafter:

[tex]t_{1} \approx 1.101\,s[/tex]

[tex]v_{o} = \frac{0.50+4.904\cdot (1.101)^{2}}{0.588\cdot (1.101)}[/tex]

[tex]v_{o} = 9.954\,\frac{m}{s}[/tex]

[tex]t_{2}\approx 1.131\,s[/tex]

[tex]v_{o} = \frac{0.50+4.904\cdot (1.131)^{2}}{0.588\cdot (1.131)}[/tex]

[tex]v_{o} = 10.185\,\frac{m}{s}[/tex]

The range of initial speeds allowed to make the basket is: [tex]9.954\,\frac{m}{s}\leq v \leq 10.185\,\frac{m}{s}[/tex].

Compare the de Broglie wavelength of a golf ball moving at 70.0 miles per hour (31.3 m/s) to that of an alpha particle moving at 3.40E+7 miles per hour (1.52E+7 m/s) and a bullet with a speed of 700 miles per hour (313 m/s). Which region of the electromagnetic spectrum are each of these wavelengths near

Answers

Answer:

1. Golf ball is in the range of only particulate detectable range

2, alpha partcle is in ultraviolet range of wavelength

3.bullet is in xray range of wavelength

All in the EMW spectrum

What must be the acceleration of a train in order for it to stop from 12m/s in a distance of 541m?

Please help!!

Answers

Answer:

The acceleration of the train must be - 0.133 m/s²

Explanation:

A train in order for it to stop 12 m/s in a distance if 541 m

That means the initial velocity of the train is 12 m/s

Its final velocity is zero (stop)

The distance it covers is 541 m

P.S. This is part of the answer of another brainly user this is not my knowledge.

But Hope I helped you

Answer:

-0.133 m/s²

Explanation:

Given:

Δx = 541 m

v₀ = 12 m/s

v = 0 m/s

Find: a

v² = v₀² + 2aΔx

(0 m/s)² = (12 m/s)² + 2a (541 m)

a = -0.133 m/s²

What would the American flag look like under a blue light?

Answers

Answer:

The flag will appear to be black.

Explanation:

This is because red is the only brighter color in the American flag, so when a blue light is shined, the red turns dark and then the flag looks just blank and black.

Answer:

As red light falls on a blue surface, it absorbs the red light and no light will be reflected back. Thus, the object appears to be black. When the flag is illuminated by red light, the red and white stripes of the flag will appear solid red, the stars will appear red, and the blue portion will appear black.

If you go 45 meters at a speed of 16 m/s, how long does the movement take? Exact answer, do NOT round.

Answers

Answer:

2 seconds

Explanation:

The time taken for the movement is 2.81 seconds.

To find the time, the given values are,

Distance = 45 meters

speed = 16 m/s.

What is distance?Distance is the total movement of an object without any regard to direction.Distance can be evaluated how much an object moves from starting point to the end point.The distance completely depends upon the speed and time, i,e., the object covering some area with some particular time interval with the particular speed.Distance will be measured in meter, kilometer, etc..Distance is a Scalar quantity.

Formula of distance,

              Distance = Speed × Time.

As we have to find the time, Formula can be rearranged as,

              Time = Distance / Speed

Substituting the given datas in the formula,

Time = 45 / 16

        = 2.81 seconds.

So, the time taken for the movement is 2.81 seconds.

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The relatively high resistivity of dry skin, about 1 × 106 O·m, can safely limit the flow of current into deeper tissues of the body. Suppose an electrical worker places his palm on an instrument whose metal case is accidentally connected to a high voltage. The skin of the palm is about 1.5 mm thick. Estimate the area of skin on the worker’s palm that would contact a flat panel, then calculate the approximate resistance of the skin of the palm.

Answers

Answer:

The area is [tex]A = 0.015 \ m^2 [/tex]

The resistance is  [tex]R =  1.0 *10^{5} \ \Omega [/tex]

Explanation:

From the question we are told that

The relativity of dry skin is [tex]\rho = 1 * 10^6\ \Omega\cdot m[/tex]

The thickness of the skin is [tex]d = 1.5 \ mm = 1.5 *10^{-3} \ m[/tex]

Generally the area of a flat palm with length = 0.10 m and breath b = 0.15 m is mathematically represented as

[tex]A = d * L[/tex]

[tex]A = 0.10 * 0.15 [/tex]

[tex]A = 0.015 \ m^2 [/tex]

Generally the resistance is mathematically represented as

[tex]R = \frac{\rho * d}{ A }[/tex]

=>    [tex]R =  \frac{ 1.0 *10^{6} *   1.5*10^{-3}}{ 0.015  }[/tex]

=> [tex]R = 1.0 *10^{5} \ \Omega [/tex]

What is the velocity of a plane to travel 3000 miles from New York to California in 5.0 hours

Answers

Answer:

10 miles per minute.

Willie swift drives a hockey puck into the goal at a speed of 34.8 m/s. From a distance of 60.0 m, how long will it take to reach the net?

