Climbing Mt. Everest is not an easy task! Not only is it a difficult hike, but the Earth's atmosphere
decreases exponentially as you climb above the Earth's surface, and this makes it harder to breathe. The air
pressure at the Earth's surface (sea level) is approximately 14.7 pounds per square inch (or 14.7 psi). In
Denver, Colorado, elevation 5280 feet, the air pressure is approximately 12.15 psi.

a.) write an exponential equation

b.) what is the air press at the top of mount everest, elevation 29,000 feet?

The G.C.F. of the expression 16n - 24 is evaluated to be 8(2n - 3).

What is an expression?

Mathematical expressions consist of at least two numbers or variables, at least one arithmetic operation, and a statement. It's possible to multiply, divide, add, or subtract with this mathematical operation.

The given expression is - 16n - 24.

The greatest common factor, which is the product of two or more numbers, is the largest number (GCF). A natural number is created by dividing them by the biggest number (factor).

First of all find the G.C.F of 16n and 24 separately.

It can be written that -

16n = 2 × 2 × 2 × 2 × n

24 = 2 × 2 × 2 × 3

The common prime factor between the two is 2 × 2 × 2 = 8.

So, the GCF of 16n and 24 is 8.

Now use the GCF to factor the expression -

= 16n - 24

= 8(2n) - 8(3)

Using the distributive property -

= 8(2n) - 8(3)

= 8(2n - 3)

Therefore, the GCF value is 8(2n - 3).

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a. (-1,5) is on the parabola

b. (1,7) is NOT on the parabola

c. (3,9) is NOT on the parabola

a. (-1,5)

The distance from the point (-1,5) to the focus (-1,6) is sqrt((-1-(-1))^2 + (5-6)^2) = sqrt(0+1) = 1

The distance from the point (-1,5) to the directrix y=4 is the absolute value of the y-coordinate of the point - the y-coordinate of the directrix = abs(5-4) = 1

Since the distances are equal, the point (-1,5) is on the parabola.

b. (1,7)

The distance from the point (1,7) to the focus (-1,6) is sqrt((1-(-1))^2 + (7-6)^2) = sqrt(2^2 + 1^2) = sqrt(5)

The distance from the point (1,7) to the directrix y=4 is the absolute value of the y-coordinate of the point - the y-coordinate of the directrix = abs(7-4) = 3

Since the distances are not equal, the point (1,7) is not on the parabola.

c. (3,9)

The distance from the point (3,9) to the focus (-1,6) is sqrt((3-(-1))^2 + (9-6)^2) = sqrt(4^2 + 3^2) = sqrt(16+9) = sqrt(25)

The distance from the point (3,9) to the directrix y=4 is the absolute value of the y-coordinate of the point - the y-coordinate of the directrix = abs(9-4) = 5

Since the distances are not equal, the point (3,9) is not on the parabola.

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Answer:

Step-by-step explanation:

You can use the equations:

x = 2y

where x is the number of $10 bills and y the number of $5 bills and:

10x+5y = 125

Solving gives x=10 and y = 5, or in other words there are 10 $10 bills and 5 $5 bills

Answer:

Step-by-step explanation:

the answer is 69

Answer:yes

Step-by-step explanation:

The Angle-Side-Angle Postulate (ASA) states that if two angles and the included side of one triangle are congruent to two angles and the included side of another triangle, then the two triangles are congruent.

Here we see two sides being congruent and one angle, this means that the other angles are also congruent, as only one triangle can be formed with two set sides and an angle. therefore we know both triangles are congruent

If a plot of the residuals shows a curved pattern, it indicates that a straight line is not a good model for the data. This does not necessarily mean that the correlation between the two variables must be 0 or positive, as the regression line might still be a good model for the data depending on the extent of the curve.

