Answer:
What was the actual the question? I am confused.
Explanation:
Explain the five generations of computer
Answer:
1 First Generation
The period of first generation: 1946-1959. Vacuum tube based.
2 Second Generation
The period of second generation: 1959-1965. Transistor based.
3 Third Generation
The period of third generation: 1965-1971. Integrated Circuit based.
4 Fourth Generation
The period of fourth generation: 1971-1980. VLSI microprocessor based.
5 Fifth Generation
The period of fifth generation: 1980-onwards. ULSI microprocessor based.
The phrase "generation" refers to a shift in the technology that a computer is/was using. The term "generation" was initially used to describe different hardware advancements. These days, a computer system's generation involves both hardware and software.
Who invented the 5th generation of computers?The Japan Ministry of International Trade and Industry (MITI) launched the Fifth Generation Computer Systems (FGCS) initiative in 1982 with the goal of developing computers that use massively parallel computing and logic programming.
The generation of computers is determined by when significant technological advancements, such as the use of vacuum tubes, transistors, and microprocessors, take place inside the computer. There will be five computer generations between now and 2020, with the first one starting around 1940.
Earlier models of computers (1940-1956)Computers of the Second Generation (1956-1963)Computers of the Third Generation (1964-1971)Computers of the fourth generation (1971-Present)Computers of the fifth generationLearn more about generations of computers here:
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Annapurno
Page
Date
corite
a programe to input length and the
breath of the rectangle and cliculate the
anecan perimeter .write a program to input length and breadth of the rectangle and calculate the area and perimeter
Answer:
The program in Python is as follows:
Length = float(input("Length: "))
Width = float(input("Width: "))
Area = Length * Width
print("Area: ",Area)
Explanation:
This gets input for length
Length = float(input("Length: "))
This gets input for width
Width = float(input("Width: "))
This calculates the area
Area = Length * Width
This prints the calculated area
print("Area: ",Area)
Need help with 9.2 Lesson Practice edhesive asap please
Answer:
Can you add an attachment please
In this exercise we have to use the computer language knowledge in python, so the code is described as:
This code can be found in the attached image.
So the code can be described more simply below, as:
height = []
height.append([16,17,14])
height.append([17,18,17])
height.append([15,17,14])
print(height)
See more about python at brainly.com/question/26104476
Identify the following terms being described. Write your answers on the space provided.
1. Worldwide Web
______________________
2.E-mail
________________________
3.Powerline networking
_______________________
5.Cable
_______________________
Answer:
Find answers below.
Explanation:
1. Worldwide Web: In computing, WWW simply means World Wide Web. The world wide web was invented by Sir Tim Berners-Lee in 1990 while working with the European Council for Nuclear Research (CERN); Web 2.0 evolved in 1999. Basically, WWW refers to a collection of web pages that are located on a huge network of interconnected computers (the Internet). Also, users from all over the world can access the world wide web by using an internet connection and a web browser such as Chrome, Firefox, Safari, Opera, etc.
In a nutshell, the World Wide Web is an information system that is generally made up of users and resources (documents) that are connected via hypertext links.
2.E-mail: An e-mail is an acronym for electronic mail and it is a software application or program designed to let users send and receive texts and multimedia messages over the internet.
It is considered to be one of the most widely used communication channel or medium is an e-mail (electronic mail).
3. Powerline networking: this is a wired networking technology that typically involves the use of existing electrical cables in a building to connect and transmit data on network devices through powerline network adapters.
4. Cable: this include network cables such as CAT-5, CAT-6 and fiber optic cables used for connecting and transmitting signals between two or more network devices.
What does getfenv() do?
Answer: getfenv() is a type of function. Particually a envirotment function. for a lua coding.
Explanation: What this does it goes thourgh line of code in a particular order.
This means. getfenv is used to get the current environment of a function. It returns a table of all the things that function has access to. You can also set the environment of a function to another environment.
Forgot to include examples of where this could be used. Although not very common uses, there are some. In the past Script Builders used getfenv to get the environment of a script, and setfenv to set the environment of a created script’s environment to a fake environment, so they couldn’t affect the real one. They could also inject custom global functions.
Not entirely sure if this uses getfenv or setfenv, but the use in Crazyman32’s AeroGameFramework is making the environment of each module have access to other modules without having to require them, and having access to remotes without having to directly reference them.
