The forest of Nepal has been described here on the basis of the levels of altitude, and different types of climate under the following vegetation zones:
Tropical zone(-1,000m) Subtropical zone (1,000-2,000m) Temperate zone (2,000-3,000m)Kamal, Kamala, Krishna invert a sum of RS= 30,000 on a business in the ratio 2 : 3 : 5. Find the each of their investment.
Answer:
Explanation:
Kamal, Kamala, Krishna invert in the ratio 2 : 3 : 5.
As 2+3+5 =10, their respective share is 2/10, 3/10 and 5/10.
Sum of investment = 30000Rs
Kamal's investment = 30000 * 2/10 = 6,000 Rs
Kamala's investment = 30000 * 3/10 = 9,000 Rs
Krishna's investment = 30000 * 5/10 = 15,000 Rs
Which of the following is NOT true about noon in the Northern Hemisphere, on January 1?
A. The sun has reached its highest altitude for that day.
B. Your shadow is the shortest it will be that day.
C. Your shadow points due north.
D. The Sun is directly overhead.
Answer:
The answer is D
Explanation:
A point source emits sound waves with a power output of 135 watts. What is the sound level (in dB) at a distance of 10 m
Answer:
The sound level of the point source at a distance of 10 meters is approximately 110.294 decibels.
Explanation:
First, we calculate the intensity ([tex]I[/tex]), in watts per square meter, by the Inverse-Square Law:
[tex]I= \frac{\dot W}{4\pi\cdot r^{2}}[/tex] (1)
Where:
[tex]\dot W[/tex] - Power, in watts.
[tex]r[/tex] - Radius, in meters.
And the sound intenity level ([tex]L[/tex]), in decibels, is expressed by:
[tex]L = 10\cdot \log_{10} \frac{I}{I_{o}}[/tex] (2)
Where [tex]I_{o}[/tex] is the reference sound intensity, in watts per square meter.
If we know that [tex]\dot W = 135\,W[/tex], [tex]r = 10\,m[/tex] and [tex]I_{o} = 10^{-12}\,\frac{W}{m^{2}}[/tex], then we find that sound level at a distance of 10 meters is:
[tex]I= \frac{\dot W}{4\pi\cdot r^{2}}[/tex]
[tex]I = 0.107\,\frac{W}{m^{2}}[/tex]
[tex]L = 10\cdot \log_{10} \frac{I}{I_{o}}[/tex]
[tex]L \approx 110.294\,dB[/tex]
The sound level of the point source at a distance of 10 meters is approximately 110.294 decibels.
Is telekinesis real??? I really wanna start learning it!
Answer:
if you only have to control your chakra and know how to get all your vibes to pass it to objects and it takes time to practice
HELPPP
A 1.50-kg cart rolls along a horizontal table at a constant speed of 1.70 m/s. A ball of soft putty is dropped from a stationary hand onto the cart as it passes underneath. If the speed of the cart is reduced to 1.53 m/s, calculate the mass of the ball of putty. This collision is completely inelastic
Answer:
0.17 kg
Explanation:
mc = mass of cart
mb = mass of ball
vc = speed of cart before collision
vb = speed of ball before collision (vb = 0)
v' = speed of cart and ball after collision
mc . vc + mb . vb = (mc + mb) . v'
(1.5)(1.7) + mb(0) = (1.5 + mb) . 1.53
2.55 + 0 = (1.5 + mb) . 1.53
2.55/1.53 = 1.5 + mb
5/3 = 3/2 + mb ( I change it to fraction)
mb = 5/3 - 3/2 = 10/6 - 9/6 = 1/6 kg
mb = 1/6 kg = 0.17 kg
If the model spacecraft were made ONLY out of plastic (no other materials) would it be repelled by the magnet launcher?
yes or no?
Answer:
no it wont i think
Explanation:
Which one i need help
Answer:
C
Explanation:
A cog system on the beginning segment of a roller coaster needs to get 29 occupied cars up a 120-m vertical rise over a time interval of 60 s. Each car experiences a gravitational force of 5900 N. The cars start at rest and end up moving at 0.50 m/s.