When a least-squares regression line is fit to a set of data, it is used to determine the linear relationship between two variables. If a plot of the residuals (the difference between the observed values and the predicted values from the regression line) shows a curved pattern, it indicates that a straight line is not a good model for the data. This could mean that there is a nonlinear relationship between the two variables or that the data contains outliers that are not accounted for by the regression line. However, it does not necessarily mean that the correlation between the two variables must be 0 or positive, as the regression line might still be a good model for the data depending on the extent of the curve. To determine if the regression line is an accurate model for the data, it is important to visually inspect the plot of the residuals and assess whether the pattern is random or systematic. If the pattern is random, it indicates that the regression line is a good model for the data. If the pattern is systematic, it indicates that the regression line is not a good model for the data and alternative models should be considered.

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First order approximation = (sin(x+dx)/(x+dx)^3 - sin(x)/x^3)/dx and ((sin(x-(2*dx))/(x-(2*dx))3) is a formula for calculating the fourth-order

Function output for the first order approximation is first order approx (x,dx)

(x3*(cos(x)) analytical derivative =

-sin(x)*3*x^2)/x^6;

First order approximation: % forward differencing = (f(x+dx) - f(x))/dx%

first-order approximation = (sin(x)/x3 - sin(x)/x+dx)/(x+dx)3)/dx;

output is equal to Abs(FirstOrderApproximation - AnalyticalDerivative);

end

Function output for the fourth-order approximation is fourth-order approx (x,dx)

(x3*(cos(x)) analytical derivative =

-sin(x)*3*x^2)/x^6;

((sin(x-(2*dx))/(x-(2*dx))3) is a formula for calculating the fourth-order approximation. 8*(sin(x-dx))/(x-dx) + 8*(sin(x+dx))/(x+dx) - ((sin(x+(2*dx))/(x+(2*dx))3))/(12*dx);

output for the error term is abs(approximation of first order - analytical derivative);

end

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The solid whose base is the region bounded by the parabola y = x^2 and the line y = 1 and whose cross sections perpendicular to the base and parallel to the x-axis are squares is a parabolic pyramid.

A parabolic pyramid is a pyramid whose base is a parabola and whose lateral faces are formed by rectangles that are perpendicular to the base. The height of the pyramid is determined by the y-coordinate of the point where the parabola and the line y = 1 intersect. The length of the side of the square cross section is determined by the x-coordinate of the point where the parabola and the line y = 1 intersect.

The base of the solid is a parabolic region, defined by the parabola y = x^2 and the line y = 1, and the cross sections are squares, perpendicular to the base, and parallel to the x-axis. This solid is called a parabolic pyramid.

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The number of kilometers that Darlene runs is given as follows:

2.4 kilometers.

The distance that Darlene runs is obtained applying the proportions in the context of the problem.

The proportion is applied to convert the mixed number to decimal, adding the integer part to the division of the numerator by the denominator.

The distances are given as follows:

Hence the total distance is of:

1 + 1.4 = 2.4 km.

She ran 1 km in the morning.

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The sequence (3n-2/n)n=1 converges to 1.

To show that (3n-2/n)n=1 converges, we need to find the limit as n approaches infinity.

Using algebraic manipulation, we have the following steps

lim (3n-2/n)n = lim (3-2/n)^n

lim (3n-2/n)n = (3-2/∞)^∞

lim (3n-2/n)n = 1^∞

lim (3n-2/n)n = 1

The basic definition of convergence states that a sequence converges if the limit of the sequence as n approaches infinity is equal to a finite number

Since the limit of (3n-2/n)n as n approaches infinity is 1, we can conclude that the sequence converges to 1.

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Here we are interested in finding the slope of the line. From the given graph we can see that that the line passes through points (-5,0) and (0,-3) . We know that slope can be calculated by ,

[tex]\longrightarrow slope \ (m)=\dfrac{y_2-y_1}{x_2-x_1} =\tan\theta [/tex]

hence here ,

[tex]\longrightarrow m =\dfrac{y_2-y_1}{x_2-x_1}\\[/tex]

[tex]\longrightarrow m =\dfrac{0-(-3)}{-5-0}\\[/tex]

[tex]\longrightarrow m =\dfrac{3}{-5}\\ [/tex]

[tex]\longrightarrow m =\dfrac{-3}{5}\\ [/tex]

[tex]\longrightarrow \underline{\underline{ m = -0.6}}[/tex]

And we are done!

