Claim: Most adults would erase all of their personal information online if they could.A software firm survey of 453 randomly selected adults showed that 60% of them would erase all of their personal information online if they could. Find the value of the test statistic. (Round to two decimal places as needed.)

Answers

Answer 1

Answer:

The value of the test statistic is 4.26.

Step-by-step explanation:

In this case a hypothesis test is performed to determine whether most adults would erase all of their personal information online if they could.

A random sample of n = 453 adults were selected and it was found that 60% of them would erase all of their personal information online if they could.

Assume that the population proportion is, p = 0.50.

A z-test for single proportion would to used to perform the test.

Compute the value of the test statistic as follows:

[tex]z=\frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n}}}[/tex]

  [tex]=\frac{0.60-0.50}{\sqrt{\frac{0.50(1-0.50)}{453}}}\\\\=\frac{0.10}{0.0235}\\\\=4.25532\\\\\approx 4.26[/tex]

Thus, the value of the test statistic is 4.26.


Related Questions

The population of the city of Peachwood is currently 12,000 and increases every year at a rate of 5%. The function that describes the model is ƒ(x) = 12000 • 1.05x. Which of the following choices would be the number of people in the city after one year?

Answers

Answer: 12600

Step-by-step explanation:

We are given the function that f(x) = 12000 * 1.05x

the x in f(x) is the amount of years that passed in the city of Peachwood, and the f(x) is the total population of Peachwood

These are two key elements in this function,

Therefore after 1 year the equation would be f(1) = 12000*1.05(1)

or f(1) = 12600

Find the area:

48 sq. cm.
0 24 sq. cm
O 30 sg. cm
O 60 sg. cm

Answers

the answer is 24cm^2.

hope it helped..

what is the solution of
[tex] \sqrt{ {x}^{2} + 49 = x + 5[/tex]

Answers

Answer:

  x = 2.4

Step-by-step explanation:

We assume you intend ...

  [tex]\sqrt{x^2+49}=x+5\\\\x^2+49=x^2+10x+25\qquad\text{square both sides}\\\\24=10x\qquad\text{subtract $x^2+25$}\\\\\boxed{2.4=x}\qquad\text{divide by 10}[/tex]

The kitchen is 15 feet wide and wight 18ft long. How many 12 inch Square tiles will it take to tile the kitchen floor?

Answers

Answer:

270 tiles.

Step-by-step explanation:

The kitchen is 15 x 18 feet. If we multiply we find the area is 270 square feet. one square foot is a 12 x 12 inch square, so we can fit one tile per square foot, giving us 270 tiles.

S=4LW+2WH;S+=136,L6,W=4 WHAT IS H

Answers

Answer:

H=5

Step-by-step explanation:

Answer:

5

Step-by-step explanation:

S=4lw+2wh

Put S as 136, l as 6, w as 4, and solve for h.

136 = 4(6)(4)+2(4)H

136 = 8h + 96

-8h = 96 - 136

-8h = -40

h = -40/-8

h = 5

Please answer question now in two minutes

Answers

Answer:

V lies in the exterior of <STU.

Step-by-step explanation:

V lies in the exterior of <STU.

An equilateral triangular plate with sides 8 m is submerged vertically in water so that the base is even with the surface. Express the hydrostatic force against one side of the plate as an integral and evaluate it.

Answers

Answer:

Hydro static force is =18377 N

Step-by-step explanation:

The hydro static force is equals to the hydro static pressure times the area.

The hydro static pressure of a fluid increases as the depth of the fluid increases and the formula of it is given below.

Hydro static Pressure, P = d·g·ρ

Where, d is the depth of the object

g is the gravitational constant

ρ is the density of the fluid

Density of water   ρ = [tex]1000 kg/m3[/tex]

=1000 kg/m^3 * 9.8m/s^2 which is √(3/2).a below the water level.

