Circular motion requires the application of a constant force in which direction?
Outward from the circle
Toward the center of the circle
Toward the object in motion
Away from an object

Answers

Answer 1
Toward the center of the circle

The final motion characteristic for an object undergoing uniform circular motion is the net force. The net force acting upon such an object is directed towards the center of the circle. The net force is said to be an inward or centripetal force.

Related Questions

A box is sitting stationary on a long level ramp on level ground. The coefficient of static friction is (1.0). One end of the ramp is slowly lifted higher and higher. What is the angle of the ramp with respect to the ground when the box begins slidig?

Answers

Answer:

45 degrees

Explanation:

Given that the coefficient of friction, [tex]\mu=1.0[/tex]

Let the angle of the ramp be [tex]\theta[/tex].

The gravitational force acting downward [tex]=mg[/tex]

The normal reaction by the ramp on the box, [tex]N=mg\cos\theta[/tex]

So, the maximum frictional force that can act on the box, [tex]f= \mu N[/tex]

The force along with the plane in the direction of sliding, [tex]F = mg\sin\theta[/tex]

When the box begins sliding, the F must have to overcome the frictional force,f.

So, F=f

[tex]mg\sin\theta=\mu N \\\\mg\sin\theta=\mu mg\cos\theta \\\\\frac {\sin\theta}{\cos\theta}=\mu \\\\\tan\theta=\mu \\\\\theta=\tan^{-1}\mu \\\\[/tex]

Putting the value of \mu, we have

[tex]\theta=\tan^{-1}1[/tex]

[tex]\theta=45[/tex] degrees.

Hence, the angle of the ramp with respect to the ground when the box begins sliding is 45 degrees.

A book that weighs 5 N sits on a table. What force does the table apply to the book?

Answers

Answer:

E =F.d =[1/2]mv^2

mad = [1/2]mv^2

d= v^2/2a ,v=u+at , v^2 = [at]^2 since u=0

So d = at^2/2

F = ma= 20a= 50 , a=5/2 and t=2

so d = [5/2][2^2]/2=5

Explanation:

Every action has an equal and opposite reaction. It is an action-reaction principle. Therefore the table exerts a force of 5 N on the book in order to be in stable condition.

What is Newton's third law of motion?

Newton's third law of motion state that every action has an equal and opposite reaction. It is an action-reaction principle. It stated that the force always exists in a pair.

Therefore the table exerts a force of 5 N on the book in order to be in stable condition.

The given data in the problem is ;

W is the weight of the book sits on table = 5N

N is the normal force on the book

From the equilibrium equation ;

Weight -Normal force on the book  =0

Weight =Normal force on the book

The normal force on the book =5N

Hence the table exerts a force of 5 N on the book in order to be in stable condition.

To learn more about Newton's third law of motion refer to the link;

https://brainly.com/question/1077877

deducing the acceleration = deduce the gradient of velocity-time graphs
true or false?

Answers

Answer:

True

Explanation:

Understanding the relationship between change in velocity with time will explain to you how the object is accelerating or decelerating. This means acceleration is a ratio calculated from the change in velocity of an object and change in time. In a velocity time graph, the y-axis represents the velocity and the x-axis represents the time.

The slope of the graph m = Δ y-axis values/Δ x-axis values

m= Δvelocity / Δ time

m= Δ v / Δ t ------this the definition of acceleration so;

a= Δ v / Δ t

Conclusion : The slope/gradient of a velocity -time graph is acceleration.

what is the KE of a 1.00 kg hammer swinging at 20.0 m/s? 200 Joules
I know the answer I just need help understanding it.

Answers

Answer:

Explanation:

From the question given above, the following data were obtained:

Mass (m) = 1250 kg

Velocity (v) = 20.0 m/s.

Kinetic energy (K.E) =?

Kinetic energy is simply defined as energy possed by a body in motion. Mathematically, it is expressed as:

K.E = ½mv²

Where:

K.E is the kinetic energy

m is the mass of the object

v is the velocity of the object.

Thus, we can obtain the kinetic energy of the automobile by using the above formula as illustrated below:

Mass (m) = 1250 kg

Velocity (v) = 20.0 m/s.

Kinetic energy (K.E) =?