The system of linear equations 4 · y - 12 · x = 3 and y + 3 · x = 1 has the following solution: (x, y) = (1 / 24, 7 / 8)

In this question we find the case of a system of two linear equations with two variables, this case may have an unique solution. This system can be solved by algebraic properties.

First, write the system of linear equations:

4 · y - 12 · x = 3

y + 3 · x = 1

Second, clear y in the second equation:

y = 1 - 3 · x

Third, substitute in the first equation:

4 · (1 - 3 · x) - 12 · x = 3

Fourth, expand the expression and clear variable x:

4 - 12 · x - 12 · x = 3

4 - 24 · x = 3

24 · x = 4 - 3

24 · x = 1

x = 1 / 24

Fifth, determine the value of variable y:

y = 1 - 3 · (1 / 24)

y = 1 - 1 / 8

y = 7 / 8

The solution to the system of linear equations 4 · y - 12 · x = 3 and y + 3 · x = 1 is (x, y) = (1 / 24, 7 / 8).

The statement reports several typing mistakes. The system of linear equations is shown below:

4 · y - 12 · x = 3

y + 3 · x = 1

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On the interval (1,b), f(x)=4x2-7 changes at an average rate of 8b-11. To determine this, divide the difference between the function at b and 1 (4b2-7-3) by the difference between the intervals (b-1).

The average rate of change of a function on an interval is a measure of the change in the output of the function over the given interval. It can be calculated by taking the difference of the output between the endpoints of the interval, and dividing by the difference between the endpoints of the interval. For the given function f(x)=4x²-7 on the interval (1,b), the average rate of change is 8b-11This is obtained by dividing the output difference between 1 and b (4b2-7-3) by the output difference between the intervals (b-1). Our average rate of change is given by this formula: (4b2-7-3) / (b-1) = 8b-11. This average rate of change provides us with a general understanding of the function's rate of change across the specified interval. The output of the function increases at a constant rate as the input increases in this situation because the rate of change grows linearly as b increases.

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The maximum error in calculating the area of the disk is approximately 0.25 cm * 2π * 26 cm = 16.3 cm².

The maximum error in the calculated area of the disk can be estimated using differentials. A = r2, where r is the circle's radius, is the formula for calculating a circle's area.. Differentiating this equation with respect to r gives us A' = 2πr. Plugging in the given values, we get A' = 2π * 26 cm = 161.6 cm². If the possible error in measuring the radius is 0.25 cm, then the maximum error in calculating the area of the disk is 0.25 cm * A' = 0.25 cm * 161.6 cm² = 16.3 cm². Therefore, the maximum error in the calculated area of the disk is approximately 16.3 cm².

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You can assess normality of data using D. Pearson's Measure of Normality

Pearson's Measure of Normality, also known as Pearson's Test for Normality, is a statistical test that is used to assess whether a set of data is normally distributed.

It is based on the skewness and kurtosis of the data, and it provides a p-value which indicates the probability that the data is from a normal distribution. Pearson's test is considered as one of the most common statistical test used to check normality of data.

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The full question is:

You can assess normality of data using A. Pearson's Index of Skewness B. Pearson's Test C. Pearson's p-value D. Pearson's Measure of Normality

Interval 1: 10 a.m. to 12 p.m., Frequency: 6, Interval 2: 12 p.m. to 14 p.m., Frequency: 8, Interval 3: 14 p.m. to 16 p.m., Frequency 5, Interval 4: 16 p.m. to 18 p.m., Frequency 2, and Interval 5: 18 p.m. to 20 p.m., Frequency 1.

The first lower limit of the sample frequency distribution for the provided data is fixed at $10.00, with an interval width of $2.00. The frequency of Interval 1 is 6, and it runs from 10:00 to 12:00. The frequency of Interval 2 is 8, and it lasts from 12:00 to 14:00. With a frequency of 5, interval 3 runs from 14:00 to 16:00. The frequency of interval 4 is 2, and it lasts from 16:00 to 18:00. With a frequency of 1, interval 5 runs from 18.00 to 20.00. The data range and frequency of each value are shown in this table, giving a comprehensive picture of the data. You can use this table to determine suitable pricing strategies for the product.