Answer: ummm, who knows
Explanation:
Two character strings may have many common substrings. Substrings are required to be contiguous in the original string. For example, photograph and tomography have several common substrings of length one (i.e., single letters), and common substrings ph, to, and ograph as well as all the substrings of ograph. The maximum common substring length is 6. Let X = X122 . Im and Y = yıy2 - - • Yn be two character strings. Using dynamic programming, design an algorithm to find the maximum common substring length for X and Y using dynamic programming. Please follow the general steps for designing a dynamic programming solution as in Q1 (other than the actual programming part).
Answer:
Explanation:
The following function is written in Java. It takes two strings as parameters and calculates the longest substring between both of them and returns that substring length.
import java.util.*;
class Test
{
public static void main(String[] args)
{
String X = "photograph";
String Y = "tomography";
System.out.println(X + '\n' + Y);
System.out.println("Longest common substring length: " + longestSub(X, Y));
}
static int longestSub(String X, String Y)
{
char[] word1 = X.toCharArray();
char[] word2 = Y.toCharArray();
int length1 = X.length();
int length2 = Y.length();
int substringArray[][] = new int[length1 + 1][length2 + 1];
int longestSubstringLength = 0;
for (int i = 0; i <= length1; i++)
{
for (int j = 0; j <= length2; j++)
{
if (i == 0 || j == 0)
substringArray[i][j] = 0;
else if (word1[i - 1] == word2[j - 1])
{
substringArray[i][j]
= substringArray[i - 1][j - 1] + 1;
longestSubstringLength = Integer.max(longestSubstringLength,
substringArray[i][j]);
}
else
substringArray[i][j] = 0;
}
}
return longestSubstringLength;
}
}
Let's implement a classic algorithm: binary search on an array. Implement a class named BinarySearcher that provides one static method named search. search takes a SearchList as its first parameter and a Comparable as its second. If either parameter is null, or if the SearchList is empty, you should throw an IllegalArgumentException. SearchList is a provided class. It provides a get(int) method that returns the Comparable at that index, and a size method that returns the size of the SearchList. Those are the only two methods you should need! search returns a boolean indicating whether the passed value is located in the sorted SearchList. To search the sorted SearchList efficiently, implement the following algorithm: Examine the value in the middle of the current array (index (start + end) / 2) If the midpoint value is the value that we are looking for, return true If the value that we are looking for is greater than the midpoint value, adjust the current array to start at the midpoint if the value that we are looking for is less than the midpoint value, adjust the current array to end at the midpoint Continue until you find the value, or until the start reaches the end, at which point you can give up and return false This is a fun problem! Good luck! Keep in mind that every time you call SearchList.get that counts as one access, so you'll need to reduce unnecessary accesses to pass the test suite.
Answer:
Hope this helped you, and if it did , do consider giving brainliest.
Explanation:
import java.util.ArrayList;
import java.util.List;
//classs named BinarySearcher
public class BinarySearcher {
// main method
public static void main(String[] args) {
// create a list of Comparable type
List<Comparable> list = new ArrayList<>();
// add elements
list.add(1);
list.add(2);
list.add(3);
list.add(4);
list.add(5);
list.add(6);
list.add(7);
// print list
System.out.println("\nList : "+list);
// test search method
Comparable a = 7;
System.out.println("\nSearch for 7 : "+search(list,a));
Comparable b = 3;
System.out.println("\nSearch for 3 : "+search(list,b));
Comparable c = 9;
System.out.println("\nSearch for 9 : "+search(list,c));
Comparable d = 1;
System.out.println("\nSearch for 1 : "+search(list,d));
Comparable e = 12;
System.out.println("\nSearch for 12 : "+search(list,e));
Comparable f = 0;
System.out.println("\nSearch for 0 : "+search(list,f));
}