Side of the plate  x = 10 m

The hydrostatic force = the pressure at the center x the area =[tex][sqrt(3)/2 m][1000 kg/m^3 * 9.8m/s^2][/tex][tex][(1/2)(3)(8)(sqrt(3)/2) m^2][/tex]=18377 N

can someONE HELP ME PLS

Answers

Answer:

64 degrees

Step-by-step explanation:

Suppose the average lifetime of a certain type of car battery is known to be 60 months. Consider conducting a two-sided test on it based on a sample of size 25 from a normal distribution with a population standard deviation of 4 months.a) If the true average lifetime is 62 months and a =0.01, what is the probability of a type II error?b) What is the required sample size to satisfy and the type II error probability of b(62) = 0.1?

Answers

Answer:

a. the probability of a type II  error is 0.5319

b. the required sample size to satisfy and the type II error probability  is 59.4441

Step-by-step explanation:

From the information given; we have:

sample size n = 25

Population standard deviation [tex]\sigma[/tex] = 4

true average lifetime = Sample Mean [tex]\bar X[/tex] = 62

We can state our null hypothesis and alternative hypothesis as follows:

Null hypothesis:

[tex]\mathbf{H_o : \mu = 60}[/tex]

Alternative hypothesis

[tex]\mathbf{H_1 : \mu \neq 60}[/tex]

Where ;

∝ = 0.01

From the standard normal tables at critical value ∝ = 0.01 ; the level of significance is -2.575 lower limit and 2.575 upper limit

The z statistics for the lower limit is:

[tex]lower \ limit = \dfrac{\bar X - \mu }{\dfrac{\sigma}{\sqrt {n}}}[/tex]

[tex]-2.575= \dfrac{\bar x - 60 }{\dfrac{4}{\sqrt 25}}}[/tex]

[tex]-2.575= \dfrac{\bar x - 60 }{0.8}}}[/tex]

[tex]-2.575*0.8= {\bar x - 60 }{}}}[/tex]

[tex]-2.06= {\bar x - 60 }{}}}[/tex]

[tex]\bar x = 60-2.06[/tex]

[tex]\bar x = 57.94[/tex]

The z statistics for the upper limit is:

[tex]lower \ limit = \dfrac{\bar X - \mu }{\dfrac{\sigma}{\sqrt {n}}}[/tex]

[tex]2.575= \dfrac{\bar x - 60 }{\dfrac{4}{\sqrt 25}}}[/tex]

[tex]2.575= \dfrac{\bar x - 60 }{0.8}}}[/tex]

[tex]2.575*0.8= {\bar x - 60 }{}}}[/tex]

[tex]2.06= {\bar x - 60 }{}}}[/tex]

[tex]\bar x = 60-(-2.06)[/tex]

[tex]\bar x = 60+2.06[/tex]

[tex]\bar x = 62.06[/tex]

Thus; the probability of a type II error is determined as follows:

β = P (  [tex]57.94 < \bar x < 62.06[/tex] )

[tex]= P ( \dfrac{57.94 -62 }{\dfrac{4}{\sqrt{25}}}<\dfrac{62.06 -62 }{\dfrac{4}{\sqrt{25}}})[/tex]

[tex]= P ( \dfrac{-4.06 }{0.8}}<\dfrac{2.06 }{0.8})[/tex]

= P ( -5.08 < Z < 0.08 )

= P ( Z < 0.08) - P ( Z < - 5.08)

Using Excel Function: [ (=NORMDIST (0.08)) - (=NORMDIST(-5.08)) ] ; we have:

= 0.531881372 - 0.00000001887

= 0.531881183

0.5319

b.

What is the required sample size to satisfy and the type II error probability of b(62) = 0.1

Recall that:

The critical value of ∝ = 2.575  ( i. e   [tex]Z_{1 - \alpha/2 } = 2.575[/tex]  )

Now ;

the critical value of β is :

[tex]Z _{1- \beta} = 1.28[/tex]

The  required sample size to satisfy and the type II error probability  is therefore determined as :

[tex]n = [\dfrac{(Z_{1 - \alpha/2} + Z_{1 - \beta} ) \sigma }{\delta}]^2[/tex]

[tex]n = [\dfrac{(2.575+1.28 ) 4 }{2}]^2[/tex]