K.E = ½mv²

K.E = ½ × 1250 × 20²

K.E = 625 × 400

K.E = 250000 J

Therefore, the kinetic energy of the automobile is 250000 J

Do machines create less work? Example: pulley system

Answers

Answer:

Technically, no the work of building machines is hard but in the long run, Yes they are easier after they're built.

Explanation:

Which element most likely interacts with water the same way lithium interacts with water?

Answers

Answer:

Is there a multiple choice or select all that apply? I would say Potassium (K) or Sodium (Na)

Explanation:


Help!! Or I get an F!!!
What planet could you jump the highest?

Answers

Answer:

Is Mercury an answer on your thing?

Explanation:

Mercury has the least amount of gravity, so therefore you can jump the highest on Mercury.

Answer:

Jupiter

Explanation:

Jupiter has more than 300 time the mass as earth. so, it's gravitational pull is stronger.

Hopefully this helps

The radius of the planet Mercury is 2.43 x 10^6m and its mass
is 3.2 x 10^23 kg. What is the speed of a satellite in orbit
265.000 m above the surface?

Answers

Hey There!_____________________________________Answer:

[tex]\huge\boxed{Option D}[/tex]

_____________________________________DATA:

Radius of Mercury = [tex]R_m[/tex] = [tex]2.43x10^6m[/tex]

Mass of Mercury = [tex]M_m = 3.2x10^{23}m[/tex]

Distance Satellite above the surface of the Mercury = d = 265,000m

Gravitational Constant =  [tex]G = 6.67x10^{-11} \frac{N.m^2}{kg^2}[/tex]

_____________________________________SOLUTION:

Since the Satellite is orbiting around the Planet Mercury, due to the centripetal force, and Centripetal force is the force that acts towards the center of the circle, Whereas The gravitational force also acts towards the center of the circle thus we can say that Centripetal force is equal or same as centripetal force.  So,

               

                                             [tex]F_g =F_C[/tex]

Fg is Given by,

                                           [tex]F_g = \frac{GM_MM_S}{r^2}[/tex]

Fc is Given by,

                                           [tex]F_c=\frac{M_SV^2}{r}[/tex]

Where,

            G is Gravitational Constant

            [tex]M_e[/tex] is mass of Planet Mercury

            [tex]M_S[/tex] is Mass of Satellite

             r(small letter) is the distance between the center of the Planet Mercury and the satellite.

             V is velocity of satellite

_____________________________________

Now,

                                 [tex]\frac{GM_MM_S}{r^2} =\frac{M_SV^2}{r}[/tex]

                         

                                 [tex]V = \sqrt\frac{GM_M}{r}[/tex]

 r can also be written as,

                           

                                  [tex]V = \sqrt\frac{GM_M}{R_M +d}[/tex]

Substitute the variables,

         

                                  [tex]V = \sqrt{\frac{(6.67x10^{-11})x(3.2x10^{23})}{2695000}[/tex]

Simplify the equation,

           

                                  V = 2814 [tex]\frac{m}{s}[/tex]

Approximately,

                                  V = 2800 [tex]\frac{m}{s}[/tex]

_____________________________________Best Regards,'Borz'

Could somebody please explain the Coriolis effect? Thank you! (also the subject is physical science but that wasn't an option so I just put physics)

Answers

Answer:

The Coriolis Effect makes things appear to move in a curve around our planet, like, for example, a plane. This is also due to the fact that our Earth is round, so nothing really moves in a straight line. It is "an effect whereby a mass moving in a rotating system experiences a force (the Coriolis force ) acting perpendicular to the direction of motion and to the axis of rotation."

Explanation:

What is the work energy transfer equation?

Answers

Answer:

The equation used to calculate the work done is: work done = force × distance. W = F × d. This is when: work done (W) is measured in joules (J)

Answer:

The equation used to calculate the work done is: work done = force × distance. W = F × d. This is when: work done (W) is measured in joules (J)

Explanation:

The net work done on a particle equals the change in the particle's kinetic energy:

An example of a poor coping mechanism is ?

Answers

Answer: A bad, maladaptive, unhealthy or destructive coping mechanism is one where the behavior does not resolve the problem in the long-term and may actually increase the harm. Unhealthy coping strategies may feel like they are having the desired effect in the short term.

