Chris drove 265 miles using 10 gallons of gas. At this rate, how many gallons of gas would he need to drive 424 miles?

Answer:

An increase of $0.94

Step-by-step explanation:

Answer:

-3.21

Step-by-step explanation:

If you pay close attention the numbers are 5 points away from each other, so after -3.2 is -3.21! Hope that helped love :)

Answer:

paying taxes, voting , serving a public office, and obeying the law.

Answer: D,C,B

Step-by-step explanation:These are the answers

Answer:

false

Step-by-step explanation: ...

Answer:

22:2, 55:5, 1:11

Step-by-step explanation:

Answer:

22:2 55:5 and no others

Step-by-step explanation:

Answer:

x = 39

Step-by-step explanation:

A circle is made up of 360 degrees

235+ 54+ x+32 = 360

Combine like terms

x+321=360

Subtract 321 from each side

x+321-321 = 360-321

x = 39

1280 cones because you would add 60 +4 and multiply by 20, and would get 1280 cones.

Answer:

Step-by-step explanation:

13/16 dived by 5/6 = 9/40

7 dived by 1/6 = 42

2 1/5 dived by 1 1/3 = 1 13/20

2 1/7 dived by 3/28 = 20

Answer:

21.97025026/250

Answer:

to convey the parametric expression to be use the explosions

Answer:

6n+1

Step-by-step explanation:

n=term#

Answer:

x=12

Step-by-step explanation:

multiply 2 from both sides to isolate x

then u should end up with 1x=12

Answer:

x=20°

Step-by-step explanation:

1.) m<DOB = m<DOE + m<BOE (or m<EOB)    

2.) m<DOB = 90°+x

3.) m<AOC = m<DOB

4.) 110° = 90° + x

5.) x = 20°

1.) given

2.) substitution

3.) vertical/reflexive

4.) substitution

5.) algebra

The possible third side to a triangle is 12.

Given that,

Based on the above information, the calculation is as follows:

Here we use the pythagoras theorem.

[tex]= \sqrt{13^2 - 4^2} \\\\= \sqrt{169-16} \\\\= \sqrt{153}[/tex]

= 12.37

= 12

Learn more: brainly.com/question/17429689

Answer:

There is not enough evidence to suggest that mean starting salary of a graduate with a bachelor in economics is different from $48,500.

Step-by-step explanation:

In this case we need to test whether the mean starting salary of a graduate with a bachelor in economics is $48,500.

The information provided are:

[tex]\bar x=\$43350\\s=\$15000\\n=50\\\alpha =0.01[/tex]

The hypothesis for the test can be defined as follows:

H₀: The mean starting salary of a graduate with a bachelor in economics is $48,500, i.e. μ = 48500.

Hₐ: The mean starting salary of a graduate with a bachelor in economics is different from $48,500, i.e. μ ≠ 48500.

As the population standard deviation is not known we will use a t-test for single mean.

Compute the test statistic value as follows:

 [tex]t=\frac{\bar x-\mu}{s/\sqrt{n}}[/tex]

   [tex]=\frac{43350-48500}{15000/\sqrt{50}}\\\\=-2.42773\\\\\approx -2.43[/tex]

Thus, the test statistic value is -2.43.

Compute the p-value of the test as follows:

 [tex]p-value=2\times P(t_{49}>-2.43)=0.0188[/tex]

*Use a t-table.

Thus, the p-value of the test is 0.0188.

Decision rule:

If the p-value of the test is less than the significance level then the null hypothesis will be rejected and vice-versa.

p-value = 0.0188 > α = 0.01

The null hypothesis will not be rejected at 1% level of significance.

Thus, concluding that there is not enough evidence to suggest that mean starting salary of a graduate with a bachelor in economics is different from $48,500.

Answer:

The answer is 11

hence 5 + 6 = 11

Answer:

hi

Step-by-step explanation:

[tex]5 + 3(2) = 11[/tex]

probably…

Answer:

Using the snowflake method, you have to find the factors of 256 that add up to get 32.

The result will look like this:

(g-16)(g-16)

Answer:

[tex](g-16)^2[/tex]

Step-by-step explanation:

[tex]g^2-32g + 256[/tex]

To factor it you should remember that

[tex](a-b)^2 = a^2 -2ab+b^2[/tex]

It is easy to seee that

[tex]32 = 2 \cdot 16[/tex]

and

[tex]256 = 16^2[/tex]

Therefore

[tex]g^2-32g + 256 = g^2 - (2\cdot 16)g+ 16^2 = (g-16)^2[/tex]

Answer:

11.8% Decrease

Step-by-step explanation:

I googles it i am sorry if it's not right

Step-by-step explanation:

7y=4x-5

y=(4/7)x-5/7

slope is equal to m where m is

y=mx+b

in this case m is 4/7

so slope =4/7

Answer:

Not 100% sure on this make sure you double check

Step-by-step explanation:

X- 10          

Y- 10

Slope- (-1)

like I said this could be wrong  

Answer:

hope it helps...