// static method named search takes arguments Comparable list and Comparable parameter
public static boolean search(List<Comparable> list, Comparable par) {
// if list is empty or parameter is null the throw IllegalArgumentException
if(list.isEmpty() || par == null ) {
throw new IllegalArgumentException();
}
// binary search
// declare variables
int start=0;
int end =list.size()-1;
// using while loop
while(start<=end) {
// mid element
int mid =(start+end)/2;
// if par equal to mid element then return
if(list.get(mid).equals(par) )
{
return true ;
}
// if mid is less than parameter
else if (list.get(mid).compareTo(par) < 0 ) {
start=mid+1;
}
// if mid is greater than parameter
else {
end=mid-1;
}
}
// if not found then retuen false
return false;
}
}import java.util.ArrayList;
import java.util.List;
//classs named BinarySearcher
public class BinarySearcher {
// main method
public static void main(String[] args) {
// create a list of Comparable type
List<Comparable> list = new ArrayList<>();
// add elements
list.add(1);
list.add(2);
list.add(3);
list.add(4);
list.add(5);
list.add(6);
list.add(7);
// print list
System.out.println("\nList : "+list);
// test search method
Comparable a = 7;
System.out.println("\nSearch for 7 : "+search(list,a));
Comparable b = 3;
System.out.println("\nSearch for 3 : "+search(list,b));
Comparable c = 9;
System.out.println("\nSearch for 9 : "+search(list,c));
Comparable d = 1;
System.out.println("\nSearch for 1 : "+search(list,d));
Comparable e = 12;
System.out.println("\nSearch for 12 : "+search(list,e));
Comparable f = 0;
System.out.println("\nSearch for 0 : "+search(list,f));
}
// static method named search takes arguments Comparable list and Comparable parameter
public static boolean search(List<Comparable> list, Comparable par) {
// if list is empty or parameter is null the throw IllegalArgumentException
if(list.isEmpty() || par == null ) {
throw new IllegalArgumentException();
}
// binary search
// declare variables
int start=0;
int end =list.size()-1;
// using while loop
while(start<=end) {
// mid element
int mid =(start+end)/2;
// if par equal to mid element then return
if(list.get(mid).equals(par) )
{
return true ;
}
// if mid is less than parameter
else if (list.get(mid).compareTo(par) < 0 ) {
start=mid+1;
}
// if mid is greater than parameter
else {
end=mid-1;
}
}
// if not found then retuen false
return false;
}
}
what is the output of this line of code?
print("hello"+"goodbye")
-"hello"+"goodbye"
-hello + goodbye
-hello goodbye
-hellogoodbye
Answer:
“hello” + “goodbye”
Explanation:
Selection Sort List the resulting array after each iteration of the outer loop of the selection sort algorithm. Indicate the number of character-to-character comparisons made for each iteration (line 07 of the Selection Sort algorithm at the end of the assignment). Sort the following array of characters (sort into alphabetical order): CQS A XBT Selection Sort 01 public static void selectionSort (int[] a) { 02 03 int n = a.length; for (int i = 0 ; i 0; j--) { if ( a[j-1] > a[j] ) { exchange(a, j-1, j); } else break; 10 } 12 private static void exchange (int[] a, int i, int j) { 13 // exchange the value at index i with the value at index j int temp = a[i]; a[i] = a[j]; a[j] = temp; 17 }
Solution :
Initial array = [tex]$\text{C,Q,S,A,X,B,T}$[/tex]
[tex]$n= 7$[/tex](length of the array)
[tex]$\text{1st}$[/tex] Iteration:
i = 1
j = 1
[tex]$\text{a[j-1]}$[/tex] = C
a[j] = Q
since [tex]$\text{a[j-1]}$[/tex] < a[j] , break from inner loop
Number of comparisons in 1st Iteration = 1
After 1st Iteration:
Array : C,Q,S,A,X,B,T
2nd Iteration:
i = 2
j = 2
a[j-1] = Q
a[j] = S
since a[j-1] < a[j], break from inner loop
Number of comparisons in 2nd Iteration = 1
After 2nd Iteration:
Array : C,Q,S,A,X,B,T
3rd Iteration:
i = 3
j = 3
a[j-1] = S
a[j] = A
since a[j-1] > a[j], exchange a[2] with a[3]
Array : C,Q,A,S,X,B,T
j = 2
a[j-1] = Q
a[j] = A
since a[j-1] > a[j], exchange a[1] with a[2]
Array : C,A,Q,S,X,B,T
j = 1
a[j-1] = C
a[j] = A
since a[j-1] > a[j], exchange a[0] with a[1]
Array : A,C,Q,S,X,B,T
j = 0, break from inner loop
Number of comparisons in 3rd Iteration = 3
After 3rd Iteration:
Array : A,C,Q,S,X,B,T
4th Iteration:
i = 4
j = 4
a[j-1] = S
a[j] = X