Explanation: Yes, it was from google...

a motorbike can travel 1000 meters in 10 minutes calculate how car it can travel in 1 sec. ​

Answers

Answer:

1.67meter

Explanation:

if it can travel 1000 meters in 10 minutes, 10 minutes are 600 secs (10×60), 1000÷600 is 1.67

Answer:

HI

Explanation:

Nore ordered an ice cream cone.

Answers

Answer:

okay

Explanation:

okay

Answer:

Cool

Explanation:

A girl pushes a wagon at constant velocity. If the
momentum of the wagon is 50 kg*m/s at a
velocity of 2 m/s, the mass of the wagon is what

Answers

Answer; 100 m/s
Explanation;
F= ma
50 kg x 2 m/s

The most important characteristic in designing the soundproof room is to create walls that

Answers

Answer:

make sound bounce off walls

Answer:

Explanation:

Walls that absorb the sound and dont just bounce or reflect the sound straight back. Like how video makers have foam walls with ridges on their walls.

What distance does a biker travel if he rides at a constant speed or 22 m/s for 45 seconds?

Answers

Answer:

it would be 990 m.

Explanation:

22 m/s x 45 seconds.

A stone dropped from the top of a 80m high building strikes the ground at 40 m/s after falling for 4 seconds. The stone's potential energy with respect to the ground is equal to its kinetic energy

Answers

Answer:

A

Explanation:

Given that a stone dropped from the top of a 80m high building strikes the ground at 40 m/s after falling for 4 seconds. The stone's potential energy with respect to the ground is equal to its kinetic energy. (use 9 - 10 m/s)

O at the moment of impact

2 seconds after the stone is released after the stone has fallen 40 m

when the stone is moving at 20 m/s

At the top of the hill, the P.E = mgh

P.E = 10 × 80 × m

P.E = 800m

At the moment of impact, K.E = 1/2mv^2

K.E = 1/2 × 40^2 × m

K.E = 1/2 × 1600 × m

K.E = 800m

Since both P.E and K.E are the same, we can therefore conclude that the stone's potential energy with respect to the ground is equal to its kinetic energy at the moment of impact.

The correct answer is option A.

I need a little help with this

Answers

Answer:

truck 1 has the most velocity

Explanation:

Because it weights less which means it faster and yea

A car travels 14 km due west, then does a
U-turn, and travels 43 km due west.
I. What total distance has the car
traveled?
II.
What is the total displacement of the
car?
III. If the entire trip took 3.20 hours.
determine the average speed of the
car. Give
your answer in both
km hour, and m s. (show
conversion)
IV. If the entire trip took 2.50 hours.
determine the average velocity of
the car. Give your answer in both
km h, and mph (show conversion)

Answers

Explanation:

It is given that,

A car travels 14 km due west, then does a U-turn and travels 43 km due east (when it takes U-turn, it will change direction from west to east)

i. Total distance = total path covered

= 14 km + 43 km

= 57 km

ii. Let east is positive and west is negative.

Displacement = final position-initial position

= 43-14

= 29 km

iii. If time taken in the entire trip = 3.2 hours

Average speed = distance/time

[tex]s=\dfrac{57\ km}{3.2\ h}\\\\=17.81\ km/h[/tex]

1 km/h = 0.2777 m/s

17.81 km/h = 4.94 m/s

iv. If time taken in the entire trip = 2.5 hours

Average velocity = displacement/time

[tex]v=\dfrac{29\ km}{2.5\ h}\\\\=11.6\ km/h[/tex]

1 km/h = 0.621 mph

11.6 km/h = 7.2 mph

Henc, this is the required solution.

When momentum is conserved it is called _____. (multiple choice)
A.) Conservation of Momentum
B.) The Law of Momentum
C.) The Physics of Momentum
D.) The Rules of Momentum

Answers

Answer:

Based off the word "conserved" I would say

A. Conservation of Momentum.

Explanation:

Answer:

A.) Conservation of Momentum

Jenny puts a book on her desk. Jenny’s book has an area of 200 cm2.It exerts a pressure of 0.05 N/cm2 on the desk. What is the weight of the book? *

Answers

The weight is 10N :))

Engine 1 produces twice the power of engine 2.
If it takes engine 1 the time T to do the work W, how long does it take engine 2 to do the same work?
Express your answer in terms of some of all of the variables T and W.
T2=________________

Answers

Answer:

[tex]T_2=\frac{T}{2}[/tex]

Explanation:

Given that engine 1 produces twice the power of engine 2.

