Classify the triangle with side lengths of 12, 16, 20

Answer:

A)  y = 6x + 8

Step-by-step explanation:

Answer:

2,351,000

Step-by-step explanation:

closest to the volume in cubic feet

Answer:

7 occurs most frequently.

Step-by-step explanation:

If we roll two dice, we do get sample space as

(1,1) = 1+1 =2        (4,1)=4+1=5

(1,2)= 1+2 =3        (4,2)= 34+2=6

(1,3)= 1+3=4         (4,3)= 4+3=7

(1,4)=1+4=5          (4,4)= 4+4=8

(1,5)=1+5=6          (4,5)= 4+5 =9

(1,6)=1+6=7           (4,6)= 4+6=10

(2,1)= 2+1=3          (5,1)= 5+1=6

(2,2)=2+2=4         (5,2)=5+2 =7

(2,3)= 2+3=5        (5,3) =5+3=8

(2,4)=2+4=6         (5,4) =5+4 =9

(2,5)=2+5=7          (5,5)=5+5=10

(2,6)=2+6=8          (5,6)=5+6=11

(3,1)=3+1=4            (6,1)= 6+1=7

(3,2)=3+2=5          (6,2)=6+2=8

(3,3)=3+3=6           (6,3)=6+3=9

(3,4)=3+4=7           (6,4) =6+4 =10  

(3,5) =3+5=8          (6,5)=6+5=11

(3,6)=3+6=9            (6,6)=6+6=12

2 occurs for 1 time

3 occurs for 2 times

4 occurs for 3 times

5 occurs for 4 times

6 occurs for 5 times

7 occurs for 6 times

8 occurs for 5 times

9 occurs for  4 times

10 occurs for 3 times

11 occurs for 2 times

12 occurs for 1 time.

So, 7 occurs most frequently.

Answer:

D. 70.53

Step-by-step explanation:

To solve this problem, one must use the right angle trigonometric rations. These ratios can be used to describe the ratio between the sides and an angle in a right triangle. Please note, each side is named relative to the angle that one is looking at, thus the same side can acquire different names based on the angle one uses to describe it. The trigonometric ratios are the following:

[tex]sin(\theta)=\frac{opposite}{hypotenuse}\\\\cos(\theta)=\frac{adjacent}{hypotenuse}\\\\tan(\theta)=\frac{opposite}{adjacent}[/tex]

In this case, one is asked to find the measure of (<CBA), one is given the hypotenuse (the side opposite the right angle), and the side adjacent to this angle. Therefore, one should use the cosine (cos) function to find this angle.

[tex]cos(\theta)=\frac{adjacent}{hypotenuse}[/tex]

Substitute,

[tex]cos(CBA) = \frac{3}{9}[/tex]

Simplify

[tex]cos(CBA) = \frac{1}{3}[/tex]

Inverse operations,

[tex]CBA=cos^-1(\frac{1}{3})[/tex]

Compute,

m<CBA = 70.53

[tex] \huge \: Answer࿐[/tex]

The values are :

Answer:

(0.30, 0.42)

Step-by-step explanation:

i took the test :)

Answer:

1/6

Hope that this helps!

Given:

P(x) is a 2nd degree polynomial.

[tex]P(1)=0,\ P(2)=3,\ P(-3)=0[/tex]

To find:

The polynomial P(x).

Solution:

If P(x) is a polynomial and P(c)=0, then c is a zero of the polynomial and (x-c) is a factor of polynomial P(x).

We have, [tex]P(1)=0,\ P(-3)=0[/tex]. It means 1 and -3 are two zeros of the polynomial P(x) and (x-1) and (x+3) are two factors of the polynomial P(x).

So, the required polynomial is defined as:

[tex]P(x)=a(x-1)(x+3)[/tex]          ...(i)

Where, a is a constant.

We have, [tex]P(2)=3[/tex]. So, substituting [tex]x=2,\ P(x)=3[/tex] in (i), we get

[tex]3=a(2-1)(2+3)[/tex]

[tex]3=a(1)(5)[/tex]

[tex]3=5a[/tex]

[tex]\dfrac{3}{5}=a[/tex]

Putting [tex]a=\dfrac{3}{5}[/tex] in (i), we get

[tex]P(x)=\dfrac{3}{5}(x-1)(x+3)[/tex]

Therefore, the required polynomial is [tex]P(x)=\dfrac{3}{5}(x-1)(x+3)[/tex].

Answer:

Lunar Eclipse

Step-by-step explanation:

Lunar eclipse is the phenomenon that occurs on the night of the full moon. During this phenomenon the Earth comes in between the Sun and the Moon. The Earth blocks the light of the Sun with which the Moon is visible to the people on the Earth. Lunar Eclipse is visible from the part of the Earth that is experiencing the night. The duration of the Lunar eclipse can be for two hours. The moon appears to be red because of the reflection of the Earth.