since a[j-1] < a[j], break from inner loop
Number of comparisons in 4th Iteration = 1
After 4th Iteration:
Array : A,C,Q,S,X,B,T
5th Iteration:
i = 5
j = 5
a[j-1] = X
a[j] = B
since a[j-1] > a[j], exchange a[4] with a[5]
Array : A,C,Q,S,B,X,T
j = 4
a[j-1] = S
a[j] = B
since a[j-1] > a[j], exchange a[3] with a[4]
Array : A,C,Q,B,S,X,T
j = 3
a[j-1] = Q
a[j] = B
since a[j-1] > a[j], exchange a[2] with a[3]
Array : A,C,B,Q,S,X,T
j = 2
a[j-1] = C
a[j] = B
since a[j-1] > a[j], exchange a[1] with a[2]
Array : A,B,C,Q,S,X,T
j = 1
a[j-1] = A
a[j] = B
since a[j-1] < a[j], break from inner loop
Number of comparisons in 5th Iteration = 5
After 5th Iteration:
Array : A,B,C,Q,S,X,T
6th Iteration:
i = 6
j = 6
a[j-1] = X
a[j] = T
since a[j-1] > a[j], exchange a[5] with a[6]
Array : A,B,C,Q,S,T,X
j = 5
a[j-1] = S
a[j] = T
since a[j-1] < a[j], break from inner loop
Number of comparisons in 6th Iteration = 2
After 6th Iteration:
Array : A,B,C,Q,S,T,X
Sorted Array : A B C Q S T X
Write a script called fact.sh that is located in your workspace directory to calculate the factorial of a number n; where n is a non-negative integer between 1 and 20 that is passed as a parameter from the command line (e.g. ./fact.sh 5). The result should be echoed to the screen as a single integer (e.g. 120).
NOTE: Do not include any other output, just output the single integer result.
Submit your code to the auto-grader by pressing Check-It!
NOTE: You can submit as many times as you want up until the due date.
Answer:
hope this helps
Explanation:
Write an algorithm (pseudo-code) that takes an unsorted list of n integers and outputs a sorted list of all duplicate integers. There must be no duplicates in the output list, also the output list should be a sorted list. The algorithm must run in O(n) time. Show your analysis of the running time. Note: Assume that inputs are integer values from 0 to 255. (Hint: use the concept that being used in the separate chaining)
Answer:
brainliest if it did help you
Explanation:
Given array : A[0...n-1]Now, create a count array Cnt[0...n-1]then, initialize Cnt to zero
for(i=0...n-1)
Cnt[i]=0 ---------O(n) time
Linearly traverse the list and increment the count of respected number in count array.
for(i=0...n-1)
Cnt[A[i]]++; ---------O(n) time
Check in the count array if duplicates exist.
for(i=0...n-1){
if(C[i]>1)
output (i); -----------O(n) time
}
analysis of the above algorithm:
Algorithm takes = O(1 + n + n + n)
= O(n)
//java code
public class SortIntegers {
public static void sort(int[] arr) {
int min = arr[0];
int max = arr[0];
for (int i = 0; i < arr.length; ++i) {
if (arr[i] > max) {
max = arr[i];
}
if (arr[i] < min) {
min = arr[i];
}
}
int counts[] = new int[max - min + 1];
for (int i = 0; i < arr.length; ++i) {
counts[arr[i] - min]++;
}
for (int i = 0; i < counts.length; ++i) {
if (counts[i] > 1) {
System.out.print((i + min) + " ");
}
}
System.out.println();
}
public static void main(String[] args) {
sort(new int[] { 5, 4, 10, 2, 4, 10, 5, 3, 1 });
}
}
Outlines help you visualize the slides and the points you will include on each slide.
False
True
Answer:
True
Explanation:
because it was correct
Write a piece of code that constructs a jagged two-dimensional array of integers named jagged with five rows and an increasing number of columns in each row, such that the first row has one column, the second row has two, the third has three, and so on. The array elements should have increasing values in top-to-bottom, left-to-right order (also called row-major order). In other words, the array's contents should be the following: 1 2, 3 4, 5, 6 7, 8, 9, 10 11, 12, 13, 14, 15
PROPER OUTPUT: jagged = [[1], [2, 3], [4, 5, 6], [7, 8, 9, 10], [11, 12, 13, 14, 15]]
INCORRECT CODE:
int jagged[][] = new int[5][];
for(int i=0; i<5; i++){
jagged[i] = new int[i+1]; // creating number of columns based on current value
for(int j=0, k=i+1; j jagged[i][j] = k;
}
}
System.out.println("Jagged Array elements are: ");
for(int i=0; i for(int j=0; j System.out.print(jagged[i][j]+" ");
}
System.out.println();
}
expected output:jagged = [[1], [2, 3], [4, 5, 6], [7, 8, 9, 10], [11, 12, 13, 14, 15]]
current output:
Jagged Array elements are:
1
2 3
3 4 5
....