[tex]n = [\dfrac{(3.855 ) 4 }{2}]^2[/tex]

[tex]n = [\dfrac{(15.42 ) }{2}]^2[/tex]

n = 7.71 ²

n= 59.4441

Thus; the required sample size to satisfy and the type II error probability  is 59.4441

A)

In order to calculate the Type II Error, we proceed with stating the factors:

Hypothesized Mean is given as  =  μ[tex]_{0} [/tex]        = 60

True Mean  is given as                 =  μa        = 62

Standard Deviation  is given as  = σ           = 4

Sample Size                                   = n           = 25

Standard error of mean                = σx          =σ/[tex]\sqrt{\\} [/tex]σ               =  0.80

given 0.01 level and two tailed test critical value Zσ             ±  2.58 or approximately 3

Acceptance region is

given as:   = μ - Z∝ * σx ≤ Π ≤ μ+Z∝⇄            =57.9360 ≤x≤   62.0640

Type II Error = probability of not rejecting β    = P(57.94-μa/σx))     <Z< (62.064-μa)/σx))

                                      = P (-5.08   <Z<    0.08)
                                      = 0.5319-0)

                                      = 0.532


B

Hypothesized mean                        = μ₀             =        60

True Mean                                        =μₐ               =       62          

Standard Deviation                          =σ                 =      4

for 0.01 level and two-tailed test critical value Z∝/2              ± 2.58

for 0.01 level of type II error critical value Z[tex]\beta [/tex]                         = 1.28

Required sample size    = n                                       = ([tex]Z_{\alpha /2} [/tex] + [tex]Z_{\beta } [/tex])²σ²/(μ₀-μ₀)²
                                                                                    = 60


See the link below for more about two-sided tests:
https://brainly.com/question/8170655

 

Please answer this correctly

Answers

Answer:

3/7

Step-by-step explanation:

We have 7 possible outcomes. Of those 7, we are looking for 4 ≤ x < 7. Since only 3 of those values work (4, 5, 6), our answer is 3/7.

Find the value of x in each of the following exercises:

Answers

Answer:

x = 25

Step-by-step explanation:

you just work out all of the degrees in the other triangles first

Suppose you toss a coin 100 times and get 65 heads and 35 tails. Based on these​ results, what is the probability that the next flip results in a tail​?

Answers

Answer:

[tex] P(Head) = \frac{65}{100}=0.65[/tex]

[tex] P(Tail) = \frac{35}{100}=0.35[/tex]

And for this case the probability that in the next flip we will get a tail would be:

[tex] P(Tail) = \frac{35}{100}=0.35[/tex]

Step-by-step explanation:

For this case we know that a coin is toss 100 times and we got 65 heads and 35 tails.

We can calculate the empirical probabilities for each outcome and we got:

[tex] P(Head) = \frac{65}{100}=0.65[/tex]

[tex] P(Tail) = \frac{35}{100}=0.35[/tex]

And for this case the probability that in the next flip we will get a tail would be:

[tex] P(Tail) = \frac{35}{100}=0.35[/tex]

Solve 3v2 – 84 = 0, where v is a real number.
Round your answer to the nearest hundredth.
If there is more than one solution, separate them with commas.
If there is no solution, click on "No solution".

Answers

Answer:

The given equation has two solutions

[tex]v = (-5.29, \: 5.29)[/tex]

Step-by-step explanation:

The given equation is

[tex]3v^2 - 84 = 0[/tex]

Let’s solve the equation

[tex]3v^2 - 84 = 0 \\\\3v^2 = 84 \\\\v^2 = \frac{84}{3} \\\\v^2 = 28 \\\\[/tex]

Take the square root on both sides

[tex]\sqrt{v^2} = \sqrt{28} \\\\v = \sqrt{28} \\\\v = \pm 5.29 \\\\[/tex]

So the equation has two solutions

[tex]v = (-5.29, \: 5.29)[/tex]

Also refer to the attached graph of the equation where you can verify that the equation has two solutions.

Note:

It is a very common mistake to consider only the positive value and not the negative value.