Step-by-step explanation:

The ratio of a number x and four added to two:

= 4x + 2 = 0

= 4x = -2

= 4x/4 = -2/4

= x = -2/4

= x = -1/2

Answer:

270 miles and 180 minutes

Step-by-step explanation:

Answer:

-

Step-by-step explanation:

I took the test

The correct operator that enters a circle is a subtraction sign.

Given the expressions

[tex](4x^5-8x) ()(3x^2-8x+9)[/tex]

We need to know which sign goes into the bracket that will give a trinomial when simplified.

A trinomial is a function containing 3-terms.

Using the subtraction sign.

[tex](4x^5-8x) - (3x^2-8x+9)[/tex]

Expand

[tex]= 4x^5-8x - 3x^2+8x-9\\= 4x^5-3x^2-8x+8x-9\\=4x^5-3x^2+0-9\\=4x^5-3x^2-9[/tex]

Since the resulting term is a trinomial (3 terms), hence the correct operator that enters a circle is a subtraction sign.

Learn more here: https://brainly.com/question/1320408

Answer:

[tex]\mathbf{y(x) = \dfrac{(c_1 + c_2) \ cos (x)}{e^{6x} }+ \dfrac{i(c_1 -c_2) \ sin (x)}{e^{6x}}+ c_3e^{3\ x}}[/tex]

Step-by-step explanation:

The objective of this question is to solve:

[tex]\dfrac{dy(x)}{dx}+ 9\dfrac{d^2y(dx)}{dx^2}+\dfrac{d^3y(x)}{dx^3}-111y(x) = 0 :[/tex]

Suppose the general solution is proportional to [tex]e^{\lambda x}[/tex] for [tex]\lambda[/tex] is constant; Then:

Let's replace [tex]y(x) = e^{\lambda\ x}[/tex] into the above equation:

i.e.

[tex]\dfrac{d^3}{dx^3}(e ^{\lambda x} )+ 9 \dfrac{d^2}{dx^2}(e ^{\lambda x} ) + \dfrac{d}{dx}(e ^{\lambda x} )- 111 \ e ^{\lambda x} = 0[/tex]

To Replace:

[tex]\dfrac{d^3}{dx^3}(e ^{\lambda x} )[/tex] with [tex]\lambda^3 e ^{\lambda x }[/tex]

[tex]\dfrac{d^2}{dx^2}(e ^{\lambda x} ) \ with \ \lambda^2 e^{\lambda\ x}[/tex]

[tex]\dfrac{d}{dx}(e ^{\lambda x} ) \ with \ \lambda e ^{\lambda \ x}[/tex]

Thus;

[tex]\lambda^3 e ^{\lambda x }[/tex] + [tex]9 \lambda^2 e^{\lambda\ x}[/tex] + [tex]\lambda e ^{\lambda \ x}[/tex] - 111 [tex]e ^{\lambda \ x}[/tex] = 0

[tex]e ^{\lambda \ x} (\lambda ^3 + 9 \lambda ^2 + \lambda - 111 )= 0[/tex]

∴

In as much as [tex]e^{ \lambda x}\neq 0[/tex] for any finite [tex]\lambda[/tex]; Then:

[tex]\lambda ^3 + 9 \lambda ^2 + 111 = 0[/tex]

By Factorization:

[tex](\lambda - 3) ( \lambda ^2 + 12 \lambda + 37) = 0[/tex]

[tex]\lambda = -6 + i \ or\ \lambda = -6 - i \ or \ \lambda = 3[/tex]

However;

The root [tex]\lambda = -6 \pm i[/tex] yield;

[tex]y_1 = (x) = c_1 e ^ {(-6+i)x}[/tex]

[tex]y_2 (x) = c_2e^{(-6-i)x}[/tex]

The root [tex]\lambda = 3[/tex] yield;

[tex]y_3(x) = c_3 e^{3x}[/tex]

∴

The general solution is:

[tex]y(x) = y_1(x) + y_2(x) + y_3(x) = \dfrac{c_1}{c^{(6-i)}x}+\dfrac{c_2}{c^{(6+i)}x}+ c_3e^{3x}[/tex]

Using Euler's Identity ;

[tex]e^{\alpha+i \beta} = e^\alpha \ cos (\beta ) + i \ e^\alpha \ sin ( \beta)[/tex]

[tex]y(x) = c_1 ( \dfrac{cos (x) }{e^{6x}}+ \dfrac{i \ sin x }{e^{6x} }) + c_2 ( \dfrac{cos (x)}{e^{6x}}- \dfrac{-i \ sin (x)}{e^{6x}})+c_3 e^{3x}[/tex]

[tex]\mathbf{y(x) = \dfrac{(c_1 + c_2) \ cos (x)}{e^{6x} }+ \dfrac{i(c_1 -c_2) \ sin (x)}{e^{6x}}+ c_3e^{3\ x}}[/tex]

Answer:

5 2/5 > 3 1/2. 5 2/5 is greater than 3 1/2

Step-by-step explanation:

Answer:

I believe that 5 2/5 is greater than 3 1/2

Answer:

y-2x -8

Step-by-step explanation:

your jus gonna right it back because it's parallel which means it's the same thing.