Answer:
Explanation:
The following code is written in Java and it uses nested for loops to create the array elements and then the same for loops in order to print out the elements in a pyramid-like format as shown in the question. The output of the code can be seen in the attached image below.
class Brainly {
public static void main(String[] args) {
int jagged[][] = new int[5][];
int element = 1;
for(int i=0; i<5; i++){
jagged[i] = new int[i+1]; // creating number of columns based on current value
for(int x = 0; x < jagged[i].length; x++) {
jagged[i][x] = element;
element += 1;
}
}
System.out.println("Jagged Array elements are: ");
for ( int[] x : jagged) {
for (int y : x) {
System.out.print(y + " ");
}
System.out.println(' ');
}
}
}
I need help
I am thinking about coming out to my mom because we are going to the store today and I will be in the car, I dont know if I should or not
Answer:
do it! you will have to one day so why not now? hopefully she will understand and say nice things as well and be like mom ive
been thinking a lot and i really want to tell you something. Explanation:
Answer:most likely she is your parent that you live with so she might already know but has not said anything it also depends her personality but if your ready and know or think she would not hate you forever go for it
Explanation:
The variable strFirst's scope is _____.
Answer:
- the usernameMaker function
Explanation:
When you look at the code, you can see it's located alongside the usernameMaker. It it only utilized then, therefore being it's scope. For reassurance, it's also correct on Edge.
I hope this helped!
Good luck <3
Which tab can be used to change the theme and background style of a presentation?
O Design
O Home
O Insert
O View
Answer:
Design
Explanation:
seems the most correct one..
Mohammed needs to ensure that users can execute a query against a table but provide different values to the query each time it is run. Which option will achieve this goal?
parameter queries
dynamic queries
query joins
static queries
Answer:
the answer is B
Explanation:
A major advantage of direct mapped cache is its simplicity and ease of implementation. The main disadvantage of direct mapped cache is: a. it is more expensive than fully associative and set associative mapping. b. it has a greater access time than any other method. c. its performance is degraded if two or more blocks that map to the same location are used alternately. d. it does not allow the cache to store the tag that corresponds to the block currently residing in that cache location.
brainlest pl jk mmmmmmmmmmmmm
The following table describes the required fields for two classes and typical values stored in those fields.
You are required to create a base class Printer and its child class PrinterCumScanner. Each of these classes should have user defined constructor and overridden Display() method so that the following test driver can work properly.
Answer:
hope this helps,if it did pls mark my ans as brainliest
Explanation:
using System;
class Printer{ string companyName; int pagesOutput;
double price;
public Printer(string companyName,int pagesOutput,double price){
this.companyName=companyName; this.pagesOutput=pagesOutput; this.price=price;
}
public virtual void Display(){ Console.WriteLine("companyName: "+companyName+" pagesOutput: "+pagesOutput+" price: "+price);
}
}
class PrinterCumScanner:Printer{ int imageDpi;
public PrinterCumScanner(string companyName,int pagesOutput,double price,int imageDpi):base(companyName,pagesOutput,price){ this.imageDpi=imageDpi; }
public override void Display(){ base.Display(); Console.WriteLine("imageDpi: "+imageDpi);
}
}
public class Program { static void Main(string[] args) { const int NUM_PRINTERS=3;
Printer []stock=new Printer[NUM_PRINTERS];
stock[0]=new Printer("HP",40,89.50);
stock[1]=new PrinterCumScanner("HP",40,215.0,320); stock[2]=new PrinterCumScanner("Cannon",30,175.0,240);
foreach(Printer aPrinter in stock){ aPrinter.Display();
}
}
}
describe how sodium ammonium chloride can be separated from a solid mixture of ammonium chloride and anhydrous calcium chloride
Answer:
There are way in separating mixtures of chlorides salts such as that of sodium chloride and ammonium chloride. It can be done by crystallization, filtration or sublimation. If we want to separate the mixture, we have to heat up to 330-350 degrees Celsius and collect the gas that will be produced.