Consider the square root of 25

[tex]\sqrt{25} = \pm 5 \\\\Since \\\\5 \times 5 = 25 \\\\-5 \times -5 = 25 \\\\[/tex]

That is why we have two solutions for the given equation.

Help me with this problem, thank you<3

Answers

Answer:

1,050 workers

Step-by-step explanation:

25% = 0.25

0.25 × 1400 = 350

1400 - 350 = 1050

Hope this helps.

The length of a rectangle is 3 yd longer than its width. If the perimeter of the rectangle is 62 yd, find its width and length

Answers

Answer:

Length=17 yds, Width=14 yds

Step-by-step explanation:

62=x+x+(x+3)+(x+3)

4x+6=62

4x=56

x=14

x+3=17

Which equation is a function of x?

Answers

Answer:

x" means that the value of y depends upon the value of x, so: y can be written in terms of x (e.g. y = 3x ). If f(x) = 3x, and y is a function of x (i.e. y = f(x) ), then the value of y when x is 4 is f(4), which is found by replacing x"s by 4"s . this should help I asked my brother for the answer and he told me to put this happy to help :0

Line segment ON is perpendicular to line segment ML. What is the length of segment NP?

Answers

Answer:

2 units.

Step-by-step explanation:

In this question we use the Pythagorean theorem which is shown below:

Given that

The right triangle OMP

The hypotenuse i.e OM is the circle radius =5 units.

The segment MP = 4 units length

Therefore

[tex]OP^2 + MP^2 = OM^2[/tex]

[tex]OP^2 + 4^2 = 5^2[/tex]

[tex]OP^2 + 16 = 25[/tex]

So OP is 3

Now as we can see that ON is also circle radius so it would be 5 units

And,

ON = OP + PN

So,

PN is

= ON - OP

= 5 units - 3 units

= 2 units

Answer:

2

Step-by-step explanation:

A local doctor’s office logged the number of patients seen in one day by the doctor for ten days. Find the means, median, range, and midrange of the patients seem in 10 days. 27 31 27 35 35 25 28 35 33 24

Answers

Answer:

Mean = 30, Median = 29.5, Range = 9 and Mid-range = 29.5.

Step-by-step explanation:

We are given that a local doctor’s office logged the number of patients seen in one day by the doctor for ten days.

Arranging the given data in ascending order we get;

24, 25, 27, 27, 28, 31, 33, 35, 35, 35.

(a) Mean is calculated by using the following formula;

         Mean, [tex]\bar X[/tex]  =  [tex]\frac{\text{Sum of all values}}{\text{Total number of observations}}[/tex]

                          =  [tex]\frac{27+ 31+ 27+ 35+ 35+ 25+ 28+ 35+ 33+ 24}{10}[/tex]

                          =  [tex]\frac{300}{10}[/tex]  = 30

So, the mean of the given data is 30.

(b) For calculating the median, we have to first have to observe that the number of observations (n) in the data is even or odd.

If n is odd, then the formula for calculating median is given by;

                     Median  =  [tex](\frac{n+1}{2})^{th} \text{ obs.}[/tex]

If n is even, then the formula for calculating median is given by;

                     Median  =  [tex]\frac{(\frac{n}{2})^{th} \text{ obs.}+ (\frac{n}{2}+1)^{th} \text{ obs.} }{2}[/tex]

Here, the number of observations is even, i.e. n = 10.

So,  Median  =  [tex]\frac{(\frac{n}{2})^{th} \text{ obs.}+ (\frac{n}{2}+1)^{th} \text{ obs.} }{2}[/tex]

                     =  [tex]\frac{(\frac{10}{2})^{th} \text{ obs.}+ (\frac{10}{2}+1)^{th} \text{ obs.} }{2}[/tex]

                     =  [tex]\frac{(5)^{th} \text{ obs.}+ (6)^{th} \text{ obs.} }{2}[/tex]

                     =  [tex]\frac{28+31}{2}[/tex]

                     =  [tex]\frac{59}{2}[/tex]  =  29.5

So, the median of the data is 29.5.