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Answer:

Step-by-step explanation:

Each mechanic worked a total of 12.5 hours each.

a) The highway affected the growth of many plant species, which serve as food for the deer. Option D

b) There will be fewer population of the birds. Option C

The carrying capacity of an ecosystem is the maximum number of individuals of a particular species that can be supported by the available resources in that ecosystem.

It is the point at which the population growth rate becomes zero, as the resources needed to sustain the population (such as food, water, and space) become limited. Carrying capacity can change over time due to factors such as climate change, pollution, and human activity.

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Use the data to create a stemplot.

Twenty-four workers were surveyed about how long it takes them to travel to work each day. The data below are given in minutes.

20 35 42 52 65 20 60 49 24 37 23 24

22 20 41 25 28 27 50 47 58 30 32 48

The data in a stem-and-leaf plot:

3/0257

2/0002344578

4/12789

5/028

6/05

Another presentation that is similar to a histogram is a stemplot. In statistics, a stemplot is a tool for presenting quantitative data in a graphical format, similar to a histogram, namely to assist in visualizing the shape of the data distribution which is often used in exploratory analysis. Stemplots were introduced by Arthur Bowley in the early 1900's. However, its general use only began in 1980 after John Tukey's published Exploratory Data Analysis in 1977.

Stem-and-leaf plots provide more information about true values than histograms. As in a histogram, the length of each bar corresponds to the number of events that fall into a given interval. On Histograms. we can only see the frequency value of the data but we don't know what the actual number value is. In contrast to the histogram, in SLP besides we can know the frequency value, we can also know what the actual data value is. This is done by dividing the observed values into two components, stem and leaf.

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Answer: 3rd Picture

Step-by-step explanation: Equation: y=1/3x+4

Intercepts y axis at 4, and with the slope equation (rise/run), then it rises 1 and runs 3, thus being the 3rd picture.

From the given formulas, formula A is a tautology or always true. Formula B is a contradiction or never true. And, formula C is contingency or sometimes true.

Using the truth table, a given expression is said to be in tautology when all the values are true. The given expression is said to be a contradiction when all the values are false or never true. And the given expression is said to be contingency when the values are either true or false.

In the given formulas, formula A (p→q)∨(q→r) is a tautology. This is because the values in all rows are true (T).

In the given formulas, formula B (¬(¬(p∧q)→(p→¬q))) is a contradiction. This is because the values in all rows are false (F).

In the given formulas, formula C ((¬p∨q)→q) is a contingency. This is because some values are true and some are false.

The complete question is -

Determine whether each of the following formulas is a tautology, contingency, or contradiction (this means always true, sometimes true, never true). Show how you arrived at each answer. Use equivalence-style proofs.

A. (p→q)∨(q→r)

B. ¬(¬(p∧q)→(p→¬q))

C. ((¬p∨q)→q)

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The ratio of two screws written in three different forms are,

2.5 : 1.5, 5 : 3 and 1.5/2.5.

A ratio is a comparison between two similar quantities in simplest form.

Proportions are of two types one is the direct proportion in which if one quantity is increased by a constant k the other quantity will also be increased by the same constant k and vice versa.

In the case of inverse proportion if one quantity is increased by a constant k the quantity will decrease by the same constant k and vice versa.

Given, Two screws are in the ratio of 1.5 inches and 2.5 inches.

It can be written as 2.5 : 1.5

It can also be written as 2.5×10 : 1.5×10 = 25 : 15 = 5 : 3.

It can also be written as a fraction as, 1.5/2.5.

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According to the social class model developed by Gilbert and Kahl, and based on the theory of Weber, the upper (capitalist) class of the United States includes about b) 1 percent of the population.

In the United States, the upper class, or capitalist class, is estimated to comprise about 1 percent of the population.

This is according to the social class model developed by Gilbert and Kahl, which is based on the theory of Weber.

This model suggests that the upper class is made up of those who own the majority of the nation's wealth and power, and are thus able to influence governmental decisions.

While the upper class may be small in size, it is highly influential and its members often have the resources to enact large-scale change.

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Quantitative variables can be used to measure and contrast data because they have numerical values. Measurements like shoe size, height, weight, and temperature are examples of quantitative variables.

Quantitative variables can be used to measure and contrast data because they have numerical values. They come in discrete or continuous forms. While continuous variables have an infinite number of possible values, such as decimal numbers, discrete variables have specific values, such as integers or whole numbers. Measurements like shoe size, height, weight, and temperature are examples of quantitative variables. Quantitative variables can be used to describe a population's varied characteristics, such as the median age or annual income of a given group. The average height of men and women, for example, might be used to compare two populations. The use of quantitative variables is crucial for comprehending and analyzing data. They enable academics to spot patterns and trends in data They enable researchers to find patterns and trends in data, anticipate the future, and form conclusions.

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the complete question is

Which of the following variables are quantitative? Number zip codeFavorite colorShoe sizeArea code and Shoe size.

The function best represents the data in the scatter plot is y = 2x + 20.

The function of the straight line has the general formula: y = mx + c

where m is the slope of the line, and c is the y-intercept

So first, we will need to find the slope (m):

The slope can be calculated with the points (x₁, y₁) and (x₂, y₂) as follows:

m = (y₂ - y₁)/(x₂ - x₁)

= 120 - 60/50 - 20

= 60/30

= 2/1

So, now we have the slope of our equation y = 2x + b but we still need to find b (or where the y intersects.)

Now, consider the ordered pair (20, 60)

y = 2x + b

60 = 2 × 20 + b

b = 60 - 40

b = 20

Now, put the value of b in y = 2x + b, and we get

y = 2x + 20

Also, b can not be -20 because this is a positive y-intercept, and we know it has a slope of 2.

Therefore the function is y = 2x + 20

--The given question is incomplete; the complete question is

"A picture is enlarged by keeping its width the same and increasing its length. The scatter plot below shows the perimeter of the picture (y) for different lengths (x):

Plot the ordered pairs 20, 60 and 30, 80 and 40, 100 and 50, 120 and 60, 140

Which function best represents the data in the scatter plot?

y = 2x − 20

y = 2x + 20

y = x − 20

y = x + 20"--

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Answer: 20

Step-by-step explanation:

Answer:

[tex] \sf \: 4 \div \frac{1}{5} = 20[/tex]

Step-by-step explanation:

Given problem,

[tex] \sf \rightarrow \: 4 \div \frac{1}{5} [/tex]

Let's solve the problem,

[tex] \sf \rightarrow \: 4 \div \frac{1}{5} [/tex]

[tex] \sf \rightarrow \: 4 \times \frac{5}{1} [/tex]

[tex] \sf \rightarrow \: 4 \times 5[/tex]

[tex] \sf \rightarrow \: 20[/tex]

Hence, the answer is 20.

Answer: 720

Step-by-step explanation:

Answer:

no more  Fortnight gift cards

Step-by-step explanation:

Ax+by is c is the equation for a line in two dimensions, the equation for a line in three dimensions.

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The different combinations of the five-digit number formed are enough to create ID numbers.

What is meant by combinations?

Combinations are ways to choose elements from a collection in mathematics where the order of the selection is irrelevant.

We first find the total number of 5-digit enrollment IDs that can be created using all possible combinations of numbers possible.

Since each digit of the five-digit number can be from 0-9, there are ten possible values for each digit.

So the total number of ways a five-digit number can be formed

= 10*10*10*10*10 = 100,000

For the given question, it is mentioned that only 75,000 students are expected to be enrolled in the next ten years,

Since 100,000 is greater than 75,000 the five-digit ID number will be enough.

But if the school is to last longer than ten years, it is safe to use a six or seven-digit ID number.

Therefore a five-digit Id number using symbols from 0-9 will be enough.

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