(main.c File)
Counting the character occurrences in a file
For this task you are asked to write a program that will open a file called “story.txt”
and count the number of occurrences of each letter from the alphabet in this file.
At the end your program will output the following report:
Number of occurrences for the alphabets:
a was used – times.
b was used – times.
c was used – times…. …and so, on
Assume the file contains only lower-case letters and for simplicity just a single
paragraph. Your program should keep a counter associated with each letter of the
alphabet (26 counters) [Hint: Use array]
Your program should also print a histogram of characters count by adding
a new function print Histogram (int counters []). This function receives the
counters from the previous task and instead of printing the number of times each
character was used, prints a histogram of the counters. An example histogram for
three letters is shown below) [Hint: Use the extended asci character 254]
Answer:
C code
Explanation:
#include <stdio.h>
void histrogram(int counters[])
{
int i,j;
int count;
for(i=0;i<26;i++)
{
count=counters[i];
printf("%c ",i+97);
for(j=0;j<count;j++)
{
printf("="); //= is used
}
printf("\n");
}
}
int main()
{
FILE* fp;
int i;
int arr[26];
char c;
int val;
// Open the file
fp = fopen("story.txt", "r");
if (fp == NULL) {
printf("Could not open file ");
return 0;
}
else
{
for(i=0;i<26;i++)
arr[i]=0;
for (c = getc(fp); c != EOF; c = getc(fp))
{
if(c>='a' && c<='z')
{
val = c-97;
//printf("%d ",val);
arr[val]++;
}
}
histrogram(arr);
}
}
14. Video game legend Shigeru Miyamoto designed all EXCEPT which of the following games?
a) Donkey Kong
b) Mario Bros
c) The Legend of Zelda
d) Pac-Man
11. Its collection of toys which could be used in the game via an implanted RFID chip made Activision’s game _______ one of the most important in gaming history.
a) 102 Dalmations
b) Skylanders
c) Lego Star Wars
d) Super Monkey Ball
Answer:
I think it's B correct me if I'm wrong
Explanation:
Answer:
B
Explanation:
I say it is the right one although in this 2021 there is no other game but it is its 10th anniversary
Define a class StatePair with two template types (T1 and T2), a constructor, mutators, accessors, and a PrintInfo() method. Three vectors have been pre-filled with StatePair data in main():vector> zipCodeState: ZIP code - state abbreviation pairsvector> abbrevState: state abbreviation - state name pairsvector> statePopulation: state name - population pairsComplete main() to use an input ZIP code to retrieve the correct state abbreviation from the vector zipCodeState. Then use the state abbreviation to retrieve the state name from the vector abbrevState. Lastly, use the state name to retrieve the correct state name/population pair from the vector statePopulation and output the pair.Ex: If the input is:21044the output is:Maryland: 6079602
Answer:
Here.Hope this helps and do read carefully ,you need to make 1 .cpp file and 1 .h file
Explanation:
#include<iostream>
#include <fstream>
#include <vector>
#include <string>
#include "StatePair.h"
using namespace std;
int main() {
ifstream inFS; // File input stream
int zip;
int population;
string abbrev;
string state;
unsigned int i;
// ZIP code - state abbrev. pairs
vector<StatePair <int, string>> zipCodeState;
// state abbrev. - state name pairs
vector<StatePair<string, string>> abbrevState;
// state name - population pairs
vector<StatePair<string, int>> statePopulation;
// Fill the three ArrayLists
// Try to open zip_code_state.txt file
inFS.open("zip_code_state.txt");
if (!inFS.is_open()) {
cout << "Could not open file zip_code_state.txt." << endl;
return 1; // 1 indicates error
}
while (!inFS.eof()) {
StatePair <int, string> temp;
inFS >> zip;
if (!inFS.fail()) {
temp.SetKey(zip);
}
inFS >> abbrev;
if (!inFS.fail()) {
temp.SetValue(abbrev);
}
zipCodeState.push_back(temp);
}
inFS.close();
// Try to open abbreviation_state.txt file
inFS.open("abbreviation_state.txt");
if (!inFS.is_open()) {
cout << "Could not open file abbreviation_state.txt." << endl;
return 1; // 1 indicates error
}
while (!inFS.eof()) {
StatePair <string, string> temp;