(c) The range of the data is given by = Highest value - Lowest value

                                                        = 35 - 24 = 9

So, the range of the data is 9.

(d) Mid-range of the data is given by the following formula;

                   Mid-range  =  [tex]\frac{\text{Highest value}+\text{Lowest value}}{2}[/tex]

                                      =  [tex]\frac{35+24}{2}[/tex] = 29.5

Three girls of a group of eight are to be chosen. In how many ways can this be done? ​

Answers

Answer:

Step-by-step explanation:

8P3=8*7*6=336

Suggest changing to “On the graph of an exponential function representing growth, what happens to the slope of the graph as x increases?”

Answers

Answer:

If we have a growing exponential relation, we can write it as:

f(x) = A*r^x

Where A is the initial amount, r is the rate of growth, in this case, r > 1 (because is a growing exponential relation)

Now, the "slope" of the graph in x, is equal to the derivate of f(x) in that point, and we have:

f'(x) = A*(r^x)*ln(r)

Now, remember that r > 1, then ln(r) > 0.

then, f'(x) is a growing function as x grows, and f'(x) grows exponentially, this means that the slope of the graph also grows exponentially as x grows.

Please answer this correctly

Answers

Answer:

1/5

Step-by-step explanation:

The number 5 or greater than 4 is 5.

1 number out of 5 total parts.

= 1/5

P(5 or greater than 4) = 1/5

What is 6 1/2 subtracted by 2 2/3

Answers

Answer:

The answer to this equation is 3 5/6

Step-by-step explanation:

in order to solve this problem, we must first turn these fractions into improper fractions. We can do this by multiplying the base number with the denominator and adding the numerator to that number.

6 1/2 = 13/2

2 2/3 = 8/3

Now, set up your equation.

13/2 - 8/3

Change the denominators to the same number so it will be easier to subtract.

39/6 - 16/6

Now subtract.

23/6 = 3 5/6

Answer:

3 5/6

Step-by-step explanation:

6 1/2 - 2 2/3 = 13/2 - 8/3

(39 - 16)/6 = 23/6 = 3 5/6

Solve for the variables: 2x+5y=37 11-2x=y

Answers

Answer:

x= 2.25

y=6.5

Step-by-step explanation:

2x+5y=37 y=11-2x

2x+5(11-2x)=37

2x+55-10x=37

-8x+55=37

-55       -55

-8x=-18

÷-8   ÷-8

x= 2.25

y=11-2x

y=11-2(2.25)

y=11-4.5

y=6.5

Answer: x= 18/8 y = 13/2

Step-by-step explanation:

We know that y = 11-2x

So, you want to do the substitution method.

The equation states : 2x+5y  = 37

So, you would substitute the y in the equation for 11-2x

2x+5(11-2x) = 37

2x+55-10x = 37  (combine like terms)

-8x +55 = 37 (subtract 55 from each side)

-8x = -18 ( divide -8 from each side)

x = 18/8

Now, we need to solve for y. For that, we just need to substitute the x in the y equation.

It would look like this: 11-2(18/8) =y

Now we solve.

11-18/4 = 13/2 (6.5)

So, y equals 13/2. Now to check , plug in each for the equation and see if it is correct.  

Explain the importance of factoring.

Answers

Answer:

Factoring is a useful skill in real life. Common applications include: dividing something into equal pieces, exchanging money, comparing prices, understanding time, and making calculations during travel.

Sorry if this is a little wordy, I can get carried away with this sort of thing

anyway, hope this helped and answered your question :)

In a test of the effectiveness of garlic for lowering​ cholesterol, 4545 subjects were treated with garlic in a processed tablet form. Cholesterol levels were measured before and after the treatment. The changes ​(beforeminus−​after) in their levels of LDL cholesterol​ (in mg/dL) have a mean of 5.15.1 and a standard deviation of 19.119.1. Construct a 9090​% confidence interval estimate of the mean net change in LDL cholesterol after the garlic treatment. What does the confidence interval suggest about the effectiveness of garlic in reducing LDL​ cholesterol?

Answers

Answer:

[tex] 5.1 - 2.015 \frac{19.1}{\sqrt{45}}= -0.637[/tex]

[tex] 5.1 + 2.015 \frac{19.1}{\sqrt{45}}= 10.837[/tex]

And for this case since the confidence interval contains the value 0 we don't have significant evidence that we have a net change in the levels

Step-by-step explanation:

For this case we have the following info given:

[tex] n=45[/tex] represent the sample size

[tex] \bar X= 5.1[/tex] represent the sample mean

[tex] s= 19.1[/tex] represent the sample deviation

We can calculate the confidence interval for the mean with the following formula:

[tex] \bar X \pm t_{\alpha/2} \frac{s}{\sqrt{n}}[/tex]

The confidence level is 0.90 then the significance level would be [tex]\alpha=0.1[/tex] and the degrees of freedom are given by:

[tex] df= n-1 = 45-1=44[/tex]

And the critical value for this case would be:

[tex] t_{\alpha/2}=2.015[/tex]

And replacing we got:

[tex] 5.1 - 2.015 \frac{19.1}{\sqrt{45}}= -0.637[/tex]

[tex] 5.1 + 2.015 \frac{19.1}{\sqrt{45}}= 10.837[/tex]

And for this case since the confidence interval contains the value 0 we don't have significant evidence that we have a net change or efectiveness in the levels

For the questions 1 - 4, in the digram below, ab is parallel to cd. Use the digram to find the unknown angles

Answers

Answer:

w=25 degrees, x= 155 degrees, y= 155 degrees, z=155 degrees

Step-by-step explanation:

Angle W and angle I are equal because they are located on same line with PARALLEL lines A and C

Angle X and angle I need to add up to 180 degrees because they together are a strait line, so angle X is 155 because 155+25 =180

Angle Y and angle I are equal because they are exactly the same but lower on the line

Angle Z is same as angle X explenation just a different strait line

Answer:

W=25 degrees

X=155 degrees

Y =155 degrees

Z= 155 degrees

Step-by-step explanation:

Which is NOT supported by this graph?
30
25
20
15
10
Profit
5
(dollars)
0
-10
-15
Cars Washed

Answers

Answer:

D -price of car wash keeps getting higher

Answer: The price of a car wash keeps getting higher

Step-by-step explanation:

Set up and evaluate the optimization problem. You are constructing a cardboard box from a piece of cardboard with the dimensions 4 m by 8 m. You then cut equal-size squares from each corner so you may fold the edges. What are the dimensions (in m) of the box with the largest volume

Answers

Answer:

[tex]Shorter\ side=4-2\times 0.845=2.31\ m\\Longest\ side=8-2\times 0.845=6.31\ m\\Height=0.845\ m[/tex]

Step-by-step explanation:

Given that , dimension of the cardboard is 4 m by 8 m.

Lets the dimensions of the square is x m by x m.

The volume after cutting the equal size of square from all the four corners is given as

[tex]V=x\times (4-2x)\times (8-2x)\\V=x\times (32-16x-8x+4x^2)\\V=x\times (4x^2-24x+32)\\V=4x^3-24x^2+32x\\[/tex]

For the maximum volume

[tex]\dfrac{dV}{dx}=12x^2-48x+32=0\\3x^2-12x+8=0\\[/tex]

For maximum value of volume , the value of x will be 0.845

x= 0.845

Therefore the dimensions will be

[tex]Shorter\ side=4-2\times 0.845=2.31\ m\\Longest\ side=8-2\times 0.845=6.31\ m\\Height=0.845\ m[/tex]

The volume of a shape is the amount of space in the shape.

The dimensions that produce the largest volume are: 2.31 m by 6.31 m by 0.845 m

The dimensions of the cardboard is given as:

[tex]\mathbf{Length = 4m}[/tex]

[tex]\mathbf{Width = 8m}[/tex]

Assume the cut-out is x.