Answer:
Hello your question has some missing part attached below is the missing part
How much work is done by the cog system on the cars?
answer : 2.053 * 10^7 J
Explanation:
Total weight of car ( wT ) = 5900 * 29 = 171100 N
mass of car ( mT ) = wT / g = 171100 / 9.81 = 17459.18 kg
Hence work done by the cog system on the cars
W = ( KE[tex]_{2}[/tex] + PE[tex]_{2}[/tex] ) - ( KE[tex]_{1}[/tex] + PE[tex]_{1}[/tex] )
= ( 1/2 mv^2 + mgh ) - ( 0 )
= ( 1/2 * 17459.18 * 0.50^2) + ( 17459.18 * 9.81 * 120 )
= 2.053 * 10^7 J
if u know anything about force and acceleration please help lol I didn't pay attention to this on 8th grade (no links pls)
Answer:
Im not fully sure but i think its
red
green
purple
yellow
blue
Explanation:
because the more mass the less acceleration hopefully im right on this
Is sodium chloride a reactant
Answer:
yes it is a reactant
A uniform plank of mass 10kg and length 10m rests on two supports, A and B as shown. A boy of weight 500N stands at a distance of 2m from A. Find the reaction forces U¹ and U² at the supports A and B respectively
Answer:
U² = 142.86 N
U¹ = 357.14 N
Explanation:
Taking summation of the moment about point A, we get the following equilibrium equation: (taking clockwise direction as positive)
[tex]W(2\ m) - U^2(7\ m) = 0[/tex]
where,
W = weight of boy = 500 N
U² = reaction ay B = ?
Therefore,
[tex](500\ N)(2\ m)-(U^2)(7\ m)=0\\U^2=\frac{1000\ Nm}{7\ m}\\[/tex]
U² = 142.86 N
Now, taking summation of forces on the plank. Taking upward direction as positive, for equilibrium position:
[tex]W-U^1-U^2=0\\500\ N - 142.86\ N = U^1\\[/tex]
U¹ = 357.14 N
What happens to energy when it is consumed?
Answer:
It converts to other energy
Help!!! If you cannot type in the box, dont answer.
Answer: lollllllllllllllllllllll
Explanation:
PLEASE ANSWER THIS ASAP I WILL MARK YOU THE BRAINLIEST The actual subject is Science but they dont have that as a option in pick a subject
Answer:
I believe it is D.
Explanation:
I say this because it is position vs. seconds and it makes the most sense based on the markings. Sorry if I am wrong, hope it is right!
Answer: D. 40/15 = 2.67m/s
Explanation:
I hope it is correct
What is the magnet field of a magnet
What type of energy is thermal energy? A. Sound energy B. Chemical energy C. Kinetic energy D. Nuclear energy
Answer:
kinetic energy
Explanation:
A 1.70 m long string has a standing wave with 2 loops at a frequency of 38.4 Hz. What is the speed of the waves in the string? (Unit = m/s)
Answer:65.28
Explanation:
A long string has a standing wave with 2 loops at a frequency. The speed of the waves in the string is 65.28 m/s
What is frequency?The frequency is the number of cycles completed per second.
Given the length of the string l = is 1.70 m, no of loops n =2, frequency of wave f =38.4 Hz, then the speed of the waves is
f = nv /2l
Substitute the following values, we get
v = 38.4 x 2 x 1.70 / 2
v =65.28 m/s
Thus, the speed of the waves in the string is 65.28 m/s.
Learn more about frequency.
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4. Earth and Venus are almost identical in size and smaller than the Sun), but Venus is located closer to the Sun. Which of the following statements must be true?
O A Earth will have a wider penumbra than Venus
O B. Earth will have a shorter umbra than Venus
O C. Earth will have a longer umbra than Venus.
OD. The umbra and penumbra of Venus and Earth will have nearly the same length and shape.
1. What do you mean by energy conservation?
Answer: Energy conservation is the decision and practice of using less energy. Turning off the light when you leave the room, unplugging appliances when they're not in use and walking instead of driving are all examples of energy conservation.
Explanation: I'm not very sure but hope this is right
● Describe what Neptune needs to sustain life.
● Describe the current conditions of Neptune. How is it there?
● What is the final recommendation for the humans living on Neptune? Explain.
Answer:
1)the planet would need to have a source of energy that bacterial life can exploit, as well as a standing source of liquid water. At its surface, the temperature of Neptune dips down to 55 Kelvin. That's very cold, and there's no way liquid water could exist.
2)Neptune has the wildest and strangest weather in the entire Solar System. It has huge storms with extremely high winds. Its atmosphere has dark spots which come and go, and bright cirrus-like clouds which change rapidly. Neptune has an average temperature of -353 Fahrenheit (-214 Celsius).
3)To find life on Neptune, the planet would need to have a source of energy that bacterial life can exploit,
the ratio between the force of sliding friction and the normal force of an object is called?
A. The rolling friction
B. The drag
C. The coefficient of friction
D. The starting friction
Answer:
the coefficient of friction
Each of these flasks contains the same number of gas molecules. In
which container is the pressure highest?