Answer:

To prove a quadrilateral is a rhombus, here are three approaches:

Answer:

the answe is 2^3

Answer:

1 inch =  3 feet

Step-by-step explanation:

A scale drawing is a reduced form in terms of dimensions of an original image / building / object

the scale drawing is usually reduced at a constant dimension

scale of the drawing = original dimensions / dimensions of the scale drawing

6 /2 = 3

1 in = 3 feet

Answer:

x + 2y = -8 = y = -4 - 1/2x

y= -1/2x + 4 =  y = 4

y= -1/2x - 4 = y = -4

y=-2x - 4 = y = -4

y=1/2x-4 = y = -4

Step-by-step explanation:

(x + 2y = -8 = y = -4 - 1/2x)

[tex]x+2y=-8\\2y=-8-x\\y=-4-\frac{1}{2}x\\[/tex]

Answer:

C)  $84

Step-by-step explanation:

40 x 14 = 560

she made $560 prior to raise

14 x 1.15 = 16.10

her new hourly rate is $16.10

40 x 16.1 = 644

she now earns $644 per week

644 - 560 = 84

Answer:

3054cm rounded to the whole number

Step-by-step explanation:

4/3xxr^3

would become 4/3 x x 9^3

once you do all of the math you get 3054 cm.

Answer:

2x + 2y = -2

Step-by-step explanation:

you can divide a 2 from all three terms in 2x + 2y = -2 to get x + y = -1 which overlaps the original equation to provide an infinite number of solutions

Answer:

Option A

Step-by-step explanation:

Area of the composite figure = Area of ΔABH + Area of BCGH + Area of ΔDEF

Area of ΔABH = [tex]\frac{1}{2}(\text{Base})(\text{Height})[/tex]

                        = [tex]\frac{1}{2}(6)(8-5)[/tex]

                        = 9 in²

Area of the trapezoid = [tex]\frac{1}{2}(CG+BH)(\text{Distance between these lines})[/tex]

                                    = [tex]\frac{1}{2}(6+4)(5)[/tex]

                                    = 25 in²

Area of ΔDEF = [tex]\frac{1}{2}(8)(6)[/tex]

                       = 24 in²

Therefore, area of the given figure = 9 + 25 + 24

                                                          = 58 in²

Option A will be the correct option.

For a graphed line to be a function it needs to pass the vertical line test.

If a vertical line goes through the graphed line in more than one x axis then it is not a function.

 Using the given point (-1,2) drawing a vertical line at X = -1, you can see the other vertical line goes through the graphed line at point  (-1,0)

Answer: (-1,0)

10.7 hours per day

The total is 64.2.

If Ravi worked for 6 days and worked the same amount of hours each day then you do:

64.2 hours ÷ 6 days = 10.7 per day

Answer:

3/4 of a pizza leftover.

Step-by-step explanation:

2 7/12 + 2/3 = 3 1/4

4 -  3 1/4 = 3/4

so 3/4 of 1 pizza is left.

Answer:

22

Step-by-step explanation:

brainliest?

Answer:

The answer is 52          

Step-by-step explanation:

the question is

30 minus 12 divided by 3 times 2

so start with 12 divided by 3 that would equal 4

30 minus 4 times 2

then go to 30 minus 4 that would be 26

26 times 2

and 26 times 2 would be 52

Answer:

j= -10/3

Step-by-step explanation:

j - 2 + 7 = - 12 - 2j + 7

*add -2 and 7 to get 5

j + 5 = -12 - 2j + 7

*add -12 and 7 to get -5

j + 5 = -5 - 2j

*add 2j to both sides

3j + 5 = -5

*subtract 5 from both sides

3j = -10

*divide both sides by 3

j= -10/3

Answer:

y=6x-14

Step-by-step explanation:

m=-8-(-2)/1-2

m=-8+2/1-2

m=-6/-1

m=6

y-y1=m(x-x1)

y-(-2)=6(x-2)

y+2=6x-12

y=6x-2-12

y=6x-14

Answer:

See attachment for drawing

Step-by-step explanation:

Given

See attachment for sketch of plan

Required

Draw a scaled plan

From the question, the garden has the following dimensions.

5.5m, 5.5m, 4m and 2.5m

Using a scale of 1m : 50 cm units, the above measurements will be represented as:

[tex]5.5m \to \frac{5.5m}{50cm} \to \frac{5.5m}{0.5m} \to 11cm[/tex]

[tex]4m \to \frac{4m}{50cm} \to \frac{4m}{0.5m} \to 8cm[/tex]

[tex]2.5m \to \frac{2.5m}{50cm} \to \frac{2.5m}{0.5m} \to 5cm[/tex]

From the question, we understand that there will be 50cm space between the greenhouse and the edge.

On the scale drawing, this will be represented as:

[tex]50cm \to \frac{50cm}{50cm} \to 1cm[/tex]

From the question, the green house has the following dimensions.

2m, 2.5m

On the scale drawing, this will be represented as:

[tex]2m \to \frac{2m}{50cm} \to \frac{2m}{0.5m} \to 4m[/tex]

[tex]2.5m \to \frac{2.5m}{50cm} \to \frac{2.5m}{0.5m} \to 5m[/tex]

See attachment 2 for scale drawing

It's (A).

................................

The above expression can be rewritten as

log(10) x^5 + log(10) 20 - log(10) 10

= log(10) [(20x^5)/10]

= log(10) (2x^5)