So, the dimension of the box is:

[tex]\mathbf{Length = 4 - 2x}[/tex]

[tex]\mathbf{Width = 8 - 2x}[/tex]

[tex]\mathbf{Height = x}[/tex]

So, the volume of the box is:

[tex]\mathbf{V = (4 - 2x)(8 - 2x)x}[/tex]

Expand

[tex]\mathbf{V = 32x -24x^2 + 4x^3}[/tex]

Differentiate

[tex]\mathbf{V' = 32 -48x + 12x^2}[/tex]

Set to 0

[tex]\mathbf{32 -48x + 12x^2 = 0}[/tex]

Divide through by 4

[tex]\mathbf{8 -12x + 3x^2 = 0}[/tex]

Rewrite as:

[tex]\mathbf{3x^2-12x +8 = 0}[/tex]

Using a calculator, we have:

[tex]\mathbf{x = 0.845,\ 3.155}[/tex]

3.155 is greater than the dimension of the box.

So, we have:

[tex]\mathbf{x = 0.845}[/tex]

Recall that:

[tex]\mathbf{Length = 4 - 2x}[/tex]

[tex]\mathbf{Width = 8 - 2x}[/tex]

[tex]\mathbf{Height = x}[/tex]

So, we have:

[tex]\mathbf{Length = 4 - 2 \times 0.845 = 2.31}[/tex]

[tex]\mathbf{Width = 8 - 2 \times 0.845 = 6.31}[/tex]

[tex]\mathbf{Height = 0.845}[/tex]

Hence, the dimensions that produce the largest volume are: 2.31 m by 6.31 m by 0.845 m

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https://brainly.com/question/15918399

The manager of the Danvers-Hilton Resort Hotel stated that the mean guest bill for a weekend is $600 or less. A member of the hotel's accounting staff noticed that the total charges for guest bills have been increasing in recent months. The accountant will use a sample of weekend guest bills to test the manager's claim.
a. Which form of the hypotheses should be used to test the manager's claim?
H0:
greater than or equal to 600
greater than 600
less than or equal to 600
less than 600
equal to 600
not equal to 600
Ha: Select
greater than or equal to 600
greater than 600
less than or equal to 600
less than 600
equal to 600
not equal to 600
b. When H0 cannot be rejected, can we conclude that the manager's claim is wrong?
Yes
No
c. When H0 can be rejected, can we conclude that the manager's claim is wrong?
Yes
No

Answers

Answer:

(a) Null Hypothesis, [tex]H_0[/tex] : [tex]\mu \leq[/tex] $600

Alternate Hypothesis, [tex]H_A[/tex] : [tex]\mu[/tex] > $600

(b) When H0 cannot be rejected, we conclude that the manager's claim is correct.

(c) When H0 can be rejected, we conclude that the manager's claim is wrong.

Step-by-step explanation:

We are given that the manager of the Danvers-Hilton Resort Hotel stated that the mean guest bill for a weekend is $600 or less.

The accountant will use a sample of weekend guest bills to test the manager's claim.

Let [tex]\mu[/tex] = population mean guest bill for a weekend

(a) Null Hypothesis, [tex]H_0[/tex] : [tex]\mu \leq[/tex] $600

Alternate Hypothesis, [tex]H_A[/tex] : [tex]\mu[/tex] > $600

Here null hypothesis states that the mean guest bill for a weekend is $600 or less.

On the other hand, alternate hypothesis states that the mean guest bill for a weekend is more than $600.

(b) When the null hypothesis ([tex]H_0[/tex]) cannot be rejected, then the correct conclusion would be: We conclude that the mean guest bill for a weekend is $600 or less which means that the manager's claim is correct.

(c) When the null hypothesis ([tex]H_0[/tex]) can be rejected, then the correct conclusion would be: We conclude that the mean guest bill for a weekend is more than $600 which means that the manager's claim is wrong.

b. Parallelogram PQRS has base RS=14 m and an area of 70 m². What is the height of
the parallelogram?


Rs=14m and an area of 70m2

Answers

Answer

h = 5m

Step-by-step explanation:

area of a parallelogram is b * h

base = 14 m

h = ?

Area = 70 m²

Area = b * h

70 = 14 * h

h = 70 / 14

h = 5 m

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