Flask 1
Flask 2
Flask 3
Flask 4
Flask 3
Flask 4
Flask 2
Flask 1
Page
Answer:
Flask 1
Explanation:
when volume goes down pressure goes up, and the first flask has the smallest volume therefore the greatest pressure
We have that from the ideal gas equation that the flask with the lowest volume will have the highest pressure therefore
Flask one has the lowest Pressure
Option D
From the question we are told
Each of these flasks contains the same number of gas molecules. In
which container is the pressure highest
Generally the equation for an Ideal gas given as is mathematically given as
The ideal gass equation
[tex]PV=nRT[/tex]
Where
P=pressure
V=Volume
n=No of mole
R=Gas Constant
T=temperature
Therefore We have that from the ideal gas equation that the flask with the lowest volume will have the highest pressure therefore
Flask one has the lowest Pressure
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An unnamed professor is walking to class when an office chair (travelling in the same direction) collides with them. The professor fails into the chair and remains in the chair after collision. The professor, with a mass of 113kg, is travelling at 1.56 m/s. The chair has a velocity of 6.5 m/s, and a mass of 10kg. After the collision, and ignoring any effects of professor falling, what would be the speed of the chair professor system
Answer: 1.96 m/s
Explanation:
Given
Mass of Professor [tex]m_1=113\ kg[/tex]
Velocity of professor [tex]u_1=1.56\ m/s[/tex]
mass of chair [tex]m_2=10\ kg[/tex]
velocity of chair [tex]u_2=6.5\ m/s[/tex]
Suppose after the collision, v is the common velocity
Conserving momentum
[tex]\Rightarrow m_1u_1+m_2u_2=(m_1+m_2)v\\\\\Rightarrow v=\dfrac{113\times 1.56+10\times 6.5}{113+10}=\dfrac{241.28}{123}\\\\\Rightarrow v=1.96\ m/s[/tex]
How does friction affect the output of machines?
Answer:
In a machine, friction reduces the mechanical advantage, or the ratio of output to input: an automobile, for instance, uses one-quarter of its energy on reducing friction. Yet, it is also friction in the tires that allows the car to stay on the road, and friction in the clutch that makes it possible to drive at all
Explanation:
hope it will help you
What is the origin behind the term " cell phone "
Answer:
Rae Young at Bell Labs. They diagrammed a network of wireless towers into what they called a cellular layout. Cellular was the chosen term because each tower and its coverage map looked like a biological cell. Eventually, phones that operated on this type of wireless network were called cellular phones.
Explanation:
What is the amplitude of the resulting wave when the two waves meet at point X?
What is the wavelength of a wave that is traveling at 343 m/s with a frequency of 1000 Hz
Answer:
[tex]343 \div 1000 = 0.343[/tex]
wavelength is equivalent to the velocity divided by the frequency
A golfer wants his shot to land
122 m away on flat ground.
His club launches balls at a 55.0°
angle. How fast should
the ball leave the club?
(Unit = m/s)
Answer:
35.67 m/s
Explanation:
Applying the formular for range,
R = u²sin2∅/g....................... Equation 1
Where R = Range, u = Initial Velocity, ∅ = angle of launch, g = acceleration due to gravity
make u the subject of the equation
u = √(Rg/sin2∅)............. Equation 2
Given: R = 122 m, g = 9.8 m/s², ∅ = 55°
Substitute these values into equation 2
u = √[(122×9.8)/(sin(2×55))]
u = √(1195.6/sin110)
u = √(1272.33)
u = 35.67 m/s
Answer:
35.67
Explanation:
Its the correct answer for Acellus
Air from a metal can is removed so the pressure in the can decreases to 70000Pa, the can is then sealed. The pressure from outside the can is atmospheric pressure which is 100kPa. The area of one side of the can is 1.5m2, find the resultant force on this side of the can.
Answer:
F = 45 KN = 45000 N
Explanation:
Considering the downward direction as the positive direction:
[tex]P = P_1 - P_2[/tex]
where,
P = Resultant Pressure = ?
P₁ = Atmospheric Pressure = 100 KPa
P₂ = Pressure inside the can = 70000 Pa = 70 KPa
Therefore,
[tex]P = 100\ KPa - 70\ KPa\\P = 30\ KPa[/tex]
Now the resultant force will be given as:
[tex]F = PA[/tex]
where,
F = resultant force = ?
A = Area of side of can = 1.5 m²
Therefore,
[tex]F = (30\ KPa)(1.5\ m^2)\\[/tex]
F = 45 KN
A 3.9 kg object is on top of a shelf that is 1.5 meters high. The object falls at a velocity of 9.2 m/s. Calculate the kinetic energy of the falling object
the answer is 165J
1/2×3.9×(9.2)^2 = 165J