inFS >> abbrev;
if (!inFS.fail()) {
temp.SetKey(abbrev);
}
getline(inFS, state); //flushes endline
getline(inFS, state);
state = state.substr(0, state.size()-1);
if (!inFS.fail()) {
temp.SetValue(state);
}
abbrevState.push_back(temp);
}
inFS.close();
// Try to open state_population.txt file
inFS.open("state_population.txt");
if (!inFS.is_open()) {
cout << "Could not open file state_population.txt." << endl;
return 1; // 1 indicates error
}
while (!inFS.eof()) {
StatePair <string, int> temp;
getline(inFS, state);
state = state.substr(0, state.size()-1);
if (!inFS.fail()) {
temp.SetKey(state);
}
inFS >> population;
if (!inFS.fail()) {
temp.SetValue(population);
}
getline(inFS, state); //flushes endline
statePopulation.push_back(temp);
}
inFS.close();
cin >> zip;
for (i = 0; i < zipCodeState.size(); ++i) {
// TODO: Using ZIP code, find state abbreviation
}
for (i = 0; i < abbrevState.size(); ++i) {
// TODO: Using state abbreviation, find state name
}
for (i = 0; i < statePopulation.size(); ++i) {
// TODO: Using state name, find population. Print pair info.
}
}
Statepair.h
#ifndef STATEPAIR
#define STATEPAIR
#include <iostream>
using namespace std;
template<typename T1, typename T2>
class StatePair {
private:
T1 key;
T2 value;
public:
// Define a constructor, mutators, and accessors
// for StatePair
StatePair() //default constructor
{}
// set the key
void SetKey(T1 key)
{
this->key = key;
}
// set the value
void SetValue(T2 value)
{
this->value = value;
}
// return key
T1 GetKey() { return key;}
// return value
T2 GetValue() { return value;}
// Define PrintInfo() method
// display key and value in the format key : value
void PrintInfo()
{
cout<<key<<" : "<<value<<endl;
}
};
#endif
In this exercise we have to use the knowledge in computational language in C++ to write the following code:
We have the code can be found in the attached image.
So in an easier way we have that the code is
#include<iostream>
#include <fstream>
#include <vector>
#include <string>
#include "StatePair.h"
using namespace std;
int main() {
ifstream inFS;
int zip;
int population;
string abbrev;
string state;
unsigned int i;
vector<StatePair <int, string>> zipCodeState;
vector<StatePair<string, string>> abbrevState;
vector<StatePair<string, int>> statePopulation;
inFS.open("zip_code_state.txt");
if (!inFS.is_open()) {
cout << "Could not open file zip_code_state.txt." << endl;
return 1;
}
while (!inFS.eof()) {
StatePair <int, string> temp;
inFS >> zip;
if (!inFS.fail()) {
temp.SetKey(zip);
}
inFS >> abbrev;
if (!inFS.fail()) {
temp.SetValue(abbrev);
}
zipCodeState.push_back(temp);
}
inFS.close();
inFS.open("abbreviation_state.txt");
if (!inFS.is_open()) {
cout << "Could not open file abbreviation_state.txt." << endl;
return 1;
}
while (!inFS.eof()) {
StatePair <string, string> temp;
inFS >> abbrev;
if (!inFS.fail()) {
temp.SetKey(abbrev);
}
getline(inFS, state);
getline(inFS, state);
state = state.substr(0, state.size()-1);
if (!inFS.fail()) {
temp.SetValue(state);
}
abbrevState.push_back(temp);
}
inFS.close();
inFS.open("state_population.txt");
if (!inFS.is_open()) {
cout << "Could not open file state_population.txt." << endl;
return 1;
}
while (!inFS.eof()) {
StatePair <string, int> temp;
getline(inFS, state);
state = state.substr(0, state.size()-1);
if (!inFS.fail()) {
temp.SetKey(state);
}
inFS >> population;
if (!inFS.fail()) {
temp.SetValue(population);
}
getline(inFS, state);
statePopulation.push_back(temp);
}
inFS.close();
cin >> zip;
for (i = 0; i < zipCodeState.size(); ++i) {
}
for (i = 0; i < abbrevState.size(); ++i) {
}
for (i = 0; i < statePopulation.size(); ++i) {
}
}
Statepair.h
#ifndef STATEPAIR
#define STATEPAIR
#include <iostream>
using namespace std;
template<typename T1, typename T2>
class StatePair {
private:
T1 key;
T2 value;
public:
StatePair()
{}
void SetKey(T1 key)
{
this->key = key;
}
void SetValue(T2 value)
{
this->value = value;
}
T1 GetKey() { return key;}
T2 GetValue() { return value;}
void PrintInfo()
{
cout<<key<<" : "<<value<<endl;
}
};
See more about C code at brainly.com/question/19705654
CHALLENGE ACTIVITY
1.6.1: Type casting: Computing average owls per zoo.