Let [tex]P_1[/tex] and [tex]P_2[/tex] be the power of engine 1 and engine2.

So, the power of the engine 2,

[tex]P_2 = 2P_1\cdots(i)[/tex]

As, Work = Power x time,

So, the work, W, done by an engine 1:

[tex]W=P_1\timesT\cdots(ii)[/tex]

The work, W, done by an engine 2:

[tex]W_2=P_2\times T_2\cdots(iii)[/tex]

If the work done by both the engines are the same, then

[tex]W_2=W[/tex]

[tex]\Rightarrow P_2\times T_2=P_1\timesT[/tex] [from (ii) nd (iii)]

[tex]\Rightarrow 2P_1\times T_2=P_1\timesT[/tex] [by using (i)]

[tex]\Rightarrow 2 T_2=T \\\\\Rightarrow T_2=\frac{T}{2}[/tex]

Hence, [tex]T_2=\frac{T}{2}.[/tex]

The time taken for engine 2 to do the same amount of work is given by:

T₂ = 2T

Let the power of the 1st engine be P₁

Let the power of the 2nd engine be P₂

Power = Work / time

From the question given above,

Engine 1 produces twice the power of engine 2.

Thus,

P₁ = 2P₂

P₂ = ½P₁

Next, we shall determine the power used by engine 1 to do the work in time T.

Work = W

Time (T₁) = T

Power (P₁) =?

Power = Work / time

[tex]P_{1} = \frac{W}{T}\\\\[/tex]

Finally, we shall determine the time taken for engine 2 to do the same work.

Work = W

Power of engine 1 (P₁) = [tex]\frac{W}{T}\\\\[/tex]

Power of engine 2 (P₂) = ½P₁

Power of engine 2 (P₂) = [tex]\frac{1}{2} (\frac{W}{T}) = \frac{W}{2T}[/tex]

Time (T₂) =?

[tex]Power = \frac{Work}{time} \\\\ P_{2} = \frac{W}{T_{2}} \\\\\frac{W}{2T} = \frac{W}{T_{2}} \\\\\frac{1}{2T} = \frac{1}{T_{2}}\\\\[/tex]

Invert

T₂ = 2T

Therefore, the time taken for engine 2 to do the same amount of work is: T₂ = 2T

Learn more: https://brainly.com/question/21822614

Please help! Will mark brainliest!

Answers

Answer:

im pretty sure its d

Explanation:

When you put on the brakes of your bike, the wheels stop
turning. Then friction between the wheels and the road slows
your bike to a stop. Which type of friction is this?
a static friction
b sliding friction
ċ fluid friction
d rolling friction
7t?
Check it

Answers

Answer:

b

Explanation:

ibecause the wheels are sliding on the ground i think

What two things does force depend on​

Answers

Hey Um think it’s Mass and distance

A rose plant inherited two alleles for white flower petals.

Which conclusion is best supported by the given information?

Answers

Answer:

a

Explanation:

Answer:

A or each parent had at least one allele for white pedals

Explanation:

Question 4 of 10
Which option is a good blackbody radiator?
O A. A lightbulb
O B. A balloon
O C. A person
O D. A mirror
SUBM

Answers

Answer:

A lightbulb

Explanation:

Answer:

Lightbulb

Explanation: got it right

Explain you own words why energy is considered to be naturals money. Give an example to support your explanation

Answers

Answer:

because we naturally use energy everyday in everyway , energy is also a bill for instance you electric bill used by energy

Explanation:

plzzzz help me this is due today. only need help with these two questions and the element is oxygen.

How do protons, neutrons, and electrons differ in terms of their electrical charges and locations within the atom?

Describe the four fundamental forces. Which of these forces are involved in chemical bonding?

Answers

Answer: thanks for the point

Explanation:

A car of mass 1500 kg starting from rest can reach a speed of 20
m/s within 10 seconds. Calculate the accelerating force of the car
engine.

Answers

Explanation:

F=MA

F=1500 * 2

F=3000N

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