Answers

Explanation:

distance = rate*time

time = distance divided by rate

now just substitute

time = distance (60 m) divided by rate (34.8 m/sec)

Question 3
A box is being pulled by a rope that makes a 25 degree angle with the ground. The
pulling force is 100.0 N
along the rope. Find the horizontal and vertical components of the force vector.
A. 90.63 N, 42.26 N
B. 86.87 N, 32.17 N
C. 60.87 N, 75,63 N
D. 80.9 N, 45.5 N
What is the answer A,B,C or D?

Answers

Answer:

A

Explanation:

ou are walking down a straight path in a park and notice there is another person walking some distance ahead of you. The distance between the two of you remains the same, so you deduce that you are walking at the same speed of 1.05 m/s. Suddenly, you notice a wallet on the ground. You pick it up and realize it belongs to the person in front of you. To catch up, you start running at a speed of 2.75 m/s. It takes you 18.5 s to catch up and deliver the lost wallet. How far ahead of you was this person when you started running

Answers

Answer:

The value is [tex]d = 31.45 \ m [/tex]

Explanation:

Generally the relative speed at which you are moving with respect to the person ahead of you is mathematically represented as

[tex]v_r = v_s - v_c[/tex]

substituting 1.05 m/s for [tex] v_c [/tex] and 2.75 m/s for [tex]v_s[/tex]

So

[tex]v_r = 2.75 - 1.05[/tex]

=> [tex]v_r = 1.7 \ m/s [/tex]

Generally the distance by which the person is ahead of you is mathematically represented as

[tex]d = v_r * t[/tex]

substituting 18.5 s for [tex] t [/tex]

       [tex]d =  1.7  * 18.5[/tex]

=>      [tex]d  =  31.45 \  m [/tex]

Three equal point charges, each with charge 1.05 μCμC , are placed at the vertices of an equilateral triangle whose sides are of length 0.500 mm . What is the electric potential energy UUU of the system? (Take as zero the potential energy of the three charges when they are infinitely far apart.)

Answers

Answer:

The value is [tex]U = 0.06 \ J [/tex]

Explanation:

From the question we are told that

The value of charge on each three point charge is

[tex]q_1 = q_2 = q_3 =q= 1.05 \mu C = 1.05 *10^{-6} \ C[/tex]

The length of the sides of the equilateral triangle is [tex]r = 0.500 \ [/tex]

Generally the total potential energy is mathematically represented as

[tex]U = k * [ \frac{q_1 * q_2}{r} + \frac{q_2 * q_3}{r} + \frac{q_3 * q_1}{r} ][/tex]

=> [tex]U = k * 3 * \frac{q^2}{r} [/tex]

Here k is coulomb constant with value [tex]k = 9*10^{9}\ kg\cdot m^3\cdot s^{-4} \cdot A^{-2}.[/tex]

=>    [tex]U  = 9*10^9 * 3 * \frac{(1.05 *10^{-6})^2}{0.5 }  [/tex]

[tex]U  = 0.06 \  J  [/tex]

What is the mass of the cube
Density is 40 g/cm3
Length of the side= 2 cm

Answers

Answer:

80

Explanation:

because of the denstiy formula

A train travels 1000 m south for 100 s. What is the
velocity of the train?

a) 0.1 m/s
b) 0.1 m/s south
c) 10 m/s
d) 10 m/s south

Answers

C. 10 m/s
You divide 1000 m by 100 s.
1000/100 to find the velocity

Which statement supports Newton’s first law of motion?

Answers

Answer:

Newton's first law of motion is that an object at rest will stay at rest, unless acted upon by an external force.

--------------------------------------------------------------------------------------------------------------

The "external force" can be anything, from a gust of wind, to a person moving the object. His first law also corresponds with the definition of inertia.

Hope this helps!

Meter #1 can measure voltage to within 0.1 volts. Meter #2 can measure voltage to within 0.01 volts.
A.) Which meter has the greatest precision?
B.) Which meter is more accurate? Why?

Answers

Meter #2 is more precise.

There's no information here that tells us which meter is more accurate.

Jesse is swinging Miguel in a circle at a tangential speed of 3.50 m/s. If the radius of the circle is 0.600 m and Miguel has a mass of 11.0 kg, what is the centripetal force on Miguel? Round to the nearest whole number. N

Answers

Answer:

224.6 N

Explanation:

We can use first the formula to calculate the centripetal acceleration, given by:

[tex]a_c=\frac{v_t^2}{R}[/tex]

where the Vt is the tangential velocity, and R is the radius of the circular motion.

Then, for our case we have:

[tex]a_c=\frac{v_t^2}{R}=\frac{3.5^2}{0.6}\approx 20.42\,\,\frac{m}{s^2}[/tex]

And now we multiply this acceleration by Miguel's mass (11 kg) to obtain the centripetal force acting on him:

[tex]F_c=11 \,*\,20.42\,N = 224.6\,\,N[/tex]

Answer:

225 N

Explanation:

Just answered the question

what is the mass of an object that is experiencing a net force of 200N and an acceleration of 500m/s2​

Answers

Answer:

F=200N

a=500m/s2​

Mass=?

Explanation:

F=ma

200=m*500

200/500=m

Mass=0.4kg

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