Assign avg_owls with the average owls per zoo. Print avg_owls as an integer.
Sample output for inputs: 1 2 4
Average owls per zoo: 2
-------------------------------------------------------------------
Someone please explain what I am doing wrong?
Answer:
avg_owls=0.0
num_owls_zooA = int(input())
num_owls_zooB = int(input())
num_owls_zooC = int(input())
num_zoos = 3
avg_owls = (num_owls_zooA + num_owls_zooB + num_owls_zooC) / num_zoos
print('Average owls per zoo:', int(avg_owls))
Explanation:
There is a problem while you are trying the calculate the average owls per zoo.
As you may know, in order to calculate the average, you need to get the total number of owls in all the zoos, then divide it to the number of zoos. That is why you need to sum num_owls_zooA + num_owls_zooB + num_owls_zooC and divide the result by num_zoos
Be aware that the average is printed as integer value. That is why you need to cast the avg_owls to an int as int(avg_owls)
Sergio needs to tell his team about some negative feedback from a client. The team has been
working hard on this project, so the feedback may upset them. Which of the following explains
the best way for Sergio to communicate this information?
A) Hold an in person meeting so that he can gauge the team's body language to assess their
reaction
B) Send a memorandum so everyone will have the feedback in writing
C) Hold a video conference so everyone can see and hear about the client's concern without the group witnessing each other's reactions
D) Send an email so everyone will have time to think about the feedback before the next team meeting
Answer:
A
Explanation:
I feel that if everyone is with eachother, there may be a better hope to improve the next time
Taran is concerned with the security of his macros in a database. Which security option could he use to provide protection?
digital signatures
hide database objects
start-up options
secure VBA code
Answer:security VBA code
Explanation:
The Basic premise of____is that objects can be tagged, tracked, and monitored through a local network, or across the Internet.
The basic premise of
a. artificial intelligence
b. intelligent workspaces
c. the Internet of Things
d. the digital divide
Answer:
C.
Explanation:
Internet of things
The Basic premise of the Internet of Things is that objects can be tagged, tracked, and monitored through a local network, or across the Internet option (c) is correct.
What is IoT?The term "Internet of things" refers to actual physical items that have sensors, computing power, software, and other innovations and can link to those other systems and gadgets via the Internet or other communication networks and share files with them.
As we know,
Using a local network or the Internet, things may be identified, tracked, and monitored is the fundamental tenet of the Internet of Things.
Thus, the Basic premise of the Internet of Things is that objects can be tagged, tracked, and monitored through a local network, or across the Internet option (c) is correct.
Learn more about the IoT here:
https://brainly.com/question/25703804
#SPJ2
how many nibbles make one kilobyte
Answer:
2000 nibbles
Explanation:
2000 nibbles is needed for 1 kilobyte
the levels of classification of organisms in order are: domain, kingdom, phylum, class, order, family, genus, and species. The broadest, least specific level is____________________
Answer:
Domain.
Explanation:
In Science, this biological classification of living organisms based on similarities or characteristics such as eyes, number of legs, etc., is generally referred to as taxonomy.
Taxonomy can be defined as the process of naming, classification and description of living organisms such as plants and animals.
Basically, the eight (8) biological classification (taxonomy) used for grouping and organizing organisms are; kingdom, domain, phylum, family, order, class, species and genus.
Hence, taxonomy helps scientist to have a good understanding and knowledge when studying various organisms.
Furthermore, the broadest, least specific level of the biological classification of living organisms is domain. The three (3) domain in which living organisms can be classified are: Bacteria, Eukaryote, and Archaea.
Answer:
doman
Explanation: